NCERT Solutions for Class 3 Maths Chapter 12 Give and Take (PDF) – 2027
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NCERT Solutions for Class 3 Maths Maths Mela Chapter 12 Give and Take – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.
This chapter is about adding and taking away with numbers up to 999. Kishan counts the saplings in his nursery and Peter uncle counts the money in his shop. Box diagrams, hundreds-tens-ones blocks, a number line and real notes and coins all help.
NCERT Solutions for Class 3 Maths Maths Mela Chapter 12 Give and Take PDF
All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.
NCERT Solutions for Class 3 Maths Maths Mela Chapter 12 Give and Take – Questions and Answers
All 53 questions of the chapter (textbook pages 150 – 164) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.
In-text Questions — Page 150The number chains on the chapter’s first page
Q1Add 2. Fill in the empty parts of the snake. The snake begins 334, 336, …The snake from the chapter opener. Two parts are already filled in.
Answer
Add 2 to each part to get the next part.
334 → 336 → 338 → 340 → 342 → 344
So the empty parts are 338, 340, 342, 344.
Q2Add 5. Fill in the empty parts of the caterpillar. The caterpillar begins 375, …The caterpillar from the chapter opener. Only the first part is filled in.
Answer
Add 5 to each part to get the next part.
375 → 380 → 385 → 390 → 395
→ 400 → 405 → 410
The caterpillar has 8 parts. So it reads 375, 380, 385, 390, 395, 400, 405, 410.
Q3Subtract 5. Fill in the empty parts of the worm. The worm begins 387, …The orange worm from the chapter opener. Only the first part is filled in.
Answer
Take away 5 each time.
387 → 382 → 377 → 372
→ 367 → 362 → 357
So the worm reads 387, 382, 377, 372, 367, 362, 357.
Q4Add 6. Fill in the row of boxes that begins with 234.The printed row of seven boxes. Only the first box is filled.
Answer
Add 6 to each box to fill the next one.
234 → 240 → 246 → 252
→ 258 → 264 → 270
The row is 234, 240, 246, 252, 258, 264, 270.
Q5Subtract 6. Fill in the row of boxes that begins with 357.The printed row of seven boxes. Only the first box is filled.
Answer
Take 6 away from each box to fill the next one.
357 → 351 → 345 → 339
→ 333 → 327 → 321
The row is 357, 351, 345, 339, 333, 327, 321.
Q6Add 9. Fill in the row of boxes that begins with 288.The printed row of seven boxes. Only the first box is filled.
Answer
Add 9 to each box to fill the next one.
288 → 297 → 306 → 315
→ 324 → 333 → 342
The row is 288, 297, 306, 315, 324, 333, 342.
Q7Subtract 9. Fill in the row of boxes that begins with 331.The printed row of seven boxes. Only the first box is filled.
Answer
Take 9 away from each box to fill the next one.
331 → 322 → 313 → 304
→ 295 → 286 → 277
The row is 331, 322, 313, 304, 295, 286, 277.
In-text Questions — Page 151How many saplings in all?
Q1Kishan had 364 saplings of different herbs and flowers. Then, he went to his friend’s village and brought 52 saplings from there. How many saplings does he have now?The book’s box diagram for Kishan’s saplings.
Q2364 Saplings + 52 Saplings = __________________ Saplings | 364 + 52 = __________The blocks left after the tens were joined into a hundred.
Answer
Count the blocks that are left in the picture.
4 hundreds + 1 ten + 6 ones
400 + 10 + 6 = 416
So 364 Saplings + 52 Saplings = 416 Saplings.
And 364 + 52 = 416.
In-text Questions — Page 152A number line, and an order for a school
Q1You can also use a number line to solve it. Fill in the last two empty boxes of the number line.The number line from the book. The last two boxes are empty.
Answer
Start at 364. Add 52 in small jumps.
52 = 5 tens + 2 ones
Five jumps of 10: 364, 374, 384, 394, 404, 414
Two jumps of 1: 414 → 415 → 416
The two empty boxes are 415 and 416.
Q2Kishan has got an order to deliver 230 saplings to a school. He has packed 75 saplings in an open box. How many more saplings does he need to pack?The book’s box diagram for the school order.
Answer
We take 75 away from 230.
230 – 5 = 225 (open 1 ten into 10 ones)
225 – 70 = 155 (open 1 hundred into 10 tens)
230 – 75 = 155
He needs to pack 155 more saplings.
In-text Questions — Page 153Kishan has ………. saplings now.
Q1Kishan has ………. saplings now.The blocks left on the page after 75 was taken away.
Let us Do — Page 154Box diagrams, HTO blocks and the number line
Q1Kishan has 456 saplings in August. He distributed 63 saplings. How many saplings are left with him?
AnswerThe box diagram for this problem.
He gave some away, so we take away.
456 – 60 = 396
396 – 3 = 393
So 456 – 63 = 393
393 saplings are left with Kishan.
Q2Kishan has a collection of 309 saplings. He gets 80 more saplings of flowering plants. How many saplings does he have now?
AnswerThe box diagram for this problem.
He got more saplings, so we add.
309 + 80
0 tens + 8 tens = 8 tens
309 + 80 = 389
He has 389 saplings now.
Q3Kishan has 270 saplings of herbs and his friend has 36 saplings of herbs. How many more saplings does Kishan have than his friend?
AnswerThe box diagram comparing the two collections.
“How many more” means we take away.
270 – 30 = 240
240 – 6 = 234
So 270 – 36 = 234
Kishan has 234 more saplings than his friend.
Q4Write word problems using the numbers given in the box diagrams below and solve them. You can take help from the pictures for appropriate contexts. (the box diagram with 234 Boys and + 156 Girls)The first box diagram printed on the page.
Answer
A school has 234 boys and 156 girls. How many children in all?
Q5Write word problems using the numbers given in the box diagrams below and solve them. You can take help from the pictures for appropriate contexts. (the box diagram with 356 Books and – 138 Books)The second box diagram printed on the page, beside the library picture.
Answer
A library has 356 books. Children take 138 books home. How many books are left in the library?
In-text Questions — Page 155One more box diagram, and the number grid
Q1Write word problems using the numbers given in the box diagrams below and solve them. You can take help from the pictures for appropriate contexts. (the box diagram with 305 Sacks and 210 Sacks)The box diagram printed beside the picture of the loaded truck.
Answer
A truck must carry 305 sacks of grain. 210 sacks are already loaded. How many sacks are still to be loaded?
305 – 200 = 105
105 – 10 = 95
So 305 – 210 = 95
95 sacks are still to be loaded.
Q2Use the grid below to solve the following questions. Colour your answers in the grid. — 405 + 23The number grid printed in the book, from 451 up to 530.
Answer
Add the tens first, then the ones.
405 + 20 = 425
425 + 3 = 428
So 405 + 23 = 428
Q3Use the grid below to solve the following questions. Colour your answers in the grid. — 481 + 19The number grid printed in the book, from 451 up to 530.
AnswerThe grid with the answer coloured green.
481 + 10 = 491 (one row up)
491 + 9 = 500 (nine boxes to the right)
So 481 + 19 = 500
Colour the box with 500.
Q4Use the grid below to solve the following questions. Colour your answers in the grid. — 467 + 51The number grid printed in the book, from 451 up to 530.
Q5Use the grid below to solve the following questions. Colour your answers in the grid. — 489 + 21 + 15The number grid printed in the book, from 451 up to 530.
Q6Use the grid below to solve the following questions. Colour your answers in the grid. — 519 – 40The number grid printed in the book, from 451 up to 530.
Do as directed — Page 156Adding 100, 10 and 1; the village of Jadupur
Q1Do as directed. Fill the first set of boxes. Each column starts at 269.The first ladder printed in the book. A few boxes are already filled.
Answer
Add 100
Add 10
Add 1
269
269
269
369
279
270
469
289
271
569
299
272
669
309
273
769
319
274
Q2Do as directed. Fill the second set of boxes. Each column starts at 454.The second ladder printed in the book. A few boxes are already filled.
Answer
Add 100
Add 10
Add 1
454
454
454
554
464
455
654
474
456
754
484
457
854
494
458
954
504
459
Q3Discuss in class why people in this village had to give different quantities while exchanging things.The two swaps told about in the story of Jadupur village.
Answer
Who gave
What
Who gave back
What
Shaamu Kaka
5 sacks of rice
Dariya Didi
10 sacks of vegetables
Dariya Didi
5 sacks of onions
Bablu Dada
2 sarees
Sample answer: Different things are worth different amounts.
One sack of rice is worth more than one sack of vegetables. So 5 sacks of rice got 10 sacks of vegetables.
A saree is worth a lot. So Dariya Didi had to give many onions for just 2 sarees.
In-text Questions — Page 157What notes and coins can buy
Q1Salma buys two bottles of milk for ₹100. Kiran buys a basket of pomegranates for ₹100. Circle the one that costs more: a milk bottle or a pomegranate?What Salma bought and what Kiran bought, each for one ₹100 note.
Answer
Circle the milk bottle.
₹100 buys only 2 bottles.
So one bottle costs ₹50.
₹100 buys a whole basket of pomegranates.
That is more than 2 fruits, so each one costs less than ₹50.
Q2Think of two things that we can buy using the same note.The empty table printed in the book.
Answer
Here is one way to fill the table.
Note
Things you can buy
₹10
one hawa mithai, or ten toffees
₹50
one notebook, or one small ball
Your answers may be different. Prices change from shop to shop.
In-text Questions — Page 158Match the notes and coins
Q1Match the notes and coins in the two columns that have the same values.The two columns printed in the book. The letters and numbers are ours, added so the rows are easy to name.
Answer
Add up each row first. Then join the rows that give the same amount.
First column
Value
Matches
Second column
A: 50 + 50
₹100
2
one ₹100 note
B: 10 + 10 + 1
₹21
3
20 + 1
C: 50 + 10 + 2 + 1
₹63
6
20 + 10 + 2 + 20 + 10 + 1
D: 5 + 5 + 2
₹12
5
10 + 1 + 1
E: ten ₹1 coins
₹10
1
one ₹10 note
F: 50 + 20
₹70
4
20 + 20 + 20 + 10
In-text Questions — Page 159Paying for things; the ₹500 note
Q1Use the following notes and coins to buy the things given below. Find at least two ways of giving the money. You may use the notes and coins more than once. — the toy car, ₹55The toy car with its price tag, and the money you may use.
Answer
The car costs ₹55. Here are two ways to pay.
Way 1: ₹50 + ₹5 = ₹55 Way 2: ₹20 + ₹20 + ₹10 + ₹5 = ₹55
Another way: ₹50 + ₹2 + ₹2 + ₹1 = ₹55.
Q2Use the following notes and coins to buy the things given below. Find at least two ways of giving the money. You may use the notes and coins more than once. — the bag of laddoos, ₹30The bag of laddoos with its price tag, and the money you may use.
Answer
The laddoos cost ₹30. Here are two ways to pay.
Way 1: ₹20 + ₹10 = ₹30 Way 2: ₹10 + ₹10 + ₹10 = ₹30
Another way: ₹20 + ₹5 + ₹5 = ₹30.
Q3Use the following notes and coins to buy the things given below. Find at least two ways of giving the money. You may use the notes and coins more than once. — the milk packet, ₹28The milk packet with its price tag, and the money you may use.
Answer
The milk packet costs ₹28. Here are two ways to pay.
Q4Use the following notes and coins to buy the things given below. Find at least two ways of giving the money. You may use the notes and coins more than once. — the box of crayons, ₹20The box of crayons with its price tag, and the money you may use.
Answer
The crayons cost ₹20. Here are two ways to pay.
Way 1: one ₹20 note Way 2: ₹10 + ₹10 = ₹20
Another way: ₹10 + ₹5 + ₹5 = ₹20.
Q5Draw as many notes of ₹100 as is equal to one ₹500 note.The note printed in the pink box on the page.
AnswerFive ₹100 notes, drawn in the empty box.
Draw five notes of ₹100 in the box.
100 + 100 + 100 + 100 + 100 = 500
Q6How many ₹100 notes are equal to a ₹500 note? _________The note printed in the pink box on the page.
Answer
5 notes of ₹100 are equal to one ₹500 note.
100, 200, 300, 400, 500
That is 5 hundreds.
Q7What things can you buy with ₹500 ?The note printed in the pink box on the page.
Answer
You can buy many things with ₹500. Sample answer: Here is one list.
A school bag ……… ₹300
A water bottle …… ₹120
A box of crayons … ₹20
Total = 300 + 120 + 20 = ₹440
₹60 will be left over. Your list may be different.
Q1In the morning, Peter uncle has ₹465 in his money box. By afternoon, he has ₹756. How much has he earned since morning? My Estimation. ₹ ____________The box diagram for Peter uncle’s money box.
Answer
First estimate. ₹756 is near ₹800 and ₹465 is near ₹500.
Q1Today, Peter uncle sold rice for ₹640 and sugar for ₹215. How much money has he earned from this sale? Draw a box diagram for the problem. My Estimate. ₹ ____________The empty box diagram printed on the page for you to fill.
AnswerThe box diagram filled in.
First estimate. ₹640 is near ₹600 and ₹215 is near ₹200.
My estimate: 600 + 200 = about ₹800
Now add:
640 + 200 = 840
840 + 15 = 855
So 640 + 215 = 855
He has earned ₹855 from this sale.
Let us Do — Pages 161–162Box diagrams with money
Q1One day, Peter uncle earned ₹650. The next day, he earned ₹250 more. How much money had he earned by the second day?
AnswerThe box diagram.
Estimate first. 650 is near 700 and 250 is near 300.
My estimate: 700 + 300 = about ₹1000
Now add:
650 + 200 = 850
850 + 50 = 900
So 650 + 250 = 900
By the second day he had earned ₹900.
Q2Reena bought groceries for ₹209. She gave a ₹500 note to Peter uncle. How much money should Peter uncle return to Reena?
AnswerThe box diagram for Reena’s change.
She gave ₹500. The goods cost ₹209. So we take away.
500 – 200 = 300
300 – 9 = 291
So 500 – 209 = 291
Peter uncle should return ₹291 to Reena.
Q3Shireen has ₹150 in her piggy bank. She puts ₹100 every week in her piggy bank. How much money does she have at the end of four weeks?
AnswerThe box diagram for the piggy bank.
She puts in ₹100 four times.
100 + 100 + 100 + 100 = 400
150 + 400 = 550
At the end of four weeks she has ₹550.
Q4Peter uncle saved ₹250 in the first month, ₹125 in the second month and ₹350 in the third month. How much has he saved in these three months?
AnswerThe box diagram for the three months’ saving.
Add the three months one at a time.
250 + 125 = 375
375 + 350 = 725
He has saved ₹725 in these three months.
In-text Questions — Page 162Estimate to the nearest hundred
Q1Estimate the answers to the nearest hundred. Discuss in class.The table printed in the book, with the second column empty.
Answer
Find the answer first. Then see which hundred it is nearest to.
Number expression
Answer
Nearest Hundred
156 + 34
190
200
125 – 15
110
100
105 + 195
300
300
205 + 215
420
400
500 – 395
105
100
765 – 567
198
200
505 + 405
910
900
In-text Questions — Page 163Compare, match and fill
Q1Compare the given problem statements in each row, without calculating. Circle the one that is more. Discuss in class.The five rows printed in the book. The book has already circled the first row.
Answer
Row
Circle this one
Reason, without calculating
373 + 23 | 373 + 40
373 + 40
Same start, but 40 is more than 23
240 + 10 | 204 + 10
240 + 10
Same 10 added, but 240 is more than 204
900 + 9 | 890 + 60
890 + 60
890 is only 10 less, but 60 is 51 more than 9
345 – 45 | 345 – 54
345 – 45
Same start, but less is taken away
800 – 8 | 700 – 8
800 – 8
Same 8 taken away, but 800 is more than 700
Q2Find the pairs that are equal.The six boxes printed in the book.
Answer
Work out each box, then join the boxes that match.
Pair
Value
516 + 100 = 816 – 200
616
400 + 15 = 615 – 200
415
450 – 50 = 350 + 50
400
Q3Fill in the boxes with appropriate numbers.The arrow diagram printed in the book. The blue boxes and four ovals are empty.
Q1Make cards with numbers 0–5. Make two 3-digit numbers using these cards. Add the two numbers and subtract the two numbers. Rearrange the cards and try to get a bigger sum. Rearrange the cards and try to get a smaller difference. Check with your friends who has got the biggest sum and smallest difference.The number cards the two children have laid out.
Answer
Look at the cards the two children made.
Child
Numbers
Sum
Difference
The boy
243 and 105
348
138
The girl
405 and 132
537
273
So the girl made the larger sum. The boy made the smaller difference. Both children are right.
Biggest sum: put the big digits first → 431 + 520 = 951 Smallest difference: 301 – 254 = 47