NCERT Solutions Class 8 Maths Chapter 12 Exponents and Powers – Here are all the NCERT solutions for Class 8 Maths Chapter 12. This solution contains questions, answers, images, explanations of the complete chapter 12 titled Exponents and Powers of Maths taught in class 8. If you are a student of class 8 who is using NCERT Textbook to study Maths, then you must come across chapter 12 Exponents and Powers. After you have studied lesson, you must be looking for answers of its questions. Here you can get complete NCERT Solutions for Class 8 Maths Chapter 12 Exponents and Powers in one place.
NCERT Solutions Class 8 Maths Chapter 12 Exponents and Powers
Here on AglaSem Schools, you can access to NCERT Book Solutions in free pdf for Maths for Class 8 so that you can refer them as and when required. The NCERT Solutions to the questions after every unit of NCERT textbooks aimed at helping students solving difficult questions.
For a better understanding of this chapter, you should also see summary of Chapter 12 Exponents and Powers , Maths, Class 8.
| Class | 8 |
| Subject | Maths |
| Book | Mathematics |
| Chapter Number | 12 |
| Chapter Name |
Exponents and Powers |
NCERT Solutions Class 8 Maths chapter 12 Exponents and Powers
Class 8, Maths chapter 12, Exponents and Powers solutions are given below in PDF format. You can view them online or download PDF file for future use.
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Question & Answer
Q.1: Find the multiplicative inverse of the following
(i) 2–4
(ii) 10–5
(iii) 7–2
(iv) 5–3
Ans : Missing
Q.2: Expand the following numbers using exponents.
(i) 1025.63
(ii) 1256.249
Ans : Missing
Q.3: Simplify and write in exponential form.
(i) (–2)–3 × (–2)– 4
(ii) p3 × p–10
(iii) 32 × 3–5 × 36
Ans : Missing
Q.4: Evaluate
\(\begin{array}{lll}{\text { (i) } 3^{-2}} & {\text { (ii) }(-4)^{-2}} & {\text { (iii) }\left(\frac{1}{2}\right)^{-5}}\end{array}\)
Ans : (i) \(3^{3^{-2}}=\frac{1}{3^{2}}=\frac{1}{9}\quad\left(a^{-m}=\frac{1}{a^{m}}\right)\) (ii) \((-4)^{(-4)^{-2}}=\frac{1}{(-4)^{2}}=\frac{1}{16}\quad\left(a^{-m}=\frac{1}{a^{m}}\right)\) (iii) \(\left(\frac{1}{2}\right)^{-5}=\frac{1}{(2)^{-5}}=(2)^{5}=2 \times 2 \times 2 \times 2 \times 2=32\)
Q.5: Simplify and express the result in power notation with positive exponent.
\(\begin{array}{l}{\text { (i) }(-4)^{5} \div(-4)^{8} \quad \text { (ii) }\left(\frac{1}{2^{3}}\right)^{2}} \\ {\text { (ii) } \quad(-3)^{4} \times\left(\frac{5}{3}\right)^{4} \text { (iv) }\left(3^{-7} \div 3^{-10}\right) \times 3^{-5}\left(\text { v) } 2^{-3} \times(-7)^{-3}\right.}\end{array}\)
Ans : \(\begin{array}{l}{\quad(i)(-4)^{5} \div(-4)^{8}=(-4)^{5-8}\left(a^{m} \div a^{n}=a^{m-n}\right)} \\ {=(-4)^{-3}}\end{array}\) \(=\frac{1}{(-4)^{3}} \quad \quad \quad \quad\left(a^{-m}=\frac{1}{a^{m}}\right)\) (ii) \(\left(\frac{1}{2^{3}}\right)^{2}=\frac{1}{\left(2^{3}\right)^{2}}=\frac{1}{2^{6}}\) \(\left(\left(a^{m}\right)^{n}=a^{a n}\right)\) (iii) \((-3)^{4} \times\left(\frac{5}{3}\right)^{4}=(-1 \times 3)^{4} \times \frac{5^{4}}{3^{4}}\) \(=(-1)^{4} \times 3^{4} \times \frac{5^{4}}{3^{4}} \quad\left[(a b)^{m}=a^{m} \times b^{m}\right]\) \(\begin{array}{l}{=(-1)^{4} \times 5^{4}} \\ {=5^{4}}\end{array}\left[(-1)^{4}=1\right]\) \(\begin{array}{l}{(\mathrm{iv})\left(3^{-7} \div 3^{-10}\right) \times 3^{-5}=\left(3^{-7-(-10)}\right) \times 3^{-5}\left(\mathrm{a}^{m} \div \mathrm{a}^{n}=a^{m-n}\right)} \\ {=3^{3} \times 3^{-5}} \\ {=3^{3+(-5)}\left(\mathrm{a}^{m} \times \mathrm{a}^{n}=\mathrm{a}^{m+n}\right)} \\ {=3^{-2}}\end{array}\) \(=\frac{1}{3^{2}}\) \(\left(a^{-m}=\frac{1}{a^{m}}\right)\) \(\begin{array}{l}{(v) 2^{-3} \times(-7)^{-3}=^{\frac{1}{2^{3}} \times \frac{1}{(-7)^{3}}}} \\ {=\frac{1}{[2 \times(-7)]^{3}}} \\ {=\frac{1}{(-14)^{3}}}\end{array}\) Hint : \(\left(a^{-m}=\frac{1}{a^{m}}\right)\) Hint : \(\left[a^{m} \times b^{m}=(a b)^{m}\right]\)
NCERT / CBSE Book for Class 8 Maths
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