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NCERT Solutions for Class 3 Maths Chapter 4 Vacation with My Nani Maa (PDF) – 2027

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NCERT Solutions for Class 3 Maths Maths Mela Chapter 4 Vacation with My Nani Maa – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.

Nandini and Chirag spend their holidays at their Nani Maa’s house. While counting marbles, balushahi, stamps, ants, radishes and apples, they learn to add and subtract on tens frames, on a bead string called a ginladi, on a number grid, on a number line and with bundles of sticks.

NCERT Solutions for Class 3 Maths Maths Mela Chapter 4 Vacation with My Nani Maa PDF

All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.

PDFChapterDownload
Solutions PDF (English medium)Vacation with My Nani MaaView PDF
Solutions PDF (Hindi medium)नानी माँ के साथ छुट्टियाँView PDF

NCERT Solutions for Class 3 Maths Maths Mela Chapter 4 Vacation with My Nani Maa – Questions and Answers

All 56 questions of the chapter (textbook pages 29 – 43) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.

Let us Do — Page 29Nani Maa’s magic trick

Q1Can you tell what the trick is?
on the tablehandkerchiefI shall tell you the number of marbles you have hidden.
In the book’s first picture there are 15 marbles on the table. After the child hides some, 11 marbles are left in the open. Nani Maa says, “You have 4 under your handkerchief.”
Answer

The trick is subtraction. Nani Maa knows the total. She takes away the marbles she can see.

15 − 11 = 4 marbles are hidden.
Q2Perform the trick with your friends. Write the numbers of hidden seeds in the table below.
Total SeedsSeeds on the TableHidden Seeds
1512 
1710 
198 
209 
237 
2712 
The book prints two tables; both are shown here as one.
Answer

Hidden seeds = Total seeds − Seeds on the table

Total SeedsSeeds on the TableHidden Seeds
15123
17107
19811
20911
23716
271215
The hidden seeds are filled in.
15 − 12 = 3    17 − 10 = 7    19 − 8 = 11
20 − 9 = 11    23 − 7 = 16    27 − 12 = 15

In-text Questions — Page 30Balushahi in the two boxes

Q1How many do we have in total?
Nandini’s boxChirag’s box
Two tens frames. Each frame has ten small boxes.
Answer

In total they have 12 balushahi.

Move 3 from Chirag’s frame to fill Nandini’s frame. Now one frame is a full ten and 2 are left.

full tentwo more
Ten dots fill the first frame and two dots go in the next frame.
7 + 5 = 10 + 2 = 12
Q2Draw the number of dots.
Nandini’s boxChirag’s box
Two tens frames. Each frame has ten small boxes.
Two empty tens frames, as printed in the book.
Answer

Draw 12 dots: fill the first frame with 10 dots, then draw 2 dots in the second frame.

full tentwo more
Ten dots fill the first frame and two dots go in the next frame.
10 + 2 = 12 dots
Q37 Balushahi + 5 Balushahi = ………. Balushahi
Nandini’s boxChirag’s box
Two tens frames. Each frame has ten small boxes.
Answer
7 Balushahi + 5 Balushahi = 12 Balushahi

Count on from 7: 8, 9, 10, 11, 12.

Q4

Nandini: We bought the same number of balushahi from the shop. Did you eat some of them?
Chirag: Hahahaha! I did eat some.

How many did he eat? ………. Balushahi

Nandini’s boxChirag’s box
Two tens frames. Each frame has ten small boxes.
Answer

Chirag ate 2 balushahi.

Both bought the same number. Nandini still has 7 and Chirag has 5.

7 − 5 = 2
Q57 Balushahi – 5 Balushahi = ………. Balushahi
Nandini’s boxChirag’s box
Two tens frames. Each frame has ten small boxes.
Answer
7 Balushahi − 5 Balushahi = 2 Balushahi

Count back 5 from 7: 6, 5, 4, 3, 2.

In-text Questions — Page 31Books for Nani Maa, Let us Do and the Card Game

Q1Chirag got 9 story books for Nani Maa and Nandini got 7 puzzle books for Nani Maa. How many total books did the children get for Nani Maa?
………. Books + ………. Books = ………. Books
story bookspuzzle books
The dots show the two kinds of books in tens frames.
Answer
9 Books + 7 Books = 16 Books

Move 1 dot to fill the first frame. Now it is a full ten, and 6 dots are left.

full tensix more
Move one dot across: the first frame becomes a full ten.
9 + 7 = 10 + 6 = 16
Q2Use the tens frame to solve the following.
(a) 6 + 8 = ………….
(b) 5 + 10 = ………….
(c) 9 – 6 = ………….
(d) 18 – 9 = ………….
Two empty tens frames, as printed in the book.
Answer
(a) 6 + 8 = 14   (6 + 4 = 10, 4 more)
(b) 5 + 10 = 15   (one full ten and 5)
(c) 9 − 6 = 3
(d) 18 − 9 = 9   (18 − 8 = 10, 10 − 1 = 9)
Q3Make four sets of number cards with numbers 1 to 10. Shuffle and spread out all cards facing down. Take turns with your friends to open one card at a time. When you open, look at your card, and the cards that are already opened. If any three cards make an addition or a subtraction statement, you can keep all three cards. Else, put it down opened. For example, Nandini opens 4. The numbers 2 and 6 are already opened. So, Nandini can keep all three cards: 2, 4 and 6. The game continues till all cards are opened. Whoever collects the greatest number of cards wins the game.
246
Cards lie face down. Three cards are open: 2, 4 and 6.
Answer

Sample turn: Nandini opens 4. The cards 2 and 6 are open. 2 + 4 = 6, so she keeps all three cards.

Other sets that work: 3, 5, 8 (3 + 5 = 8)   1, 9, 10   2, 5, 7.

In-text Questions — Page 32The stamp collection on the ginladi

Q1

Nandini and Chirag have got their stamps to show to their friends and Nani Maa.
Children: Look, Nani Maa. We have collected 15 stamps.
Nani Maa: Let me give you some more. Here are 7 more.

How many stamps do they have now?

Answer
15 Stamps + 7 Stamps = 22 Stamps
Or 15 + 7 = 22

They now have 22 stamps. Start at bead 15 on the ginladi and move 7 beads ahead.

Q2Nandini and Chirag have 22 stamps. Nani Maa’s brother gives them his collection of 30 stamps. How many stamps do they have now?
22 Stamps + ………. Stamps = ………. Stamps
Or 22 + ………. = ……….
A plain ginladi. The beads are tied in groups of ten.
Answer
22 Stamps + 30 Stamps = 52 Stamps
Or 22 + 30 = 52

30 is three tens. From 22, make three jumps of 10: 22 → 32 → 42 → 52.

22324252+10+10+10
Three jumps of ten carry the bead from 22 to 52.

In-text Questions — Page 33Stamps of famous persons and of monuments

Q1

They now have 52 stamps. Nandini and Chirag count and find that they have 37 stamps with faces of famous persons and the remaining with pictures of monuments.

How many stamps with pictures of monuments do they have?
52 Stamps – 37 Stamps = ………. Stamps
Or 37 Stamps + ………. Stamps = 52 Stamps

A plain ginladi. The beads are tied in groups of ten.
Answer
52 Stamps − 37 Stamps = 15 Stamps
Or 37 Stamps + 15 Stamps = 52 Stamps

They have 15 monument stamps. Nandini’s way: jump back 2, then 10, then 3. 2 + 10 + 3 = 15.

37405052−2−10−3
Nandini’s way on the ginladi: she jumps back from 52.
Q2They have 15 stamps with pictures of monuments. Can you find other ways of doing it?
A plain ginladi. The beads are tied in groups of ten.
Answer

Yes. Two other ways:

Way 1: 52 − 30 = 22, then 22 − 7 = 15
Way 2: count up from 37: 37 + 3 = 40, 40 + 12 = 52. 3 + 12 = 15
Q3

Children: Nani Maa, we have 52 stamps now. Next time when we come, we will have 75 stamps!

How many more stamps will they need? Figure it out using the number line.
………. Stamps + ………. Stamps = ………. Stamps
Or, ………. + ………. = ……….

A plain ginladi. The beads are tied in groups of ten.
Answer

They will need 23 more stamps.

52 Stamps + 23 Stamps = 75 Stamps
Or, 52 + 23 = 75

From 52, jump 8 to reach 60, then jump 15 to reach 75. 8 + 15 = 23.

526075+8+15
Counting on from 52 up to 75 on the ginladi.

Let us Do — Page 34Jumping on the ginladi, and the ants under the leaves

Q11. Solve using a ginladi.
(a) 34 + 6    (b) 23 + 12    (c) 33 – 5    (d) 42 – 15
A plain ginladi. The beads are tied in groups of ten.
Answer
(a) 34 + 6 = 40
(b) 23 + 12: 23 + 10 = 33, 33 + 2 = 35
(c) 33 − 5: 33 − 3 = 30, 30 − 2 = 28
(d) 42 − 15: 42 − 10 = 32, 32 − 5 = 27
Q22. A frog is jumping on the ginladi. He is at 7. He wants to jump 10 beads at a time. Mark the beads that he will jump on and write the numbers.
7
The frog is sitting on the 7th bead.
Answer

The frog jumps on 17, 27, 37, 47, 57, 67, 77, 87 and 97.

7172737475767778797
Every jump of 10 lands on a bead whose number ends in 7.

Each jump adds 10. The 7 at the end never changes.

Q33. The frog again jumps forward by 10 each time. Mark all the places where the frog will land.
23
The frog is now on the 23rd bead.
Answer

The frog starts at 23 and lands on 33, 43, 53, 63, 73, 83 and 93.

2333435363738393
Each landing bead ends in 3.

Each jump adds 10. The 3 at the end stays the same.

Q44. The grasshopper jumps backward by 10 each time. Mark all the beads that the grasshopper will jump on and write the numbers.
76
The grasshopper is on the 76th bead.
Answer

The grasshopper starts at 76 and jumps on 66, 56, 46, 36, 26, 16 and 6.

766656463626166
Jumping back by 10 each time, every bead ends in 6.

Each jump back takes away 10. The 6 at the end stays the same.

Q5

Some ants are carrying big leaves to their homes. They will eat these leaves in the rainy season. Nani Maa can tell how many ants there are without looking under the leaves.

Can you also tell how many ants there are under the leaves? Fill the answers in the boxes provided.

1 to 40123426272829303132333435363738394041 to 72414243444546474849505152656667686970717272 to 1007284858687888990919293949596979899100
Ants stand on every number. A leaf hides some of them; the white box is where the number goes.
Answer

The boxes get 21, 12 and 11.

Leaf 1 (ants 5 to 25): 25 − 4 = 21
Leaf 2 (ants 53 to 64): 64 − 52 = 12
Leaf 3 (ants 73 to 83): 83 − 72 = 11
1 to 4012342627282930313233343536373839402141 to 7241424344454647484950515265666768697071721272 to 100728485868788899091929394959697989910011
The number of ants hidden under each leaf.

In-text Questions — Page 35Jump tables, and Adding and Subtracting Smartly with the Number Grid

Q15. Fill in the tables by jumping as instructed.
Jump 5345687398266Jump 6285973346771Jump 9291293388439
Each arrow means one jump. Follow the arrow to the next box.
Answer
Jump 53456873961824466Jump 628597334656771Jump 92912933821843039
The new numbers are shown in yellow boxes.
Jump 5: 56 + 5 = 61, 39 + 5 = 44
Jump 6: 59 + 6 = 65
Jump 9: 12 + 9 = 21, 21 + 9 = 30
Q2Let us play a grid game. Each player takes turns rolling two dice to make a two-digit number, and moves the counter by the number they have made. They can choose to move forward or backward. The first to reach a number between 91 and 100 is the winner!
919293949596979899100
81828384858687888990
71727374757677787980
61626364656667686970
51525354555657585960
41424344454647484950
31323334353637383940
21222324252627282930
11121314151617181920
12345678910
The number grid. The bottom row starts at 1 and the top row ends at 100.
Answer

Sample turn: My counter is on 28. The dice show 4 and 3, so I make 43. I go 4 rows up to 68, then 3 boxes right to 71.

28 + 40 = 68, 68 + 3 = 71

In-text Questions — Page 36Moving the counter on the number grid

Q1

Chirag: Nandini is at 23. She has got 11 on the dice. She thinks of two ways of moving to 34.

A jump from 23 to 34 is ………. steps.

Way 1 — one row up (+10), then one box right (+1)233334+10+1Way 2 — one box right (+1), then one row up (+10)232434+1+10
Nandini’s two ways of moving from 23 to 34 on the grid.
Answer

A jump from 23 to 34 is 11 steps.

Way 1: 23 + 10 = 33, 33 + 1 = 34
Way 2: 23 + 1 = 24, 24 + 10 = 34
10 + 1 = 11
Q2

Nandini: Chirag is at 19. He gets 54 on the dice.

Help him move his counter to the correct number.

919293949596979899100
81828384858687888990
71727374757677787980
61626364656667686970
51525354555657585960
41424344454647484950
31323334353637383940
21222324252627282930
11121314151617181920
12345678910
The number grid. The bottom row starts at 1 and the top row ends at 100.
Answer

Chirag’s counter goes to 73.

54 is 5 tens and 4 ones. Go 5 rows up from 19 to 69. Then go 4 boxes on to 73.

19 + 50 = 69, 69 + 4 = 73
Q31. Use the number grid to answer the following. Show your thinking by drawing arrows in the grid.
(a) Nandini is at 45. She gets 34. She will land on ……….
919293949596979899100
81828384858687888990
71727374757677787980
61626364656667686970
51525354555657585960
41424344454647484950
31323334353637383940
21222324252627282930
11121314151617181920
12345678910
The number grid. The bottom row starts at 1 and the top row ends at 100.
Answer

She will land on 79.

Arrows: 3 rows up from 45 to 75, then 4 boxes right to 79.

45 + 30 = 75, 75 + 4 = 79
Q4(b) Chirag is at 75. He gets 56. He will land on ……….
919293949596979899100
81828384858687888990
71727374757677787980
61626364656667686970
51525354555657585960
41424344454647484950
31323334353637383940
21222324252627282930
11121314151617181920
12345678910
The number grid. The bottom row starts at 1 and the top row ends at 100.
Answer

He will land on 19.

Going forward 56 goes past 100, so he moves backward. Arrows: 5 rows down from 75 to 25, then 6 boxes left to 19.

75 − 50 = 25, 25 − 6 = 19
Q5(c) Nandini is at 30. She gets 66. She will land on ……….
919293949596979899100
81828384858687888990
71727374757677787980
61626364656667686970
51525354555657585960
41424344454647484950
31323334353637383940
21222324252627282930
11121314151617181920
12345678910
The number grid. The bottom row starts at 1 and the top row ends at 100.
Answer

She will land on 96.

Arrows: 6 rows up from 30 to 90, then 6 more to 96.

30 + 60 = 90, 90 + 6 = 96

96 is between 91 and 100, so this move wins the grid game!

Q6(d) Chirag is at 89. He gets 63. He will land on ……….
919293949596979899100
81828384858687888990
71727374757677787980
61626364656667686970
51525354555657585960
41424344454647484950
31323334353637383940
21222324252627282930
11121314151617181920
12345678910
The number grid. The bottom row starts at 1 and the top row ends at 100.
Answer

He will land on 26.

Going forward 63 goes past 100, so he moves backward. Arrows: 6 rows down from 89 to 29, then 3 boxes left to 26.

89 − 60 = 29, 29 − 3 = 26

Magic Sums — Page 37Nani Maa’s number puzzles and the magic square

Q1

Nandini and Chirag find some puzzles that Nani Maa had solved.

Observe the numbers. What do you notice?

52815316109472017721
The puzzle Nani Maa had already solved.
Answer
  • All numbers from 1 to 9 are used, each only once.
  • Each row adds up to the number on its right: 5 + 2 + 8 = 15.
  • Each column adds up to the number below it: 5 + 3 + 9 = 17.
Q2Fill the boxes below. In each puzzle, all numbers 1 – 9 are there. The numbers in each row add up to the number in the box on the right. The numbers in each column add up to the number in the box below. (first puzzle)
581622147111618
The first puzzle, as printed.
Answer
35816796221247111618
The completed first puzzle.
Top row: 16 − 5 − 8 = 3   Bottom row: 7 − 1 − 4 = 2
Column 1: 11 − 3 − 1 = 7   Column 2: 16 − 5 − 2 = 9
Column 3: 18 − 8 − 4 = 6   Check: 7 + 9 + 6 = 22 ✓
Q3Fill the boxes below. In each puzzle, all numbers 1 – 9 are there. The numbers in each row add up to the number in the box on the right. The numbers in each column add up to the number in the box below. (second puzzle)
312515741871523
The second puzzle, as printed.
Answer
13812456152791871523
How the second puzzle works if the last 4 is read as 9.
Q4Fill the boxes below. In each puzzle, all numbers 1 – 9 are there. The numbers in each row add up to the number in the box on the right. The numbers in each column add up to the number in the box below. (third puzzle)
61019916101223
The third puzzle, as printed.
Answer
136104781952916101223
One way to complete the third puzzle.
Column 3: 23 − 6 − 9 = 8
Top row: 10 − 6 = 4 = 1 + 3
Middle row: 19 − 8 = 11 = 4 + 7
Bottom row: 16 − 9 = 7 = 5 + 2
Q5Add the numbers in the blue boxes and the numbers in the red boxes in each of the puzzles. What do you find?
52815316109472017721
The puzzle Nani Maa had already solved.
581622147111618
The first puzzle, as printed.
312515741871523
The second puzzle, as printed.
61019916101223
The third puzzle, as printed.
Answer

The blue boxes and the red boxes both add up to 45 in every puzzle.

PuzzleRed boxesBlue boxes
Nani Maa’s15 + 10 + 20 = 4517 + 7 + 21 = 45
First16 + 22 + 7 = 4511 + 16 + 18 = 45
Second12 + 15 + 18 = 457 + 15 + 23 = 45
Third10 + 19 + 16 = 4510 + 12 + 23 = 45
Q6

Nani Maa was doing something in the newspaper. Nandini and Chirag looked into what she was doing.

Magic magic magic!!!
With numbers 1 to 9
Add the numbers in a line
From left to right
And from top to bottom
Did you find the magic?
Now, try from right to left
And from bottom to top
Isn’t it magical?
There is something more, something more
Add the numbers on the diagonal
Isn’t it magical?

Nandini: Nani Maa, What is so magical about this Square?

276951438
The square Nani Maa was making in the newspaper.
Answer

The magic: every row, every column and both corner-to-corner lines add up to 15.

Rows: 2 + 7 + 6 = 15, 9 + 5 + 1 = 15, 4 + 3 + 8 = 15
Columns: 2 + 9 + 4 = 15, 7 + 5 + 3 = 15, 6 + 1 + 8 = 15
Diagonals: 2 + 5 + 8 = 15, 6 + 5 + 4 = 15
Q7Fill the blanks to complete the Magic square
396
The magic square to be completed.
Answer
834159672
The completed magic square.

Every line must make 15, and the middle box is 5, as in Nani Maa’s square.

Middle column: 15 − 3 − 5 = 7   Middle row: 15 − 5 − 9 = 1
First column: 15 − 1 − 6 = 8   Top row: 15 − 8 − 3 = 4
Bottom row: 15 − 6 − 7 = 2

In-text Questions — Page 38Nani Maa’s radish fields

Q1

Nani Maa has plucked 25 red radishes and 36 white radishes. Nandini starts by drawing the problem on the ground.

Nandini: Estimate the total number of radishes. …………

red radish25white radish36
Nandini’s drawing of the problem on the ground.
Answer

There are about 60 radishes.

36 is close to 35. 25 + 35 = 60
Q2Nani Maa has plucked 25 red radishes and 36 white radishes. How many total radishes has she plucked?
25 red radishes + 36 white radishes = ………. radishes
25 + 36 = ……….
25 red radishes36 white radishes
Bundles of ten sticks and loose sticks for the two kinds of radish.
Answer
25 red radishes + 36 white radishes = 61 radishes
25 + 36 = 61

Bundles: 2 + 3 = 5. Sticks: 5 + 6 = 11 = 1 bundle and 1 stick. So 6 bundles and 1 stick = 61.

6 bundles and 1 stick = 61
Eleven loose sticks make one more bundle and one stick is left.
Q3Find other ways of solving the same problem on the number line.
0102030405060708090100
A number line from 0 to 100.
Answer

Two other ways. Both reach 61.

Way 1: 25 + 30 = 55, 55 + 6 = 61
Way 2: start at 36. 36 + 20 = 56, 56 + 5 = 61
0102030405060708090100+30+6
Two shorter ways to reach the same answer.

In-text Questions — Page 39The box of 100 vegetables

Q1

Nani Maa puts tomatoes and carrots in a box and writes 100 on it.
Nandini: I remember she had put 65 tomatoes.
Chirag: We need not count the carrots.

Nandini draws the given problem.

Your estimation of carrots …………

10065 tomatoes? carrots
The whole box holds 100 vegetables.
Answer

About 30 to 35 carrots.

65 is close to 70. 70 + 30 = 100

So there are a little more than 30 carrots.

Q2Circle the bundle of sticks that shows the correct number of carrots.
ABCD
The four choices of bundles and sticks printed in the book.
Answer

Circle group C (the third one): 3 bundles and 5 sticks = 35.

100 − 65 = 35 carrots
A = 30,   B = 34,   C = 35,   D = 52
Q3Solve the above problem on the number line.
0102030405060708090100
A number line from 0 to 100.
Answer

Count up from 65 to 100: jump 5 to 70, then 30 to 100.

0102030405060708090100+5+30
Counting on from 65 to 100.
5 + 30 = 35, so 100 − 65 = 35 carrots
Q4……… tomatoes and ……… carrots total ……… vegetables ……… + ……… = 100
10065 tomatoes? carrots
The whole box holds 100 vegetables.
Answer
65 tomatoes and 35 carrots total 100 vegetables
65 + 35 = 100
10065 tomatoes35 carrots
The two parts of the box of 100.

The two parts together make the whole box.

Q5………tomatoes taken out from a box of 100 vegetables, leaves ……… carrots 100 – ……… = ………
10065 tomatoes? carrots
The whole box holds 100 vegetables.
Answer
65 tomatoes taken out from a box of 100 vegetables, leaves 35 carrots
100 − 65 = 35

If we know the whole and one part, we take that part away to find the other part.

In-text Questions — Page 40Plucking the ripe apples

Q1

Nani Maa asks Nandini and Chirag to pluck the ripe apples. Woho! So many of them.
Nandini: I collected 85 apples.
Chirag: I plucked 67 apples.
Let us see how many total apples we have collected.
Nandini: 80 and 20 is 100. So they would be more than 100 in all.

Draw a box diagram for the problem below.

Nandini85 applesChirag67 apples
What the two children said they had plucked.
Answer
?8567
A box diagram: the two parts are known and the whole is not.

Draw one long box with two parts. Write 85 (Nandini) in one part and 67 (Chirag) in the other. Write ? above the whole box for the total.

Q2How many apples in all?
85 apples67 apples
The two collections shown in bundles of ten and loose sticks.
Answer
85 + 67 = 152 apples

Bundles: 8 + 6 = 14. Sticks: 5 + 7 = 12, that is 1 more bundle and 2 sticks. 15 bundles and 2 sticks. Ten bundles make 100, so 100 + 50 + 2 = 152.

In-text Questions — Page 41Who collected more apples?

Q1Try finding out the answer on the number line below.
85 Apples + 67 Apples = ………. Apples
85 + 67 = ……….
708090100110120130140150160170
The number line printed in the book, from 70 to 170.
Answer
85 Apples + 67 Apples = 152 Apples
85 + 67 = 152

Start at 85. Jump 60 to 145, then 5 to 150, then 2 to 152.

708090100110120130140150160170+60+5+2
Three jumps take 85 up to 152.
Q2

Who collected more, Nandini or Chirag? How much more?

Chirag draws a box diagram for the problem. The book also shows Nandini’s apples (8 bundles and 5 sticks), Chirag’s apples (6 bundles and 7 sticks) and a box “How much more?” with two circles to fill.

8567?
Chirag’s box diagram: 85 is the whole, 67 is one part.
Answer

Nandini collected more, 18 apples more.

85 − 67 = 18   (1 bundle and 8 sticks)

Count up from 67: 67 + 3 = 70, 70 + 15 = 85. 3 + 15 = 18.

856718
The missing part is 18.
Q3……………. collected ……… apples more than ……………. .
8567?
Chirag’s box diagram: 85 is the whole, 67 is one part.
Answer
Nandini collected 18 apples more than Chirag.

85 − 67 = 18

In-text Questions — Page 42Word problems with box diagrams, and the game of reaching 100

Q1

Solve the following problems by first drawing the box diagrams. Use matchstick bundles or a number line to find the answer.

1. Babli didi sold 34 books on Monday and 45 books on Tuesday. How many books did she sell in the two days? How many more did she sell on Tuesday than on Monday?

Answer
?34 on Monday45 on Tuesday
Box diagram for the two days of book selling.
34 + 45 = 79 books   (34 + 40 = 74, 74 + 5 = 79)
4534?
Comparing the two days: Tuesday is the longer bar.
45 − 34 = 11 books

She sold 79 books in two days and 11 more on Tuesday.

Q22. In a cricket match at Rosary school, Team Red made 56 runs before lunch and 65 runs after lunch. How many total runs did they make?
Answer
?56 before lunch65 after lunch
Box diagram for the runs made in the match.
56 + 60 = 116, 116 + 5 = 121
56 + 65 = 121 runs

Team Red made 121 runs in all.

Q33. Rama sells vadas in the school canteen. She has sold 39 vadas the first day. She sold 12 more the next day. How many vadas did she sell in these two days?
Answer
?39 first day12 next day
Box diagram for the vadas sold on two days.
39 + 1 = 40, 40 + 11 = 51
39 + 12 = 51 vadas

She sold 51 vadas in the two days.

Q44. Gehu brings 56 plants for her terrace garden. Some plants dried up. She is left with 29 plants. How many plants dried up?
Answer
5629 left? dried up
Box diagram for the plants: 56 is the whole.
Count up from 29: 29 + 1 = 30, 30 + 26 = 56. 1 + 26 = 27
56 − 29 = 27 plants

27 plants dried up.

Q55. Choose any two numbers. Make a word problem using the two numbers. Share it with your classmates.
Answer

(numbers 48 and 35): A shop had 48 mangoes. It got 35 more. How many mangoes does it have now?

48 + 35 = 83 mangoes
8348 mangoes35 mangoes
A box diagram for a word problem you make yourself.
Q6

This game is to be played between two children. The first player should say a number between 1 and 10. The second player adds a number between 1 and 10 to the first player’s number. The first player again adds a number between 1 and 10 to the previous sum. The player to reach 100 first is the winner. An example is given here:

Player 1Player 2Total
99
1019
827
936
1046
854
1064
1074
983
790
10100
The round printed in the book. Player 1 reaches 100 first.

Player 1 wins this round! Play this game with your friends.

Answer

Sample round: I say 6. My friend adds 10 → 16. I add 7 → 23. We go on taking turns. When the total is 92, I add 8 and reach 100. I win!

Let us Do — Page 43Estimating — more or less than 100

Q1

1. Estimate the answer and say if it will be more or less than 100. Match with the correct one.

Nandini: 150 – 50 is 100. So, 150 – 49 is more than 100.

First boxSecond box
134 − 5668 − 26
20 + 4195 + 10 + 5
150 − 49109 − 80
199 − 9063 + 26
70 + 30 + 1124 + 23 + 20
156 − 65
The eleven problems printed in the two pink boxes. Each one has to be matched with ‘More than 100’ or ‘Less than 100’.
Answer
More than 100Less than 100
150 − 49134 − 56
199 − 9020 + 41
70 + 30 + 1156 − 65
95 + 10 + 568 − 26
124 + 23 + 20109 − 80
63 + 26
130 − 50 = 80, so 134 − 56 is less than 100
70 + 30 = 100, so 70 + 30 + 1 is more than 100
Q22. Solve the above problems using a number line. Write the answer next to the problem.
First boxSecond box
134 − 5668 − 26
20 + 4195 + 10 + 5
150 − 49109 − 80
199 − 9063 + 26
70 + 30 + 1124 + 23 + 20
156 − 65
The eleven problems printed in the two pink boxes. Each one has to be matched with ‘More than 100’ or ‘Less than 100’.
Answer
ProblemAnswerMore or less than 100?
134 − 5678Less than 100
20 + 4161Less than 100
150 − 49101More than 100
199 − 90109More than 100
70 + 30 + 1101More than 100
156 − 6591Less than 100
68 − 2642Less than 100
95 + 10 + 5110More than 100
109 − 8029Less than 100
63 + 2689Less than 100
124 + 23 + 20167More than 100
Every problem with its exact answer.
134 − 56: 134 − 50 = 84, 84 − 6 = 78
124 + 23 + 20: 124 + 20 = 144, 144 + 3 = 147, 147 + 20 = 167

Chapter 4 of 14 – Maths Mela

Also for This Chapter

NCERT Solutions Class 3 Maths Maths Mela Chapter 4 Vacation with My Nani Maa – Overview

ClassClass 3
SubjectMaths
BookMaths Mela
Chapter4 – Vacation with My Nani Maa
Textbook pages29 – 43
Questions solved56
Session2027
FormatFull answers on this page + PDF

NCERT Solutions Class 3 Maths Chapter 4 – FAQs

Where can I download NCERT Solutions Class 3 Maths Maths Mela Chapter 4 Vacation with My Nani Maa PDF?

Read every answer on this page, or download the free PDF from the table at the top.

Is this for the 2027 session?

Yes, it follows the latest NCERT Class 3 Maths book for 2027.

How many questions are solved in NCERT Class 3 Maths Chapter 4?

All 56 questions of the chapter (textbook pages 29 – 43) – the in-text questions, activities and the end-of-chapter exercises.

How should I use these solutions?

Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.

Official website: ncert.nic.inNational Council of Educational Research and Training publishes date sheets, admit cards and results here
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