Candidates can download NCERT Exemplar Class 12 Chemistry Chapter 9 from this page. The exemplar has been provided by the National Council of Educational Research & Training (NCERT) and the candidates can check it from below for free of cost. It contains objective, very short answer type, short answer type, and long answer type questions. Along with it, the answer for each question has also been provided. From the NCERT Exemplar Class 12 Chemistry Chapter 9, candidates can understand the level and type of questions that are asked in the exam.
NCERT Exemplar Class 12 Chemistry Chapter 9 Coordination Compounds
NCERT Class 12 Chemistry Chapter 9 is for Coordination Compounds. The type of questions that will be asked from NCERT Class 12 Chemistry Chapter 9 are displayed in the below provided NCERT Exemplar Class 12 Chemistry Chapter 9. With the help of it, candidates can prepare well for the examination.
Also Check: NCERT Solutions for Class 12 Chemistry
Multiple Choice Questions (Type-I)
- Which of the following complexes formed by Cu2+ ions is most stable?
- The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, [Co(NH3)6]3+ , [Co(CN)6]3-, [Co(H2O)3]3+
(i) [Co(CN)6]3- > [Co(NH3)6]3+ > [Co(H2O)6]3+
(ii) [Co(NH3)6]3+ > [Co(H2O)6]3+ > [Co(CN)6]3-
(iii) [Co(H2O)6]3+ > [Co(NH3)6]3+ > [Co(CN)6]3-
(iv) [Co(CN)6]3- > [Co(NH3)6]3+ > [Co(H2O)6]3+
- When 0.1 mol CoCl3(NH3)5 is treated with excess of AgNO3,0.2 mol of AgCl are obtained. The conductivity of solution will correspond to
(i) 1:3 electrolyte
(ii) 1:2 electrolyte
(iii) 1:1 electrolyte
(iv) 3:1 electrolyte
- When 1 mol CrCl3⋅6H2O is treated with excess of AgNO3, 3 mol of AgCl are obtained. The formula of the complex is :
- The correct IUPAC name of [Pt(NH3)2Cl2] is
(i) Diamminedichloridoplatinum (II)
(ii) Diamminedichloridoplatinum (IV)
(iii) Diamminedichloridoplatinum (0)
(iv) Dichloridodiammineplatinum (IV)
- The stabilisation of coordination compounds due to chelation is called the chelate effect. Which of the following is the most stable complex species?
- Indicate the complex ion which shows geometrical isomerism.
- The CFSE for octahedral [CoCl6]4– is 18,000 cm-1. The CFSE for tetrahedral [CoCl4]2- will be
(i) 18,000 cm-1
(ii) 16,000 cm-1
(iii) 8,000 cm-1
(iv) 20,000 cm-1
- Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] are
(i) linkage isomers
(ii) coordination isomers
(iii) ionisation isomers
(iv) geometrical isomers
- The compounds [Co(SO4)(NH3)5]Br and [Co(SO4)(NH3)5]Cl represent
(i) linkage isomerism
(ii) ionisation isomerism
(iii) coordination isomerism
(iv) no isomerism
- A chelating agent has two or more than two donor atoms to bind to a single metal ion. Which of the following is not a chelating agent?
- Which of the following species is not expected to be a ligand?
- What kind of isomerism exists between [Cr(H2O)6]Cl3 (violet) and [Cr(H2O)5Cl]Cl2⋅H2O (greyish-green)?
(i) linkage isomerism
(ii) solvate isomerism
(iii) ionisation isomerism
(iv) coordination isomerism
- IUPAC name of [Pt(NH3)2Cl(NO2)] is :
(i) Platinum diaminechloronitrite
(ii) Chloronitrito-N-ammineplatinum (II)
(iii) Diamminechloridonitrito-N-platinum (II)
(iv) Diamminechloronitrito-N-platinate (II)
Multiple Choice Questions (Type-II)
Note : In the following questions two or more options may be correct.
- Atomic number of Mn, Fe and Co are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?
- Atomic number of Mn, Fe, Co and Ni are 25, 26 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number
- Which of the following options are correct for [Fe(CN) 6 ] complex?
(i) d2 sp3 hybridisation
(ii) sp3d2 hybridisation
- An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because____________.
(i) [Co(H2O)6]2+ is transformed into [CoCl6]4-
(ii) [Co(H2O)6]2+ is transformed into [CoCl4]2-
(iii) tetrahedral complexes have smaller crystal field splitting than octahedral complexes.
(iv) tetrahedral complexes have larger crystal field splitting than octahedral complex.
- Which of the following complexes are homoleptic?
- Which of the following complexes are heteroleptic?
- Identify the optically active compounds from the following :
(ii) trans– [Co(en)2Cl2]+
(iii) cis– [Co(en)2Cl2]+
(iv) [Cr (NH3)5Cl]
- Identify the correct statements for the behaviour of ethane-1, 2-diamine as a ligand.
(i) It is a neutral ligand.
(ii) It is a didentate ligand.
(iii) It is a chelating ligand.
(iv) It is a unidentate ligand.
- Which of the following complexes show linkage isomerism?
Short Answer Type Questions
- Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2]Cl, [Co(NH3)6]Cl3, [Cr(NH3)5Cl]Cl2
- A coordination compound CrCl3⋅4H2O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write structural formula of the compound and name it.
- A complex of the type [M(AA)2X2]n+ is known to be optically active. What does this indicate about the structure of the complex? Give one example of such complex.
- Magnetic moment of [MnCl4]2– is 5.92 BM. Explain giving reason.
- On the basis of crystal field theory explain why Co(III) forms paramagnetic octahedral complex with weak field ligands whereas it forms diamagnetic octahedral complex with strong field ligands.
- Why are low spin tetrahedral complexes not formed?
- Give the electronic configuration of the following complexes on the basis of Crystal Field Splitting theory.
[CoF6]3- , [Fe(CN)6]4- and [Cu(NH3)6]2+.
- Explain why [Fe(HO)6]3+ has magnetic moment value of 5.92 BM whereas
[Fe(CN)6]3- has a value of only 1.74 BM.
- Arrange following complex ions in increasing order of crystal field splitting energy (ΔO) :
[Cr(Cl)6]3– , [Cr(CN)6]3–, [Cr(NH3)6]3+.
- Why do compounds having similar geometry have different magnetic moment?
- CuSO4.5H2O is blue in colour while CuSO4 is colourless. Why?
- Name the type of isomerism when ambidentate ligands are attached to central metal ion. Give two examples of ambidentate ligands.
Matching Type Questions
Note : In the following questions match the items given in Columns I and II.
- Match the complex ions given in Column I with the colours given in Column II and assign the correct code :
- Match the coordination compounds given in Column I with the central metal atoms given in Column II and assign the correct code :
- Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code :
- Match the complex species given in Column I with the possible isomerism given in Column II and assign the correct code :
- Match the compounds given in Column I with the oxidation state of cobalt present in it (given in Column II) and assign the correct code.
Assertion and Reason Type Questions
Note : In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
(i) Assertion and reason both are true, reason is correct explanation of assertion.
(ii) Assertion and reason both are true but reason is not the correct explanation of assertion.
(iii) Assertion is true, reason is false.
(iv) Assertion is false, reason is true.
- Assertion : Toxic metal ions are removed by the chelating ligands.
Reason : Chelate complexes tend to be more stable.
- Assertion : [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 are reducing in nature.
Reason : Unpaired electrons are present in their d-orbitals.
- Assertion : Linkage isomerism arises in coordination compounds containing ambidentate ligand.
Reason : Ambidentate ligand has two different donor atoms.
- Assertion : Complexes of MX6 and MX5 L type (X and L are unidentate) do not show geometrical isomerism.
Reason : Geometrical isomerism is not shown by complexes of coordination number 6.
- Assertion : ([Fe(CN)6]3- ion shows magnetic moment corresponding to two unpaired electrons.
Reason : Because it has d2sp3 type hybridisation.
Long Answer Type Questions
- Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following :
(i) [CoF6]3– , [Co(H2O)6]2+, [Co(CN)6]3–
(ii) [FeF6]3– , [Fe(H2O)6]2+ , [Fe(CN)6]4–
- Using valence bond theory, explain the following in relation to the complexes given below:
[Mn(CN) 6 ]3– , [Co(NH3)6]3+ , [Cr(H2O)6]3+ , [FeCl6]4–
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.
- CoSO4 Cl.5NH3 exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO 3 to give white precipitate, but does not react with BaCl2. Isomer ‘B’ gives white precipitate with BaCl2 but does not react with AgNO3 . Answer the following questions.
(i) Identify ‘A’ and ‘B’ and write their structural formulas.
(ii) Name the type of isomerism involved.
(iii) Give the IUPAC name of ‘A’ and ‘B’.
- What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex?
- Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?
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