**NCERT Solutions Class 8 Maths Chapter 13 Direct and Inverse Proportions** – Here are all the NCERT solutions for Class 8 Maths Chapter 13. This solution contains questions, answers, images, explanations of the complete chapter 13 titled Direct and Inverse Proportions of Maths taught in class 8. If you are a student of class 8 who is using NCERT Textbook to study Maths, then you must come across chapter 13 Direct and Inverse Proportions. After you have studied lesson, you must be looking for answers of its questions. Here you can get complete NCERT Solutions for Class 8 Maths Chapter 13 Direct and Inverse Proportions in one place.

## NCERT Solutions Class 8 Maths Chapter 13 Direct and Inverse Proportions

Here on **AglaSem Schools**, you can access to **NCERT Book Solutions** in free pdf for Maths for Class 8 so that you can refer them as and when required. The NCERT Solutions to the questions after every unit of NCERT textbooks aimed at helping students solving difficult questions.

For a better understanding of this chapter, you should also see summary of Chapter 13 Direct and Inverse Proportions , Maths, Class 8.

Class | 8 |

Subject | Maths |

Book | Mathematics |

Chapter Number | 13 |

Chapter Name |
Direct and Inverse Proportions |

### NCERT Solutions Class 8 Maths chapter 13 Direct and Inverse Proportions

Class 8, Maths chapter 13, Direct and Inverse Proportions solutions are given below in PDF format. You can view them online or download PDF file for future use.

### Direct and Inverse Proportions

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### Download NCERT Solutions Class 8 Maths chapter 13 Direct and Inverse Proportions In PDF Format

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### Question & Answer

Q.1:Observe the following tables and find if x and y are directly proportional. (i) \(\begin{array}{|c|c|c|c|c|c|c|c|}\hline x & {20} & {17} & {14} & {11} & {8} & {5} & {2} \\ \hline y & {40} & {34} & {28} & {22} & {16} & {10} & {4} \\ \hline\end{array}\) (ii) \( \begin{array}{|c|c|c|c|c|c|c|}\hline x & {6} & {10} & {14} & {18} & {22} & {26} & {30} \\ \hline y & {4} & {8} & {12} & {16} & {20} & {24} & {28} \\ \hline\end{array}\) (iii) \(\begin{array}{|c|c|c|c|c|c|c|}\hline x & {5} & {8} & {12} & {15} & {18} & {20} \\ \hline y & {15} & {24} & {36} & {60} & {72} & {100} \\ \hline\end{array}\)

Ans :Missing

Q.2:Principal = Rs 1000, Rate = 8% per annum. Fill in the following table and find which type of interest (simple or compound) changes in direct proportion with time period.

Ans :Missing

Q.3:If we fix time period and the rate of interest, simple interest changes proportionally with principal. Would there be a similar relationship for compound interest? Why?

Ans :Missing

Q.4:Following are the car parking charges near a railway station upto 4 hours = Rs 60 8 hours = Rs 100 12 hours = Rs 140 24 hours = Rs 180 Check if the parking charges are in direct proportion to the parking time.

Ans :A table Of the given information is formed as \(\begin{array}{|c|c|c|c|c|}\hline \text { Number of hours } & {4} & {8} & {12} & {24} \\ \hline \text { Parking charges (in Rs) } & {60} & {100} & {140} & {180} \\ \hline\end{array}\) The ratio of parking charges to the respective number Of hours (Rs/ hour) can be calculated as \(\frac{60}{4}=15, \quad \frac{100}{8}=\frac{25}{2}, \frac{140}{12}=\frac{35}{3}, \frac{180}{24}=\frac{15}{2}\) As each ratio is not same, therefore, the parking charges are not in a direct proportion to the parking time.

Q.5:A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. In the following table, find the parts of base that need to be added. \(\begin{array}{|c|c|c|c|c|c|}\hline \text { Parts of red pigment } & {1} & {4} & {7} & {12} & {20} \\ \hline \text { Parts of base } & {8} & {\dots} & {\dots} & {\dots} \\ \hline\end{array}\)

Ans :The given mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. For more parts of red pigments, the parts of the base will also be more. Therefore, the parts of red pigments and the parts Of base are in direct proportion. The given information in the form of a table is as follows. \(\begin{array}{|c|c|c|c|c|}\hline \text { Parts of red pigment } & {1} & {4} & {7} & {12} & {20} \\ \hline \text { Parts of base } & {8} & {x_{1}} & {x_{2}} & {x_{3}} \\ \hline\end{array}\) According to direct proportion , \(\begin{array}{l}{\frac{x_{1}}{4}=\frac{8}{1} \Rightarrow x_{1}=4 \times 8=32} \\ {\frac{x_{2}}{7}=\frac{8}{1} \Rightarrow x_{2}=7 \times 8=56} \\ {\frac{x_{3}}{12}=\frac{8}{1} \Rightarrow x_{3}=8 \times 12=96} \\ {\frac{x_{4}}{20}=\frac{8}{1} \Rightarrow x_{4}=8 \times 20=160}\end{array}\) The Table can be drawn as follows. \(\begin{array}{|c|c|c|c|c|c|}\hline \text { Parts of red pigment } & {1} & {4} & {7} & {12} & {20} \\ \hline \text { Parts of base } & {\text { 8 }} & {32} & {56} & {96} & {160} \\ \hline\end{array}\)

## NCERT / CBSE Book for Class 8 Maths

You can download the NCERT Book for Class 8 Maths in PDF format for free. Otherwise you can also buy it easily online.

- Click here for NCERT Book for Class 8 Maths
- Click here to buy NCERT Book for Class 8 Maths

### All NCERT Solutions Class 8

- NCERT Solutions for Class 8 English
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- NCERT Solutions for Class 8 Sanskrit

### All NCERT Solutions

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