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Home » 12th Class » NCERT Exemplar Class 12 Maths Unit 5 Continuity and Differentiability

NCERT Exemplar Class 12 Maths Unit 5 Continuity and Differentiability

by aglasem
November 24, 2023
in 12th Class

Candidates can download NCERT Exemplar Class 12 Maths Unit 5 from this page. The exemplar has been provided by the National Council of Educational Research & Training (NCERT) and the candidates can check it from below for free of cost. It contains objective, very short answer type, short answer type, and long answer type questions. Along with it, the answer for each question has also been provided. From the NCERT Exemplar Class 12 Maths Unit 5, candidates can understand the level and type of questions that are asked in the exam.

Click Here for Class 12 Maths Notes

NCERT Exemplar Class 12 Maths Unit 5 Continuity and Differentiability

NCERT Class 12 Maths Unit 5 is for Continuity and Differentiability. The type of questions that will be asked from NCERT Class 12 Maths Unit 5 are displayed in the below provided NCERT Exemplar Class 12 Maths Unit 5. With the help of it, candidates can prepare well for the examination.

Also Check: NCERT Solutions for Class 12 Maths


5.1 Overview
5.1.1 Continuity of a function at a point
Let f be a real function on a subset of the real numbers and let c be a point in the domain of f. Then f is continuous at c if


More elaborately, if the left hand limit, right hand limit and the value of the function at x = c exist and are equal to each other, i.e.,

then f is said to be continuous at x = c.

5.1.2 Continuity in an interval

(i) f is said to be continuous in an open interval (a, b) if it is continuous at every point in this interval.
(ii) f is said to be continuous in the closed interval [a, b] if

5.1.3 Geometrical meaning of continuity

(i) Function f will be continuous at x = c if there is no break in the graph of the function at the point (c,f(c)).
(ii) In an interval, function is said to be continuous if there is no break in the graph of the function in the entire interval.

5.1.4 Discontinuity

The function f will be discontinuous at x = a in any of the following cases :


5.1.5 Continuity of some of the common functions




5.1.6 Continuity of composite functions


Let f and g be real valued functions such that (fog) is defined at a. If g is continuous at a and f is continuous at g (a), then (fog) is continuous at a.


5.1.7 Differentiability



5.1.8 Algebra of derivatives


If u, v are functions of x, then



5.1.9 Chain rule is a rule to differentiate composition of functions. Let f = vou. If



5.1.10 Following are some of the standard derivatives (in appropriate domains)



5.1.11 Exponential and logarithmic functions


(i) The exponential function with positive base b > 1 is the function y = f (x) = bx . Its domain is R, the set of all real numbers and range is the set of all positive real numbers. Exponential function with base 10 is called the common exponential function and with base e is called the natural exponential function.
(ii) Let b > 1 be a real number. Then we say logarithm of a to base b is x if bx =a, Logarithm of a to the base b is denoted by logb a. If the base b = 10, we say it is common logarithm and if b = e, then we say it is natural logarithms. logx denotes the logarithm function to base e. The domain of logarithm function is R+ , the set of all positive real numbers and the range is the set of all real numbers.
(iii) The properties of logarithmic function to any base b > 1 are listed below:




5.1.12 Logarithmic differentiation is a powerful technique to differentiate functions of the form f (x) = (u (x)) v(x) , where both f and u need to be positive functions for this technique to make sense.


5.1.13 Differentiation of a function with respect to another function


Let u = f (x) and v = g (x) be two functions of x, then to find derivative of f (x) w.r.t. to g (x), i.e., to find
du/dv , we use the formula



5.1.14 Second order derivative



5.1.15 Rolle’s Theorem


Let f : [a, b] → R be continuous on [a, b] and differentiable on (a, b), such that f (a) = f (b), where a and b are some real numbers. Then there exists at least one point c in (a, b) such that f ′ (c) = 0.
Geometrically Rolle’s theorem ensures that there is at least one point on the curve y = f (x) at which tangent is parallel to x-axis (abscissa of the point lying in (a, b)).


5.1.16 Mean Value Theorem (Lagrange)


Let f : [a, b] → R be a continuous function on [a, b] and differentiable on (a, b). Then there exists at least one point c in (a, b) such that



Geometrically, Mean Value Theorem states that there exists at least one point c in (a, b) such that the tangent at the point (c, f (c)) is parallel to the secant joining the points (a, f (a) and (b, f (b)).


Short Answer Type Questions (Solved Examples)
















Long Answer Type Questions (Solved Examples)












Objective Type Questions (Solved Examples)







Match the Following (Solved Example)




Fill in the Blanks (Solved Examples)



True or False Statements Type Questions (Solved Examples)




Short Answer Type Questions (Exercise)


Class 12 Important Questions for Maths - Continuity and Differentiability


Long Answer Type Questions (Exercise)


Class 12 Important Questions for Maths - Continuity and Differentiability


Multiple Choice Questions


Class 12 Important Questions for Maths - Continuity and Differentiability


Fill In Blanks Type Questions


Class 12 Important Questions for Maths - Continuity and Differentiability


True or False Statements Type Questions


Class 12 Important Questions for Maths - Continuity and Differentiability


Click Here to download NCERT Exemplar Class 12 Maths Unit 5 Continuity and Differentiability.


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