NCERT Solutions for Class 2 Maths Joyful Mathematics Chapter 6 Decoration for Festival – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.
This chapter is about adding and taking away. We use garlands, the ginladi, the number line, and tens and ones.
NCERT Solutions for Class 2 Maths Joyful Mathematics Chapter 6 Decoration for Festival PDF
All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.
| Chapter | Download | |
|---|---|---|
| Solutions PDF (English medium) | Decoration for Festival | View PDF |
| Solutions PDF (Hindi medium) | त्यौहार पर सजावट | View PDF |
NCERT Solutions for Class 2 Maths Joyful Mathematics Chapter 6 Decoration for Festival – Questions and Answers
All 91 questions of the chapter (textbook pages 50 – 70) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.
Decoration for Celebration! — Page 50Complete the table from the picture
Suwali’s row: the number of flowers.
| Name | Number of garlands | Number of flowers | Total number of flowers |
|---|---|---|---|
| Rohan | 1 | 2 | 10 + 2 = 12 |
| Simran | 3 | 7 | 30 + 7 = 37 |
| Akash | 4 | 8 | 40 + 8 = 48 |
| Suwali | 5 | 50 + 3 = 53 | |
| Javed | |||
| Zoha |
Suwali has 3 loose flowers.
- Suwali has 5 garlands. That is 50 flowers.
- Her total is 50 + 3 = 53.
- So 3 flowers are loose.
Javed’s row.
| Name | Number of garlands | Number of flowers | Total number of flowers |
|---|---|---|---|
| Rohan | 1 | 2 | 10 + 2 = 12 |
| Simran | 3 | 7 | 30 + 7 = 37 |
| Akash | 4 | 8 | 40 + 8 = 48 |
| Suwali | 5 | 50 + 3 = 53 | |
| Javed | |||
| Zoha |
Javed: 4 garlands, 3 flowers, 40 + 3 = 43.
- Count Javed’s garlands: 4.
- Count his loose flowers: 3.
- 4 garlands are 40 flowers. 40 + 3 = 43.
Zoha’s row.
| Name | Number of garlands | Number of flowers | Total number of flowers |
|---|---|---|---|
| Rohan | 1 | 2 | 10 + 2 = 12 |
| Simran | 3 | 7 | 30 + 7 = 37 |
| Akash | 4 | 8 | 40 + 8 = 48 |
| Suwali | 5 | 50 + 3 = 53 | |
| Javed | |||
| Zoha |
Zoha: 2 garlands, 0 flowers, 20 + 0 = 20.
- Count Zoha’s garlands: 2.
- She has no loose flowers. Write 0.
- 2 garlands are 20 flowers.
| Name | Number of garlands | Number of flowers | Total number of flowers |
|---|---|---|---|
| Rohan | 1 | 2 | 10 + 2 = 12 |
| Simran | 3 | 7 | 30 + 7 = 37 |
| Akash | 4 | 8 | 40 + 8 = 48 |
| Suwali | 5 | 3 | 50 + 3 = 53 |
| Javed | 4 | 3 | 40 + 3 = 43 |
| Zoha | 2 | 0 | 20 + 0 = 20 |
In-text Questions — Page 51Rohan and Suwali add their flowers
“I have 10 + 2 = 12 flowers.” “I have 50 + 3 = 53 flowers.”
| Rohan brings | 1 garland, 2 flowers | 10 + 2 = 12 |
| Suwali brings | 5 garlands, 3 flowers | 50 + 3 = 53 |
| Suwali and Rohan together bring | ________ | ________ |
65 flowers.
- Add the ones: 2 + 3 = 5.
- Add the tens: 1 + 5 = 6.
- 6 tens and 5 ones make 65.
In-text Questions — Page 52Zoha, Javed and Akash
| Zoha brings | 2 garlands, 0 flowers | 20 + 0 = 20 |
| Javed brings | 4 garlands, 3 flowers | 40 + 3 = 43 |
| Zoha and Javed together bring | ________ | ________ |
63 flowers.
- Add the ones: 3 + 0 = 3.
- Add the tens: 4 + 2 = 6.
- So 43 + 20 = 63.
| Zoha brings | 2 garlands, 0 flowers | 20 + 0 = 20 |
| Akash brings | ________ | ________ |
| Zoha and Akash together bring | ________ | ________ |
68 flowers.
- Akash has 4 garlands and 8 flowers: 48.
- Add the ones: 8 + 0 = 8.
- Add the tens: 4 + 2 = 6. So 68.
| Zoha brings | 2 garlands, 0 flowers | 20 + 0 = 20 |
| Akash brings | 4 garlands, 8 flowers | 40 + 8 = 48 |
| Zoha and Akash together bring | 6 garlands, 8 flowers | 60 + 8 = 68 |
In-text Questions — Page 53Rohan and Simran
| Rohan brings | ________ | ________ |
| Simran brings | ________ | ________ |
| Rohan and Simran together bring | ________ | ________ |
49 flowers.
- Rohan has 12. Simran has 37.
- Add the ones: 2 + 7 = 9.
- Add the tens: 1 + 3 = 4. So 49.
| Rohan brings | 1 garland, 2 flowers | 10 + 2 = 12 |
| Simran brings | 3 garlands, 7 flowers | 30 + 7 = 37 |
| Rohan and Simran together bring | 4 garlands, 9 flowers | 40 + 9 = 49 |
Let us do it on Ginladi! — Page 53Adding on a string of beads
“Count 12 ahead of 25.”
25 + 12 = 37
- Find bead 25.
- Count 12 beads ahead: 26, 27, … 37.
- You stop at 37.
Count ____ ahead of ____
57 + 34 = 91. Count 34 ahead of 57.
- Start at 57.
- Jump 3 tens: 67, 77, 87.
- Then 4 ones: 88, 89, 90, 91.
We can write 24 + 40 + 3 = 64 + 3 = 67
24 + 43 = 67
- Start at 24.
- Jump 4 tens: 34, 44, 54, 64.
- Then 3 ones: 65, 66, 67.
Now add numbers on the number line — Page 54A (23 + 14 = 37) is done in the book
B. 24 + 16 = ____
24 + 16 = 40
- Start at 24.
- Jump 10: you reach 34.
- Jump 6 more: 35, 36, … 40.
C. 11 + 22 = ____
11 + 22 = 33
- Start at 11.
- Jump 10 two times: 21, 31.
- Then 2 more: 32, 33.
Read the number line and fill the boxes — Pages 54–55Find the missing numbers from the jumps
A. 22 + ____ = 38
22 + 16 = 38
- The jumps are +10 and +6.
- 10 + 6 = 16.
B. 18 + ____ = ____
18 + 13 = 31
- The jumps are +10 and +3. That is 13.
- The last jump stops at 31.
C. ____ + ____ = ____
11 + 23 = 34
- The jumps start at 11.
- +10, +10 and +3 make 23.
- They stop at 34.
Add these Numbers — Page 55Tens and ones
67
- Add the ones: 4 + 3 = 7.
- Add the tens: 4 + 2 = 6.
79
- Add the ones: 6 + 3 = 9.
- Add the tens: 5 + 2 = 7.
85
- Add the ones: 0 + 5 = 5.
- Add the tens: 6 + 2 = 8.
82
- Add the ones: 2 + 0 = 2.
- Add the tens: 5 + 3 = 8.
Playing with Blocks — Page 55Mahi’s blocks and Isha’s blocks
61 blocks. That is 6 tens 1 one.
- Tens: 2 + 3 = 5 tens.
- Ones: 3 + 8 = 11 ones.
- 10 ones make 1 more ten. So 6 tens and 1 one.
Let us find the total number of blocks — Page 56Rows 2 to 5
Row 1 is done: 3 tens 6 ones + 4 tens 7 ones → 7 tens 13 ones → 8 tens and 3 ones → 80 + 3 = 83.
Fill the two empty boxes for this row.
8 tens 14 ones → 9 tens and 4 ones. 90 + 4 = 94
- Put the tens together: 4 + 4 = 8 tens.
- Put the ones together: 5 + 9 = 14 ones.
- 14 ones = 1 ten and 4 ones.
Row 1 is done: 3 tens 6 ones + 4 tens 7 ones → 7 tens 13 ones → 8 tens and 3 ones → 80 + 3 = 83.
Fill the two empty boxes for this row.
8 tens 10 ones → 9 tens and 0 ones. 90 + 0 = 90
- Put the tens together: 5 + 3 = 8 tens.
- Put the ones together: 8 + 2 = 10 ones.
- 10 ones = 1 ten and 0 ones.
Row 1 is done: 3 tens 6 ones + 4 tens 7 ones → 7 tens 13 ones → 8 tens and 3 ones → 80 + 3 = 83.
Fill the two empty boxes for this row.
9 tens 4 ones. 90 + 4 = 94
- Put the tens together: 8 + 1 = 9 tens.
- Put the ones together: 4 ones.
Row 1 is done: 3 tens 6 ones + 4 tens 7 ones → 7 tens 13 ones → 8 tens and 3 ones → 80 + 3 = 83.
Fill the two empty boxes for this row.
6 tens 14 ones → 7 tens and 4 ones. 70 + 4 = 74
- Put the tens together: 2 + 4 = 6 tens.
- Put the ones together: 6 + 8 = 14 ones.
- 14 ones = 1 ten and 4 ones.
Add — Page 57Adding ones, adding tens, shifting the tens
“Oh really, Mahi! Can you show me how?”
Yes! 36 + 47 = 83.
- Adding ones: 6 + 7 = 13. That is 1 ten and 3 ones.
- Write 3. Shift the 1 ten to the tens.
- Adding tens: 3 + 4 + 1 = 8.
85
- Add the ones: 6 + 9 = 15. That is 1 ten 5 ones.
- Write 5. Shift the 1 ten to the tens.
- Add the tens: 4 + 3 + 1 = 8.
75
- Add the ones: 6 + 9 = 15. That is 1 ten 5 ones.
- Write 5. Shift the 1 ten to the tens.
- Add the tens: 5 + 1 + 1 = 7.
44
- Add the ones: 6 + 8 = 14. That is 1 ten 4 ones.
- Write 4. Shift the 1 ten to the tens.
- Add the tens: 3 + 1 = 4.
88
- Add the ones: 0 + 8 = 8.
- Add the tens: 3 + 5 = 8.
80
- Add the ones: 5 + 5 = 10. That is 1 ten 0 ones.
- Write 0. Shift the 1 ten to the tens.
- Add the tens: 4 + 3 + 1 = 8.
Let us Do — Pages 57–58Adding in word problems
101 runs.
- Add the ones: 3 + 8 = 11. Write 1. Shift the 1 ten.
- Add the tens: 4 + 5 + 1 = 10 tens.
- 10 tens make 100. So 100 + 1 = 101.
48 colour pencils.
- Add the ones: 2 + 6 = 8.
- Add the tens: 1 + 3 = 4.
91 marbles.
- Add the ones: 4 + 7 = 11. That is 1 ten 1 one.
- Write 1. Shift the 1 ten to the tens.
- Add the tens: 3 + 5 + 1 = 9.
₹91
- Add the ones: 6 + 5 = 11. That is 1 ten 1 one.
- Write 1. Shift the 1 ten to the tens.
- Add the tens: 5 + 3 + 1 = 9.
83 people.
- Add the ones: 6 + 7 = 13. That is 1 ten 3 ones.
- Write 3. Shift the 1 ten to the tens.
- Add the tens: 3 + 4 + 1 = 8.
Let us Count Diyas — Pages 58–59Taking away by counting back
“Let me count how many diyas are left now? 1, 2, 3…”
40 diyas are left.
- Start at 75.
- Selling 35 means count 35 back.
- Back 10 three times: 65, 55, 45. Then 5 more: 40.
“Interesting! Is there any other way to find out?”
Yes. Use the ginladi.
- Count 75 beads first.
- Then go 35 steps backward.
- You reach bead 40. So 75 − 35 = 40.
20 diyas are left.
- Start at 32 on the ginladi.
- Go back 10: 22.
- Go back 2 more: 20.
In-text Questions — Page 60We can also use the ginladi to find the answers
A. Take away 9 from 18 18 − 9 = ____
18 − 9 = 9
- Start at bead 18.
- Go back 9 steps: 17, 16, … 9.
B. Take away 8 from 12 12 − 8 = ____
12 − 8 = 4
- Start at bead 12.
- Go back 8 steps: 11, 10, … 4.
C. Take away 18 from 30 30 − 18 = ____
30 − 18 = 12
- Start at bead 30.
- Go back 10: 20.
- Go back 8 more: 12.
D. Take away 14 from 23 23 − 14 = ____
23 − 14 = 9
- Start at bead 23.
- Go back 10: 13.
- Go back 4 more: 9.
E. Take away 17 from 26 26 − 17 = ____
26 − 17 = 9
- Start at bead 26.
- Go back 10: 16.
- Go back 7 more: 9.
In-text Questions — Page 61A ginladi on paper
“Tell me how you did it? But, I don’t have a ginladi at my home.”
“Let us make a ginladi on the paper then.”
Draw a number line on paper. Use it like a ginladi.
- Write 1 to 20 on a line.
- For 19 − 15, start at 19.
- Jump back 10 to 9. Then 5 steps back to 4.
Let us do some practice on number line — Page 62Taking away on the number line
A. 26 − ____ = ____
26 − 15 = 11
- Count the small jumps: 15.
- They start at 26 and stop at 11.
B. 39 − 28 = ____
39 − 28 = 11
- Two big jumps back: 29, then 19.
- Then 8 small jumps: 11.
- 10 + 10 + 8 = 28 steps.
C. ____ − ____ = ____
40 − 31 = 9
- The jumps start at 40.
- Three jumps of 10 and one of 1: 31.
- They stop at 9.
D. 38 − 11 = ____
38 − 11 = 27
- Jump back 10: 28.
- Jump back 1: 27.
E. 22 − 22 = ____
22 − 22 = 0
- Start at 22.
- Go back 22 steps.
- Nothing is left.
F. 14 − 0 = ____
14 − 0 = 14
- Start at 14.
- Go back 0 steps.
- You stay at 14.
G. 35 − 12 = ____
35 − 12 = 23
- Start at 35.
- Jump back 10: 25.
- Go back 2 more: 23.
Playing with Blocks — Page 63Subtract 24 from 37
13
- Take away the ones: 7 − 4 = 3.
- Take away the tens: 3 − 2 = 1.
Let us Do — Page 63Subtract. No ten needs opening here.
11
- Take away the ones: 4 − 3 = 1.
- Take away the tens: 2 − 1 = 1.
23
- Take away the ones: 4 − 1 = 3.
- Take away the tens: 5 − 3 = 2.
20
- Take away the ones: 2 − 2 = 0.
- Take away the tens: 3 − 1 = 2.
12
- Take away the ones: 6 − 4 = 2.
- Take away the tens: 4 − 3 = 1.
₹60
- Take away the ones: 2 − 2 = 0.
- Take away the tens: 8 − 2 = 6.
₹40
- Take away the ones: 0 − 0 = 0.
- Take away the tens: 6 − 2 = 4.
Decorating with Garlands — Pages 64–66Opening a garland (a ten) to take away
“Jyoti, can I have 1 garland and 8 flowers?”
“I have only 6 loose flowers. I think I should open a garland.”
“Now I can give 8 flowers to mummy.”
46 − 18 = 28. Jyoti is left with 28 flowers.
- Jyoti has 4 garlands and 6 flowers: 46.
- 6 flowers are too few to give 8. She opens 1 garland: 3 garlands and 16 flowers.
- 16 − 8 = 8. Then 3 − 1 = 2.
23 flowers.
- Take away the ones: 8 − 5 = 3.
- The tens stay 2.
26 flowers. That is 2 garlands and 6 flowers.
- 4 ones are too few to take away 8.
- Open 1 ten. Now there are 4 tens and 14 ones.
- 14 − 8 = 6. Then 4 − 2 = 2.
| Garlands | Flowers | |
|---|---|---|
| Jyoti has | 7 | 3 |
| Jyoti gives | 4 | 7 |
| Jyoti is left with |
26 flowers: 2 garlands and 6 flowers.
- 3 ones are too few to take away 7.
- Open 1 ten. Now there are 6 tens and 13 ones.
- 13 − 7 = 6. Then 6 − 4 = 2.
| Garlands | Flowers | |
|---|---|---|
| Jyoti has | 7 | 3 |
| Jyoti gives | 4 | 7 |
| Jyoti is left with | 2 | 6 |
Let us Do — Page 67Subtract. Open a ten when the ones are too few.
27
- 5 ones are too few to take away 8.
- Open 1 ten. Now there are 3 tens and 15 ones.
- 15 − 8 = 7. Then 3 − 1 = 2.
47
- 4 ones are too few to take away 7.
- Open 1 ten. Now there are 7 tens and 14 ones.
- 14 − 7 = 7. Then 7 − 3 = 4.
20
- Take away the ones: 5 − 5 = 0.
- Take away the tens: 6 − 4 = 2.
0
- Take away the ones: 7 − 7 = 0.
- Take away the tens: 2 − 2 = 0.
- Nothing is left. Write 0.
45
- 3 ones are too few to take away 8.
- Open 1 ten. Now there are 8 tens and 13 ones.
- 13 − 8 = 5. Then 8 − 4 = 4.
Skip the Rope — Page 67How many more to make 20?
A. Aman skipped 14 times in the first chance. How many more skips he has to make to complete 20 skips?
20 − 14 = ____ 14 + ____ = 20
6 more skips. 20 − 14 = 6. 14 + 6 = 20.
- Start at 14.
- Count on to 20: 15, 16, 17, 18, 19, 20.
- That is 6 counts.
B. Avni skipped 12 times in the first chance. How many more skips she has to make to complete 20 skips? ____
20 − 12 = ____ 12 + ____ = 20
8 more skips. 20 − 12 = 8. 12 + 8 = 20.
- Start at 12.
- Count on to 20: 13, 14, … 20.
- That is 8 counts.
Let us Do — Page 68Taking away in word problems
A. Anushka collected 63 shells. She gave 26 shells to her brother. How many shells are left with her? ____
37 shells.
- 3 ones are too few to take away 6.
- Open 1 ten. Now there are 5 tens and 13 ones.
- 13 − 6 = 7. Then 5 − 2 = 3.
38 passengers.
- 4 ones are too few to take away 6.
- Open 1 ten. Now there are 4 tens and 14 ones.
- 14 − 6 = 8. Then 4 − 1 = 3.
27 balloons.
- 0 ones are too few to take away 3.
- Open 1 ten. Now there are 3 tens and 10 ones.
- 10 − 3 = 7. Then 3 − 1 = 2.
36 bangles.
- 2 ones are too few to take away 6.
- Open 1 ten. Now there are 6 tens and 12 ones.
- 12 − 6 = 6. Then 6 − 3 = 3.
31 birds came later.
- Take away the ones: 7 − 6 = 1.
- Take away the tens: 8 − 5 = 3.
17 more times.
- 5 ones are too few to take away 8.
- Open 1 ten. Now there are 2 tens and 15 ones.
- 15 − 8 = 7. Then 2 − 1 = 1.
Addition and Subtraction Facts — Page 69Fact families
20, 30, 50
30 + ____ = 50
50 − 30 = 20
____ − 20 = 30
20 + 30 = 50
30 + 20 = 50
50 − 30 = 20
50 − 20 = 30
50 is the whole. 20 and 30 are its parts.
10, 20, 30
___ + ___ = ___
30 − ____ = 10
30 − ____ = 20
10 + 20 = 30
20 + 10 = 30
30 − 20 = 10
30 − 10 = 20
30 is the whole. 10 and 20 are its parts.
20, 80, 100
80 + 20 = 100
20 + 80 = 100
100 − 20 = 80
100 − 80 = 20
100 is the whole. 80 and 20 are its parts.
Addition and Subtraction Pyramid — Page 69Addition pyramid and subtraction pyramid
Addition pyramid (first one)
Top: 40. Next row: 17, 23. Middle gap: 9.
- 3 + 6 = 9.
- 8 + 9 = 17. 9 + 14 = 23.
- 17 + 23 = 40.
Addition pyramid (second one)
Top: 35. Next row: 17, 18. Middle gap: 7.
- 4 + 3 = 7.
- 10 + 7 = 17. 7 + 11 = 18.
- 17 + 18 = 35.
Subtraction pyramid (first one)
Row 2: 21. Row 3: 5, 10. Bottom: 1, 7.
- 37 − 16 = 21.
- 16 − 11 = 5. 21 − 11 = 10.
- 5 − 4 = 1. 11 − 4 = 7.
Subtraction pyramid (second one)
Row 2: 26. Row 3: 15, 13. Bottom: 6, 8.
- 50 − 24 = 26.
- 26 − 11 = 15. 24 − 11 = 13.
- 15 − 9 = 6. 13 − 5 = 8.
Look at this diagram — Page 70Now complete the following diagrams
Now complete the following diagrams.
A.
Top right 4, bottom left 8, bottom right 6.
- 1 + 4 = 5. So top right is 4.
- 1 + 8 = 9. So bottom left is 8.
- 4 + 6 = 10. So bottom right is 6.
Now complete the following diagrams.
B.
One answer: top 4 and 6, bottom 5 and 7.
- Pick top left: 4.
- 10 − 4 = 6 (top right). 9 − 4 = 5 (bottom left).
- 13 − 6 = 7 (bottom right).
Hania and Mansi’s Gift — Page 70Add, then take away
There are ₹78 in the purse. The cost of a gift wrapper is ₹24 and the cost of ribbons is ₹37.
A. How much money did they spend? ____
₹61
- Add the ones: 4 + 7 = 11. That is 1 ten 1 one.
- Write 1. Shift the 1 ten to the tens.
- Add the tens: 2 + 3 + 1 = 6.
There are ₹78 in the purse. The cost of a gift wrapper is ₹24 and the cost of ribbons is ₹37.
B. How much money is left with them? ____
₹17
- Take away the ones: 8 − 1 = 7.
- Take away the tens: 7 − 6 = 1.
Project Work — Page 70Check Daljeet’s answers
Wrong. 25 + 36 = 61.
- Ones: 5 + 6 = 11. Write 1. Shift 1 ten.
- Tens: 2 + 3 + 1 = 6.
Wrong. 37 + 58 = 95.
- Ones: 7 + 8 = 15. Write 5. Shift 1 ten.
- Tens: 3 + 5 + 1 = 9.
Wrong. 35 − 17 = 18.
- 5 ones are too few to take away 7.
- Open 1 ten. Now there are 2 tens and 15 ones.
- 15 − 7 = 8. Then 2 − 1 = 1.
Wrong. We cannot take 78 away from 57.
- 78 is more than 57.
- You cannot give 78 when you have only 57.
- Daljeet really worked out 78 − 57 = 21. That is right.
Wrong. 30 − 17 = 13.
- 0 ones are too few to take away 7.
- Open 1 ten. Now there are 2 tens and 10 ones.
- 10 − 7 = 3. Then 2 − 1 = 1.
Chapter 6 of 11 – Joyful Mathematics
- Previous: Chapter 5 Playing with Lines
- Next: Chapter 7 Rani’s Gift
- All chapters: NCERT Solutions Class 2 Maths
NCERT Solutions Class 2 Maths Joyful Mathematics Chapter 6 Decoration for Festival – Overview
| Class | Class 2 |
| Subject | Maths |
| Book | Joyful Mathematics |
| Chapter | 6 – Decoration for Festival |
| Textbook pages | 50 – 70 |
| Questions solved | 91 |
| Session | 2027 |
| Format | Full answers on this page + PDF |
NCERT Solutions Class 2 Maths Chapter 6 – FAQs
Where can I download NCERT Solutions Class 2 Maths Joyful Mathematics Chapter 6 Decoration for Festival PDF?
Read every answer on this page, or download the free PDF from the table at the top.
Is this for the 2027 session?
Yes, it follows the latest NCERT Class 2 Maths book for 2027.
How many questions are solved in NCERT Class 2 Maths Chapter 6?
All 91 questions of the chapter (textbook pages 50 – 70) – the in-text questions, activities and the end-of-chapter exercises.
How should I use these solutions?
Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.