**NCERT Solutions Class 6 Mathematics Chapter 3 Playing with Numbers** – Here are all the NCERT solutions for Class 6 Mathematics Chapter 3. This solution contains questions, answers, images, explanations of the complete Chapter 3 titled Playing with Numbers of Mathematics taught in Class 6. If you are a student of Class 6 who is using NCERT Textbook to study Mathematics, then you must come across Chapter 3 Playing with Numbers. After you have studied lesson, you must be looking for answers of its questions. Here you can get complete NCERT Solutions for Class 6 Mathematics Chapter 3 Playing with Numbers in one place.

## NCERT Solutions Class 6 Maths Chapter 3 Playing With Numbers

Here on **AglaSem Schools**, you can access to **NCERT Book Solutions** in free pdf for Maths for Class 6 so that you can refer them as and when required. The NCERT Solutions to the questions after every unit of NCERT textbooks aimed at helping students solving difficult questions.

For a better understanding of this chapter, you should also see summary of Chapter 3 Playing With Numbers , Maths, Class 6.

Class | 6 |

Subject | Maths |

Book | Mathematics |

Chapter Number | 3 |

Chapter Name |
Playing With Numbers |

### NCERT Solutions Class 6 Maths chapter 3 Playing With Numbers

Class 6, Maths chapter 3, Playing With Numbers solutions are given below in PDF format. You can view them online or download PDF file for future use.

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### Question & Answer

Q.1:Find the possible factors of 45, 30 and 36

Ans :Missing

Q.2:Write all the factors of the following numbers : (a) 24 (b) 15 (c) 21 (d) 27 (e) 12 (f) 20 (g) 18 (h) 23 (i) 36

Ans :(a) 24 \( \begin{array} { l } { 24 = 1 \times 24,24 = 2 \times 12, 24 = 3 \times 8 } \\ { 24 = 4 \times 624 = 6 \times 4 } \\ { \therefore \text { Factors of } 24 \text { are } 1,2,3,4,6,8,12 , \text { and } 24 } \end{array} \) (b) 15 \( \begin{array} { l } { 15 = 1 \times 15,15 = 3 \times 5,15 = 5 \times 3 } \\ { \therefore \text { Factors of } 15 \text { are } 1,3,5 , \text { and } 15 } \end{array} \) (c) 21 \( \begin{array} { l } { 21 = 1 \times 21,21 = 3 \times 7,21 = 7 \times 3 } \\ { \therefore \text { Factors of } 21 \text { are } 1,3,7 , \text { and } 21 } \end{array} \) (d) 27 \( \begin{array} { l } { 27 = 1 \times 27,27 = 3 \times 9,27 = 9 \times 3 } \\ { \therefore \text { Factors of } 27 \text { are } 1,3,9 , \text { and } 27 } \end{array} \) (e) 12 \( \begin{array} { l } { 12 = 1 \times 12,12 = 2 \times 6,12 = 3 \times 4,12 = 4 \times 3 } \\ { \therefore \text { Factors of } 12 \text { are } 1,2,3,4,6 , \text { and } 12 } \end{array} \) (f) 20 \( \begin{array} { l } { 20 = 1 \times 20,20 = 2 \times 10,20 = 4 \times 5,20 = 5 \times 4 } \\ { \therefore \text { Factors of } 20 \text { are } 1,2,4,5,10 , \text { and } 20 } \end{array} \) (g) 18 \( \begin{array} { l } { 18 = 1 \times 18,18 = 2 \times 9,18 = 3 \times 6,18 = 6 \times 3 } \\ { \therefore \text { Factors of } 18 \text { are } 1,2,3,6,9 , \text { and } 18 } \end{array} \) (h) 23 \( \begin{array} { l } { 23 = 1 \times 23,23 = 23 \times 1 } \\ { \therefore \text { Factors of } 23 \text { are } 1 \text { and } 23 } \end{array} \) (i) 36 \( \begin{array} { l } { 36 = 1 \times 36,36 = 2 \times 18,36 = 3 \times 12,36 = 4 \times 9 } \\ { 36 = 6 \times 6 } \end{array} \)

Q.3:Write first five multiples of : (a) 5 (b) 8 (c) 9

Ans :(a) \( \begin{array} { l } { \text 5 \times 1 = 5,5 \times 2 = 10,5 \times 3 = 15,5 \times 4 = 20,5 \times 5 = 25 } \\ { \therefore \text { The required multiples are } 5,10,15,20 , \text { and } 25 . } \end{array} \) (b) \( \begin{array} { l } { \text 8 \times 1 = 8,8 \times 2 = 16,8 \times 3 = 24,8 \times 4 = 32,8 \times 5 = 40 } \\ { \therefore \text { The required multiples are } 8,16,24,32 , \text { and } 40 . } \end{array} \) (c) \( \begin{array} { l } { \text 9 \times 1 = 9,9 \times 2 = 18,9 \times 3 = 27,9 \times 4 = 36,9 \times 5 = 45 } \\ { \therefore \text { The required multiples are } 9,18,27,36 , \text { and } 45 . } \end{array} \)

Q.4:Match the items in column 1 with the items in column 2 \( \begin{array} { l l } { \text { Column } 1 } & { \text { Column } 2 } \\ { \text { (i) } 35 } & { \text { (a) Multiple of } 8 } \\ { \text { (ii) } 15 } & { \text { (b) Multiple of } 7 } \\ { \text { (iii) } 16 } & { \text { (c) Multiple of } 70 } \\ { \text { (iv) } 20 } & { \text { (d) Factor of } 30 }\\ { \text { (v) } 35 } & { \text { (e) Factor of } 50 } \\ & { \text { (f) Multiple of } 20 } \\ \end{array} \)

Ans :\( \begin{array} { l l } { \text { Column } 1 } & { \text { Column } 2 } \\ { \text { (i) } 35 } & { \text { (b) Multiple of } 7 } \\ { \text { (ii) } 15 } & { \text { (d) Factor of } 30 } \\ { \text { (iii) } 16 } & { \text { (a) Multiple of } 8 } \\ { \text { (iv) } 20 } & { \text { (d) Factor of } 20 } \\ { \text { (v) } 25 } & { \text { (e) Factor of } 50 } \end{array} \)

Q.5:Find all the multiples of 9 upto 100.

Ans :\( \begin{array} { l } { 9 \times 1 = 9,9 \times 2 = 18,9 \times 3 = 27,9 \times 4 = 36,9 \times 5 = 45 } \\ { 9 \times 6 = 54,9 \times 7 = 63,9 \times 8 = 72,9 \times 9 = 81,9 \times 10 = 90 } \\ { 9 \times 11 = 99 } \\ { \text { Therefore, the multiples of } 9 \text { up to } 100 \text { are } } \\ { 9,18,27,36,45,54,63,72,81,90 , \text { and } 99 } \end{array} \)

## NCERT / CBSE Book for Class 6 Maths

You can download the NCERT Book for Class 6 Maths in PDF format for free. Otherwise you can also buy it easily online.

- Click here for NCERT Book for Class 6 Maths
- Click here to buy NCERT Book for Class 6 Maths

### All NCERT Solutions Class 6

- NCERT Solutions for Class 6 English
- NCERT Solutions for Class 6 Hindi
- NCERT Solutions for Class 6 Maths
- NCERT Solutions for Class 6 Science
- NCERT Solutions for Class 6 Social Science
- NCERT Solutions for Class 6 Sanskrit

### All NCERT Solutions

You can also check out NCERT Solutions of other classes here. Click on the class number below to go to relevant NCERT Solutions of Class 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.

Class 1 | Class 2 | Class 3 |

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