Prob 1.    End products of the following sequence of reactions is

              

A.

B.

C.

D.

Sol.Intermediate is

 which loses CO2 on heating.

∴     (C)

Prob 2.    End product of the reaction    is

A.

B.

C.

D.

Sol.         NaBH4 reduces ketonic group but not acidic group

 is the intermediate which forms cyclic ester.

Prob 3.    R – CH2 – CH2OH can be converted into R- CH2CH2COOH. The correct sequence of reagents is

(A)                          (B) 

(C)                                         (D) 

Sol.        

      (A)

Prob 4.    The ease of alkaline hydrolysis is more for

A.

B  

C.

D.

Sol.         There is more electron deficiency on carbonyl carbon in

     (A)

 

Prob 5.    Which of the following undergoes HVZ reaction?

(A) HCOOH                                                    (B)  CCl3COOH

(C) C6H5COOH                                                (D)  none

Sol.         None of these contains a – hydrogen.

        (D) 

Prob 6.    The product C in the reaction

(A)  CH3CH = CHCHO                                     (B)  CH3CH = CHCOOH

(C)  CH3CH2CHO                                             (D)  CH3CH­2CH2COOH

Sol.        

 

Prob 7.    The end product of the reaction is

C is

(A)     propanoic acid                                      (B)  adipic acid

(C)     malonic acid                                         (D)  succinic acid

Sol.

Prob 8.    Find out D in the following sequence

A.

B. 218

C.

D.

Sol.

Prob 9.    The order of the acidic strength of following acids is

               (i) CH3CH2COOH           (ii) CH2 = CHCOOH            (iii) CH º CCOOH

               (A)     i > ii > iii                                                (B)  iii > ii > i

               (C)     ii > i > iii                                                (D)  iii > i > ii

Sol.      sp hybridized carbon is most electronegative and it stabilizes the carboxylate ion. to the maximum extent

Prob 10.

A and B are 

(A) CH3COCH2COOH, CH3COCH3                    (B)  CH3CH(OH)CH3, CH­3COCH3

(C) CH3COCH3, CH3COOH                               (D)  CH3CH = CHCOOH, CH3CH = CH2

Sol.

Prob 11. 

B is

(A)                                    (B) 

(C)                                 (D) 

Sol.        

 

∴ (A)

Prob 12

 A is

A.

B.

C.

D.

Sol.

Prob 13.  The carboxylic acid which has maximum solubility in water is

               (A) phthalic acid                                              (B)  succinic acid

               (C) malonic acid                                              (D)  salicylic acid

 

Sol.         Salicylic acid has intramolecular hydrogen bonding. So it is least soluble. Out of the first three acids malonic acid has smallest non – polar alkyl part. So it is most soluble.

 (C)

Prob. 14

A.

B.

C.

D. None of these

Sol.

Prob.

In the reaction

               Identify C.

               (A)     CH3CH2CN                                             (B)  CH3CH2CH2NH2

               (C)     CH3CH2CH2OH                                       (D)  (CH3CH2CO)2

Sol.

 

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Class 12 Chemistry Aldehydes, Ketones and Carboxylic Acids All Topic Notes Class 12 Chemistry All Chapters Notes

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