1. i.   From Alcohols:-

It involves substitution of (-OH) group by halogen atom


       i.    The reactivity of halogen acids for given alcohol in the above reaction order HI >HBr>HCl

      ii.   Of alcohols for the halogen reactivity order is tertiary > secondary > primary.

Reasons of order of reactivity:-

Above reaction is nucleophilic substitution reaction in which (halide ion) Nucleophile attacks prolonated alcohol molecule


iii.      Nucleophilicity (tendency to donote eto carbon atom) follows order I> Br>Cl

iv.  Order of stability of carbocation is 3o> 2o> 1o that’s why reactivity order follows the same as discussed above

  1. Example


ii. Bromoalkanes are obtained by mixing a suitable alcohol with constant boiling hydro bromic acid (48%) in presen of con. H2SO4

2.  By Action of PhosPhorus Halides:-

They gives (80%) yield of haloalkenes

3. By Action of ThioxylChlorides:-

Reagent used (C5H5N) pyridine




4. From Hydrocarbons:-

i. From alkenes and alkynes:-

Order of reactivity HI >HBr>HCl> HF


ii. Markonikove’s Rule:-

ii.   In presence of the peroxide, the addition of HBr (notHCl and HI) to unsyimmetrical alkenes takes place contrary to markoniekove’srulemeas

1 – haloproduct will be major in quantity.

This is also called as peroxide or kharasch effect



It takes place by Free radical Mechanism

i. Chain Initiation Step:-


ii. Chain Propagation Step:-



iii. Chain Termination Step:-


  • 5.   By Allylic Halogenation:-


  • Such Reactions in which Halogenation occurs at allylic position no of an alkene are called allylic Halogenation reactions


6. From Alkanes By Free Radical Halogenation:-


This reaction is called swartsreaction.

7. By Halogen Exchange:-

Iodoalkanes can be easily prepared from the corresponding chloroalkanes by heating with sodium iodide in acetone.


This reaction is called Finleelstein reaction.
1. FROM Aromatic Hydrocarbons/ Direct Halogenations:-

The reaction is carried out at law temperature 310 – 320 K in absence of sun light



     i. Generation of electrophile:-


   ii.  Formation of Complex (Carbocation intermediate):-


This step is slow Hence rate determining step.

iii. Loss of proton to give final product:-






  • 2. From Diazonium Salts:- (sandmeyer reaction):-







3. By Gattermann Reaction:-

4. From Silver Salt of Aromatic Acid/ Hansdieker reaction


« Click Here for Previous Topic Click Here for Next Topic »

Class 12 Chem Haloalkanes and Haloarenes All Topic Notes Class 12 Chemistry All Chapters Notes