NCERT Solutions for Class 3 Maths Chapter 7 Raksha Bandhan (PDF) – 2027
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NCERT Solutions for Class 3 Maths Maths Mela Chapter 7 Raksha Bandhan – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.
Raksha Bandhan brings Gopal, Dhara and their Atya together. As they make rakhis, buy laddoos and share sweets, we learn multiplication as repeated addition and division as equal sharing.
NCERT Solutions for Class 3 Maths Maths Mela Chapter 7 Raksha Bandhan PDF
All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.
NCERT Solutions for Class 3 Maths Maths Mela Chapter 7 Raksha Bandhan – Questions and Answers
All 95 questions of the chapter (textbook pages 82 – 106) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.
In-text Questions — Page 82Chapter opener — Gopal’s house
Q1Carefully observe Gopal’s house. What do you find interesting here?Gopal’s house drawn again, with the leaves, glasses, baskets and flower plates.
Answer
The house is ready for the festival. Here are three things I found interesting.
A green toran of leaves hangs over the door.
The same things are kept in equal groups — 5 pomegranates in every basket.
The glasses stand in neat rows, so they are easy to count.
Q2Find and count the number of each of these objects and write. Leaves ______ Glasses ______ Pomegranate ______ Flowers ______Gopal’s house drawn again, with the leaves, glasses, baskets and flower plates.
Answer
Count each set in groups. Do not count one by one.
Object
How to count
Number
Leaves
12 on one side, 12 on the other
24
Glasses
20 on the table and 10 on the tray
30
Pomegranate
4 baskets, 5 in each basket
20
Flowers
2 plates, 10 in each plate
20
Celebration Begins! / Let’s Make Rakhis — Page 83Guessing the festival and planning the rakhis
Q1Dhara’s mother has bought some material for the festival. Guess the festival they are preparing for.The festival material on the table; described here, see the textbook for the painting.
Answer
They are getting ready for Raksha Bandhan.
On the table are coloured threads, beads and flowers. These are used to make rakhis.
There are sweets and a gift too.
Dhara herself says, “Raksha bandhan!”
Q2For each Rakhi, we need one flower, ………. threads and ………. beads.One rakhi with its flower, threads and beads.
Answer
Look at one rakhi in the picture and count its parts.
For each rakhi we need
1 flower 2 threads 4 beads
Q3We need to make 5 Rakhis. How many threads, flowers and beads do they need?The flowers, the threads and the beads laid out for five rakhis.
Answer
One rakhi takes 1 flower, 2 threads and 4 beads. Take that 5 times.
Q1Each Rakhi uses 1 flower. We need to make 5 Rakhis. 1 + 1 + 1 + 1 + 1 = …… This can also be said as 5 times 1 or 5 × 1 = 5. For 5 Rakhis, we need ……… flowers.The flowers, the threads and the beads laid out for five rakhis.
Answer
Five rakhis need 5 flowers.
1 + 1 + 1 + 1 + 1 = 5
5 times 1
5 × 1 = 5
Q2Each Rakhi uses 2 threads. We need to make 5 Rakhis. 2 + 2 + 2 + 2 + 2 = …… or 5 times 2 or 5 × 2 = …… For 5 Rakhis, we need ………….. threads.The flowers, the threads and the beads laid out for five rakhis.
Answer
Five rakhis need 10 threads.
2 + 2 + 2 + 2 + 2 = 10
5 times 2
5 × 2 = 10
Q3Each Rakhi uses 4 beads. We need to make 5 Rakhis. 4 + 4 + 4 + 4 + 4 = …… or 5 times 4 or 5 × 4 = …… For 5 Rakhis, we need ………….. beads.The flowers, the threads and the beads laid out for five rakhis.
Answer
Five rakhis need 20 beads.
4 + 4 + 4 + 4 + 4 = 20
5 times 4
5 × 4 = 20
Try it Out! — Page 85Rakhis for more people
Try This
Q1For making 10 such Rakhis, we need ……… flowers, ……… threads and ……… beads.One rakhi with its flower, threads and beads.
Q2There are 30 flowers, 30 threads and 30 beads. How many Rakhis can you make with this material? Use drawings if needed to find out the answer.One rakhi with its flower, threads and beads.
Answer
We can make 7 rakhis.
Each rakhi needs 4 beads.
7 × 4 = 28 beads. 2 beads are left.
8 rakhis would need 32 beads. We have only 30.
Threads (14) and flowers (7) are enough for 7 rakhis.
Q3FUN ACTIVITY: Try making a colourful Rakhi at your home. Show it in class.
Answer
I made a rakhi with 1 paper flower, 2 threads and 4 beads. I showed it in class.
In-text Questions — Page 86Jagannath Sweet Shop
Q1How would we count the laddoos in this box? 3 + 3 + 3 = …… or, three times three equals 9 or, 3 × 3 = …… There are …… laddoos in this box.The box of laddoos from the sweet shop.
Answer
Count the laddoos row by row. There are 3 rows of 3.
3 + 3 + 3 = 9
three times three equals 9
3 × 3 = 9
There are 9 laddoos in this box.
Q2Please give me 2 boxes of laddoos. 9 + 9 = 18, 2 × 9 = 18. Also, 3 + 3 + 3 + 3 + 3 + 3 = ……. Or, 6 times 3 equals 18. Or, 6 × 3 = 18.The two boxes of laddoos Dhara asked for.
Q1After Atya and children come, we will be 9 people in the house. When we distribute 18 laddoos equally to all, how many will each of us get?The laddoos that are to be shared at home.
Answer
Each person gets 2 laddoos.
18 shared equally by 9
18 ÷ 9 = 2 laddoos
Q2Imagine yourself to be Dhara. Distribute 18 laddoos equally among nine of your friends. Items left: …….. Items left: …….. When 18 laddoos are shared equally among nine people, each of them gets ………… laddoos.The 18 laddoos and the nine empty plates.
Answer
Put one laddoo in each plate, then go round again.
Round
Laddoos given
Items left
First
1 to each of 9
18 – 9 = 9
Second
1 more to each of 9
9 – 9 = 0
Each of them gets 2 laddoos. 18 ÷ 9 = 2.
Try it Out! — Pages 88–89Sharing kaju katlis among 5 people
Try This
Q1Look at the figure carefully. Estimate the number of kaju katlis. Count and write the number of kaju katlis. Total number of kaju katlis = ………The kaju katlis lying in the tray.
Answer
First guess, then count in rows.
My estimate: about 20.
There are 4 rows with 5 kaju katlis in each row.
5 + 5 + 5 + 5 = 20.
Total number of kaju katlis = 20.
Q2Distribute all kaju katlis equally among 5 people. You can do it by drawing kaju katlis on the plates. How many will each get?The tray of kaju katlis and the five empty plates.
Answer
Each person gets 4 kaju katlis.
Put 1 in each plate. 15 are left.
Put 1 more in each. 10 are left.
Put 1 more in each. 5 are left.
Put 1 more in each. None is left.
20 equally shared by 5 is 4 each.
20 ÷ 5 = 4
Q3Compare your work with Dhara’s work. Items left: …….. Items left: …….. Items left: …….. Items left: ……..
Round
Taken away
Items left
Start
20
1
– 5
2
– 5
3
– 5
4
– 5
Answer
Dhara takes away 5 each time and writes what is left.
20 – 5 = 15
15 – 5 = 10
10 – 5 = 5
5 – 5 = 0
She subtracted 5 four times, so each person got 4.
Let us Do — Pages 90–91Sharing sweets equally
Q1Distribute all the kaju katlis equally among 4 people. How many kaju katlis will each get? Let us do this in the picture given below. Strike out the kaju katlis from the tray and draw them in the plates. Each will get …….. kaju katlis. 16 ÷ 4 = ……..The tray of kaju katlis and the four empty plates.
Answer
Each will get 4 kaju katlis.
16 – 4 = 12 left
12 – 4 = 8 left
8 – 4 = 4 left
4 – 4 = 0 left
16 ÷ 4 = 4.
Q2Distribute 15 pedas in plates equally among 5 people. How many pedas will each get? 15 equally shared by 5 is …….. each. 15 ÷ 5 = …….. .The pedas and the five plates they go into.
Answer
Each person gets 3 pedas.
15 – 5 = 10 left
10 – 5 = 5 left
5 – 5 = 0 left
15 equally shared by 5 is 3 each. 15 ÷ 5 = 3.
Let us Think — Pages 91–92Cycle wheels and jalebis
Math Talk
Q1Each cycle needs 2 wheels. How many cycles can be fitted with 12 wheels? 12 equally divided by 2 is …….. . 12 ÷ 2 = …….. .The cycle frames and the wheels lying beside them.
Answer
6 cycles can be fitted.
Put the wheels in pairs: 2, 2, 2, 2, 2, 2.
Count the pairs — there are 6.
12 equally divided by 2 is 6.
12 ÷ 2 = 6
Q2Look at the picture carefully. Count the number of jalebis. There are …….. jalebis. How did you count? Discuss with your friends.The plates of jalebis Gopal bought.
Answer
There are 24 jalebis.
Every plate has 4 jalebis.
There are 6 plates.
Skip count by 4 — 4, 8, 12, 16, 20, 24.
Q3Counting in groups, we see there are six groups of four jalebis each, or, 4 + 4 + 4 + 4 + 4 + 4 = ……. or …….. × 4 = …….. jalebis.The plates of jalebis Gopal bought.
Answer
Six groups of four make 24.
4 + 4 + 4 + 4 + 4 + 4 = 24 6 × 4 = 24 jalebis
Q4Are there enough jalebis for everyone in Dhara’s family to have four each? Share your thoughts in the class.The plates of jalebis Gopal bought.
Answer
No, there are not enough jalebis.
9 members, 4 jalebis each
9 × 4 = 36 jalebis needed
They have only 24.
Q5How many jalebis should Dhara buy so that everyone can get four each?The plates of jalebis Gopal bought.
Q3Can you complete this equal grouping and write it as multiplication?The same dots with the first two groups already ringed.
Answer
Ring the dots in groups of 4 — two dots across and two down.
Each ring holds 4 dots.
There are 12 such rings in all.
12 × 4 = 48
Q4Can you find more equal groups of different sizes? Draw them and write as multiplication.The dots printed in the book, drawn again.
Answer
Yes. The same 48 dots can be grouped in many ways.
Group size
Number of groups
Multiplication
2
24
24 × 2 = 48
3
16
16 × 3 = 48
6
8
8 × 6 = 48
8
6
6 × 8 = 48
Visit to a Farm — Page 94Counting the chickens in twos
Q1Let us count chickens in the farm! 4 times 2 is ……. or, 4 × 2 = ……. ; 5 times 2 is ……. or, 5 × 2 = ……. ; 6 times 2 is ……. or, 6 × 2 = ……. ; ……. times 2 is ……. or, ……. × 2 = ……. ; ……. times ……. is ……. or, 8 × 2 = ……. ; ……. times ……. is ……. or, 9 × 2 = ……. ; ……. times ……. is ……. or, 10 × 2 = …….The chicks in the farm, standing in pairs.
Answer
The chicks stand in pairs. Each new row has one pair more.
In words
Is
Multiplication
4 times 2
8
4 × 2 = 8
5 times 2
10
5 × 2 = 10
6 times 2
12
6 × 2 = 12
7 times 2
14
7 × 2 = 14
8 times 2
16
8 × 2 = 16
9 times 2
18
9 × 2 = 18
10 times 2
20
10 × 2 = 20
Skip Jumping Game — Page 95Dhara skip jumps by 3
Try This
Q1Starting from 0, Dhara jumps to 3. From 3 she goes to 6. From 6 she goes to 9. Now, continue to see how Dhara jumps after 9.The number track with Dhara’s first three jumps drawn on it.
Answer
After 9 she lands on 12, then 15, then 18.
9 + 3 = 12
12 + 3 = 15
15 + 3 = 18
Q2DHARA IS SKIP JUMPING BY 3. Number of jumps → Number reached. 4 jumps → ……… , 5 jumps → ……… , 6 jumps → ……… , 7 jumps → ……… , 8 jumps → ……… , 9 jumps → ……… , 10 jumps → ………The number track with Dhara’s first three jumps drawn on it.
Answer
Each jump adds one more 3.
Jumps
Addition
Number reached
4
3 + 3 + 3 + 3 = 4 × 3
12
5
5 × 3
15
6
6 × 3
18
7
7 × 3
21
8
8 × 3
24
9
9 × 3
27
10
10 × 3
30
Let us Do — Pages 96–97Skip jumping and times tables
Q1Guess and write the next number she will jump onto.The number track with Dhara’s first three jumps drawn on it.
Answer
She has reached 9. The next number is 12.
9 + 3 = 12
Q2Is there a pattern in these numbers: 3, 6, 9, …?The number track with Dhara’s first three jumps drawn on it.
Answer
Yes, there is a pattern.
Each number is 3 more than the one before it.
3, 6, 9, 12, 15, 18, 21, 24, 27, 30.
These are exactly the numbers of the times-3 table.
Q3How many steps forward is Dhara jumping each time?The number track with Dhara’s first three jumps drawn on it.
Answer
Dhara jumps 3 steps each time.
0 → 3 → 6 → 9
3 – 0 = 3, 6 – 3 = 3, 9 – 6 = 3
Q4Continue skip jumping by 6, by drawing the jumps on the number track.The number track from 0 to 25, with the first two jumps of 6 drawn on it.
Answer
Start at 0 and add 6 each time.
0 → 6 → 12 → 18 → 24
Draw two more jumps: 12 to 18 and 18 to 24. The track ends at 25, so stop at 24.
The jumps of 6 drawn up to 24 (new jumps in green).
Q5Can this skip jumping be used to form times-6 table? Write times-6 table in your notebook.The number track from 0 to 25, with the first two jumps of 6 drawn on it.
Answer
Yes. The landing numbers make the times-6 table.
1 × 6 = 6
6 × 6 = 36
2 × 6 = 12
7 × 6 = 42
3 × 6 = 18
8 × 6 = 48
4 × 6 = 24
9 × 6 = 54
5 × 6 = 30
10 × 6 = 60
Q6Is there repeated addition happening? Make times-4 table using repeated addition in the picture given below.The number track with the first two jumps of 4 drawn on it.
Answer
Yes, 4 is being added again and again.
Jumps
Repeated addition
Number reached
1
4
4
2
4 + 4
8
3
4 + 4 + 4
12
4
4 + 4 + 4 + 4
16
5
5 × 4
20
6
6 × 4
24
7
7 × 4
28
8
8 × 4
32
9
9 × 4
36
10
10 × 4
40
Q7Gopal is doing skip jumping of …………. steps. After 27 he will jump on …………., …………..The number track with Gopal’s jumps drawn on it.
Q8What times table can you construct from Gopal’s jumps? Make it in your notebook.The number track with Gopal’s jumps drawn on it.
Answer
We get the times-9 table.
1 × 9 = 9
6 × 9 = 54
2 × 9 = 18
7 × 9 = 63
3 × 9 = 27
8 × 9 = 72
4 × 9 = 36
9 × 9 = 81
5 × 9 = 45
10 × 9 = 90
Q9Dhara also skip jumps. Gopal notes down the jumps but he misses the first few numbers.The numbers Gopal wrote down. The first three boxes are empty.By what numbers was Dhara skip jumping? Construct the times table of this number in your notebook.
Answer
Dhara was skip jumping by 8.
40 – 32 = 8
48 – 40 = 8
56 – 48 = 8
The missed numbers are 8, 16 and 24. The table is:
1 × 8 = 8
6 × 8 = 48
2 × 8 = 16
7 × 8 = 56
3 × 8 = 24
8 × 8 = 64
4 × 8 = 32
9 × 8 = 72
5 × 8 = 40
10 × 8 = 80
Let us Play — Page 97Reaching the flower on 12
Try This
Q1Atya places a flower on 12. Skip jump with equal steps to reach the flower. No direct jumping to the flower is allowed. The one who reaches the flower in the smallest number of jumps wins. What skip jumping number will you choose? ……….The playing track with Atya’s flower placed on it.
Answer
I will choose 6. I reach 12 in only 2 jumps.
Jump size
Landing numbers
Jumps needed
2
2, 4, 6, 8, 10, 12
6
3
3, 6, 9, 12
4
4
4, 8, 12
3
6
6, 12
2
Q2Are there numbers that can be reached only through skip jumping by 1? Find 3 such numbers.The number track from 0 to 50.
Answer
Yes. Three such numbers are 7, 11 and 13.
7 — jumps of 2, 3, 4, 5 or 6 all miss it.
11 — no equal jump lands on it except 1.
13 — the same thing happens.
Q3Play this game with your friends by putting the flower on different numbers on the track. See who is able to reach in the minimum number of jumps.
Answer
Choose the biggest jump that lands on the flower but is smaller than the flower’s number.
Flower on
Best jump
Jumps needed
10
5
2
15
5
3
18
9
2
20
10
2
Fun Way of Writing Tables — Page 98Mithu’s sticks
Try This
Q1Mithu figures out another way of writing multiplication tables by drawing sticks! Do you see repeated addition in this?The sticks Mithu arranged, with a red dot at every crossing.
Answer
Yes. Each new standing stick adds 5 more red dots.
Mithu has 5 lying sticks and 4 standing sticks.
Each standing stick crosses all 5 lying sticks and makes 5 dots.
5 + 5 + 5 + 5 = 20 dots
4 × 5 = 20
Q2Complete the times-5 table using sticks. 1 × 5 = 5, 2 × 5 = 10, 3 × 5 = 15, 4 × 5 = , 5 × 5 = , 6 × 5 = , 7 × 5 = , 8 × 5 = , 9 × 5 =The first three rows of the times-5 table made with sticks.
Answer
Add one more standing stick each time. It crosses the 5 lying sticks and makes 5 more red dots.
Q3Make times-6 to times-10 tables using the sticks method shown above.The sticks Mithu arranged, with a red dot at every crossing.
Answer
For the times-6 table keep 6 lying sticks, for times-7 keep 7, and so on. Add standing sticks one by one and count the red dots.
Standing sticks
× 6
× 7
× 8
× 9
× 10
1
6
7
8
9
10
2
12
14
16
18
20
3
18
21
24
27
30
4
24
28
32
36
40
5
30
35
40
45
50
6
36
42
48
54
60
7
42
49
56
63
70
8
48
56
64
72
80
9
54
63
72
81
90
10
60
70
80
90
100
Seeing Patterns in Multiplication Tables — Page 99The times-5 table
Math Talk
Q1Look at the times-5 table. What patterns do you see?
Row
Answer
1 × 5
5
2 × 5
10
3 × 5
15
4 × 5
20
5 × 5
25
6 × 5
30
7 × 5
35
8 × 5
40
9 × 5
45
10 × 5
50
Answer
The times-5 table has a clear pattern.
The answers end in 5, 0, 5, 0, 5, 0 …
Odd rows (1, 3, 5, 7, 9) end in 5.
Even rows (2, 4, 6, 8, 10) end in 0.
Each answer is 5 more than the one above it.
Q2Guess what will be the last digits of 11 × 5 and 12 × 5.
Row
Answer
1 × 5
5
2 × 5
10
3 × 5
15
4 × 5
20
5 × 5
25
6 × 5
30
7 × 5
35
8 × 5
40
9 × 5
45
10 × 5
50
Answer
The last digit of 11 × 5 is 5. The last digit of 12 × 5 is 0.
11 × 5 = 55
12 × 5 = 60
Q3Give 3 examples of numbers that when taken 5 times gives an answer ending with (a) 0 ……. ……. ……. (b) 5 ……. ……. …….
Row
Answer
1 × 5
5
2 × 5
10
3 × 5
15
4 × 5
20
5 × 5
25
6 × 5
30
7 × 5
35
8 × 5
40
9 × 5
45
10 × 5
50
Answer
Even numbers give an answer ending in 0. Odd numbers give an answer ending in 5.
Answer ends with
Numbers
Check
(a) 0
2, 4, 6
2 × 5 = 10, 4 × 5 = 20, 6 × 5 = 30
(b) 5
1, 3, 7
1 × 5 = 5, 3 × 5 = 15, 7 × 5 = 35
Q4Without finding the answer, can you tell the last digits of 18 × 5, 23 × 5, 32 × 5, 50 × 5.
Row
Answer
1 × 5
5
2 × 5
10
3 × 5
15
4 × 5
20
5 × 5
25
6 × 5
30
7 × 5
35
8 × 5
40
9 × 5
45
10 × 5
50
Answer
Yes. Just look at whether the number is even or odd.
Product
Even or odd
Last digit
18 × 5
18 is even
0
23 × 5
23 is odd
5
32 × 5
32 is even
0
50 × 5
50 is even
0
In-text Questions — Page 100How the tables of 2, 3 and 5 are joined
Math Talk
Q1Look at the times tables of 2, 3, 5. They have a relation between them. Can you see it?The three table cards printed in the book.
Answer
Yes. The times-2 answer plus the times-3 answer gives the times-5 answer.
2 + 3 = 5
4 + 6 = 10
6 + 9 = 15
8 + 12 = 20
Q2Is there a relation between the two circled numbers and the boxed number? Does this happen for the next rows also?The three table cards printed in the book.
Answer
Yes. The two circled numbers add up to the boxed number.
Circled: 2 and 3. Boxed: 5.
2 + 3 = 5
It happens in the next rows too: 4 + 6 = 10, 6 + 9 = 15, 8 + 12 = 20.
Q3Can you find other examples of two tables adding up to a third table?The three table cards printed in the book.
Answer
Yes, there are many such pairs.
Two tables
Third table
Example
2 and 2
4
6 + 6 = 12, and 3 × 4 = 12
3 and 4
7
9 + 12 = 21, and 3 × 7 = 21
4 and 5
9
8 + 10 = 18, and 2 × 9 = 18
6 and 4
10
18 + 12 = 30, and 3 × 10 = 30
Let us Do — Page 100Word problems on multiplication and division
Q1Draw pictures for each of the following problems in your notebook. Use counting, number line jumps or any other method to solve the problems. (a) There are 5 jars with 4 cookies in each jar. How many cookies are there?
Answer
There are 20 cookies.
4 + 4 + 4 + 4 + 4 = 20
5 × 4 = 20
Q2(b) An idli vessel contains 6 idli plates. In each plate we can make 4 idlis. How many idlis can be cooked in one go?
Answer
24 idlis can be cooked in one go.
4 + 4 + 4 + 4 + 4 + 4 = 24
6 × 4 = 24
Q3(c) 30 cookies are to be distributed among 5 children equally. How many cookies will each child get?
My word problem: 45 laddoos are put equally in 5 boxes. How many laddoos go in each box?
In-text Questions — Page 101Bhim’s cardboard rath
Q1Bappa, I am making a cardboard rath. I need to make spokes for 20 wheels of the rath. Each wheel needs 5 spokes. Help Bhim! Bhim will need …….. spokes.Ten wheels of the rath, each with its spokes.
Answer
Bhim will need 100 spokes.
20 wheels × 5 spokes
10 wheels need 50 spokes
Another 10 wheels need 50 spokes
50 + 50 = 100 spokes
Q210 wheels will need: 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 10 × 5 = …….. spokes. Another 10 wheels will need …….. × …….. = …….. spokes. So, the total number of spokes needed is …….. + …….. = …….. spokes.Ten wheels of the rath, each with its spokes.
Q130 × 5 = ………. (Hint: You can find this by counting the spokes in 30 wheels.) First 10 wheels will have …….. spokes. Second 10 wheels will have …….. spokes. Third 10 wheels will have …….. spokes. Total = …….. spokes. 30 × 5 = …….. spokes.Ten wheels of the rath, each with its spokes.
Answer
Break 30 wheels into three groups of 10.
First 10 wheels: 50 spokes
Second 10 wheels: 50 spokes
Third 10 wheels: 50 spokes
Total = 50 + 50 + 50 = 150 spokes
30 × 5 = 150 spokes
Q4Here is a 3-wheeled auto rickshaw. How many wheels are there in: (a) 18 auto rickshaws? (b) 34 auto rickshaws?The three-wheeled auto rickshaw from the book.
Answer
Each auto rickshaw has 3 wheels.
(a) 18 autos: 10 autos have 30 wheels
8 autos have 24 wheels
30 + 24 = 54 wheels
(b) 34 autos: 30 autos have 90 wheels
4 autos have 12 wheels
90 + 12 = 102 wheels
Q5Auto rickshaws in a garage have a total of 36 wheels. How many auto rickshaws are there in the garage?The three-wheeled auto rickshaw from the book.
Q8Karry, the crow, can see 24 horns of cows in the shed. What is the total number of legs in the shed?
Answer
There are 48 legs in the shed.
One cow has 2 horns. So 24 ÷ 2 = 12 cows.
One cow has 4 legs. So 12 × 4 = 48 legs.
Let us Think — Page 103The frog’s jumps of 7
Math Talk
Q1A frog is at 0. It takes jumps of only 7. What would be the largest number that the frog will reach before crossing 50?The number track from 0 to 50.
Answer
The largest such number is 49.
0 → 7 → 14 → 21 → 28 → 35 → 42 → 49
49 + 7 = 56, which is past 50.
Q2A frog wants to jump backwards from 50. It continues to take jumps of 7. What is the number after which it is not possible for the frog to make a jump of 7?The number track from 0 to 50.
Answer
The frog stops at 1.
50 → 43 → 36 → 29 → 22 → 15 → 8 → 1
From 1 it cannot take another jump of 7.
Q3What numbers should the frog start from to reach 0, taking jumps of 7 each time? What do you observe?The number track from 0 to 50.
Answer
It should start from 7, 14, 21, 28, 35, 42 or 49.
49 → 42 → 35 → 28 → 21 → 14 → 7 → 0
What I observe: All these are numbers of the times-7 table.
Puri Beach — Page 104Shopping at the beach
Q1One wall-hanging costs ₹42. How much do two wall hangings cost? Two wall hangings cost ₹42 + ₹42 = 2 × ₹42. The cost of the two wall hangings: ……….A wall hanging from the Puri beach shop.
Answer
Two wall hangings cost ₹ 84.
₹ 42 + ₹ 42
40 + 40 = 80
2 + 2 = 4
80 + 4 = ₹ 84
Q2One rabdi cup costs ₹75. Preeti buys 5 cups of rabdi. She has her mother’s purse which has only ₹100 notes. How many ₹100 notes should she give to the shopkeeper? How much will the shopkeeper then return to Preeti? What is the total cost of 5 cups of rabdi?A cup of rabdi from the shop.
She should give 4 notes of ₹ 100 (₹ 400).
The shopkeeper returns ₹ 400 – ₹ 375 = ₹ 25.
Sea-Shells — Pages 104–105Dhruv makes necklaces from 112 shells
Q1I will make a necklace of 28 shells. Will these shells be enough to make necklaces for my three friends?Dhruv and the shells he collected; described here, see the textbook for the painting.
He still has 28 shells left after three necklaces.
Q2He took 28 shells for one necklace. 112 – 28 = 84. Now, he was left with 84 shells. Again, he took 28 more shells for the second necklace. How many shells are left now?Dhruv and the shells he collected; described here, see the textbook for the painting.
Answer
56 shells are left.
84 – 28
84 – 20 = 64
64 – 8 = 56
Q3Then, he took 28 shells for the third necklace. So, he was left with ……….. shells.Dhruv and the shells he collected; described here, see the textbook for the painting.
Answer
He was left with 28 shells.
56 – 28
56 – 20 = 36
36 – 8 = 28
Q4Are the shells enough for making necklaces for all his friends? ………..Dhruv and the shells he collected; described here, see the textbook for the painting.
Answer
Yes, the shells are enough.
Three friends need 3 × 28 = 84 shells
Dhruv has 112 shells
112 – 84 = 28 shells still left
Q5How many necklaces can Dhruv make from 112 shells? ………..Dhruv and the shells he collected; described here, see the textbook for the painting.
Q3Preeti has a ₹500 note and wants to exchange it for lower denomination notes. How many notes will she get if she wants— (a) All 50 rupees notes? (b) All 20 rupees notes? (c) All 10 rupees notes?
Answer
Skip count up to 500 with each note.
Note
Skip counting
Number of notes
₹ 50
50, 100, 150 … 500
10
₹ 20
5 notes make ₹ 100, so 5 × 5
25
₹ 10
10 notes make ₹ 100, so 10 × 5
50
Let us Explore — Page 106The five sealed envelopes
Math Talk
Q1There are ten number cards from 1–10. There are five sealed envelopes. Each has two cards on the top of each envelope, the multiplication of the numbers contained in it is written. The fifth envelope contains the cards 5 and 9. The number 5 × 9 = 45 is written on the envelope. Identify the number cards inside each of the envelopes.The ten number cards and the five envelopes.
Answer
Cards 5 and 9 are already used. Eight cards are left: 1, 2, 3, 4, 6, 7, 8, 10.
