NCERT Solutions for Class 7 Maths Chapter 1 Large Numbers Around Us – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.
Chapter 1 of Ganita Prakash (Grade 7, Part I) starts with a farmer buying rice seeds and ends with numbers in the crores. On the way you meet lakhs, crores and arabs, the Indian and American comma systems, rounding, quick multiplication tricks and a set of calculators called Thoughtful Thousands, Tedious Tens, Handy Hundreds, Creative Chitti and Systematic Sippy.
NCERT Solutions for Class 7 Maths Chapter 1 Large Numbers Around Us PDF
All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.
| Chapter | Download | |
|---|---|---|
| Solutions PDF (English medium) | Large Numbers Around Us | View PDF |
| Solutions PDF (Hindi medium) | हमारे आस-पास की बड़ी संख्याएँ | View PDF |
NCERT Solutions for Class 7 Maths Chapter 1 Large Numbers Around Us – Questions and Answers
All 83 questions of the chapter (textbook pages 1 – 22) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.
In-text Questions — Pages 1–21.1 A Lakh Varieties!
No — not even close. One new variety a day for 100 years gives only about 36,500 varieties, which is roughly a third of a lakh.
Days in 100 years = 365 × 100 = 36,500
Varieties tasted = 36,500 × 1 = 36,500
Still needed = 1,00,000 − 36,500 = 63,500 varieties
Each arrow is simply “+ 1”, so every largest number is one step below the next smallest number.
| Statement | Number |
|---|---|
| The largest 3-digit number is | 999 |
| The smallest 4-digit number is | 1,000 |
| The largest 4-digit number is | 9,999 |
| The smallest 5-digit number is | 10,000 |
| The largest 5-digit number is | 99,999 |
| The smallest 6-digit number is | 1,00,000 |
The chain of ten boxes below it is just counting on by 1:
2 varieties a day: No — only 73,000 varieties in 100 years. 3 varieties a day: Yes — 1,09,500 varieties, which is more than one lakh.
2 a day: 36,500 × 2 = 73,000 < 1,00,000 (27,000 short)
3 a day: 36,500 × 3 = 1,09,500 > 1,00,000 (9,500 extra)
In-text Questions — Page 31.1 A Lakh Varieties!
Take y = 274 — it is the value that lands almost exactly on one lakh.
365 × 274 = 365 × 200 + 365 × 74
= 73,000 + 27,010
= 1,00,010 days
1,00,010 − 1,00,000 = only 10 days more than a lakh
A few other choices:
| y (years) | Days = 365 × y | Compared with 1,00,000 |
|---|---|---|
| 50 | 18,250 | 81,750 less |
| 100 | 36,500 | 63,500 less |
| 200 | 73,000 | 27,000 less |
| 274 | 1,00,010 | only 10 more |
| 300 | 1,09,500 | 9,500 more |
Figure it Out — Page 31.1 A Lakh Varieties!
75,000 is 25,000 less than one lakh.
1,00,000 − 75,000
= 25,000
1,06,000 is 6,000 more than one lakh.
= 6,000
The population went up by 31,000.
Population in 2011 = 75,000
Increase = 1,06,000 − 75,000
= 31,000 people
In-text Questions — Page 3 (Getting a Feel of Large Numbers)1.1 A Lakh Varieties!
The building in the picture has 10 floors, so its height is about 40 metres.
Height of one floor = 4 × 1 m = 4 m
Number of floors in the picture = 10
Height of building = 10 × 4 m = 40 m
The Statue of Unity is taller, by 140 m.
Height of Somu’s building = 40 m
Difference = 180 − 40 = 140 m
The waterfall is 410 m taller than the building.
Height of Somu’s building = 40 m
Difference = 450 − 40 = 410 m
About 113 floors.
Height of one floor = 4 m
Number of floors = 450 ÷ 4
= 112.5
= 113 floors (you cannot build half a floor, so round up)
In-text Questions — Pages 4–5Reading and Writing Numbers
Both — it depends on what you are counting. A lakh is big for slow things and small for crowded things.
| A lakh feels BIG when… | A lakh feels SMALL when… |
|---|---|
| 1 lakh days = 274 years of living | 1 lakh people fit in the Ahmedabad cricket stadium |
| 1 lakh people in a line stretch 38 km | 80,000–1,20,000 hairs sit on one head |
| 1 lakh varieties of rice is a huge treasure of seeds | One female fish can lay nearly a lakh eggs at a time |
Read the groups from the left: crore, lakh, thousand, then the last three digits.
| Number | Number name (Indian system) |
|---|---|
| (a) 3,00,600 | Three lakh six hundred |
| (b) 5,04,085 | Five lakh four thousand eighty five |
| (c) 27,30,000 | Twenty seven lakh thirty thousand |
| (d) 70,53,138 | Seventy lakh fifty three thousand one hundred thirty eight |
Write each group in its own place, and fill any missing group with zeroes.
| Number name | Number |
|---|---|
| (a) One lakh twenty three thousand four hundred and fifty six | 1,23,456 |
| (b) Four lakh seven thousand seven hundred and four | 4,07,704 |
| (c) Fifty lakhs five thousand and fifty | 50,05,050 |
| (d) Ten lakhs two hundred and thirty five | 10,00,235 |
two hundred thirty five = 235
10,00,000 + 235 = 10,00,235
Land of Tens — Pages 5–61.2 Land of Tens
Every press adds 1000, so the number of presses is simply the number divided by 1000.
| Target | Working | Presses |
|---|---|---|
| (a) Three thousand | 3000 ÷ 1000 | 3 times |
| (b) 10,000 | 10000 ÷ 1000 | 10 times |
| (c) Fifty three thousand | 53000 ÷ 1000 | 53 times |
| (d) 90,000 | 90000 ÷ 1000 | 90 times |
| (e) One lakh | 1,00,000 ÷ 1000 | 100 times |
| (f) 1,53,000 | 153 × 1000 | 153 times |
(g) 100 thousands are required to make one lakh.
1,00,000 ÷ 1,000 = 100
So 100 × 1000 = 1,00,000 ✓
Divide each number by 10.
| Target | Working | Presses |
|---|---|---|
| (a) Five hundred | 500 ÷ 10 | 50 times |
| (b) 780 | 780 ÷ 10 | 78 times |
| (c) 1000 | 1000 ÷ 10 | 100 times |
| (d) 3700 | 3700 ÷ 10 | 370 times |
| (e) 10,000 | 10000 ÷ 10 | 1000 times |
| (f) One lakh | 1,00,000 ÷ 10 | 10,000 times |
| (g) 4,350 | 435 × 10 | 435 times |
Divide each number by 100.
| Target | Working | Presses |
|---|---|---|
| (a) Four hundred | 400 ÷ 100 | 4 times |
| (b) 3,700 | 3700 ÷ 100 | 37 times |
| (c) 10,000 | 10000 ÷ 100 | 100 times |
| (d) Fifty three thousand | 53000 ÷ 100 | 530 times |
| (e) 90,000 | 90000 ÷ 100 | 900 times |
| (f) 97,600 | 97600 ÷ 100 | 976 times |
| (g) 1,00,000 | 100000 ÷ 100 | 1000 times |
| (h) 58,200 | 582 × 100 | 582 times |
(i) 10,000 ÷ 100 = 100 hundreds make ten thousand.
(j) 1,00,000 ÷ 100 = 1000 hundreds make one lakh.
(k) No, the statement is not true.
Every multiple of 100 is also a multiple of 10.
e.g. 3,700 = 37 × 100 = 370 × 10
So Tedious Tens can show every number Handy Hundreds can show.
Yes, both ways give exactly 321.
= 320 + 1 = 321 ✓ (33 clicks)
Way 2: (2 × 100) + (12 × 10) + (1 × 1)
= 200 + 120 + 1 = 321 ✓ (15 clicks)
| Buttons | 5072 | |
|---|---|---|
| +10,00,000 | ||
| +1,00,000 | ||
| +10,000 | ||
| +1,000 | 3 | |
| +100 | 50 | 20 |
| +10 | 7 | |
| +1 | 2 | 72 |
These two ways can be expressed as: (a) (50 × 100) + (7 × 10) + (2 × 1) = 5072 (b) (3 × 1000) + (20 × 100) + (72 × 1) = 5072. Find a different way to get 5072 and write an expression for the same.
Here are three fresh ways, each different from the two given.
= 5000 + 70 + 2 = 5072 (14 clicks)
Way 2: (4 × 1000) + (10 × 100) + (7 × 10) + (2 × 1)
= 4000 + 1000 + 70 + 2 = 5072 (23 clicks)
Way 3: (5 × 1000) + (72 × 1)
= 5000 + 72 = 5072 (77 clicks)
Figure it Out — Page 61.2 Land of Tens
The first way in each pair uses the digits of the number itself; the second trades one big button for ten smaller ones.
| Number | Way 1 | Way 2 |
|---|---|---|
| (a) 8300 | (8 × 1000) + (3 × 100) | (83 × 100) |
| (b) 40629 | (4 × 10000) + (6 × 100) + (2 × 10) + (9 × 1) | (40 × 1000) + (62 × 10) + (9 × 1) |
| (c) 56354 | (5 × 10000) + (6 × 1000) + (3 × 100) + (5 × 10) + (4 × 1) | (56 × 1000) + (35 × 10) + (4 × 1) |
| (d) 66666 | (6 × 10000) + (6 × 1000) + (6 × 100) + (6 × 10) + (6 × 1) | (66 × 1000) + (6 × 100) + (66 × 1) |
| (e) 367813 | (3 × 100000) + (6 × 10000) + (7 × 1000) + (8 × 100) + (1 × 10) + (3 × 1) | (36 × 10000) + (78 × 100) + (13 × 1) |
62 × 10 = 620
9 × 1 = 9
40,000 + 620 + 9 = 40,629 ✓
Check (e), Way 2: 36 × 10,000 = 3,60,000
78 × 100 = 7,800
13 × 1 = 13
3,60,000 + 7,800 + 13 = 3,67,813 ✓
In-text Questions — Page 71.2 Land of Tens
Largest = 993. Smallest = 102.
(9 × 100) + (8 × 10) + (13 × 1)
= 900 + 80 + 13 = 993
Presses = 9 + 8 + 13 = 30 ✓
Smallest: put as few presses as possible on +100.
(0 × 100) + (8 × 10) + (22 × 1)
= 0 + 80 + 22 = 102
Presses = 0 + 8 + 22 = 30 ✓
Yes — 997 can be made with many different click counts.
Clicks = 9 + 9 + 7 = 25
34 clicks: (9 × 100) + (8 × 10) + (17 × 1) = 900 + 80 + 17 = 997
Clicks = 9 + 8 + 17 = 34
106 clicks: (99 × 10) + (7 × 1) = 990 + 7 = 997
Clicks = 99 + 7 = 106
997 clicks: (997 × 1) = 997
| Buttons | 5072 |
|---|---|
| +10,00,000 | |
| +1,00,000 | |
| +10,000 | |
| +1,000 | 5 |
| +100 | 0 |
| +10 | 6 |
| +1 | 12 |
Is there another way to get 5072 using less than 23 button clicks? Write the expression for the same.
Yes. 5072 can be made in just 14 clicks, and 8300 in 11 clicks.
Clicks = 5 + 0 + 7 + 2 = 14
(b) 8300 = (8 × 1000) + (3 × 100) + (0 × 10) + (0 × 1)
Clicks = 8 + 3 + 0 + 0 = 11
Figure it Out — Page 71.2 Land of Tens
Use each digit of the number as the number of presses of its own button.
| Number | Expression with least clicks | Clicks |
|---|---|---|
| (a) 8300 | (8 × 1000) + (3 × 100) | 8 + 3 = 11 |
| (b) 40629 | (4 × 10000) + (0 × 1000) + (6 × 100) + (2 × 10) + (9 × 1) | 4 + 0 + 6 + 2 + 9 = 21 |
| (c) 56354 | (5 × 10000) + (6 × 1000) + (3 × 100) + (5 × 10) + (4 × 1) | 5 + 6 + 3 + 5 + 4 = 23 |
| (d) 66666 | (6 × 10000) + (6 × 1000) + (6 × 100) + (6 × 10) + (6 × 1) | 6 × 5 = 30 |
| (e) 367813 | (3 × 100000) + (6 × 10000) + (7 × 1000) + (8 × 100) + (1 × 10) + (3 × 1) | 3 + 6 + 7 + 8 + 1 + 3 = 28 |
Yes — the smallest number of clicks is the sum of the digits of the number.
| Number | Digit sum | Least clicks |
|---|---|---|
| 8300 | 8 + 3 + 0 + 0 = 11 | 11 |
| 40629 | 4 + 0 + 6 + 2 + 9 = 21 | 21 |
| 56354 | 5 + 6 + 3 + 5 + 4 = 23 | 23 |
| 66666 | 6 + 6 + 6 + 6 + 6 = 30 | 30 |
| 367813 | 3 + 6 + 7 + 8 + 1 + 3 = 28 | 28 |
Because place value notation is itself the “no waste” way of writing a number.
Digits: 5 | 6 | 3 | 5 | 4
Buttons: +10000, +1000, +100, +10, +1
In-text Questions — Pages 8–91.3 Of Crores and Crores!
You get 1,00,00,000 — one crore — and it has 7 zeroes.
= 1,00,00,000
= 100 lakhs = 1 crore
1 followed by 7 zeroes
8 zeroes.
= 10,00,00,000
= 10 crore
Zeroes: 3 (from 1,000) + 5 (from 1 lakh) = 8
5 zeroes.
= 1,00,000
Zeroes: 2 + 3 = 5
And 1,00,000 = 1 lakh
Figure it Out — Page 91.3 Of Crores and Crores!
Place the commas first — 3-2-2-2 from the right for the Indian system, 3-3-3 for the American system.
| Number | Indian system | American system |
|---|---|---|
| (a) 4050678 | 40,50,678 Forty lakh fifty thousand six hundred seventy eight | 4,050,678 Four million fifty thousand six hundred seventy eight |
| (b) 48121620 | 4,81,21,620 Four crore eighty one lakh twenty one thousand six hundred twenty | 48,121,620 Forty eight million one hundred twenty one thousand six hundred twenty |
| (c) 20022002 | 2,00,22,002 Two crore twenty two thousand two | 20,022,002 Twenty million twenty two thousand two |
| (d) 246813579 | 24,68,13,579 Twenty four crore sixty eight lakh thirteen thousand five hundred seventy nine | 246,813,579 Two hundred forty six million eight hundred thirteen thousand five hundred seventy nine |
| (e) 345000543 | 34,50,00,543 Thirty four crore fifty lakh five hundred forty three | 345,000,543 Three hundred forty five million five hundred forty three |
| (f) 1020304050 | 1,02,03,04,050 One arab two crore three lakh four thousand fifty | 1,020,304,050 One billion twenty million three hundred four thousand fifty |
For (b) and (d), first build the number in the American system, then re-comma it the Indian way.
| Number name | Indian place value notation |
|---|---|
| (a) One crore one lakh one thousand ten | 1,01,01,010 |
| (b) One billion one million one thousand one | 1,00,10,01,001 |
| (c) Ten crore twenty lakh thirty thousand forty | 10,20,30,040 |
| (d) Nine billion eighty million seven hundred thousand six hundred | 9,08,07,00,600 |
1 million = 1,000,000
1 thousand = 1,000, and one = 1
Total = 1,001,001,001
Indian commas → 1,00,10,01,001
(d) 9,000,000,000 + 80,000,000 + 700,000 + 600
= 9,080,700,600
Indian commas → 9,08,07,00,600
Bring both sides into plain digits first, then compare.
| Comparison | Left in digits | Right in digits | Sign |
|---|---|---|---|
| (a) 30 thousand ? 3 lakhs | 30,000 | 3,00,000 | < |
| (b) 500 lakhs ? 5 million | 5,00,00,000 | 50,00,000 | > |
| (c) 800 thousand ? 8 million | 8,00,000 | 80,00,000 | < |
| (d) 640 crore ? 60 billion | 6,40,00,00,000 | 60,00,00,00,000 | < |
5 million = 5 × 10,00,000 = 50,00,000 (50 lakh)
5 crore is ten times 50 lakh, so 500 lakhs > 5 million
(d) 640 crore = 6,40,00,00,000 (10 digits)
60 billion = 60 × 100 crore = 6,000 crore = 60,00,00,00,000 (11 digits)
640 crore < 6,000 crore, so 640 crore < 60 billion
In-text Questions — Page 101.4 Exact and Approximate Values
The joke is that the headline number was never meant to be exact — it is a rounded figure.
Headlines of this kind are everywhere:
- “Over 50,000 devotees at the temple on Ekadashi.”
- “Nearly 1 crore people watched the match.”
- “About 2 lakh vehicles cross the bridge every day.”
Round the way that keeps you safe from a shortfall.
| Situation | Example | Why |
|---|---|---|
| (a) Round up | A school with 732 people orders 750 sweets; buying chairs for 118 guests → order 125 | Running short is worse than having a little extra |
| (b) Round down | A shopkeeper says an item costing ₹470 is “around ₹450”; a bag holds 27 kg → “about 25 kg” | A modest claim is safer than an exaggerated one |
| (c) Either is fine | Distance between two towns, 268 km → “about 270 km”; population of a city | Only a rough idea of size is needed |
| (d) Exact numbers | Money in a bank account, marks in an exam, votes counted, a phone number, medicine dose | Even a difference of 1 changes the meaning completely |
In-text Questions — Page 11 (Nearest Neighbours)1.4 Exact and Approximate Values
Look only at the digits to the right of the place you are rounding to: 5 or more rounds up, less than 5 rounds down.
| Nearest… | (a) 3,87,69,957 | (b) 29,05,32,481 |
|---|---|---|
| thousand | 3,87,70,000 | 29,05,32,000 |
| ten thousand | 3,87,70,000 | 29,05,30,000 |
| lakh | 3,88,00,000 | 29,05,00,000 |
| ten lakh | 3,90,00,000 | 29,10,00,000 |
| crore | 4,00,00,000 | 29,00,00,000 |
last 4 digits 9957 ≥ 5000 → ten thousand also 3,87,70,000
last 5 digits 69,957 ≥ 50,000 → lakh up to 3,88,00,000
last 6 digits 7,69,957 ≥ 5,00,000 → ten lakh up to 3,90,00,000
last 7 digits 87,69,957 ≥ 50,00,000 → crore up to 4,00,00,000
(b) 481 < 500 → down; 2481 < 5000 → down; 32,481 < 50,000 → down;
5,32,481 ≥ 5,00,000 → up; 05,32,481 < 50,00,000 → down
The number must lie between 4,99,99,500 and 5,00,00,499, and there are exactly 1000 such whole numbers.
Nearest ten lakh = 5,00,00,000 → 4,95,00,000 to 5,04,99,999
Nearest lakh = 5,00,00,000 → 4,99,50,000 to 5,00,49,999
Nearest ten thousand = 5,00,00,000 → 4,99,95,000 to 5,00,04,999
Nearest thousand = 5,00,00,000 → 4,99,99,500 to 5,00,00,499
Count = 5,00,00,499 − 4,99,99,500 + 1 = 1000 numbers
Estimating Sums and Differences — Pages 11–121.4 Exact and Approximate Values
(a) Both estimates are correct, but Estu’s is closer.
Distance from 8,00,000 = 82,810 (Roxie)
Distance from 9,00,000 = 17,190 (Estu)
17,190 < 82,810 → Estu is closer
(b) The sum is greater than 8,50,000.
So the sum > 4,50,000 + 4,00,000 = 8,50,000 ✓
(c) The sum is less than 8,83,128.
But the second number is 4,19,682, which is 318 less than 4,20,000
So the sum = 8,83,128 − 318 = 8,82,810 < 8,83,128
(d) Exact value = 8,82,810.
(a) Both are correct, but Roxie’s estimate is closer.
Distance from 10,00,000 = 26,892 (Roxie)
Distance from 9,00,000 = 73,108 (Estu)
26,892 < 73,108 → Roxie is closer
(b) The difference is greater than 9,50,000.
We are actually subtracting 4,90,020, which is less than 5,00,000
Subtracting less leaves more, so difference > 9,63,128 > 9,50,000 ✓
(c) The difference is greater than 9,63,128.
5,00,000 − 4,90,020 = 9,980
So the difference = 9,63,128 + 9,980 = 9,73,108
(d) Exact value = 9,73,108.
Populations of Cities — Page 131.4 Exact and Approximate Values
| Rank | City | Population (2011) | Population (2001) |
|---|---|---|---|
| 1 | Mumbai | 1,24,42,373 | 1,19,78,450 |
| 2 | New Delhi | 1,10,07,835 | 98,79,172 |
| 3 | Bengaluru | 84,25,970 | 43,01,326 |
| 4 | Hyderabad | 68,09,970 | 36,37,483 |
| 5 | Ahmedabad | 55,70,585 | 35,20,085 |
| 6 | Chennai | 46,81,087 | 43,43,645 |
| 7 | Kolkata | 44,86,679 | 45,72,876 |
| 8 | Surat | 44,67,797 | 24,33,835 |
| 9 | Vadodara | 35,52,371 | 16,90,000 |
| 10 | Pune | 31,15,431 | 25,38,473 |
| 11 | Jaipur | 30,46,163 | 23,22,575 |
| 12 | Lucknow | 28,15,601 | 21,85,927 |
| 13 | Kanpur | 27,67,031 | 25,51,337 |
| 14 | Nagpur | 24,05,665 | 20,52,066 |
| 15 | Indore | 19,60,631 | 14,74,968 |
| 16 | Thane | 18,18,872 | 12,62,551 |
| 17 | Bhopal | 17,98,218 | 14,37,354 |
| 18 | Visakhapatnam | 17,28,128 | 13,45,938 |
| 19 | Pimpri-Chinchwad | 17,27,692 | 10,12,472 |
| 20 | Patna | 16,84,222 | 13,66,444 |
From the information given in the table, answer the following questions by approximation: What is your general observation about this data? Share it with the class.
Almost every city in the table grew between 2001 and 2011 — several of them enormously — and only one shrank.
- The top two, Mumbai and New Delhi, are the only cities above 1 crore (1,24,42,373 and 1,10,07,835 in 2011).
- Bengaluru, Hyderabad, Surat and Vadodara nearly doubled in ten years.
- Kolkata is the only city that lost people — it fell from 45,72,876 to 44,86,679, a drop of about 86,000.
- Mumbai grew by only about 4.6 lakh, far less than Bengaluru’s 41 lakh, so being the biggest does not mean growing the fastest.
- All 20 cities in the table had more than 16 lakh people in 2011.
| Rank | City | Population (2011) | Population (2001) |
|---|---|---|---|
| 1 | Mumbai | 1,24,42,373 | 1,19,78,450 |
| 2 | New Delhi | 1,10,07,835 | 98,79,172 |
| 3 | Bengaluru | 84,25,970 | 43,01,326 |
| 4 | Hyderabad | 68,09,970 | 36,37,483 |
| 5 | Ahmedabad | 55,70,585 | 35,20,085 |
| 6 | Chennai | 46,81,087 | 43,43,645 |
| 7 | Kolkata | 44,86,679 | 45,72,876 |
| 8 | Surat | 44,67,797 | 24,33,835 |
| 9 | Vadodara | 35,52,371 | 16,90,000 |
| 10 | Pune | 31,15,431 | 25,38,473 |
| 11 | Jaipur | 30,46,163 | 23,22,575 |
| 12 | Lucknow | 28,15,601 | 21,85,927 |
| 13 | Kanpur | 27,67,031 | 25,51,337 |
| 14 | Nagpur | 24,05,665 | 20,52,066 |
| 15 | Indore | 19,60,631 | 14,74,968 |
| 16 | Thane | 18,18,872 | 12,62,551 |
| 17 | Bhopal | 17,98,218 | 14,37,354 |
| 18 | Visakhapatnam | 17,28,128 | 13,45,938 |
| 19 | Pimpri-Chinchwad | 17,27,692 | 10,12,472 |
| 20 | Patna | 16,84,222 | 13,66,444 |
What is an appropriate title for the above table?
A good title names the what, the where and the when. For example:
- “Population of the 20 largest Indian cities, 2001 and 2011”
- “Census populations of major Indian cities (2001 vs 2011)”
- “Twenty most populous Indian cities and how they grew, 2001–2011”
Pune’s 2011 population is 31,15,431, an increase of about 6 lakh over 2001.
Population in 2001 = 25,38,473
Increase = 31,15,431 − 25,38,473 = 5,76,958
Rounded to the nearest lakh = about 6,00,000 (6 lakh)
Bengaluru, by 41,24,644 people — more than 41 lakh.
| City | 2011 | 2001 | Increase |
|---|---|---|---|
| Bengaluru | 84,25,970 | 43,01,326 | 41,24,644 |
| Hyderabad | 68,09,970 | 36,37,483 | 31,72,487 |
| Ahmedabad | 55,70,585 | 35,20,085 | 20,50,500 |
| Surat | 44,67,797 | 24,33,835 | 20,33,962 |
| Vadodara | 35,52,371 | 16,90,000 | 18,62,371 |
| Mumbai | 1,24,42,373 | 1,19,78,450 | 4,63,923 |
Yes — Bengaluru, Hyderabad, Surat and Vadodara. Vadodara has more than doubled.
| City | 2001 | 2011 | Roughly how many times |
|---|---|---|---|
| Vadodara | 16,90,000 | 35,52,371 | about 2.1 times |
| Bengaluru | 43,01,326 | 84,25,970 | about 2 times |
| Hyderabad | 36,37,483 | 68,09,970 | about 1.9 times |
| Surat | 24,33,835 | 44,67,797 | about 1.8 times |
| Pimpri-Chinchwad | 10,12,472 | 17,27,692 | about 1.7 times |
By about 7 (more precisely about 7.4).
Mumbai (2011) = 1,24,42,373 ≈ 124 lakh
124 ÷ 17 ≈ 7.3
Check: 16,84,222 × 7 = 1,17,89,554 (a bit less than Mumbai)
16,84,222 × 8 = 1,34,73,776 (a bit more than Mumbai)
In-text Questions — Page 141.5 Patterns in Products
Because 5 is half of 10.
So n × 5 = n × (10 ÷ 2) = (n ÷ 2) × 10
Roxie’s example: 116 × 5
= 116 ÷ 2 × 10
= 58 × 10
= 580
Figure it Out — Page 141.5 Patterns in Products
Regroup the factors so that a 100, 1000 or 10,000 appears.
= (2 × 50) × 1768
= 100 × 1768
= 1,76,800
(b) 72 × 125
= 72 × (1000 ÷ 8)
= (72 ÷ 8) × 1000
= 9 × 1000
= 9,000
(c) 125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000
= 10,00,000
Replace 25 by 100 ÷ 4, 250 by 1000 ÷ 4 and 2500 by 10,000 ÷ 4.
(b) 25 × 240 = 100 × (240 ÷ 4) = 100 × 60 = 6,000
(c) 250 × 120 = 1000 × (120 ÷ 4) = 1000 × 30 = 30,000
(d) 2500 × 12 = 10,000 × (12 ÷ 4) = 10,000 × 3 = 30,000
(e) 12,00,00,000 can be split in many ways. Three easy ones:
12,000 × 10,000 = 12,00,00,000
1,20,000 × 1,000 = 12,00,00,000
In-text Questions — Pages 14–15 (How Long is the Product?)1.5 Patterns in Products
Work each one out and the pattern jumps out.
| Multiplication | Product | Multiplication | Product |
|---|---|---|---|
| 11 × 11 | 121 | 66 × 61 | 4,026 |
| 111 × 111 | 12,321 | 666 × 661 | 4,40,226 |
| 1111 × 1111 | 12,34,321 | 6666 × 6661 | 4,44,02,226 |
| Extend: 11111 × 11111 | 12,34,54,321 | Extend: 66666 × 66661 | 4,44,40,22,226 |
| 3 × 5 | 15 | 101 × 101 | 10,201 |
| 33 × 35 | 1,155 | 102 × 102 | 10,404 |
| 333 × 335 | 1,11,555 | 103 × 103 | 10,609 |
| Extend: 3333 × 3335 | 1,11,15,555 | Extend: 104 × 104 | 10,816 |
1’s: the product counts up and back down — 1, 121, 12321, 1234321, 123454321
6’s: 4026 → 440226 → 44402226 — one extra 4, one extra 2 each time
3 & 5: 15 → 1155 → 111555 — as many 1’s as 5’s
101, 102, 103: 10201, 10404, 10609 — the middle jumps 2, 4, 6 and the end 1, 4, 9 (the squares)
Yes. The number of digits in the product is either the total number of digits in the two numbers, or one less than that. If one number has m digits and the other has n digits, the product has (m + n − 1) or (m + n) digits.
| Multiplication | m + n | Digits in product |
|---|---|---|
| 11 × 11 = 121 | 2 + 2 = 4 | 3 = m + n − 1 |
| 1111 × 1111 = 12,34,321 | 4 + 4 = 8 | 7 = m + n − 1 |
| 66 × 61 = 4,026 | 2 + 2 = 4 | 4 = m + n |
| 666 × 661 = 4,40,226 | 3 + 3 = 6 | 6 = m + n |
| 3 × 5 = 15 | 1 + 1 = 2 | 2 = m + n |
Yes, Roxie is correct.
Largest 2-digit × largest 2-digit = 99 × 99 = 9,801 → 4 digits
So every such product lies between 100 and 9,801
→ it must have 3 or 4 digits
There is a far better way — check only the smallest and the largest case. There is no need to test all 8,100 pairs.
So every product lies between 10 × 10 = 100
and 99 × 99 = 9,801.
Both ends have 3 or 4 digits → all products do
No. The product always has 5 or 6 digits.
Largest case: 999 × 999 = 9,98,001 → 6 digits
The smallest possible product, 10,000, is already a 5-digit number.
Yes.
Largest case: 9999 × 99 = 9,89,901 → 6 digits
Example: 1234 × 12 = 14,808, a 5-digit number
| 1-digit | × | 1-digit | = | 1-digit | or | 2-digit |
| 2-digit | × | 1-digit | = | 2-digit | or | 3-digit |
| 2-digit | × | 2-digit | = | 3-digit | or | 4-digit |
| 3-digit | × | 3-digit | = | 5-digit | or | 6-digit |
| 5-digit | × | 5-digit | = | or | ||
| 8-digit | × | 3-digit | = | or | ||
| 12-digit | × | 13-digit | = | or |
The blanks follow the same rule: the answer has (m + n − 1) or (m + n) digits.
| m-digit | × | n-digit | = | m + n − 1 | or | m + n |
|---|---|---|---|---|---|---|
| 1-digit | × | 1-digit | = | 1-digit | or | 2-digit |
| 2-digit | × | 1-digit | = | 2-digit | or | 3-digit |
| 2-digit | × | 2-digit | = | 3-digit | or | 4-digit |
| 3-digit | × | 3-digit | = | 5-digit | or | 6-digit |
| 5-digit | × | 5-digit | = | 9-digit | or | 10-digit |
| 8-digit | × | 3-digit | = | 10-digit | or | 11-digit |
| 12-digit | × | 13-digit | = | 24-digit | or | 25-digit |
10,000 × 10,000 = 10,00,00,000 → 9 digits
99,999 × 99,999 = 9,99,98,00,001 → 10 digits ✓
Fascinating Facts about Large Numbers — Pages 16–181.5 Patterns in Products
The hidden number is 4,75,000.
= 1250 × 38 × 10
= 47,500 × 10
= 4,75,000
Indian system: four lakh seventy five thousand
American system: four hundred seventy five thousand
How many songs per year? Purandaradāsa is said to have lived about 80 years (1484–1564).
4,75,000 ÷ 80 = about 5,938 songs a year
= about 16 songs every single day
If he began at about age 30 and composed for 50 years:
4,75,000 ÷ 50 = 9,500 songs a year
= about 26 songs every day
The hidden number is 14,70,00,000 km — about 14 crore 70 lakh kilometres.
= 21 × 7 × 100 × 10,000
= 147 × 10,00,000
= 14,70,00,000
Indian system: fourteen crore seventy lakh
American system: one hundred forty seven million
How was it measured? Astronomers first worked it out with geometry, by watching the planet Venus pass across the face of the Sun from places far apart on the Earth. Today it is measured very precisely by sending radar signals to planets and timing the echoes.
The hidden number is 40,00,00,000 litres every second — 40 crore litres.
= 64 × 625 × 100 × 100
= 40,000 × 10,000
= 40,00,00,000
Indian system: forty crore
American system: four hundred million
The hidden number is 9,300 km.
= 13,95,000 ÷ 15 ÷ 10
= 93,000 ÷ 10
= 9,300
Both systems: nine thousand three hundred
The hidden number is 1,50,000 kg — one lakh fifty thousand kilograms, or 150 tonnes.
= 10,50,00,000 ÷ 7 ÷ 100
= 1,50,00,000 ÷ 100
= 1,50,000
Indian system: one lakh fifty thousand
American system: one hundred fifty thousand
The hidden number is 4,00,00,000 tonnes — four crore (forty million) tonnes.
= 52,00,00,00,000 ÷ 13 ÷ 10
= 40,00,00,000 ÷ 10
= 4,00,00,000
Indian system: four crore
American system: forty million
In-text Questions — Pages 18–191.6 Did You Ever Wonder…?
No, it could not. One lakh buses hold about 50 lakh people, but Mumbai has more than 1 crore 24 lakh.
1 lakh buses hold = 1,00,000 × 50
= 50,00,000 = 50 lakh people
Population of Mumbai (2011) = 1,24,42,373
1,24,42,373 > 50,00,000
Left standing = 1,24,42,373 − 50,00,000 = 74,42,373 people
Yes — just barely.
= 5 × 25 × 1000 × 100
= 125 × 1,00,000
= 1,25,00,000 people (1 crore 25 lakh)
Population of Mumbai = 1,24,42,373
1,24,42,373 < 1,25,00,000 ✓
Space to spare = 57,627 places
No — after 10 years she would still be about 19,400 km short.
= 36,500 km
Distance in 10 years = 36,500 × 10
= 3,65,000 km
Distance to the Moon = 3,84,400 km
Short by = 3,84,400 − 3,65,000 = 19,400 km
No. The journey would take about 403 years — far more than a lifetime.
Distance in 1 year = 1000 × 365 = 3,65,000 km
Years needed = 14,70,00,000 ÷ 3,65,000
= 1,47,000 ÷ 365
≈ 402.7 years
All three answers are no.
= 5,00,000 g = 500 kg
A person can lift perhaps 40–50 kg, so no — 500 kg is about the weight of 8 adults.
(b) Minutes in a day = 60 × 24 = 1,440
Babies in a day = 250 × 1,440 = 3,60,000
1 million = 10,00,000
3,60,000 < 10,00,000 → no, only about a third of a million.
(c) Seconds in a day = 60 × 60 × 24 = 86,400
So at most 86,400 coins a day.
86,400 < 10,00,000 → no, not even a tenth of a million.
Figure it Out — Pages 19–211.6 Did You Ever Wonder…?
(a) 98,76,54,32,10 (b) 1,02,34,56,798
Ending in 0 is better — it frees the 5 for a higher place.
Put the rest in decreasing order: 9,8,7,6,5,4,3,2,1
Largest = 9876543210
(b) An even number must end in 0, 2, 4, 6 or 8.
To be small, the front should read 1,0,2,3,4,…
Ending in 8 keeps the front smallest: 102345679 | 8
Smallest = 1023456798
77,77,777 — “seventy seven lakh seventy seven thousand seven hundred seventy seven” — with 60 letters (61 if you write “lakhs”, as the book does in its example).
lakh (4) → 16
seventy (7) + seven (5) = 12 → 28
thousand (8) → 36
seven (5) → 41
hundred (7) → 48
seventy (7) + seven (5) = 12 → 60 letters
The number is 123456789, and there is exactly one such number.
Swap the 1 and the 9 → 923456781 > 123456789 ✓
Swap the 8 and the 9 → 123456798 > 123456789 ✓
Every swap makes it bigger.
The largest number left is 5534512345.
Step 1: for the 1st kept digit, scan positions 1–11 → biggest is 5 (position 5)
Step 2: for the 2nd, scan positions 6–12 → biggest is 5 (position 10)
Step 3: for the 3rd, scan positions 11–13 → biggest is 3 (position 13)
Step 4: only 7 digits are left (positions 14–20) and 7 are still needed → keep them all: 4512345
Result: 5 5 3 4512345 = 5534512345
You would have to count for ever — no such pair exists, however far you go.
| Pair | Shared letter(s) | Pair | Shared letter(s) |
|---|---|---|---|
| one, two | o | six, seven | s |
| two, three | t | seven, eight | e |
| three, four | r | eight, nine | e, i |
| four, five | f | nine, ten | n, e |
| five, six | i | ten, eleven | e, n |
(a) The 1000th digit is 3, the first digit of the number 370.
Digits still needed = 1000 − 189 = 811
811 ÷ 3 = 270 remainder 1
270 three-digit numbers: 100 to 369 → uses 810 digits (total 999)
The next digit, the 1000th, is the 1st digit of 370, which is 3
(b) The millionth digit lies in the number 1,85,185.
9 + 180 + 2,700 + 36,000 + 4,50,000 = 4,88,889
Digits still needed = 10,00,000 − 4,88,889 = 5,11,111
5,11,111 ÷ 6 = 85,185 remainder 1
85,185 six-digit numbers: 1,00,000 to 1,85,184 → 5,11,110 digits (total 9,99,999)
The next digit, the millionth, is the 1st digit of 1,85,185
(c) You write the digit ‘5’ for the 5000th time at the number 13,495 — it is the units digit of 13,495.
13,495 contains one 5 (in the units place)
4,999 + 1 = 5,000 ✓
Take as many ten-thousands as you can, then make up the rest in hundreds.
| Number | Expression | Total clicks |
|---|---|---|
| (a) 20,800 | (2 × 10,000) + (8 × 100) | 2 + 8 = 10 |
| (b) 92,100 | (9 × 10,000) + (21 × 100) | 9 + 21 = 30 |
| (c) 1,20,500 | (12 × 10,000) + (5 × 100) | 12 + 5 = 17 |
| (d) 65,30,000 | (653 × 10,000) | 653 + 0 = 653 |
| (e) 70,25,700 | (702 × 10,000) + (57 × 100) | 702 + 57 = 759 |
57 × 100 = 5,700
70,20,000 + 5,700 = 70,25,700 ✓
10,000 lakhs make one billion.
1 lakh = 1,00,000 (5 zeroes)
Number of lakhs = 1,00,00,00,000 ÷ 1,00,000
= 10,000 lakhs
(a) Largest sum = 1,00,75,308 (b) Smallest difference = 10,22,447
+ 87,654
= 1,00,75,308
(b) 11,22,334
− 99,887
= 10,22,447
Four of the five targets can be hit exactly; for (e) the closest we found is 20,90,750, only 50 away.
| Target | Expression | Value |
|---|---|---|
| (a) 1,10,000 | (13,000 × 20) − 1,50,000 | 1,10,000 — exact |
| (b) 2,00,000 | (70,000 × 5) − 1,50,000 | 2,00,000 — exact |
| (c) 5,80,000 | (70,000 × 5) + 1,50,000 + (4,000 × 20) | 5,80,000 — exact |
| (d) 12,45,000 | (13,000 + 70,000) × 300 ÷ 20 | 12,45,000 — exact |
| (e) 20,90,800 | 70,000 + (300 − 5) × ((1,50,000 − 13,000) ÷ 20) | 20,90,750 — 50 less |
Check (c): 3,50,000 + 1,50,000 + 80,000 = 5,80,000 ✓
Check (d): 83,000 × 300 = 2,49,00,000; ÷ 20 = 12,45,000 ✓
Check (e): 1,50,000 − 13,000 = 1,37,000; 1,37,000 ÷ 20 = 6,850;
300 − 5 = 295; 295 × 6,850 = 20,20,750; 20,20,750 + 70,000 = 20,90,750
1,80,000 coins — one lakh eighty thousand.
1 m = 100 cm and 1 cm = 10 mm
So 180 m = 180 × 100 × 10 mm
= 1,80,000 mm
Thickness of one coin = 1 mm
Number of coins = 1,80,000 ÷ 1
= 1,80,000 coins
About 12 to 14 days.
At 900 km a day: 12,000 ÷ 900 = 13.3 → about 14 days
(13 full days cover only 11,700 km, so a 14th day is needed)
So the trip takes roughly 12 to 14 days
About 1,233 km a day and about 51 km an hour.
= 1232.7…
≈ 1,233 km per day
Hours in the journey = 11 × 24 = 264
Distance per hour = 13,560 ÷ 264
= 51.36…
≈ 51 km per hour
(Or: 1,233 ÷ 24 ≈ 51 km per hour)
Somu’s building is 40 m tall, so divide every height by 40.
| Height | Working | Times Somu’s building |
|---|---|---|
| Bald eagle (lower) 4,500 m | 4500 ÷ 40 | 112.5 ≈ 112 times |
| Bald eagle (upper) 6,000 m | 6000 ÷ 40 | 150 times |
| Mount Everest 8,850 m | 8850 ÷ 40 | 221.25 ≈ 221 times |
| Aeroplane (lower) 10,000 m | 10000 ÷ 40 | 250 times |
| Aeroplane (upper) 12,800 m | 12800 ÷ 40 | 320 times |
Mount Everest is about 221 times as tall,
and aeroplanes fly about 250 to 320 times as high.
Puzzle Time: Toothpick Digits — Page 23Puzzle Time
To make the digit 7, three sticks are needed. Write or make the number 5108. How many sticks are required?
20 sticks.
| Digit | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
|---|---|---|---|---|---|---|---|---|---|---|
| Sticks | 6 | 2 | 5 | 5 | 4 | 5 | 6 | 3 | 7 | 6 |
1 → 2 sticks
0 → 6 sticks
8 → 7 sticks
Total = 5 + 2 + 6 + 7 = 20 sticks
2. Starting with 42,019, add or write two more sticks, and make a bigger number. One example is 42,078. What other numbers bigger than 42,019 can you make in this way?
3. Preetham wants to insert the digit ‘1’ somewhere among the digits ‘4’, ‘2’, ‘0’, ‘1’ and ‘9’. Where should he place the digit ‘1’ to get the biggest possible number?
4. What other numbers can he make by placing the digit ‘1’?
1. 42,019 needs 4 + 5 + 6 + 2 + 6 = 23 sticks ✓
2. Adding two sticks (without moving any) can turn digits into bigger digits, or make a new ‘1’. The numbers bigger than 42,019 are:
42,078 (the book’s example) · 42,818 · 42,879
2 sticks on one digit (1 → 4, 2 → 8, 4 → 9):
42,049 · 48,019 · 92,019
A new ‘1’ (2 sticks) written in:
1,42,019 · 4,12,019 · 4,20,119 · 4,20,191 · 4,21,019 (the biggest)
3. He should place the ‘1’ between the ‘2’ and the ‘0’, giving 4,21,019.
4. The other numbers he can make are 1,42,019 · 4,12,019 · 4,20,119 · 4,20,191.
2. Starting with 63,890, rearrange exactly four sticks and make a bigger number. One example is 88,078. What other numbers bigger than 63,890 can you make in this way?
1. 63,890 needs 6 + 5 + 7 + 6 + 6 = 30 sticks.
2. Moving sticks keeps the total at 30, and exactly four sticks must leave their places. Some bigger numbers made this way:
66,066 · 66,069 · 90,000 · 90,999 · 92,008
99,985 — the largest possible
2. What is the biggest number that can be made using 24 sticks or lines?
3. What is the smallest number that can be made using 24 sticks or lines?
1. Many numbers use exactly 24 sticks. Three easy ones:
4,44,444 → 4 + 4 + 4 + 4 + 4 + 4 = 24 ✓
2008 → 5 + 6 + 6 + 7 = 24 ✓
2. The biggest number is 1,11,11,11,11,111 — twelve 1’s. The digit 1 uses the fewest sticks (2), and 24 ÷ 2 = 12, so no number made with 24 sticks can have more than 12 digits.
3. The smallest number is 2008 (5 + 6 + 6 + 7 = 24). Three digits use at most 3 × 7 = 21 sticks, so 4 digits are needed. The first digit is 2 (a first digit 1 would leave 22 sticks for three digits — too many), and then 0, 0 and 8 use up the remaining 19 sticks.
Chapter 1 of 8 – Maths
- Next: Chapter 2 Arithmetic Expressions
- All chapters: NCERT Solutions Class 7 Maths
Also for This Chapter
NCERT Solutions Class 7 Maths Chapter 1 Large Numbers Around Us – Overview
| Class | Class 7 |
| Subject | Maths |
| Chapter | 1 – Large Numbers Around Us |
| Textbook pages | 1 – 22 |
| Questions solved | 83 |
| Session | 2027 |
| Format | Full answers on this page + PDF |
NCERT Solutions Class 7 Maths Chapter 1 – FAQs
Where can I download NCERT Solutions Class 7 Maths Chapter 1 Large Numbers Around Us PDF?
Read every answer on this page, or download the free PDF from the table at the top.
Is this for the 2027 session?
Yes, it follows the latest NCERT Class 7 Maths book for 2027.
How many questions are solved in NCERT Class 7 Maths Chapter 1?
All 83 questions of the chapter (textbook pages 1 – 22) – the in-text questions, activities and the end-of-chapter exercises.
How should I use these solutions?
Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.