Skip to content

NCERT Solutions for Class 7 Maths Chapter 8 Working with Fractions (PDF) – 2027

NCERT Solutions for Class 7 Maths Chapter 8 Working with Fractions – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.

Chapter 8 of Ganita Prakash Part I takes fractions beyond adding and subtracting. Using a walking tortoise, a unit square and the area of a rectangle, the chapter builds multiplication and division of fractions — and shows that both rules were written down in general form by Brahmagupta in 628 CE.

NCERT Solutions for Class 7 Maths Chapter 8 Working with Fractions PDF

All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.

PDFChapterDownload
Solutions PDF (English medium)Working with FractionsView PDF
Solutions PDF (Hindi medium)भिन्नों के साथ कार्य करनाView PDF

NCERT Solutions for Class 7 Maths Chapter 8 Working with Fractions – Questions and Answers

All 62 questions of the chapter (textbook pages 173 – 199) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.

In-text Questions — Pages 173–175Section 8.1 Multiplication of Fractions

Q1Aaron walks 3 kilometres in 1 hour. How far can he walk in 5 hours?
Answer

Walking for 5 hours means covering the 1-hour distance 5 times.

Distance covered in 1 hour = 3 km
Distance covered in 5 hours = 5 × 3 km
= 3 + 3 + 3 + 3 + 3 km
= 15 km
Q2Aaron’s pet tortoise walks at a much slower pace. It can walk only 1⁄4 kilometre in 1 hour. How far can it walk in 3 hours?
Answer

The speed is a fraction now, but nothing else changes — still multiply.

Distance in 1 hour = 1/4 km
Distance in 3 hours = 3 × 1/4 km
= 1/4 + 1/4 + 1/4 km
= 3/4 km

The tortoise can walk 3⁄4 km in 3 hours.

Q3We saw that Aaron can walk 3 kilometres in 1 hour. How far can he walk in 1⁄5 hours?
Answer

One-fifth of an hour covers one-fifth of the 1-hour distance.

Distance in 1 hour = 3 km
Distance in 1/5 hour = 3 km divided into 5 equal parts
= 3 ÷ 5
= 3/5 km

So 1⁄5 × 3 = 3⁄5.

Q4How far can Aaron walk in 2⁄5 hours?
Answer

Work in two steps — first one-fifth of an hour, then double it.

Step 1: distance in 1/5 hour = 3 ÷ 5 = 3/5 km
Step 2: 2/5 hour is twice 1/5 hour
Distance = 2 × 3/5
= 6/5 km = 1 1/5 km

So 2⁄5 × 3 = 6⁄5.

In-text Questions — Page 176Section 8.1 Worked Examples

Q1Example 1: A farmer had 5 grandchildren. She distributed 2⁄3 acre of land to each of her grandchildren. How much land in all did she give to her grandchildren?
Answer

Five equal shares of 2⁄3 acre each.

5 × 2/3 = 2/3 + 2/3 + 2/3 + 2/3 + 2/3
= 10/3
= 3 1/3 acres
Q2Example 2: 1 hour of internet time costs ₹8. How much will 1 1⁄4 hours of internet time cost?
Answer

First change the mixed fraction into an improper fraction.

1 1/4 hours = 5/4 hours
Cost = 5/4 × 8
= (5 × 8) ÷ 4
= 5 × 2
= ₹10

Figure it Out — Pages 176–177Section 8.1 Multiplication of Fractions

Q1Tenzin drinks 1⁄2 glass of milk every day. How many glasses of milk does he drink in a week? How many glasses of milk did he drink in the month of January?
Answer

Multiply the daily amount by the number of days.

In a week (7 days) = 7 × 1/2 = 7/2 = 3 1/2 glasses
January has 31 days
In January = 31 × 1/2 = 31/2 = 15 1/2 glasses
Q2A team of workers can make 1 km of a water canal in 8 days. So, in one day, the team can make ___ km of the water canal. If they work 5 days a week, they can make ___ km of the water canal in a week.
Answer

One kilometre of work is spread equally over 8 days.

Work in 1 day = 1 ÷ 8 = 1/8 km
Work in 5 days = 5 × 1/8 = 5/8 km
Q3Manju and two of her neighbours buy 5 litres of oil every week and share it equally among the 3 families. How much oil does each family get in a week? How much oil will one family get in 4 weeks?
Answer

Five litres shared equally by 3 families.

Oil per family in 1 week = 5 ÷ 3 = 5/3 litres = 1 2/3 litres
In 4 weeks = 4 × 5/3 = 20/3 = 6 2/3 litres
Q4Safia saw the Moon setting on Monday at 10 pm. Her mother, who is a scientist, told her that every day the Moon sets 5⁄6 hour later than the previous day. How many hours after 10 pm will the moon set on Thursday?
Answer

Monday to Thursday is 3 days, so the delay builds up three times.

Delay = 3 × 5/6
= 15/6
= 5/2
= 2 1/2 hours after 10 pm

So the Moon sets at about 12:30 am (past midnight).

Q5Multiply and then convert it into a mixed fraction: (a) 7 × 3⁄5   (b) 4 × 1⁄3   (c) 9⁄7 × 6   (d) 13⁄11 × 6
Answer

Multiply the whole number into the numerator, then split off the whole part.

QuestionProductMixed fraction
(a) 7 × 3/521/54 1/5
(b) 4 × 1/34/31 1/3
(c) 9/7 × 654/77 5/7
(d) 13/11 × 678/117 1/11
21 ÷ 5 = 4 remainder 1 → 4 1/5
54 ÷ 7 = 7 remainder 5 → 7 5/7
78 ÷ 11 = 7 remainder 1 → 7 1/11

In-text Questions — Pages 177–179Multiplying Two Fractions

Math Talk
Q1We know, that Aaron’s pet tortoise can walk only 1⁄4 km in 1 hour. How far can it walk in half an hour?
Answer

Half an hour covers half of the one-hour distance.

Distance = 1/2 × 1/4 km
= 1/4 divided into 2 equal parts
= 1/8 km
Q2Now we divide this 1⁄4 into 2 equal parts. What do we get? What fraction of the whole is shaded?
?
Page 178 — the unit square is the whole; its top row (1⁄4, yellow) is divided into 2 equal parts, and the hatched part is marked “?”. Printed label: 1⁄4 divided into 2 equal parts.
Answer

The whole is now in 8 equal parts and one of them is shaded.

Whole ÷ 8 equal parts
Shaded = 1 part
= 1/8 of the whole

So 1⁄2 × 1⁄4 = 1⁄8, and the tortoise walks 1⁄8 km in half an hour.

Q3If the tortoise walks faster and it can cover 2⁄5 km in 1 hour, how far will it walk in 3⁄4 of an hour?
Answer

Same two steps: divide by 4, then multiply by 3.

(i) Distance in 1/4 hour = 2/5 ÷ 4
The whole is cut into 5 rows and 4 columns = 20 equal parts
Parts shaded = 2, so distance = 2/20

(ii) Distance in 3/4 hour = 3 × 2/20
= 6/20
= 3/10 km

So 3⁄4 × 2⁄5 = 6⁄20 = 3⁄10.

Q4Using this understanding, multiply 5⁄4 × 3⁄2.
Answer

Draw 3⁄2 as one whole and a half, then cut it into 4 equal parts.

Whole cut into 2 rows and 4 columns = 8 equal parts
3/2 ÷ 4 = 3 of those parts = 3/8
Now multiply by 5:
5/4 × 3/2 = (5 × 3)/8
= 15/8 = 1 7/8

In-text Questions — Page 180Connection between the Area of a Rectangle and Fraction Multiplication

Q1In the Fig. 8.3, what is the length and breadth of the shaded rectangle?
?
Fig. 8.3, page 180 — the shaded rectangle inside the unit square. (The book labels it with its area; that label is shown here as “?” because the next question asks for it.)
Answer

The big square is a unit square, so each side is 1 unit long.

The square is cut into 2 columns → each column is 1/2 unit wide
The square is cut into 4 rows → each row is 1/4 unit tall
Length = 1/2 unit, Breadth = 1/4 unit
Q2What is the area of this rectangle? Do you see any relation between the area and the product of length and breadth?
Answer

Eight of these rectangles tile the unit square.

8 rectangles = 1 square unit
Area of one rectangle = 1 ÷ 8 = 1/8 square unit
Length × breadth = 1/2 × 1/4 = 1/8

They are equal — the area of a rectangle with fractional sides is the product of its sides.

Figure it Out — Pages 180–181Multiplying Fractional Units

Q1Find the following products. Use a unit square as a whole for representing the fractions: (a) 1⁄3 × 1⁄5   (b) 1⁄4 × 1⁄3   (c) 1⁄5 × 1⁄2   (d) 1⁄6 × 1⁄5
Answer

Cut the unit square into rows (denominator of the second fraction) and columns (denominator of the first fraction), then shade one cell.

QuestionRows × columnsProduct
(a) 1/3 × 1/55 × 3 = 15 parts1/15
(b) 1/4 × 1/33 × 4 = 12 parts1/12
(c) 1/5 × 1/22 × 5 = 10 parts1/10
(d) 1/6 × 1/55 × 6 = 30 parts1/30
1/155 rows × 3 columns = 15 equal parts
The picture for (a): 1/5 gives 5 rows and 1/3 gives 3 columns; one cell out of 15 is 1⁄15.
Q2Now, find 1⁄12 × 1⁄18.
Answer

Use the rows-and-columns pattern instead of drawing 216 cells.

Number of rows = 18 (denominator of the multiplicand)
Number of columns = 12 (denominator of the multiplier)
Whole is cut into 18 × 12 = 216 equal parts
1/18 × 1/12 = 1/(18 × 12) = 1/216

In general, for two fractional units:

1⁄b × 1⁄d = 1/(b × d)
Q3Find the following products. Use a unit square as a whole for representing the fractions and carrying out the operations. (a) 2⁄3 × 4⁄5   (b) 1⁄4 × 2⁄3   (c) 3⁄5 × 1⁄2   (d) 4⁄6 × 3⁄5
Answer

Now more than one cell gets shaded — as many as (numerator × numerator).

QuestionTotal partsParts shadedProduct
(a) 2/3 × 4/53 × 5 = 152 × 4 = 88/15
(b) 1/4 × 2/34 × 3 = 121 × 2 = 22/12 = 1/6
(c) 3/5 × 1/25 × 2 = 103 × 1 = 33/10
(d) 4/6 × 3/56 × 5 = 304 × 3 = 1212/30 = 2/5
8/158 of the 15 equal parts shaded
The picture for (a): 4⁄5 is 4 of the 5 rows, and 2⁄3 of it is 2 of the 3 columns — 2 × 4 = 8 cells out of 3 × 5 = 15, so 8⁄15. Draw (b), (c), (d) the same way.

In-text Questions — Pages 181–182Multiplying Numerators and Denominators; Simplifying to Lowest Form

Q1Now, find 5⁄12 × 7⁄18.
Answer

Follow the same two steps, but with the general numbers.

Whole cut into 18 rows and 12 columns = 12 × 18 parts
7/18 ÷ 12 = 7/(12 × 18)
Multiply by 5: (5 × 7)/(12 × 18)
= 35/216

5⁄12 × 7⁄18 = 35⁄216

Q2Multiply the following fractions and express the product in its lowest form: 12⁄7 × 5⁄24
Answer

Cancel the common factor before multiplying.

12/7 × 5/24 = (12 × 5)/(7 × 24)
12 and 24 share the factor 12
12 ÷ 12 = 1,   24 ÷ 12 = 2
= (1 × 5)/(7 × 2)
= 5/14
Q3Let us use the same technique to do one more multiplication. 14⁄15 × 25⁄42
Answer

Cancel across the numerators and denominators, then multiply.

14/15 × 25/42 = (14 × 25)/(15 × 42)
14 and 42 share 14 → 1 and 3
25 and 15 share 5 → 5 and 3
= (1 × 5)/(3 × 3)
= 5/9

Figure it Out — Pages 183–184Section 8.1 Multiplication of Fractions

Try This
Q1A water tank is filled from a tap. If the tap is open for 1 hour, 7⁄10 of the tank gets filled. How much of the tank is filled if the tap is open for (a) 1⁄3 hour ____ (b) 2⁄3 hour ____ (c) 3⁄4 hour ____ (d) 7⁄10 hour ____ (e) For the tank to be full, how long should the tap be running?
Answer

Each part is (time) × 7⁄10.

Tap open forWorkingPart of tank filled
(a) 1/3 hour1/3 × 7/107/30
(b) 2/3 hour2/3 × 7/10 = 14/307/15
(c) 3/4 hour3/4 × 7/1021/40
(d) 7/10 hour7/10 × 7/1049/100

(e) The tank is full when the filled part is 1.

Time = 1 ÷ 7/10
= 1 × 10/7
= 10/7 hours = 1 3/7 hours ≈ 1 hour 26 minutes
Q2The government has taken 1⁄6 of Somu’s land to build a road. What part of the land remains with Somu now? She gives half of the remaining part of the land to her daughter Krishna and 1⁄3 of it to her son Bora. After giving them their shares, she keeps the remaining land for herself. (a) What part of the original land did Krishna get? (b) What part of the original land did Bora get? (c) What part of the original land did Somu keep for herself?
Answer

First find what is left after the road is built.

Land left = 1 − 1/6 = 5/6 of the original land

(a) Krishna gets half of that:

1/2 × 5/6 = 5/12

(b) Bora gets one-third of that:

1/3 × 5/6 = 5/18

(c) Somu keeps the rest:

5/6 − 5/12 − 5/18
LCM of 6, 12, 18 = 36
= 30/36 − 15/36 − 10/36
= 5/36
Q3Find the area of a rectangle of sides 3 3⁄4 ft and 9 3⁄5 ft.
Answer

Change both mixed fractions into improper fractions, then multiply.

3 3/4 = 15/4    9 3/5 = 48/5
Area = 15/4 × 48/5
Cancel: 15 and 5 → 3 and 1; 48 and 4 → 12 and 1
= 3 × 12
= 36 square feet
Q4Tsewang plants four saplings in a row in his garden. The distance between two saplings is 3⁄4 m. Find the distance between the first and last sapling. [Hint: Draw a rough diagram with four saplings with distance between two saplings as 3⁄4 m]
Answer

Four saplings in a row leave 3 gaps, not 4.

3/4 m 3/4 m 3/4 m 1st 4th
Four saplings, three gaps of 3⁄4 m each.
Distance = 3 × 3/4
= 9/4
= 2 1/4 m
Q5Which is heavier: 12⁄15 of 500 grams or 3⁄20 of 4 kg?
Answer

Bring both to the same unit — grams.

12/15 of 500 g = (12 × 500)/15
= 6000/15
= 400 g

4 kg = 4000 g
3/20 of 4000 g = (3 × 4000)/20
= 12000/20
= 600 g

3⁄20 of 4 kg (600 g) is heavier than 12⁄15 of 500 g (400 g), by 200 g.

In-text Questions — Pages 184–186Is the Product Always Greater than the Numbers Multiplied? / Order of Multiplication

Q1When do you think the product is greater than both the numbers multiplied, when is it in between the two numbers, and when is it smaller than both? [Hint: The relationship between the product and the numbers multiplied depends on whether they are between 0 and 1 or they are greater than 1.]
Answer

Everything depends on where each number sits compared with 1.

SituationMultiplicationRelationship
Both numbers greater than 14/3 × 4 = 16/3Product is greater than both
Both numbers between 0 and 13/4 × 2/5 = 3/10Product is less than both
One between 0 and 1, one greater than 13/4 × 5 = 15/4Product lies in between the two
Check the middle row: 3/4 = 15/20 and 2/5 = 8/20
Product 3/10 = 6/20
6/20 < 8/20 < 15/20 ✔
Q2Create more such examples for each situation and observe the relationship between the product and the numbers being multiplied. What can you conclude about the relationship between the numbers multiplied and the product? Fill in the blanks: • When one of the numbers being multiplied is between 0 and 1, the product is ____ (greater/less) than the other number. • When one of the numbers being multiplied is greater than 1, the product is ____ (greater/less) than the other number.
Answer
  • When one of the numbers is between 0 and 1, the product is less than the other number.
  • When one of the numbers is greater than 1, the product is greater than the other number.
Your own exampleProductCompared with the other number
1/2 × 99/2 = 4 1/2less than 9
5/2 × 615greater than 6
2/3 × 3/72/7less than both
7/5 × 10/914/9greater than both
Q3We know that 1⁄2 × 1⁄4 = 1⁄8. Now, what is 1⁄4 × 1⁄2?
Answer

It is 1⁄8 too.

1/4 × 1/2 = (1 × 1)/(4 × 2) = 1/8
So a⁄b × c⁄d = c⁄d × a⁄b

In-text Questions — Pages 186–188Section 8.2 Division of Fractions

Q1What is 12 ÷ 4? You know this already. But can this problem be restated as a multiplication problem? What should be multiplied by 4 to get 12?
Answer

12 ÷ 4 = 3, and the same fact can be written the other way round.

12 ÷ 4 = 3
means   4 × ? = 12
4 × 3 = 12 ✔
Q2What is 1 ÷ 2⁄3?
Answer

Ask instead: what times 2⁄3 gives 1?

2/3 × ? = 1
Turn 2/3 upside down: 2/3 × 3/2 = 6/6 = 1 ✔
So 1 ÷ 2/3 = 3/2
Q3Let us try another problem: 3 ÷ 2⁄3. This is the same as 2⁄3 × ? = 3. Can you find the answer?
Answer

We already know what makes 2⁄3 into 1 — now make it 3 times as much.

2/3 × 3/2 = 1
2/3 × (3/2 × 3) = 3
So 3 ÷ 2/3 = 3/2 × 3
= 9/2 = 4 1/2
Q4What is 1⁄5 ÷ 1⁄2?
Answer

Rewrite as a multiplication and use the reciprocal of the divisor.

1/2 × ? = 1/5
1/2 × 2 = 1, so 1/2 × (2 × 1/5) = 1/5
1/5 ÷ 1/2 = 2 × 1/5
= 2/5
Q5What is 2⁄3 ÷ 3⁄5?
Answer

The reciprocal of the divisor 3⁄5 is 5⁄3.

3/5 × ? = 2/3
3/5 × 5/3 = 1, so 3/5 × (5/3 × 2/3) = 2/3
2/3 ÷ 3/5 = 5/3 × 2/3
= 10/9 = 1 1/9
Q6In each of the division problems above, observe how we found the answer. Can we frame a rule that tells us how to divide two fractions?
Answer

Yes. To divide two fractions:

  1. Find the reciprocal of the divisor (turn it upside down).
  2. Multiply the dividend by that reciprocal.
a⁄b ÷ c⁄d = a⁄b × d⁄c = (a × d)/(b × c)

In-text Questions — Page 189Dividend, Divisor and the Quotient

Q1When do you think the quotient is less than the dividend and when is it greater than the dividend?
Answer

It depends on the divisor, exactly as with multiplication.

  • Divisor greater than 1 → quotient is less than the dividend.
  • Divisor between 0 and 1 → quotient is greater than the dividend.
  • Divisor equal to 1 → quotient equals the dividend.
Q2Is there a similar relationship between the divisor and the quotient? Use your understanding of such relationships in multiplication to answer the questions above.
Answer

Yes — for a fixed dividend, the divisor and the quotient move in opposite directions.

12 ÷ 2 = 6
12 ÷ 4 = 3  (divisor doubled → quotient halved)
12 ÷ 1/2 = 24  (divisor made 4 times smaller than 2 → quotient 4 times bigger)

So the bigger the divisor, the smaller the quotient, and the smaller the divisor, the bigger the quotient. The two are equal only when divisor × divisor = dividend, for example 9 ÷ 3 = 3.

In-text Questions — Pages 190–191Section 8.3 Some Problems Involving Fractions

Q1Example 3: Leena made 5 cups of tea. She used 1⁄4 litre of milk for this. How much milk is there in each cup of tea?
Answer

One-quarter litre of milk is shared equally by 5 cups.

Milk per cup = 1/4 ÷ 5
Reciprocal of 5 is 1/5
= 1/5 × 1/4
= 1/20 litre = 50 ml
Q2Example 4: Here is an example from Baudhāyana’s Śhulbasūtra (c. 800 BCE). Cover an area of 7 1⁄2 square units with square bricks each of whose sides is 1⁄5 units. How many such square bricks are needed?
Answer

Find the area of one brick first.

Area of one brick = 1/5 × 1/5 = 1/25 square units
Total area = 7 1/2 = 15/2 square units
Number of bricks = 15/2 ÷ 1/25
Reciprocal of 1/25 is 25
= 25 × 15/2
= 375/2 = 187 1/2 bricks
Q3Example 5: Four fountains fill a cistern. The first fountain can fill the cistern in a day. The second can fill it in half a day. The third can fill it in a quarter of a day. The fourth can fill the cistern in one fifth of a day. If they all flow together, in how much time will they fill the cistern? In a day, the number of times — the first fountain will fill the cistern is 1 ÷ 1 = 1; the second is 1 ÷ 1⁄2 = ____; the third is 1 ÷ 1⁄4 = ____; the fourth is 1 ÷ 1⁄5 = ____. The number of times the four fountains together will fill the cistern in a day is ___ + ___ + ___ + ___ = 12.
Answer

Count how many cisterns each fountain fills in one full day.

FountainTime for one fillingFillings in a day
First1 day1 ÷ 1 = 1
Second1/2 day1 ÷ 1/2 = 2
Third1/4 day1 ÷ 1/4 = 4
Fourth1/5 day1 ÷ 1/5 = 5
Together in a day = 1 + 2 + 4 + 5 = 12 fillings
Time for 1 filling = 1 ÷ 12
= 1/12 day = 2 hours

Math Talk — Pages 192–193Fractional Relations

Math Talk
Q1Here is a square with some lines drawn inside (Fig. 8.4). What fraction of area of the whole square does the shaded region occupy?
Fig. 8.4, page 192 — the square with lines drawn inside it; the region in question is hatched.
Answer

Peel the picture one layer at a time, taking the whole square as 1 square unit.

Step 1: the top-right square is a quarter of the whole = 1/4 sq unit
Step 2: the yellow triangle inside it is half of that = 1/2 × 1/4 = 1/8 sq unit
Step 3: the shaded part is 3/4 of that triangle = 3/4 × 1/8
= 3/32 square units

So the shaded region occupies 3⁄32 of the whole square.

Q2What fraction of this yellow triangle is shaded? Are you able to see why?
The yellow triangle inside the red square (the top-right quarter of Fig. 8.4), page 193. The hatched part is the shaded region.
Answer

3⁄4 of the yellow triangle is shaded.

12344 equal pieces;pieces 2, 3, 4 are shaded
The two lines through the middle of the slanting side cut the triangle into 4 equal triangles (the square in the corner is 2 of them). Pieces 2, 3 and 4 are shaded.
Unshaded piece = 1 of the 4 equal pieces = 1/4
Shaded = 1 − 1/4 = 3/4
Q3In each of the figures given below, find the fraction of the big square that the shaded region occupies.
(a)
(b)
The two figures printed with this question on page 193.
Answer

Figure (a): 3⁄8. The shaded band lies between two parallel diagonals.

Big triangle below the main diagonal = 1/2 of the square
Small triangle below the shorter parallel line = 1/2 × 1/2 × 1/2 = 1/8
Shaded band = 1/2 − 1/8
= 4/8 − 1/8
= 3/8

Figure (b): 1⁄16. Everything happens inside the top-left quarter.

Top-left quarter = 1/4 of the square
The tilted square joining its midpoints = 1/2 × 1/4 = 1/8
The 4 corner triangles together = 1/4 − 1/8 = 1/8, so each = 1/32
Two corner triangles are shaded = 2 × 1/32
= 1/16

In-text Questions — Pages 193–194A Dramma-tic Donation

Q1“O wise one! A miser gave to a beggar 1⁄5 of 1⁄16 of 1⁄4 of 1⁄2 of 2⁄3 of 3⁄4 of a dramma. If you know the mathematics of fractions well, tell me O child, how many cowrie shells were given by the miser to the beggar.” (1 dramma = 1280 cowrie shells)
Answer

“Of” means multiply — so multiply all six fractions.

1/2 × 2/3 × 3/4 × 1/5 × 1/16 × 1/4
1/2 × 2/3 = 1/3
1/3 × 3/4 = 1/4
1/4 × 1/5 = 1/20
1/20 × 1/16 = 1/320
1/320 × 1/4 = 1/1280 of a dramma
1 dramma = 1280 cowrie shells
Gift = 1/1280 × 1280
= 1 cowrie shell
Q2If we assume 1 gold dinar = 12 silver drammas, 1 silver dramma = 4 copper panas, 1 copper pana = 6 mashakas, and 1 pana = 30 cowrie shells, then 1 copper pana = 1⁄48 gold dinar. 1 cowrie shell = ____ copper panas. 1 cowrie shell = ____ gold dinar.
Answer

Work backwards along the chain of coins.

1 pana = 30 cowrie shells
So 1 cowrie shell = 1/30 copper pana

1 pana = 1/48 gold dinar
1 cowrie shell = 1/30 × 1/48
= 1/1440 gold dinar

Figure it Out — Pages 196–198Chapter Exercises

Q1Evaluate the following: 3 ÷ 7⁄9;   14⁄4 ÷ 2;   2⁄3 ÷ 2⁄3;   14⁄6 ÷ 7⁄3;   4⁄3 ÷ 3⁄4;   7⁄4 ÷ 1⁄7;   8⁄2 ÷ 4⁄15;   1⁄5 ÷ 1⁄9;   1⁄6 ÷ 11⁄12;   3 2⁄3 ÷ 1 3⁄8
Answer

Turn every divisor upside down and multiply.

DivisionMultiply by the reciprocalAnswer
3 ÷ 7/93 × 9/727/7 = 3 6/7
14/4 ÷ 214/4 × 1/214/8 = 7/4 = 1 3/4
2/3 ÷ 2/32/3 × 3/21
14/6 ÷ 7/314/6 × 3/742/42 = 1
4/3 ÷ 3/44/3 × 4/316/9 = 1 7/9
7/4 ÷ 1/77/4 × 749/4 = 12 1/4
8/2 ÷ 4/154 × 15/415
1/5 ÷ 1/91/5 × 99/5 = 1 4/5
1/6 ÷ 11/121/6 × 12/1112/66 = 2/11
3 2/3 ÷ 1 3/811/3 × 8/118/3 = 2 2/3
Q2For each of the questions below, choose the expression that describes the solution. Then simplify it. (a) Maria bought 8 m of lace to decorate the bags she made for school. She used 1⁄4 m for each bag and finished the lace. How many bags did she decorate? (i) 8 × 1⁄4 (ii) 1⁄8 × 1⁄4 (iii) 8 ÷ 1⁄4 (iv) 1⁄4 ÷ 8.   (b) 1⁄2 meter of ribbon is used to make 8 badges. What is the length of the ribbon used for each badge? (i) 8 × 1⁄2 (ii) 1⁄2 ÷ 1⁄8 (iii) 8 ÷ 1⁄2 (iv) 1⁄2 ÷ 8.   (c) A baker needs 1⁄6 kg of flour to make one loaf of bread. He has 5 kg of flour. How many loaves of bread can he make? (i) 5 × 1⁄6 (ii) 1⁄6 ÷ 5 (iii) 5 ÷ 1⁄6 (iv) 5 × 6
Answer

(a) Option (iii) — how many quarter-metre pieces are in 8 m?

8 ÷ 1/4 = 8 × 4 = 32 bags

(b) Option (iv) — half a metre is shared among 8 badges.

1/2 ÷ 8 = 1/2 × 1/8 = 1/16 m (6.25 cm each)

(c) Option (iii) — how many sixth-kilogram scoops are in 5 kg?

5 ÷ 1/6 = 5 × 6 = 30 loaves
Q3If 1⁄4 kg of flour is used to make 12 rotis, how much flour is used to make 6 rotis?
Answer

Six rotis are half of twelve rotis.

Flour for 1 roti = 1/4 ÷ 12 = 1/48 kg
Flour for 6 rotis = 6 × 1/48
= 6/48
= 1/8 kg
Q4Pāṭīgaṇita, a book written by Sridharacharya in the 9th century CE, mentions this problem: “Friend, after thinking, what sum will be obtained by adding together 1 ÷ 1⁄6, 1 ÷ 1⁄10, 1 ÷ 1⁄13, 1 ÷ 1⁄9, and 1 ÷ 1⁄2”. What should the friend say?
Answer

Dividing 1 by a unit fraction just gives back its denominator.

1 ÷ 1/6 = 6
1 ÷ 1/10 = 10
1 ÷ 1/13 = 13
1 ÷ 1/9 = 9
1 ÷ 1/2 = 2
Sum = 6 + 10 + 13 + 9 + 2 = 40

The friend should say 40.

Q5Mira is reading a novel that has 400 pages. She read 1⁄5 of the pages yesterday and 3⁄10 of the pages today. How many more pages does she need to read to finish the novel?
Answer

Find the pages read on each day, then subtract from 400.

Yesterday = 1/5 × 400 = 80 pages
Today = 3/10 × 400 = 120 pages
Read so far = 80 + 120 = 200 pages
Left = 400 − 200 = 200 pages
Q6A car runs 16 km using 1 litre of petrol. How far will it go using 2 3⁄4 litres of petrol?
Answer

Multiply the mileage by the number of litres.

2 3/4 litres = 11/4 litres
Distance = 11/4 × 16
= 11 × 4
= 44 km
Q7Amritpal decides on a destination for his vacation. If he takes a train, it will take him 5 1⁄6 hours to get there. If he takes a plane, it will take him 1⁄2 hour. How many hours does the plane save?
Answer

The time saved is the difference of the two times.

5 1/6 = 31/6 hours
Saving = 31/6 − 1/2
= 31/6 − 3/6
= 28/6
= 14/3 hours = 4 2/3 hours

The plane saves 4 2⁄3 hours, that is 4 hours 40 minutes.

Q8Mariam’s grandmother baked a cake. Mariam and her cousins finished 4⁄5 of the cake. The remaining cake was shared equally by Mariam’s three friends. How much of the cake did each friend get?
Answer

Find what is left, then split it three ways.

Cake left = 1 − 4/5 = 1/5
Each friend = 1/5 ÷ 3
= 1/5 × 1/3
= 1/15 of the cake
Q9Choose the option(s) describing the product of (565⁄465 × 707⁄676): (a) > 565⁄465 (b) < 565⁄465 (c) > 707⁄676 (d) < 707⁄676 (e) > 1 (f) < 1
Answer

You do not have to multiply — just check where each fraction sits compared with 1.

565 > 465, so 565/465 > 1
707 > 676, so 707/676 > 1

Both numbers are greater than 1. So the product is greater than each of them, and greater than 1.

Correct options: (a), (c) and (e).

Q10What fraction of the whole square is shaded?
The square printed with this question (page 197). The hatched part is the shaded region.
Answer

The shading lies entirely inside the bottom-right quarter of the square.

Take that quarter as 1 unit.
The shading fills the left half of the quarter, except one small triangle at its top.
Left half of the quarter = 1/2
Triangle cut away = 1/2 × 1/2 × 1/2 = 1/8
Shaded part of the quarter = 1/2 − 1/8 = 3/8

Shaded part of the whole square = 3/8 × 1/4
= 3/32
Q11A colony of ants set out in search of food. As they search, they keep splitting equally at each point (as shown in the Fig. 8.7) and reach two food sources, one near a mango tree and another near a sugarcane field. What fraction of the original group reached each food source?
Mango treeSugarcane field
Fig. 8.7, page 198 — the ants’ paths. At every red point the group splits equally among the paths going out.
Answer

Take the whole colony as 1. At each red point the ants that arrive split equally among the paths going out.

Red pointAnts arrivingPaths outEach path gets
1st121/2 — one path to the mango tree, one to the 2nd point
2nd1/221/4 — one to the mango tree, one to the 3rd point
3rd1/441/16 — two to the mango tree, one to the sugarcane field, one to the 4th point
4th1/1621/32 — one to the mango tree, one to the sugarcane field
Mango tree = 1/2 + 1/4 + 1/16 + 1/16 + 1/32
= 16/32 + 8/32 + 2/32 + 2/32 + 1/32
= 29/32

Sugarcane field = 1/16 + 1/32
= 2/32 + 1/32
= 3/32
Q12What is 1 − 1⁄2?
(1 − 1⁄2) × (1 − 1⁄3)?
(1 − 1⁄2) × (1 − 1⁄3) × (1 − 1⁄4) × (1 − 1⁄5)?
(1 − 1⁄2) × (1 − 1⁄3) × (1 − 1⁄4) × (1 − 1⁄5) × (1 − 1⁄6) × (1 − 1⁄7) × (1 − 1⁄8) × (1 − 1⁄9) × (1 − 1⁄10)?
Make a general statement and explain.
Answer
1 − 1/2 = 1/2

(1 − 1/2) × (1 − 1/3) = 1/2 × 2/3 = 1/3

1/2 × 2/3 × 3/4 × 4/5 = 1/5

1/2 × 2/3 × 3/4 × 4/5 × 5/6 × 6/7 × 7/8 × 8/9 × 9/10 = 1/10

General statement:

(1 − 1/2) × (1 − 1/3) × (1 − 1/4) × … × (1 − 1/n) = 1/n

Explanation: each bracket 1 − 1⁄k = k − 1⁄k. So the product is 1⁄2 × 2⁄3 × … × n − 1⁄n, and each denominator cancels the next numerator, leaving 1⁄n.

Puzzle Time — Page 199Chess Puzzles — Non-attacking Queens

Try This
Q1Chess is a popular 2-player strategy game. This game has its origins in India. It is played on an 8 × 8 chequered grid. There are 2 sets of pieces — black and white — one set for each player. Find out how each piece should move and the rules of the game.
Answer

Chess grew out of the ancient Indian game chaturanga. Here is how the six pieces move.

PieceHow it movesNumber per player
King (राजा)One square in any direction1
Queen (वज़ीर)Any number of squares along a row, column or diagonal1
Rook (हाथी)Any number of squares along a row or column2
Bishop (ऊँट)Any number of squares along a diagonal2
Knight (घोड़ा)In an “L”: two squares one way, one square across; it may jump over pieces2
Pawn (प्यादा)One square forward (two on its first move); captures diagonally8

The aim is checkmate — trapping the opponent’s King so that it cannot escape capture.

Q2From its current position, a Queen piece can move along the horizontal, vertical or diagonal. Place 4 Queens such that no 2 queens attack each other.
QQ
The example printed on page 199 — a 4 × 4 board. This arrangement is not valid, as the queens are in the line of attack of each other.
Answer

On a 4 × 4 board there must be exactly one Queen in every row and every column, and no two on a diagonal.

QQQQ rows 1–4 → columns 2, 4,1, 3
One valid arrangement of 4 non-attacking Queens on a 4 × 4 board.
Row 1 → column 2
Row 2 → column 4
Row 3 → column 1
Row 4 → column 3
Q3Now, place 8 queens on this 8 × 8 grid so that no 2 queens attack each other!
The 8 × 8 chequered grid printed on page 199.
Answer

Again, one Queen per row and per column, with all diagonals clear.

QQQQQQQQ
One valid arrangement of 8 non-attacking Queens (row 1 at the top, column 1 at the left).
Row12345678
Column15863724

So no two Queens share a row, a column or a diagonal.

Chapter 8 of 8 – Maths

Also for This Chapter

NCERT Solutions Class 7 Maths Chapter 8 Working with Fractions – Overview

ClassClass 7
SubjectMaths
Chapter8 – Working with Fractions
Textbook pages173 – 199
Questions solved62
Session2027
FormatFull answers on this page + PDF

NCERT Solutions Class 7 Maths Chapter 8 – FAQs

Where can I download NCERT Solutions Class 7 Maths Chapter 8 Working with Fractions PDF?

Read every answer on this page, or download the free PDF from the table at the top.

Is this for the 2027 session?

Yes, it follows the latest NCERT Class 7 Maths book for 2027.

How many questions are solved in NCERT Class 7 Maths Chapter 8?

All 62 questions of the chapter (textbook pages 173 – 199) – the in-text questions, activities and the end-of-chapter exercises.

How should I use these solutions?

Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.

Official website: ncert.nic.inNational Council of Educational Research and Training publishes date sheets, admit cards and results here
Visit

Ask a question

?

Loading comments…