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NCERT Solutions for Class 7 Maths Chapter 13 Connecting the Dots… (PDF) – 2027

NCERT Solutions for Class 7 Maths Chapter 13 Connecting the Dots… – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.

Chapter 5 of Ganita Prakash Grade 7 Part II is about reading data honestly. It starts with a guess — is the 6-foot-tall friend a man? — and then builds the tools that turn guesses into claims you can defend: the mean, the median, outliers, dot plots and clustered bar graphs. The habit the chapter teaches matters more than any formula: say exactly how much the data lets you say, and no more.

NCERT Solutions for Class 7 Maths Chapter 13 Connecting the Dots… PDF

All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.

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NCERT Solutions for Class 7 Maths Chapter 13 Connecting the Dots… – Questions and Answers

All 86 questions of the chapter (textbook pages Part II, 98 – 134) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.

In-text Questions — Page 98Section 5.1 Of Questions and Statements

Q1Which of the following are statistical questions?
(a) What is the price of a tennis ball in India?
(b) How old are the dogs that live on this street?
(c) What fraction of the students in your class like walking up a hill?
(d) Do you like reading?
(e) Approximately how many bricks are in this wall?
(f) Who was the best bowler in the match yesterday?
(g) What was the rainfall pattern in Barmer last year?
Answer

Statistical questions: (a), (b), (c), (f) and (g). Not statistical: (d) and (e). A statistical question is answered by collecting data that varies.

QuestionStatistical?Reason
(a) Price of a tennis ball in IndiaYesThe price is not the same in every shop or every city. You would collect prices and then summarise them.
(b) How old are the dogs on this street?YesThe dogs are of different ages. You collect the ages and describe them.
(c) What fraction of the class likes walking up a hill?YesYou must ask every student and count. The answer is a proportion found from data.
(d) Do you like reading?NoThis is asked of one person and has one answer, yes or no. Nothing varies, so no data is collected.
(e) Approximately how many bricks are in this wall?NoOne particular wall has one fixed number of bricks. Estimating is not the same as collecting data that varies.
(f) Who was the best bowler in the match yesterday?YesTo answer it you must look at wickets, runs given and overs bowled for each bowler — that is data, and people may still disagree on how to combine it.
(g) What was the rainfall pattern in Barmer last year?YesRainfall changes from month to month. You need the whole year’s readings to describe a pattern.

Math Talk — Pages 98 – 99Section 5.2 Representative Values

Math Talk
Q1The runs scored by Shubman and Yashasvi in a cricket series are given in the table below. Who do you think performed better?
Match 1Match 2Match 3Match 4
Shubman0172190
Yashasvi67551835
Runs scored by the two players in the first series — page 98.
Answer

Yashasvi performed better in this series. Both played 4 matches, so the totals can be compared: Yashasvi scored 175 runs, Shubman 128. Yashasvi was also more consistent (18 to 67), while Shubman swung from 0 to 90.

Way of comparingShubmanYashasviBetter
Highest score9067Shubman
Total runs0+17+21+90 = 12867+55+18+35 = 175Yashasvi
Mean per match128 ÷ 4 = 32175 ÷ 4 = 43.75Yashasvi
Range (max − min)90 − 0 = 9067 − 18 = 49Yashasvi (steadier)
Matches won head-to-headMatches 3, 4Matches 1, 2Equal
Q2The table below shows the runs scored by these two players in another series. Who do you think performed better in this series?
Match 1Match 2Match 3Match 4Match 5
Shubman2307105218
Yashasvi265302–15
Runs scored by the two players in the second series — page 99.
Answer

Yashasvi performed better — he averaged more runs per match, even though Shubman’s total is larger.

Shubman: 23 + 7 + 10 + 52 + 18 = 110 runs in 5 matches
Yashasvi: 26 + 53 + 2 + 15 = 96 runs in 4 matches  (he did not play Match 4)
Mean for Shubman = 110 ÷ 5 = 22 runs per match
Mean for Yashasvi = 96 ÷ 4 = 24 runs per match
Q3Vaishnavi says, “Here, Shubman performed better since his total is 110 runs, while Yashasvi’s total is 96 runs”. What do you think of Vaishnavi’s statement?
Answer

Her arithmetic is right, but her conclusion is not safe. The two totals are not comparable, because they come from different numbers of matches.

110 runs from 5 matches → 110 ÷ 5 = 22 per match
96 runs from 4 matches → 96 ÷ 4 = 24 per match
Q4Can a single number act as a representative of a group of numbers? For example, can we represent Shubman’s or Yashasvi’s batting in this series with one number? Discuss.
Answer

Yes — one number can represent a group, but it can never replace it.

  • The total is one such number, and it works when the groups are the same size.
  • The mean (average) works even when the groups differ in size, because it balances the highs and the lows: Shubman 22, Yashasvi 24.
  • The highest score and the range are also single numbers, but each tells only one thing.

In-text Questions — Page 100Average as Fair-Share

Q1Shreyas and 4 of his friends have collected the following numbers of guavas: 3, 8, 10, 5, and 4. Parag and 5 of his friends have collected the following numbers of guavas: 5, 4, 6, 3, 4, and 8. Each group will share their guavas equally amongst themselves. In which group will each member get a bigger share of guavas?
Answer

Each member of Shreyas’s group gets more — 6 guavas each, against 5 each in Parag’s group.

Shreyas’s group: 3 + 8 + 10 + 5 + 4 = 30 guavas among 5 people
Each member gets 30 ÷ 5 = 6 guavas

Parag’s group: 5 + 4 + 6 + 3 + 4 + 8 = 30 guavas among 6 people
Each member gets 30 ÷ 6 = 5 guavas

Difference = 6 − 5 = 1 guava more each in Shreyas’s group
Q2Vaishnavi tracks the number of Hibiscus flowers blooming in her garden each day. The data for the last few days’ is 2, 7, 9, 4, 3. What is the average number of Hibiscus flowers blooming per day in Vaishnavi’s garden?
Answer

5 flowers per day.

Average = (total number of flowers bloomed) ÷ (number of days)
= (2 + 7 + 9 + 4 + 3) ÷ 5
= 25 ÷ 5
= 5

Figure it Out — Page 101Section 5.2 Representative Values

Try This
Q1Shreyas is playing with a bat and a ball — but not cricket. He counts the number of times he can bounce the ball on the bat before it falls to the ground. The data for 8 attempts is 6, 2, 9, 5, 4, 6, 3, 5. Calculate the average number of bounces of the ball that Shreyas is able to make with his bat.
Answer

5 bounces per attempt.

Total bounces = 6 + 2 + 9 + 5 + 4 + 6 + 3 + 5
= 8 + 9 + 5 + 4 + 6 + 3 + 5
= 40
Number of attempts = 8
Average = 40 ÷ 8 = 5 bounces
Q2Try the activity above on your own. Collect data for 7 or more attempts and find the average.
Answer

Record at least 7 attempts, add the counts and divide the total by the number of attempts.

Sample answer: suppose your 8 attempts give 3, 5, 1, 7, 4, 6, 4, 2.

Total = 3 + 5 + 1 + 7 + 4 + 6 + 4 + 2 = 32
Average = 32 ÷ 8 = 4 bounces per attempt
Q3Identify a flowering plant in your neighbourhood. Track the number of flowers that bloom every day over a week during its flowering season. What is the average number of flowers that bloomed per day?
Answer

Count the flowers on one plant at the same time each day for 7 days (write 0 on a day with none), add the counts and divide by 7.

Sample answer: a hibiscus plant gives 4, 6, 0, 3, 5, 7, 3 flowers over one week.

Total = 4 + 6 + 0 + 3 + 5 + 7 + 3 = 28
Average = 28 ÷ 7 = 4 flowers per day
Q4Two friends are training to run a 100 m race. Their running times over the past week are given in seconds — Nikhil: 17, 18, 17, 16, 19, 17, 18; Sunil: 20, 18, 18, 17, 16, 16, 17. Who on average ran quicker?
Answer

Neither. Their averages are exactly the same — about 17.43 seconds each.

Nikhil’s total = 17 + 18 + 17 + 16 + 19 + 17 + 18 = 122 s
Nikhil’s mean = 122 ÷ 7 ≈ 17.43 s

Sunil’s total = 20 + 18 + 18 + 17 + 16 + 16 + 17 = 122 s
Sunil’s mean = 122 ÷ 7 ≈ 17.43 s
Q5The enrolment in a school during six consecutive years was as follows: 1555, 1670, 1750, 2013, 2040, 2126. Find the mean enrolment in the school during this period.
Answer

Mean enrolment = 1859 students.

Total = 1555 + 1670 + 1750 + 2013 + 2040 + 2126
1555 + 1670 = 3225
3225 + 1750 = 4975
4975 + 2013 = 6988
6988 + 2040 = 9028
9028 + 2126 = 11154

Mean = 11154 ÷ 6 = 1859 students

Math Talk — Pages 101 – 102Know Your Onions!

Math Talk
Q1The table shows the monthly price of onions, in rupees per kilogram (kg), at two towns. Where are onions costlier, according to you?
MonthYahapurWahapur
Jan2519
Feb2417
Mar2623
Apr2830
May3038
Jun3535
Jul3942
Aug4339
Sep4953
Oct5660
Nov5952
Dec4442
Monthly price of onions, in rupees per kilogram, at the two towns — page 101.
Answer

On the whole, onions are slightly costlier in Yahapur — its total (₹458 against ₹450), its average (≈ ₹38.17 against ₹37.50) and its number of dearer months (6 against 5) are higher. But the two towns are very close: Wahapur has the higher median and the single highest price.

MeasureYahapurWahapurCostlier
Total of the 12 prices₹458₹450Yahapur
Mean price458 ÷ 12 ≈ ₹38.17450 ÷ 12 = ₹37.50Yahapur
Median price(35 + 39) ÷ 2 = ₹37(38 + 39) ÷ 2 = ₹38.50Wahapur
Highest price₹59 (Nov)₹60 (Oct)Wahapur
Lowest price₹24 (Feb)₹17 (Feb)Yahapur (never as cheap)
Range (max − min)59 − 24 = ₹3560 − 17 = ₹43Wahapur swings more
Months with the higher price6 months5 monthsYahapur (1 month equal)
Q2Can you think of any other ways to compare the data?
Answer

Yes. Some other ways:

  • Compare the medians (₹37 and ₹38.50).
  • Compare the prices month by month.
  • Count the months above ₹50 (Yahapur 2, Wahapur 3).
  • Group the prices into bands (₹11–20, ₹21–30, …) and count — as a dot plot does.
  • Compare the two halves of the year (Jan–Jun and Jul–Dec).

In-text Questions — Page 103Dot Plots

Q1Does this visualisation capture all the data presented in the tables earlier?
102030405060Yahapur102030405060Wahapur
The dot plot on page 103. Green circles are Yahapur’s twelve monthly prices, purple diamonds are Wahapur’s.
Answer

No. The dot plot keeps every price, but it throws away every month.

InformationIn the table?In the dot plot?
All 24 price valuesYesYes — one dot each
Which town each price belongs toYesYes — by colour
How many times a price repeatsHard to seeYes — stacked dots
Which month a price belongs toYesNo — lost
The order of the monthsYesNo — lost
Q2Looking at it, can we tell the price of onions in Yahapur in the month of January?
Answer

No, we cannot. The dot plot shows that Yahapur had a price of ₹25 at some point in the year, but nothing on it says when.

Math Talk — Page 104Know Your Onions!

Math Talk
Q1Find the average price of onions at Yahapur and Wahapur.
Answer

Yahapur ≈ ₹38.17 per kg; Wahapur = ₹37.50 per kg.

Yahapur: 25 + 24 + 26 + 28 + 30 + 35 + 39 + 43 + 49 + 56 + 59 + 44
= 458
Average = 458 ÷ 12 = ₹38.17 (to two decimal places)

Wahapur: 19 + 17 + 23 + 30 + 38 + 35 + 42 + 39 + 53 + 60 + 52 + 42
= 450
Average = 450 ÷ 12 = ₹37.50
Q2What else do you wonder about?
Answer

Why are onions cheapest in February and dearest in October–November in both towns? Do the seasons and the new crop decide the price? Why are Wahapur’s prices more spread out than Yahapur’s?

Math Talk — Pages 105 – 106Outliers and Medians

Math Talk
Q1The heights of the family members of Yaangba and Poovizhi are as follows: Yaangba’s family: 169 cm, 173 cm, 155 cm, 165 cm, 160 cm, 164 cm. Poovizhi’s family: 170 cm, 173 cm, 165 cm, 118 cm, 175 cm. Find the average height of each family. Can we say that Yaangba’s family is taller than Poovizhi’s family?
Answer

Averages: Yaangba’s family ≈ 164.3 cm, Poovizhi’s family = 160.2 cm. But we cannot safely say Yaangba’s family is taller: four of Poovizhi’s five members are taller than 164 cm, and their average is pulled down by one very short child (118 cm).

Yaangba: 169 + 173 + 155 + 165 + 160 + 164 = 986 cm, 6 members
Average = 986 ÷ 6 ≈ 164.3 cm

Poovizhi: 170 + 173 + 165 + 118 + 175 = 801 cm, 5 members
Average = 801 ÷ 5 = 160.2 cm
Q2Can you think of any other number that can represent the data better?
Answer

Yes — sort the data and take the middle value. That number is called the Median.

Poovizhi’s family sorted: 118, 165, 170, 173, 175
Middle value → Median = 170 cm

Yaangba’s family sorted: 155, 160, 164, 165, 169, 173
Even number of values, so take the average of the two middle ones
Median = (164 + 165) ÷ 2 = 164.5 cm
Q3In this case, does the median represent the heights of the families better than the average?
Answer

Yes, for Poovizhi’s family. Its median (170 cm) is close to most members’ heights, while its mean (160.2 cm) is lower than 4 of the 5 heights because of the outlier 118 cm. For Yaangba’s family (no outlier) the mean and median are almost equal, so either works.

FamilyMeanMedianGapOutlier?
Yaangba164.3 cm164.5 cm0.2 cmNone
Poovizhi160.2 cm170 cm9.8 cm118 cm

In-text Questions — Pages 107 – 108Are you a bookworm?

Q1Find the mean and median in Poovizhi’s data without the outlier value 118. What change do you notice?
Answer

Without the outlier the mean jumps by more than 10 cm, while the median barely moves.

Remaining heights: 165, 170, 173, 175
Sum = 165 + 170 + 173 + 175 = 683 cm, 4 values
New mean = 683 ÷ 4 = 170.75 cm

Sorted: 165, 170, 173, 175  (even count)
New median = (170 + 173) ÷ 2 = 171.5 cm
With 118 cmWithout 118 cmChange
Mean160.2 cm170.75 cm+10.55 cm
Median170 cm171.5 cm+1.5 cm
Q2After the summer vacation, a class teacher asked his class how many short stories they had read. Each student answered the number of stories read on a piece of paper, as shown below. Find the mean and median number of short stories read. Before calculating them, can you guess whether the mean will be less than or greater than the median?
6308257151210405018
The fifteen slips of paper handed in by the class — page 107.
Answer

Guess: the mean will be greater than the median, because one student read 40 stories — far more than everyone else.

Sum = 6 + 8 + 5 + 15 + 40 + 0 + 8 + 3 + 0 + 2 + 7 + 12 + 5 + 1 + 10
= 122
Mean = 122 ÷ 15 ≈ 8.13 stories

Sorted: 0, 0, 1, 2, 3, 5, 5, 6, 7, 8, 8, 10, 12, 15, 40
15 values, so the middle one is the 8th → Median = 6 stories
Q3Mark the data, the mean, and the median on the dot plot below. (The numbers on the slips: 6, 8, 5, 15, 3, 0, 2, 7, 12, 40, 10, 5, 0, 1, 8.)
0510152025303540
The empty dot plot printed with this question on page 107, with its scale running from 0 to 40.
Answer

The number line runs from 0 to 40. Place one dot for each value, stacking repeats. Then draw a solid line at the mean 8.13 and a dashed line at the median 6.

Value0123567810121540
Number of dots211121121111
0 5 10 15 20 25 30 35 40 Mean = 8.13 Median = 6
Dot plot of the number of short stories read. The dots crowd between 0 and 15; the lone dot at 40 is the outlier, and it pulls the mean (solid line) to the right of the median (dashed line).
Q4Which of the values would you consider an outlier?
Answer

40 is the outlier.

All the other values: 0, 0, 1, 2, 3, 5, 5, 6, 7, 8, 8, 10, 12, 15
Next highest value after 40 is 15
Gap between them = 40 − 15 = 25 stories
Gap between any other neighbouring pair ≤ 3
Q5Find the mean and median in the absence of the outlier. What change do you notice?
Answer

Removing 40 pulls the mean down by more than 2 stories; the median drops by only half a story.

New sum = 122 − 40 = 82, and 14 values remain
New mean = 82 ÷ 14 ≈ 5.86 stories

Sorted: 0, 0, 1, 2, 3, 5, 5, 6, 7, 8, 8, 10, 12, 15
Even count, so New median = (5 + 6) ÷ 2 = 5.5 stories
With 40Without 40Change
Mean8.135.86−2.27
Median65.5−0.5

In-text Questions — Page 108Are We on the Same Page?

Q1Do you read newspapers? Have you noticed how many pages a newspaper has on different days of the week — is it the same or different?
Answer

Different. The number of pages changes from day to day. For the newspaper in the book it is 16, 18, 20, 22, 26, 16, 10 from Monday to Sunday — most on Friday (26) and fewest on Sunday (10).

DayMonTueWedThuFriSatSun
Pages16182022261610
Q2Mark the data, the mean, and the median on the dot plot below. (The number of pages of a particular newspaper from Monday to Sunday: 16, 18, 20, 22, 26, 16, 10.)
0510152025
The empty dot plot printed with this question on page 108, with its scale running from 0 to 25.
Answer

The number line runs from 0 to 25 and a little beyond. Place the seven dots, stacking the two 16s, then draw the mean at 18.29 and the median at 18.

0 5 10 15 20 25 Mean = 18.29 Median = 18
Newspaper pages, Monday to Sunday. The mean (solid) and the median (dashed) almost coincide, because the data has no strong outlier.

Math Talk — Pages 108 – 109Measures of Central Tendency

Math Talk
Q1In the three examples we considered — the heights, short-stories, and newspaper pages — observe the variability in data when:
(a) the mean and median are close to each other
(b) the mean and median are comparatively far apart, with mean < median
(c) the mean and median are comparatively far apart, with mean > median
Answer

Each of the three examples illustrates exactly one of the three cases.

CaseExampleMeanMedianWhat the data looks like
(a) close togetherNewspaper pages
10, 16, 16, 18, 20, 22, 26
18.2918Values spread out evenly, no value far from the rest
(b) mean < medianPoovizhi’s family
118, 165, 170, 173, 175
160.2170One value far below the rest — a low outlier
(c) mean > medianShort stories
0, 0, 1, 2, 3, 5, 5, 6, 7, 8, 8, 10, 12, 15, 40
8.136One value far above the rest — a high outlier
Q2Discuss the effect on the mean and median when outliers are present on both sides. You may take some example data to examine and explain this.
Answer

With outliers on both sides the two pulls work against each other. The median hardly changes; the mean moves towards the outlier that is farther from the middle, and stays near the median if the two outliers balance.

Example dataMeanMedianResult
2, 18, 19, 20, 21, 22, 38140 ÷ 7 = 2020mean = median
2, 18, 19, 20, 21, 22, 60162 ÷ 7 ≈ 23.1420mean > median
0, 18, 19, 20, 21, 22, 26126 ÷ 7 = 1820mean < median

In-text Questions — Pages 109 – 110Of Ends and the Essence — How Tall is Your Class?

Q1Suppose you are asked the question, “How tall is your class?” What would you say? [Boys: 147, 135, 130, 154, 128, 135, 134, 158, 155, 146, 146, 142, 140, 141, 144, 145, 150. Girls: 143, 136, 150, 144, 154, 140, 145, 148, 156, 150, 150.]
Answer

the class is about 145 cm tall on average (mean 144.5 cm, median 145 cm), and every student is between 128 cm and 158 cm. Boys: mean ≈ 142.94 cm, median 144 cm; girls: mean ≈ 146.9 cm, median 148 cm.

Q2What can we infer from the dot plots and the central tendency measures?
125130135140145150155160Whole classMean = 144.4Median = 145125130135140145150155160BoysMean = 142.94Median = 144125130135140145150155160GirlsMean = 146.9Median = 148
The dot plots printed in the book for the whole class (grey), the boys (blue) and the girls (orange), each with its mean (solid line) and median (dashed line) as labelled in the book.
Answer

Four things can be said, and the book states them all.

Boys (17)Girls (11)Whole class (28)
Shortest128 cm136 cm128 cm
Tallest158 cm156 cm158 cm
Range30 cm20 cm30 cm
Mean142.94 cm146.9 cm144.5 cm
Median144 cm148 cm145 cm
  • The boys’ heights are more spread out, from 128 to 158 cm. The girls lie in a narrower band, 136 to 156 cm.
  • Both the tallest and the shortest student in the class are boys.
  • Yet the boys’ mean is below the class mean and below the girls’ mean. In this class the girls are taller on average.
  • For both groups mean < median (142.94 < 144 and 146.9 < 148), which shows a small pull from values on the lower side.
Q3How many students are taller than the class’ average height?
Answer

15 students out of 28 are taller than the class average of 144.5 cm.

All 28 heights sorted:
128, 130, 134, 135, 135, 136, 140, 140, 141, 142, 143, 144, 144,
145, 145, 146, 146, 147, 148, 150, 150, 150, 150, 154, 154, 155, 156, 158

Class mean = 144.5 cm
Heights above 144.5: 145, 145, 146, 146, 147, 148, 150, 150, 150, 150, 154, 154, 155, 156, 158
Count = 15 students
Q4How many boys are taller than the class’ average height?
Answer

8 boys are taller than 144.5 cm.

Boys sorted: 128, 130, 134, 135, 135, 140, 141, 142, 144,
145, 146, 146, 147, 150, 154, 155, 158

Boys above 144.5 cm: 145, 146, 146, 147, 150, 154, 155, 158 → 8 boys
Boys at or below 144.5 cm: 17 − 8 = 9 boys

Math Talk — Page 110How long is a minute?

Math Talk
Q1Discuss how well both the groups fared at this activity. Describe and compare the variability in data and their central tendency.
4045505560657075Group AMean = 58.21Median = 604045505560657075Group BMean = 59.28Median = 59.5
The two dot plots printed in the book: the seconds after which each child in Group A and Group B opened their eyes, with the mean (solid line) and median (dashed line) of each group.
Answer

Both groups did well — most children opened their eyes between about 55 and 65 seconds. Group B was slightly better as a whole: its mean (59.28 s) is closer to 60 s and almost equal to its median (59.5 s). Group A’s median is exactly 60 s, but a few very early openers (as early as 42 s) pull its mean down to 58.21 s. Group A’s dots spread from 42 s to 68 s, Group B’s from 47 s to 71 s.

Group AGroup B
Mean58.21 s59.28 s
Median60 s59.5 s
Distance of mean from 60 s1.79 s0.72 s
Gap between mean and median1.79 s0.22 s
Spread of the dots42 s to 68 s47 s to 71 s

In-text Questions — Page 111Zero Median Runs Scored! / Zero vs No value

Q1In a cricket match, can a team’s median runs scored by a player be 0 but the team’s total score be 407/10?
Answer

Yes, it can. The median only depends on the middle value of the sorted scores, so it says nothing about the total.

A team has 11 players, so the median is the 6th score in sorted order.
If 6 or more players score 0, that 6th score is 0 → median = 0.

Example: 0, 0, 0, 0, 0, 0, 12, 41, 96, 108, 131
Median = 6th value = 0
Runs off the bat = 0×6 + 12 + 41 + 96 + 108 + 131 = 388
Extras = 19
Team total = 388 + 19 = 407

Figure it Out — Pages 112 – 113Section 5.2 Representative Values

Math Talk
Q1Find the median of onion prices in Yahapur and Wahapur.
Answer

Yahapur: ₹37. Wahapur: ₹38.50.

Yahapur sorted: 24, 25, 26, 28, 30, 35, 39, 43, 44, 49, 56, 59
12 values, so average the 6th and the 7th
Median = (35 + 39) ÷ 2 = 74 ÷ 2 = ₹37

Wahapur sorted: 17, 19, 23, 30, 35, 38, 39, 42, 42, 52, 53, 60
Median = (38 + 39) ÷ 2 = 77 ÷ 2 = ₹38.50
Q2Sanskruti asked her class how many domestic animals and pets each had at home. Some of the students were absent. The data values are 0, 1, 0, 4, 8, 0, 0, 2, 1, 1, 5, 3, 4, 0, 0, —, 10, 25, 2, — , 2, 4. Find the mean and median. How would you describe this data?
Answer

Mean = 3.6 animals; Median = 2 animals. The two dashes are absent students, so they are left out: 20 values.

Sum = 0×6 + 1×3 + 2×3 + 3 + 4×3 + 5 + 8 + 10 + 25 = 72
Mean = 72 ÷ 20 = 3.6
Sorted: 0, 0, 0, 0, 0, 0, 1, 1, 1, 2, 2, 2, 3, 4, 4, 4, 5, 8, 10, 25
Median = (10th + 11th) ÷ 2 = (2 + 2) ÷ 2 = 2

Description: most students have 0 to 2 animals; 25 is an outlier, so the mean is pulled above the median. The median (2) describes a typical home better.

Q3Rintu takes care of a date-palm tree farm in Habra. The heights of the trees (in feet) in his farm are given as: 50, 45, 43, 52, 61, 63, 46, 55, 60, 55, 59, 56, 56, 49, 54, 65, 66, 51, 44, 58, 60, 54, 52, 57, 61, 62, 60, 60, 67. Fill the dot plot, and mark the mean and median. How would you describe the heights of these palm trees? Can you think of quicker ways to find the mean? How many trees are shorter than the average height?
05101520253035404550556065707580
Page 112 — the empty dot plot printed with this question, with its scale running from 0 to 80 feet.
Answer

Mean ≈ 55.9 feet, Median = 56 feet; 13 trees are shorter than the average.

40 45 50 55 60 65 Mean ≈ 55.9 Median = 56
The 29 heights (line drawn from 40 to 67 ft); mean solid, median dashed.
Sum of the 29 heights = 1621 ft → Mean = 1621 ÷ 29 ≈ 55.9 ft
Median = 15th of the 29 sorted heights = 56 ft
Shorter than 55.9 ft: 43, 44, 45, 46, 49, 50, 51, 52, 52, 54, 54, 55, 55 → 13 trees

Description: heights from 43 to 67 ft, mostly in the 50s and low 60s; no outlier, and mean ≈ median. Quicker way: add the differences from 55 ft (total +26), so mean = 55 + 26 ÷ 29 ≈ 55.9 ft.

Q4The daily water usage from a tap was measured. The usage in liters for the first few days are: 5.6, 8, 3.09, 12.9, 6.5, 12.1, 11.3, 20.5, 7.4.
(a) Can the mean or median daily usage lie between 25 and 30? Justify your claim using the meaning of mean and median.
(b) Can the mean or median be lesser than the minimum value or greater than the maximum value in a data?
Answer

(a) No. The largest reading is only 20.5 litres. The mean is a fair share of the total, so it cannot be more than the largest value; the median is a middle value of the sorted data, so it also lies between 3.09 and 20.5. (Here the mean ≈ 9.71 L and the median = 8 L.)

(b) No. The mean and the median always lie between the minimum and the maximum of the data (they can equal them, but never go outside).

Q5The weights of a few newborn babies are given in kgs. Fill the dot plot provided below. Analyse and compare this data.
Boys3.54.12.63.23.43.8
Girls4.03.13.43.72.53.4
00.511.522.533.544.5
Page 113 — the empty dot plot printed with this question, with its scale running from 0 to 4.5 kg.
Answer

Dot plot of the twelve weights (drawn here from 2 to 4.5 kg):

Boys Girls 2.0 2.5 3.0 3.5 4.0 4.5
Birth weights in kg (line drawn from 2 to 4.5 kg): boys above, girls below.
Boys: 2.6, 3.2, 3.4, 3.5, 3.8, 4.1
Sum = 20.6 kg, Mean = 20.6 ÷ 6 ≈ 3.43 kg
Median = (3.4 + 3.5) ÷ 2 = 3.45 kg

Girls: 2.5, 3.1, 3.4, 3.4, 3.7, 4.0
Sum = 20.1 kg, Mean = 20.1 ÷ 6 = 3.35 kg
Median = (3.4 + 3.4) ÷ 2 = 3.4 kg
BoysGirls
Lightest2.6 kg2.5 kg
Heaviest4.1 kg4.0 kg
Range1.5 kg1.5 kg
Mean3.43 kg3.35 kg
Median3.45 kg3.40 kg

Comparison: the two groups are very alike — the same range (1.5 kg), and means and medians that differ by less than 0.1 kg. These boys and girls weighed about the same at birth, roughly 3.4 kg.

Q6The dot plots of heights of another section of Grade 5 students of the same school are shown below. Can you share your observations? What can we infer from the dot plots and the central tendency measures? Compare the heights of the two sections. Share your observations.
125130135140145150155Whole classMean = 141.21Median = 142.5125130135140145150155BoysMean = 142.05Median = 143125130135140145150155GirlsMean = 140.14Median = 140
Section 2 dot plots of height in cm, page 113. The solid line marks the mean and the dashed line the median.
Answer
  • Girls’ heights are more spread out (about 126 to 158 cm) than boys’ (about 130 to 148 cm), so the tallest and the shortest students are both girls.
  • Most boys are bunched at 142–146 cm, so the boys are taller on average in this section (mean 142.05 cm against 140.14 cm).
  • Whole class and boys: mean < median, a small pull from a few short students; girls: mean ≈ median.
  • Compared with Section 1 (page 109), this section is shorter on average (mean 141.21 cm against 144.5 cm), and the result reverses — there the girls were taller, here the boys are.
Section 1 (page 109)Section 2Difference
Whole class mean144.5 cm141.21 cmSection 1 taller by ≈ 3.3 cm
Whole class median145 cm142.5 cmSection 1 taller by 2.5 cm
Boys’ mean142.94 cm142.05 cmAlmost the same
Girls’ mean146.9 cm140.14 cmSection 1 girls taller by ≈ 6.8 cm
Taller groupGirlsBoysReversed!
Widest spreadBoysGirlsReversed!
Q7The weights of some sumo wrestlers and ballet dancers are: Sumo wrestlers: 295.2 kg, 250.7 kg, 234.1 kg, 221.0 kg, 200.9 kg. Ballet dancers: 40.3 kg, 37.6 kg, 38.8 kg, 45.5 kg, 44.1 kg, 48.2 kg. Approximately how many times heavier is a sumo wrestler compared to a ballet dancer?
Answer

About 5.7 times — roughly 6 times heavier.

Sumo wrestlers (5 people):
295.2 + 250.7 + 234.1 + 221.0 + 200.9 = 1201.9 kg
Mean = 1201.9 ÷ 5 = 240.38 kg

Ballet dancers (6 people):
40.3 + 37.6 + 38.8 + 45.5 + 44.1 + 48.2 = 254.5 kg
Mean = 254.5 ÷ 6 ≈ 42.42 kg

How many times heavier = 240.38 ÷ 42.42 ≈ 5.67

In-text Questions — Pages 114 – 115Section 5.3 Visualising Data — Clubbing the Columns

Q1The two graphs can also be combined into a single graph. We just draw the bars side by side! Verify if the data in the table matches the graph below.
JanFebMarAprMayJunJulAugSepOctNovDec
Yahapur252426283035394349565944
Wahapur191723303835423953605242
0102030405060JanFebMarAprMayJunJulAugSepOctNovDecMonthly onion prices in Yahapur and WahapurPrice (in ₹)YahapurWahapur
The table of monthly onion prices and the clustered column graph drawn from it — pages 114–115.
Answer

Yes, it matches. Check the two bars of each cluster against the two rows of the table, month by month.

MonthJanFebMarAprMayJunJulAugSepOctNovDec
Yahapur (₹)252426283035394349565944
Wahapur (₹)191723303835423953605242
Taller barYYYWW=WYWWYY
Q2What is the scale used in this graph?
0102030405060JanFebMarAprMayJunJulAugSepOctNovDecMonthly onion prices in Yahapur and WahapurPrice (in ₹)YahapurWahapur
The clustered column graph on page 115.
Answer

1 unit length = ₹10 per kg. The vertical line is marked 0, 10, 20, 30, 40, 50, 60.

Gridlines at 0, 10, 20, 30, 40, 50, 60
Gap between two gridlines = ₹10
Highest gridline needed = 60, because the largest price is ₹60 (Wahapur, October)
Q3Is it now easier to compare month-wise prices in both places?
Answer

Yes — much easier. The two bars for each month stand side by side, so we see at once which town was dearer that month and roughly by how much (for example, May: Wahapur dearer by ₹8; June: equal).

In-text Questions — Pages 116 – 11810…9…8…7…6…5…4…3…2…1…Take Off!

Q1Look at the graph below showing the number of worldwide rocket launches by different organisations. Share your observations (you may take the teacher’s help to identify the countries these organisations belong to).
Number of worldwide rocket launches by companies/space agencies020406080100SpaceXCASCRoscosmosArianespaceRocket LabUnited Launch AllianceISROGalactic EnergyExpaceOther202120222023
Worldwide rocket launches by organisation for 2021, 2022 and 2023 — page 116.
Answer

Observations: SpaceX (USA) launched by far the most rockets, and its launches grew fast (about 31 → 61 → 96). CASC (China) comes second. Roscosmos (Russia), Arianespace (France), Rocket Lab and United Launch Alliance (USA), ISRO (India), Galactic Energy and Expace (China) launched far fewer. ISRO’s launches rose every year; Arianespace’s fell every year.

OrganisationCountry202120222023
SpaceXUSA≈ 31≈ 61≈ 96
CASCChina≈ 48≈ 35≈ 45
RoscosmosRussia≈ 16≈ 21≈ 18
ArianespaceFrance≈ 15≈ 6≈ 3
Rocket LabUSA≈ 6≈ 6≈ 9
United Launch AllianceUSA≈ 5≈ 8≈ 3
ISROIndia≈ 2≈ 5≈ 7
Galactic EnergyChina≈ 1≈ 2≈ 7
ExpaceChina≈ 4≈ 4≈ 6
Othermany≈ 18≈ 17≈ 26
Q2Step 1: Identify what is given. Notice how the graph is organised, what scale is used, and what patterns the data shows.
Number of worldwide rocket launches by companies/space agencies020406080100SpaceXCASCRoscosmosArianespaceRocket LabUnited Launch AllianceISROGalactic EnergyExpaceOther202120222023
Worldwide rocket launches by organisation for 2021, 2022 and 2023 — page 116.
Answer

Organisation: each organisation has three adjacent bars, for 2021, 2022 and 2023. Scale: 1 unit length = 20 rockets (marks 0, 20, 40, 60, 80, 100). Patterns: SpaceX increases year on year (its 2022 bar is almost double its 2021 bar); Arianespace decreases year on year (2023 about half of 2022); United Launch Alliance increases, then decreases. ‘Others’ groups many small organisations.

Q3Step 2: Infer from what is given. Analyse and interpret each of your observations.
Number of worldwide rocket launches by companies/space agencies020406080100SpaceXCASCRoscosmosArianespaceRocket LabUnited Launch AllianceISROGalactic EnergyExpaceOther202120222023
Page 116 — the graph of worldwide rocket launches by different organisations in 2021, 2022 and 2023.
Answer
  • The USA, China and Russia are the leading rocket-launching countries.
  • SpaceX launched about twice as many rockets in 2022 as in 2021, and about 35 more in 2023 than in 2022.
  • Arianespace’s launches fell every year.
  • United Launch Alliance launched more in 2022 than in 2021, but fewer in 2023 than in either year.
  • Other organisations launched about 25 rockets in 2023.
Q4Identify which of the following statements can be justified using this data.
(a) All organisations launched more rockets than the previous years.
(b) Only an organisation from the USA launched more than 50 rockets in a single year.
(c) The total number of rockets launched by France in all 3 years is less than 40.
(d) The average number of rockets launched by CASC in these 3 years is around 40.
(e) ISRO launched more rockets than Galactic Energy in these 3 years.
(f) Russia launched more than 60 rockets in these 3 years.
Answer

Justified: (b), (c), (d) and (e). Not justified: (a) and (f).

StatementJustified?The evidence in the graph
(a) All organisations increased every yearNoArianespace fell every year; CASC fell in 2022; United Launch Alliance and Roscosmos fell in 2023. One counter-example is enough to break a claim that says all.
(b) Only a USA organisation crossed 50 in one yearYesSpaceX (USA) passed 50 twice — about 61 in 2022 and about 96 in 2023. The next longest bar anywhere is CASC’s 2021 bar at about 48, which does not reach the halfway point between the 40 and 60 marks.
(c) France’s total over 3 years is less than 40YesFrance’s only entry is Arianespace: about 15 + 6 + 3 = 24, comfortably under 40.
(d) CASC averages around 40YesAbout 48 + 35 + 45 = 128, and 128 ÷ 3 ≈ 42.7 — which is “around 40”.
(e) ISRO launched more than Galactic EnergyYesISRO ≈ 2 + 5 + 7 = 14; Galactic Energy ≈ 1 + 2 + 7 = 10. Their 2023 bars are nearly equal, but ISRO’s 2021 and 2022 bars are clearly longer.
(f) Russia launched more than 60 in 3 yearsNoRussia’s only entry is Roscosmos: about 16 + 21 + 18 = 55, which is below 60.
Q5List the organisations that have consistently launched more rockets every year.
Answer

Reading the three bars of each cluster from dark to light, the ones that get longer every single time are:

  • SpaceX — about 31 → 61 → 96
  • ISRO — about 2 → 5 → 7
  • Galactic Energy — about 1 → 2 → 7
Q6Estimate the total number of rockets launched worldwide in 2023.
(a) less than 200
(b) 200 to 400
(c) 400 to 600
(d) more than 600
Answer

(b) 200 to 400. Adding the ten 2023 bars (the lightest ones) gives roughly 220.

SpaceX ≈ 96
CASC ≈ 45
Roscosmos ≈ 18
Arianespace ≈ 3
Rocket Lab ≈ 9
United Launch Alliance ≈ 3
ISRO ≈ 7
Galactic Energy ≈ 7
Expace ≈ 6
Other ≈ 26
Total ≈ 220
Q7What are you curious to know after looking at this graph?
Number of worldwide rocket launches by companies/space agencies020406080100SpaceXCASCRoscosmosArianespaceRocket LabUnited Launch AllianceISROGalactic EnergyExpaceOther202120222023
Worldwide rocket launches by organisation for 2021, 2022 and 2023 — page 116.
Answer

Why does the USA launch so many more rockets than other countries? What were the numbers before 2021 and after 2023? Which organisations are inside ‘Others’? How many of these launches were successful?

Math Talk — Pages 118 – 121Summer and Winter at the Same Time

Math Talk
Q1The tables below show data related to weather in two cities in different countries. The numbers given are in hours. Can you guess what the data might be related to?

City 1

JanFebMarAprMayJunJulAugSepOctNovDec
210257372441536564555465394310222186

City 2

JanFebMarAprMayJunJulAugSepOctNovDec
459384381327304276295318369409435468
The two tables printed on page 118. Every number is in hours.
Answer

The data is the number of hours of daylight in each month (hours when the Sun is at least partly above the horizon).

Reason: dividing by the number of days gives a sensible number of hours per day (City 1: 564 ÷ 30 ≈ 18.8 h in June, 186 ÷ 31 = 6 h in December), and the two cities change in opposite directions through the year.

Q2Does this give some idea of where these two cities are located?
Answer

Yes. City 1 has its longest days in June, so it is in the Northern Hemisphere; City 2 has its shortest days in June, so it is in the Southern Hemisphere. The large change in day length through the year shows that both are far from the Equator. (City 1 is Helsinki, Finland; City 2 is Wellington, New Zealand.)

Q3Is there anything more that you wish to explore?
Answer

How long are the days in my own town in each month? What happens at the Equator, and near the poles, where the Sun can be seen at midnight in summer? Does longer daylight always mean hotter weather?

In-text Questions — Page 122All it Takes is a Minute

Q1Answer the following questions based on the graph: Can we tell who batted first? Who won the match?
0510151234567891011121314151617181920Runs per overOvers
Runs scored in each over by the two teams, page 122. A circle above a bar marks an over in which a wicket fell.
Answer

Yes, it can be worked out: the blue team batted first, and the blue team won by 11 runs.

First read the bars, over by over. The scale is 1 unit = 5 runs.

Over1234567891011121314151617181920
Blue2118796349861569410913177
Red108421183610995161197717——
Blue total = 2+11+8+7+9+6+3+4+9+8+6+15+6+9+4+10+9+13+17+7 = 163 runs in 20 overs
Red total = 10+8+4+2+11+8+3+6+10+9+9+5+16+11+9+7+7+17 = 152 runs in 18 overs

The blue team had 156 runs after 19 overs — already more than the red team’s 152 — yet it still batted the 20th over, so it was not chasing: blue batted first. The red team batted second, and its innings stopped after 18 overs.

Q2How many runs did the blue team score in over 12?
Answer

15 runs.

Scale: 1 unit length = 5 runs, so the gridlines are at 0, 5, 10 and 15
In over 12 the blue bar reaches exactly the third gridline
Runs = 3 × 5 = 15
Q3In which over did the red team score the least number of runs?
Answer

Over 4, with 2 runs — the shortest red bar in the whole graph.

Red team’s smallest bars:
Over 4 → 2 runs (shortest)
Over 7 → 3 runs
Over 3 → 4 runs
Over 12 → 5 runs
Q4Is it easy to tell the target set by the team batting first?
Answer

No, not easily. The graph shows the runs in each over, not the running total. To find the target we must read all 20 blue bars and add them: 163 runs, so the target was 164.

Figure it Out — Pages 122 – 125Section 5.3 Visualising Data

Math Talk
Q1The following infographic shows the speeds of a few animals in air, on land, and in water. Can we call this graph a bar graph?
(a) What is the scale used in this graph?
(b) What did you find interesting in this infographic? What do you want to explore further?
(c) Identify a pair of creatures where one’s speed is about twice that of the other.
(d) Can we say that a sailfish is about 4 times faster than a humpback whale? Can we say that a sailfish is the fastest aquatic animal in the world?
01664112161209257322Peregrine falcon322 kphSpine-tailed swift170 kphFree-tailed bat96 kphGreen darner dragonfly64 kphFlying fish56 kphCheetah103 kphPronghorn antelope88 kphOstrich64 kphHuman37 kphAustralian tiger beetle8 kphSailfish109 kphDolphin40 kphCalifornia sea lion40 kphGentoo penguin35 kphspeed in airspeed on landspeed in waterMaximum speed of animals in air, on land and in water (kph)
The speeds infographic on page 123, redrawn with the speeds printed in the book.
Answer

Yes. Each animal has one bar whose length shows its top speed, all on the same scale.

(a) 1 unit length = 16 kilometres per hour (marks 0, 16, 32, 48, … up to 322 kph).

(b) Sample answer: the fastest animal is a bird, the peregrine falcon (322 kph). I would like to explore which animals are fastest for their body size.

(c) Sailfish (109 kph) and flying fish (56 kph): 109 ÷ 56 ≈ 2. (Also: peregrine falcon 322 kph and spine-tailed swift 170 kph.)

(d) No, to both. The humpback whale is not in this infographic, so the first claim cannot be checked. The graph shows only four water animals, so it tells us only that the sailfish is the fastest of these four.

Q2Preyashi asked her students ‘If you were to get a super power to become aquatic (water-borne), aerial (air-borne), or spaceborne which one would you choose?’. The responses are shown below. Some chose none. Draw a double-bar graph comparing how both grades chose each option. Choose an appropriate scale.
Grade 5w, a, a, a, w, n, s, a, n, w, a, a, a, a, a, w, w, s, a, a, n, w, a, a, n
Grade 9n, w, s, a, s, w, s, s, a, a, w, s, s, a, s, a, n, w, s, s, a, w, a, w, a
The responses of the two classes, page 124 — w = water-borne, a = air-borne, s = spaceborne, n = none.
Answer

First count each letter. Both grades have 25 students, so the two sets of bars can be compared directly.

ChoiceGrade 5Grade 9
Aquatic (w)66
Aerial (a)138
Spaceborne (s)29
None (n)42
Total2525

Scale: 1 unit length = 2 students (the largest count is 13, so the vertical line goes up to 14).

024 6810 1214 AquaticAerial SpaceNone Grade 5 Grade 9
Double-bar graph of the super-power survey. Scale: 1 unit = 2 students.

Observation: most Grade 5 students chose aerial (13 of 25); Grade 9 students chose spaceborne most (9, against only 2 in Grade 5). Both grades had 6 students choosing aquatic.

Q3The temperature variation over two days in different months in Jodhpur, Rajasthan, is given below. Draw a double-bar graph. Use the scale 1 unit = 4°C. Can you guess which two months these days might belong to?
 12 am3 am6 am9 am12 pm3 pm6 pm9 pm
Day 120°C18°C16°C20°C26°C34°C30°C24°C
Day 237°C34°C30°C33°C37°C43°C42°C39°C
Answer

With the scale 1 unit = 4°C, the vertical line is marked 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44. The highest reading is 43°C, so 44 is the top gridline.

0816 243240 12am3am6am9am 12pm3pm6pm9pm Day 1 Day 2
Temperature in Jodhpur through two days, read every three hours. Scale: 1 unit = 4°C.

Months: Day 2 (30°C to 43°C) is a peak-summer day — May or June. Day 1 (16°C to 34°C) is a milder day — about February–March or October–November.

Q4The following clustered-bar graph shows the number of electric vehicles registered in some states every year from 2022 to 2024.
(a) The data (rounded-off to thousands) for the states of Gujarat and Delhi are given in the table below. Mark the corresponding bars on the bar graph.
(b) Notice how the graph is organised, what scale is used, and what patterns the data shows.
(c) How would you describe the change for various states between 2022 and 2024?
(d) Approximately how many more registrations did Assam get in 2023 compared to 2022?
(e) How many times more did the registrations in West Bengal increase from 2022 to 2024?
(f) Is this statement correct — ‘There were very few new registrations in Uttarakhand in 2023 and 2024, as the increase in the bar lengths is minimal’?
0250005000075000100000UttarakhandWest BengalAndhraPradeshOdishaAssamGujaratDelhiNumber of Electric Vehicles Registered Per Year202220232024
202220232024
Gujarat690008900078000
Delhi620007400081000
The clustered-bar graph on page 124, and the Gujarat and Delhi figures given with the question. The last two positions on the graph are left empty for you to mark.
Answer
State202220232024
Uttarakhand≈ 15,000≈ 16,000≈ 19,000
West Bengal≈ 10,000≈ 21,000≈ 43,000
Andhra Pradesh≈ 29,000≈ 34,000≈ 55,000
Odisha≈ 27,000≈ 44,000≈ 62,000
Assam≈ 40,000≈ 60,000≈ 64,000
Gujarat (given)69,00089,00078,000
Delhi (given)62,00074,00081,000

(a) Draw the Gujarat and Delhi bars to the heights in the table (for example, Gujarat 2023 just below the 90,000 line — the tallest bar of all).

(b) Three bars per state (2022, 2023, 2024); labels every 25,000, guidelines every 5,000.

(c) Every state registered more in 2024 than in 2022; West Bengal grew fastest (more than 4 times); Gujarat fell in 2024.

(d) About 60,000 − 40,000 = 20,000 more. (e) About 43,000 ÷ 10,000 ≈ 4 times.

(f) No. Each bar shows that year’s new registrations — about 16,000 in 2023 and 19,000 in 2024 in Uttarakhand — which is not “very few”. The small change in bar length only shows that the yearly number grew slowly.

Math Talk — Pages 125 – 126Section 5.4 Data Detective — Telling Tall Tales

Math Talk
Q1Following are the dot plots of heights of boys (in blue) and girls (in orange) of Grades 6, 7 and 8 (in that order) of two different schools. What do you notice? Share your observations.
Figure
The twelve dot plots printed in the book, redrawn from the dots: School A (circles) on the left, School B (diamonds) on the right; in each grade the boys (blue) are above the girls (orange). The solid line in each plot marks the mean.
Answer
  • School B’s students are much taller than School A’s in every grade (Grade 6 boys: 149.84 cm against 134.8 cm — about 15 cm more).
  • Heights increase from Grade 6 to Grade 8 in both schools.
  • Boys and girls of the same grade have almost the same mean height; sometimes the girls are a little taller, sometimes the boys.
  • The dots in each plot are spread over about 20 cm, so many girls are taller than many boys.
GradeSchool A boysSchool A girlsSchool B boysSchool B girlsB − A (boys)
Grade 6134.80137.78149.84150.20+15.0 cm
Grade 7141.80141.83156.14155.41+14.3 cm
Grade 8149.35147.81156.14156.83+6.8 cm

Math Talk — Pages 127 – 128Telling Tall Tales — heights in India, 1989 to 2019

Math Talk
Q1Spend sufficient time observing the data presented in this table. Share your findings with the class. These are some prompts for you to probe —
• Changes in the heights of boys or girls of a certain age from 1989 to 2019.
• The heights of boys vs. girls at different ages in a particular year.
• Changes in height between successive ages in boys and girls in 2019.
Age1989199920092019
BoysGirlsBoysGirlsBoysGirlsBoysGirls
5101.3100102.4101.7105.1104107.1107.2
6107.5106108.7107.5111109.7113.1112.9
7113111.4114.2112.6116.2114.8118.6118
8118.1116.5119.2117.5120.9119.6123.5122.7
9122.9121.7123.9122.4125.2124.5128.1127.6
10127.5127.3128.3127.8129.4129.9132.6132.8
11132.2133.4132.8133.6133.7135.7137138.6
12137.7139138139.1138.9141.1142.2143.8
13144.2143.2144.3143.1145.2145.1148.4147.7
14150.6146.2150.5146.1151.5148154.4150.4
15155.4148.5155.2148.4156.3150.1159152.4
16158.9150.1158.7150.1159.9151.6162.3153.8
17161.3151.2161.4151.3162.6152.6164.6154.7
18162.9151.8163.2152.1164.3153166155.2
19163.5151.9164.2152.4165.1153166.5155.2
Average heights, in cm, of boys and girls at each age in 1989, 1999, 2009 and 2019 — page 127.
Answer

Sample findings:

  • At every age, both boys and girls were taller in 2019 than in 1989 (5-year-olds by about 6 to 7 cm).
  • Boys are a little taller at ages 5 to 9; girls are taller at ages 11 and 12; from 13 onwards boys are taller (by 11.3 cm at age 19 in 2019).
  • In 2019 girls grew fastest between ages 10 and 11, boys between 12 and 13; by 18–19 growth has almost stopped.
Q2Which of the following statements can be justified using the data?
1. The average heights of both boys and girls at every age increased from 1989 to 2019.
2. The average height of 13-year-old girls in 1989 is more than the average height of 14-year-old girls in 2009.
3. The average height of 15-year-old boys in 2019 is more than the average height of 16-year-old boys in 1989.
4. All girls aged 13 are taller than all girls aged 11.
5. Throughout the age period 5 to 19, the average boy’s height is more than the average girl’s height.
6. Boys keep growing even beyond age 19.
Answer

Can be justified: 1 and 3. Cannot be justified: 2, 4, 5 and 6.

StatementJustified?The evidence
1. Every age increased, 1989 → 2019YesCompare the 1989 and 2019 columns row by row. Every one of the 15 ages is higher in 2019, for boys and for girls.
2. 13-year-old girls in 1989 > 14-year-old girls in 2009No1989, age 13 girls = 143.2 cm. 2009, age 14 girls = 148.0 cm. So 143.2 < 148.0 — the statement is the wrong way round.
3. 15-year-old boys in 2019 > 16-year-old boys in 1989Yes2019, age 15 boys = 159.0 cm. 1989, age 16 boys = 158.9 cm. True — but by only 0.1 cm.
4. All girls aged 13 are taller than all girls aged 11NoThe table gives averages only. It contains nothing at all about individual girls, so it can neither prove nor disprove a claim about every girl.
5. Boys taller than girls throughout ages 5 to 19NoAt ages 11 and 12, girls are taller in all four years. In 2019, age 11: girls 138.6 vs boys 137.0; age 12: girls 143.8 vs boys 142.2. Girls are also taller at age 10 in 2009 and 2019.
6. Boys keep growing beyond age 19NoThe table stops at 19, so it holds no evidence either way. What it does show is that growth is nearly over: boys gain only 0.5 cm from 18 to 19 in 2019.
Q3In 2019, between which two successive ages from 5 to 19 did boys grow the most? Between which two successive ages from 5 to 19 did girls grow most?
Answer

Boys grew most between ages 12 and 13 (+6.2 cm). Girls grew most between ages 10 and 11 (+5.8 cm).

Boys 2019, biggest steps:
12 → 13: 148.4 − 142.2 = 6.2 cm  (largest)
5 → 6: 113.1 − 107.1 = 6.0 cm
13 → 14: 154.4 − 148.4 = 6.0 cm

Girls 2019, biggest steps:
10 → 11: 138.6 − 132.8 = 5.8 cm  (largest)
5 → 6: 112.9 − 107.2 = 5.7 cm
9 → 10: 132.8 − 127.6 = 5.2 cm
11 → 12: 143.8 − 138.6 = 5.2 cm
Q4Suppose the average height of a newborn is 50 cm. Estimate the average height of young children of ages 1 to 4.
Answer

Sample estimate: growth is fastest in the first year and then slows down, so heights of about 75 cm at age 1, 87 cm at age 2, 95 cm at age 3 and 101 cm at age 4 (from 50 cm at birth to about 107 cm at age 5 in 2019).

AgeBirth12345
Even-share estimate5061738496107
Slowing-growth estimate50≈ 75≈ 87≈ 95≈ 101107
Growth that year (cm)—2512866
Q5Based on the trend observed in the table, write your estimates of the heights of boys and girls for ages 5 to 19 in the year 2029.
Age1989199920092019
BoysGirlsBoysGirlsBoysGirlsBoysGirls
5101.3100102.4101.7105.1104107.1107.2
6107.5106108.7107.5111109.7113.1112.9
7113111.4114.2112.6116.2114.8118.6118
8118.1116.5119.2117.5120.9119.6123.5122.7
9122.9121.7123.9122.4125.2124.5128.1127.6
10127.5127.3128.3127.8129.4129.9132.6132.8
11132.2133.4132.8133.6133.7135.7137138.6
12137.7139138139.1138.9141.1142.2143.8
13144.2143.2144.3143.1145.2145.1148.4147.7
14150.6146.2150.5146.1151.5148154.4150.4
15155.4148.5155.2148.4156.3150.1159152.4
16158.9150.1158.7150.1159.9151.6162.3153.8
17161.3151.2161.4151.3162.6152.6164.6154.7
18162.9151.8163.2152.1164.3153166155.2
19163.5151.9164.2152.4165.1153166.5155.2
Average heights, in cm, of boys and girls at each age in 1989, 1999, 2009 and 2019 — page 127.
Answer

Look first at how much each age gained in the most recent ten years, 2009 → 2019, and then add a similar amount again.

AgeBoys 2009Boys 2019GainEstimate 2029
5105.1107.1+2.0≈ 109
8120.9123.5+2.6≈ 126
11133.7137.0+3.3≈ 140
14151.5154.4+2.9≈ 157
17162.6164.6+2.0≈ 167
19165.1166.5+1.4≈ 168
AgeGirls 2009Girls 2019GainEstimate 2029
5104.0107.2+3.2≈ 110
8119.6122.7+3.1≈ 126
11135.7138.6+2.9≈ 141
14148.0150.4+2.4≈ 153
17152.6154.7+2.1≈ 157
19153.0155.2+2.2≈ 157

The rule of thumb: add about 2 to 3 cm to each 2019 value — a little more at the younger ages, a little less at 18 and 19.

Q6How is the graph organised? What information is presented?
145155165175185Timor-LesteYemenBangladeshLiberiaIndonesiaIndiaBhutanPakistanMaldivesKenyaSaudi ArabiaJapanSudanTaiwanItalyEgyptSouth KoreaChinaIsraelTurkeyLibyaNew ZealandU.K.AustraliaNorwayUkraineIcelandNetherlandsB-1989B-2019G-1989G-2019Height (in cm)
Average heights of 19-year-old boys and girls in 28 countries in 1989 and 2019 — page 128. Values read off the printed graph.
Answer

The countries are placed along the horizontal line, roughly from the shortest to the tallest. The vertical line shows height in cm and starts at 145 cm (zoomed in). Each country has four marks — × for boys, ▲ for girls; orange for 1989, blue for 2019. Every mark is the average height of 19-year-olds.

MarkMeaning
Orange ×Boys in 1989 (B-1989)
Blue ×Boys in 2019 (B-2019)
Orange ▲Girls in 1989 (G-1989)
Blue ▲Girls in 2019 (G-2019)
Q7What do you find interesting?
Answer
  • Heights differ a lot between countries — 19-year-old boys average about 184 cm in the Netherlands but only about 160 cm in Timor-Leste.
  • In every country the boys are taller than the girls on average.
  • Most countries became taller from 1989 to 2019; China and South Korea gained the most, while a few, such as Pakistan, hardly changed.
  • India is in the lower part of the chart (boys about 166.5 cm, girls about 155 cm in 2019).

Figure it Out — Pages 129 – 133Section 5.4 Data Detective

Try This
Q1The dot plots below show the distribution of the number of pockets on clothing for a group of boys and for a group of girls. Based on the dot plots, which of the following statements are true?
(a) The data varies more for the boys than for the girls.
(b) The median number of pockets for the boys is more than that for the girls.
(c) The mean number of pockets for the girls is more than that for the boys.
(d) The maximum number of pockets for boys is greater than that for the girls.
01234567BoysNumber of Pockets01234567GirlsNumber of Pockets
Page 129 — the two dot plots: the number of pockets on clothing for a group of boys and for a group of girls.
Answer

Only (b) is true.

Number of pockets01234567Total
Boys (dots)0001452012
Girls (dots)1014511013
Boys: mean = 56 ÷ 12 ≈ 4.67, median = 5, range = 6 − 3 = 3
Girls: mean = 45 ÷ 13 ≈ 3.46, median = 4, range = 6 − 0 = 6
StatementTrue?Why
(a) Data varies more for boysFalseBoys run only from 3 to 6 (range 3). Girls run from 0 to 6 (range 6). The girls vary more.
(b) Boys’ median > girls’ medianTrue5 > 4.
(c) Girls’ mean > boys’ meanFalse3.46 < 4.67. It is the other way round.
(d) Boys’ maximum > girls’ maximumFalseBoth groups have a maximum of 6 pockets. Equal is not “greater than”.
Q2The following table shows the points scored by each player in four games: A — 14, 16, 10, 10; B — 0, 8, 6, 4; C — 8, 11, Did not play, 13. Now answer the following questions:
(a) Find the average number of points scored per game by A.
(b) To find the mean number of points scored per game by C, would you divide the total points by 3 or by 4? Why? What about B?
(c) Who is the best performer?
PlayerGame 1Game 2Game 3Game 4
A14161010
B0864
C811Did not play13
The points table on page 129.
Answer

(a) (14 + 16 + 10 + 10) ÷ 4 = 50 ÷ 4 = 12.5 points per game.

(b) For C, divide by 3: C did not play Game 3, so that game has no value. For B, divide by 4: B played all 4 games, and 0 is a real score. (C: 32 ÷ 3 ≈ 10.67; B: 18 ÷ 4 = 4.5.)

(c) A is the best performer — highest mean (12.5), highest total (50), and never below 10 points.

PlayerGamesTotalMean per gameBestWorst
A45012.51610
B4184.580
C33210.67138
Q3The marks (out of 100) obtained by a group of students in a General Knowledge quiz are 85, 76, 90, 85, 39, 48, 56, 95, 81 and 75. Another group’s scores in the same quiz are 68, 59, 73, 86, 47, 79, 90, 93 and 86. Compare and describe both the groups performance using, mean and median.
Answer

Group 2 did slightly better on both measures, and Group 1’s marks are far more spread out.

Group 1 (10 students): 85, 76, 90, 85, 39, 48, 56, 95, 81, 75
Total = 730   Mean = 730 ÷ 10 = 73
Sorted: 39, 48, 56, 75, 76, 81, 85, 85, 90, 95
Median = (76 + 81) ÷ 2 = 78.5

Group 2 (9 students): 68, 59, 73, 86, 47, 79, 90, 93, 86
Total = 681   Mean = 681 ÷ 9 ≈ 75.67
Sorted: 47, 59, 68, 73, 79, 86, 86, 90, 93
Median = 5th value = 79
Group 1Group 2
Number of students109
Mean7375.67
Median78.579
Lowest mark3947
Highest mark9593
Range5646
Q4Consider this data collected from a survey of a colony.
Favourite SportCricketBasket BallSwimmingHockeyAthletics
Watching1240470510430250
Participating620320320250105
Choose an appropriate scale and draw a double-bar graph. Write down your observations.
Answer

The largest value is 1240, so take 1 unit length = 200 people and run the vertical line to 1400.

0200400 6008001000 12001400 CricketBasketballSwimming HockeyAthletics Watching Participating
Favourite sports in the colony. Scale: 1 unit = 200 people.

Observations: in every sport more people watch than take part; cricket is the most popular for both watching (1240) and participating (620); athletics is the least popular for both.

Q5Consider a group of 17 students with the following heights (in cm): 106, 110, 123, 125, 117, 120, 112, 115, 110, 120, 115, 102, 115, 115, 109, 115, 101. The sports teacher wants to divide the class into two groups so that each group has an equal number of students: one group has students with height less than a particular height and the other group has students with heights greater than the particular height. Suggest a way to do this. Can you guess the age of these students based on the tabular data in the ‘Telling Tall Tales’ section?
Answer

Use the median height, 115 cm, as the dividing height. Since 17 is odd and five students are exactly 115 cm tall, the groups can only be as equal as 9 and 8: put the students below 115 cm with two of the 115 cm students, and the rest in the other group.

Sorted heights (17 students):
101, 102, 106, 109, 110, 110, 112, 115, 115, 115, 115, 115, 117, 120, 120, 123, 125
Median = 9th value = 115 cm

Age: the mean (≈ 113.5 cm) and median (115 cm) are close to the 2019 average height at age 6 (about 113 cm), so these students are probably about 6 to 7 years old.

Q6Describe the mean and median of heights of your class. You can visualise the heights on a dot plot.
Answer

Method: measure every student’s height, find the mean (sum ÷ number of students) and the median (middle of the sorted heights), and draw a dot plot.

Sample answer for a Grade 7 class of 20 students:

Heights (cm): 138, 141, 142, 144, 145, 145, 146, 147, 148, 148,
149, 150, 150, 151, 152, 152, 154, 156, 158, 164

Sum = 2980 cm   Mean = 2980 ÷ 20 = 149 cm
Median = (10th + 11th) ÷ 2 = (148 + 149) ÷ 2 = 148.5 cm

The heights run from 138 cm to 164 cm; the mean (149 cm) and median (148.5 cm) are close, so the data is fairly balanced.

Q7There are two 7th grade sections at a school. Each section has 15 boys and 15 girls. In one section, the mean height of students is 154.2 cm. From this information, what must be true about the mean height of students in the other section?
(a) The mean height of students in the other section is 154.2 cm.
(b) The mean height of students in the other section is less than 154.2 cm.
(c) The mean height of students in the other section is more than 154.2 cm.
(d) The mean height of students in the other section cannot be determined.
Answer

(d) The mean height of students in the other section cannot be determined.

Q8Standing tall in the storm. [Infographic: Cities with Most Skyscrapers (buildings taller than 150 m) — Hong Kong 553, Shenzhen 367, New York —, Dubai 251, Guangzhou 188, Shanghai 183, Tokyo —, Kuala Lumpur 154, Chongqing 144, Jakarta 112, Bangkok 110, Singapore 95, Mumbai 86, Seoul 82, Toronto 81, Melbourne 69, Miami 58, Istanbul 48, Moscow 46, London —]
(a) Write estimated values for the number of skyscrapers in New York, Tokyo, and London.
(b) Are the following statements valid?
(i) Only 12 cities have more skyscrapers than Mumbai.
(ii) Only 7 cities have fewer skyscrapers than Mumbai.
(iii) The tallest building in the world is in Hong Kong.
Answer

(a) New York ≈ 315, Tokyo ≈ 165, London ≈ 30 (estimated from the bar lengths).

(b) (i) Valid — 12 cities are above Mumbai on the chart. (ii) Not valid — 7 cities on this chart have fewer, but the chart shows only the top 20 cities; every other city in the world also has fewer. (iii) Not valid — the chart counts how many tall buildings a city has, not how tall any one building is.

Q9Estimate and then measure the objects listed in the following table. Draw a double bar graph based on the data. How accurate were your estimates? Find the average difference between the estimated and measured values.
ObjectEstimate (in cm)Measure (in cm)Positive Difference
Length of a pen
Length of an eraser
Length of your palm
Length of your geometry box
Length of your math notebook
The table to fill in — page 132.
Answer

Estimate all five lengths first, then measure them, and find each positive difference (larger − smaller).

ObjectEstimate (cm)Measure (cm)Positive difference
Length of a pen15141
Length of an eraser451
Length of your palm10177
Length of your geometry box18202
Length of your math notebook25294
Average difference = (1 + 1 + 7 + 2 + 4) ÷ 5
= 15 ÷ 5
= 3 cm

Double bar graph: for each object draw two bars side by side — the estimate and the measurement — with a scale such as 1 unit = 5 cm.

Q10Aditi likes solving puzzles. She recently started attempting the ‘Easy’ level Sudoku puzzles. The time she took (in seconds) to solve these puzzles are — 410, 400, 370, 340, 360, 400, 320, 330, 310, 320, 290, 380, 280, 270, 230, 220, 240. The first nine values correspond to Week 1 and the rest to Week 2.
(a) Construct a dot plot below showing the data for both weeks.
(b) Describe the mean, median, and any observations you may have about the data.
200220240260280300320340360380400Week 1Week 2
Page 132 — the empty dot plot printed with this question, with its scale running from 200 to 400 seconds.
Answer
Week 1 (9 puzzles)410400370340360400320330310
Week 2 (8 puzzles)320290380280270230220240
200 220 240 260 280 300 320 340 360 380 400 Week 1 Week 2
Week 1 (triangles) and Week 2 (circles), in seconds.
Week 1: mean = 3240 ÷ 9 = 360 s; sorted 310, 320, 330, 340, 360, 370, 400, 400, 410 → median = 360 s
Week 2: mean = 2230 ÷ 8 ≈ 278.75 s; sorted 220, 230, 240, 270, 280, 290, 320, 380 → median = (270 + 280) ÷ 2 = 275 s

Observations: Aditi became much faster in Week 2 (her mean dropped by about 81 s). In Week 2 the 380 s puzzle is an outlier, so the mean is a little above the median.

Q11Individual Project: Pick at least one of the following:
(a) How Long is a Sentence? Pick any two textbooks from different subjects. Choose any page with a lot of text from each book.
(i) Use a dot plot to describe how many words the sentences have on each page.
(ii) Compare the data of both the pages using mean and median.
(b) What is in a Name? Write down the names of all of your classmates.
(i) Find the mean and median name length (number of letters in a name).
(ii) Visualise the data and describe its variability and central tendency.
(iii) Which starting letters are more popular? Which are less popular?
(iv) What is the median starting letter? What does this say about the number of names starting with the letters A – M and N – Z?
(v) Plot a double-bar graph showing the number of boys’ names and girls’ names that:
• start and end with vowels,
• start with vowels and end with consonants,
• start with consonants and end with vowels,
• start and end with consonants.
Answer

Sample answer (part b, 12 classmates): name lengths 5, 4, 6, 5, 5, 5, 6, 5, 6, 5, 5, 6 letters → mean = 63 ÷ 12 = 5.25 letters, median = 5 letters; the lengths vary only from 4 to 6. The sorted initials A, A, D, I, K, M, N, P, R, S, T, V have their median between M and N, so about half the names start with A–M and half with N–Z.

(v) The double-bar graph. Sort every name into one of four boxes and count boys and girls separately.

PatternExampleBoysGirls
Vowel start, vowel endAnaya01
Vowel start, consonant endAarav, Ishaan20
Consonant start, vowel endDiya, Meera, Kavya, Priya, Tanvi05
Consonant start, consonant endRohan, Sanjay, Vikram, Nikhil40
Q12Individual project (long term): This requires collecting data over 2 weeks or more. In and Out: Track how many times you step out of your house in a day. Do this for a month.
(i) Describe the variability and central tendency of this data. Make a dot plot.
(ii) Do you find anything interesting about this data? Share your observations.
(iii) You can ask any of your family members or friends to do this as well.
Answer

(30 days): 2, 3, 2, 4, 5, 6, 1, 2, 3, 3, 2, 5, 7, 1, 2, 3, 2, 4, 5, 6, 0, 2, 3, 3, 2, 4, 6, 1, 2, 3.
Mean = 94 ÷ 30 ≈ 3.13 times a day; median = 3; range = 7 − 0 = 7. The dot plot runs from 0 to 7 with the tallest stack at 2; mean ≈ median, so the data is balanced.

Q13Small-group project: Pick at least one of the following. Make groups of 8 to 10. Collect data individually as needed. Put together everyone’s data and do the appropriate analysis and visualisation.
(a) Our heights vs. our family’s heights: Collect the heights of your family members.
(i) Make a dot plot showing heights of just your family members. Describe its variability and central tendency.
(ii) Make a double-bar graph showing each student’s height next to their family’s mean height.
(iii) Look at everyone’s data and share your observations.
(b) Estimating time: Check the time and close your eyes. Open them when you think 1 minute has passed (no counting). Note down after how many seconds you opened your eyes. Collect this data for yourself and for your family members. Repeat this activity to estimate 3 minutes.
(i) Make two dot plots (for 1 minute and 3 minutes) showing estimates of just your family members.
(ii) Mark these on the respective dot plots. Describe its variability and central tendency.
(iii) Make a double bar graph showing each family’s mean 1 minute estimate and mean 3 minute estimate.
(iv) Look at everyone’s data and share your observations.
Answer

Sample answer (a): family heights 168, 155, 172, 149, 161 cm → mean = 805 ÷ 5 = 161 cm, median = 161 cm, range = 172 − 149 = 23 cm; no outlier.

Sample answer (b): 1-minute estimates 52, 58, 61, 47, 65 s → mean = 56.6 s, median = 58 s; 3-minute estimates 150, 172, 195, 138, 205 s → mean = median = 172 s. Both are a little short of the true time, and the 3-minute estimates spread much more (range 67 s against 18 s).

Puzzle Time — Connect the Dots…End-of-chapter puzzle

Q1A number lock has a 3-digit code. Find the code using the hints below. 265 — One digit is correct and well placed. 271 — One digit is correct but wrongly placed. 542 — Two digits are correct but wrongly placed. 036 — Nothing is correct. 064 — One digit is correct but wrongly placed.
Answer

The code is 415.

036: nothing is correct → 0, 3 and 6 are not in the code.
064: so 4 is in the code, but not in position 3.
542: 4 is also not in position 2 → 4 is in position 1.
265: 2 cannot be in position 1 (4 is there), so 5 is in position 3 and 2 is not in the code.
271: 7 cannot be the correct digit (in position 2 it would be well placed), so 1 is → 1 is in position 2.
HintWhat the hint saysCheck against 415
265One correct, well placed✔ only 5, and it is in position 3 in both
271One correct, wrongly placed✔ only 1; shown in position 3, actually in position 2
542Two correct, wrongly placed✔ 5 and 4; 5 shown in position 1 (really 3), 4 shown in position 2 (really 1)
036Nothing correct✔ none of 0, 3, 6 appears in 415
064One correct, wrongly placed✔ only 4; shown in position 3, actually in position 1

Chapter 13 of 15 – Maths

Also for This Chapter

NCERT Solutions Class 7 Maths Chapter 13 Connecting the Dots… – Overview

ClassClass 7
SubjectMaths
Chapter13 – Connecting the Dots…
Textbook pagesPart II, 98 – 134
Questions solved86
Session2027
FormatFull answers on this page + PDF

NCERT Solutions Class 7 Maths Chapter 13 – FAQs

Where can I download NCERT Solutions Class 7 Maths Chapter 13 Connecting the Dots… PDF?

Read every answer on this page, or download the free PDF from the table at the top.

Is this for the 2027 session?

Yes, it follows the latest NCERT Class 7 Maths book for 2027.

How many questions are solved in NCERT Class 7 Maths Chapter 13?

All 86 questions of the chapter (textbook pages Part II, 98 – 134) – the in-text questions, activities and the end-of-chapter exercises.

How should I use these solutions?

Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.

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