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**Class:**12th**Subject:**Maths**Topic:**Differentiation**Resource:**Notes

## CBSE Notes Class 12 Maths Differentiation

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**Derivative**

The rate of change of a quantity y with respect to another quantity x is called the derivative or differential coefficient of y with respect to x .

**Differentiation of a Function**

Let f(x) is a function differentiable in an interval [a, b]. That is, at every point of the interval, the derivative of the function exists finitely and is unique. Hence, we may define a new function g: [a, b] → R, such that, ∀ x ∈ [a, b], g(x) = f'(x).

This new function is said to be differentiation (differential coefficient) of the function f(x) with respect to x and it is denoted by df(x) / d(x) or Df(x) or f'(x).

**Differentiation ‘from First Principle**

Let f(x) is a function finitely differentiable at every point on the real number line. Then, its derivative is given by

**Standard Differentiations**

1. d / d(x) (x^{n}) = nx^{n – 1}, x ∈ R, n ∈ R

2. d / d(x) (k) = 0, where k is constant.

3. d / d(x) (e^{x}) = e^{x}

4. d / d(x) (a^{x}) = a^{x} log_{e} a > 0, a ≠ 1

**Fundamental Rules for Differentiation**

(v) if d / d(x) f(x) = φ(x), then d / d(x) f(ax + b) = a φ(ax + b)

(vi) Differentiation of a constant function is zero i.e., d / d(x) (c) = 0.

**Geometrically Meaning of Derivative at a Point**

Geometrically derivative of a function at a point x = c is the slope of the tangent to the curve y = f(x) at the point {c, f(c)}.

Slope of tangent at P = lim_{ x → c} f(x) – f(c) / x – c = {df(x) / d(x)}_{ x = c} or f’ (c).

**Different Types of Differentiable Function**

1. **Differentiation of Composite Function** (Chain Rule)

If f and g are differentiable functions in their domain, then fog is also differentiable and

(fog)’ (x) = f’ {g(x)} g’ (x)

More easily, if y = f(u) and u = g(x), then dy / dx = dy / du * du / dx.

If y is a function of u, u is a function of v and v is a function of x. Then,

dy / dx = dy / du * du / dv * dv / dx.

2. **Differentiation Using Substitution**

In order to find differential coefficients of complicated expression involving inverse trigonometric functions some substitutions are very helpful, which are listed below .

3. **Differentiation of Implicit Functions**

If f(x, y) = 0, differentiate with respect to x and collect the terms containing dy / dx at one side and find dy / dx.

Shortcut for Implicit Functions For Implicit function, put d /dx {f(x, y)} = – ∂f / ∂x / ∂f / ∂y, where ∂f / ∂x is a partial differential of given function with respect to x and ∂f / ∂y means Partial differential of given function with respect to y.

4. **Differentiation of Parametric Functions**

If x = f(t), y = g(t), where t is parameter, then

dy / dx = (dy / dt) / (dx / dt) = d / dt g(t) / d / dt f(t) = g’ (t) / f’ (t)

5. **Differential Coefficient Using Inverse Trigonometrical Substitutions**

Sometimes the given function can be deducted with the help of inverse Trigonometrical substitution and then to find the differential coefficient is very easy.

**Logarithmic Differentiation Function**

(i) If a function is the product and quotient of functions such as y = f_{1}(x) f_{2}(x) f_{3}(x)… / g_{1}(x) g_{2}(x) g_{3}(x)… , we first take algorithm and then differentiate.

(ii) If a function is in the form of exponent of a function over another function such as [f(x)]^{g(x)} , we first take logarithm and then differentiate.

**Differentiation of a Function with Respect to Another Function**

Let y = f(x) and z = g(x), then the differentiation of y with respect to z is

dy / dz = dy / dx / dz / dx = f’ (x) / g’ (x)

**Successive Differentiations**

If the function y = f(x) be differentiated with respect to x, then the result dy / dx or f’ (x), so obtained is a function of x (may be a constant).

Hence, dy / dx can again be differentiated with respect of x.

The differential coefficient of dy / dx with respect to x is written as d /dx (dy / dx) = d^{2}y / dx^{2} or f’ (x). Again, the differential coefficient of d^{2}y / dx^{2} with respect to x is written as

d / dx (d^{2}y / dx^{2}) = d^{3}y / dx^{3} or f”'(x)……

Here, dy / dx, d^{2}y / dx^{2}, d^{3}y / dx^{3},… are respectively known as first, second, third, … order differential coefficients of y with respect to x. These alternatively denoted by f’ (x), f” (x), f”’ (x), … or y_{1}, y_{2}, y_{3}…., respectively.

Note dy / dx = (dy / dθ) / (dx / dθ) but d^{2}y / dx^{2} ≠ (d^{2}y / dθ^{2}) / (d^{2}x / dθ^{2})

**Leibnitz Theorem**

If u and v are functions of x such that their nth derivative exist, then

**nth Derivative of Some Functions**

**Derivatives of Special Types of Functions**

(vii) **Differentiation of a Determinant**

(viii) **Differentiation of Integrable Functions** If g_{1} (x) and g_{2} (x) are defined in [a, b], Differentiable at x ∈ [a, b] and f(t) is continuous for g_{1}(a) ≤ f(t) ≤ g_{2}(b), then

**Partial Differentiation**

The partial differential coefficient of f(x, y) with respect to x is the ordinary differential coefficient of f(x, y) when y is regarded as a constant. It is a written as ∂f / ∂x or D_{x}f or f_{x}.

e.g., If z = f(x, y) = x^{4} + y^{4} + 3xy^{2} + x^{4}y + x + 2y

Then, ∂z / ∂x or ∂f / ∂x or f_{x} = 4x^{3} + 3y^{2} + 2xy + 1 (here, y is consider as constant)

∂z / ∂y or ∂f / ∂y or f_{y} = 4y^{3} + 6xy + x^{2} + 2 (here, x is consider as constant)

**Higher Partial Derivatives**

Let f(x, y) be a function of two variables such that ∂f / ∂x , ∂f / ∂y both exist.

(i) The partial derivative of ∂f / ∂y w.r.t. ‘x’ is denoted by ∂^{2}f / ∂x^{2} / or f_{xx}.

(ii) The partial derivative of ∂f / ∂y w.r.t. ‘y’ is denoted by ∂^{2}f / ∂y^{2} / or f_{yy}.

(iii) The partial derivative of ∂f / ∂x w.r.t. ‘y’ is denoted by ∂^{2}f / ∂y ∂x / or f_{xy}.

(iv) The partial derivative of ∂f / ∂x w.r.t. ‘x’ is denoted by ∂^{2}f / ∂y ∂x / or f_{yx}.

Note ∂^{2}f / ∂x ∂y = ∂^{2}f / ∂y ∂x

These four are second order partial derivatives.

**Euler’s Theorem on Homogeneous Function**

If f(x, y) be a homogeneous function in x, y of degree n, then

x (&partf / ∂x) + y (&partf / ∂y) = nf

**Deduction Form of Euler’s Theorem**

If f(x, y) is a homogeneous function in x, y of degree n, then

(i) x (∂^{2}f / ∂x^{2}) + y (∂^{2}f / ∂x ∂y) = (n – 1) &partf / ∂x

(ii) x (∂^{2}f / ∂y ∂x) + y (∂^{2}f / ∂y^{2}) = (n – 1) &partf / ∂y

(iii) x^{2} (∂^{2}f / ∂x^{2}) + 2xy (∂^{2}f / ∂x ∂y) + y^{2} (∂^{2}f / ∂y^{2}) = n(n – 1) f(x, y)

**Important Points to be Remembered**

If α is m times repeated root of the equation f(x) = 0, then f(x) can be written as

f(x) =(x – α)^{m} g(x), where g(α) ≠ 0.

From the above equation, we can see that

f(α) = 0, f’ (α) = 0, f” (α) = 0, … , f^{(m – l)} ,(α) = 0.

Hence, we have the following proposition

f(α) = 0, f’ (α) = 0, f” (α) = 0, … , f^{(m – l)} ,(α) = 0.

Therefore, α is m times repeated root of the equation f(x) = 0.

### Class 12 Key Points, Important Questions & Practice Papers

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### Class 12 NCERT Solutions

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### Class 12 Mock Test / Practice

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### Class 12 Exemplar Questions

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