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NCERT Solutions for Class 5 Maths Chapter 11 Grandmother s Quilt (PDF) – 2027

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NCERT Solutions for Class 5 Maths Chapter 11 Grandmother s Quilt – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.

Chapter 11 of Math Mela is about perimeter and area — the two measurements you need whenever you cover something or go round it. Preetha and Adrit’s grandmother stitches a quilt cover, a rug of square patches and two patchwork mats, and from her sewing come both ideas: the lace round the edge is the perimeter, and the cloth that fills the middle is the area. The chapter builds up from counting tiles to the two rules a Class 5 student should carry away — Area of a rectangle = Length × Breadth and Perimeter of a rectangle = 2 × Length + 2 × Breadth — and shows, again and again, that two shapes can share one and still differ in the other.

NCERT Solutions for Class 5 Maths Chapter 11 Grandmother s Quilt PDF

All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.

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Solutions PDF (English medium)Grandmother s QuiltView PDF
Solutions PDF (Hindi medium)दादी माँ की रजाईView PDF

NCERT Solutions for Class 5 Maths Chapter 11 Grandmother s Quilt – Questions and Answers

All 59 questions of the chapter (textbook pages 142 – 154) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.

The Quilt Border — Page 142Grandmother’s quilt cover and the three reels of lace

Q1Preetha and Adrit’s grandmother made a quilt cover using old clothes. Now she wants to decorate it with lace. Tick the lace option that would cover the entire border of the quilt.
(i) Red lace 40 units
(ii) Green lace 50 units
(iii) Blue lace 25 units
Grandmother’s quilt cover, made of square patches. Each side of a patch is 1 unit.
Answer

Tick (ii) — the green lace, 50 units. The quilt is 15 patches long and 10 patches wide, and each patch side is 1 unit.

Perimeter of the quilt = 15 + 10 + 15 + 10 = 50 units
Red 40 units ✗ (10 units short) · Blue 25 units ✗ (25 units short) · Green 50 units ✓
Q2She decides to use two different coloured laces. How much lace of each kind will be needed to cover the entire border?
Answer

The two laces together must measure 50 units. The neatest answer is 25 units of blue lace and 25 units of red lace.

Blue + Red = 25 + 25 = 50 units ✓

Let Us Do — Page 142Perimeter of shapes with equal sides; drawing rectangles to a given perimeter

Let Us Do
Q1Find the perimeter of the following shapes. All sides of the following shapes are equal. (First shape.)
4 cm
A shape with five equal sides. One side is marked.
Answer

Perimeter = 20 cm.

Perimeter = 4 + 4 + 4 + 4 + 4
Perimeter = 5 × 4 cm
Perimeter = 20 cm
Q2Find the perimeter of the following shapes. All sides of the following shapes are equal. (Second shape.)
5 cm
Two triangles joined at one point. All the sides are equal.
Answer

Perimeter = 30 cm.

Number of sides on the outside = 6
Perimeter = 6 × 5 cm
Perimeter = 30 cm
Q3Draw two rectangles each having the following perimeter: (a) 26 cm
Answer

Two rectangles with perimeter 26 cm: one of 8 cm × 5 cm, and one of 10 cm × 3 cm.

8 cm5 cm10 cm3 cm
Two different rectangles, both with a 26 cm border.
Check the first: 8 + 5 + 8 + 5 = 26 cm ✓
Check the second: 10 + 3 + 10 + 3 = 26 cm ✓
Q4Draw two rectangles each having the following perimeter: (b) 18 cm
Answer

Two rectangles with perimeter 18 cm: one of 6 cm × 3 cm, and one of 7 cm × 2 cm.

6 cm3 cm7 cm2 cm
Both rectangles need exactly 18 cm of ribbon to go round.
Check the first: 6 + 3 + 6 + 3 = 18 cm ✓
Check the second: 7 + 2 + 7 + 2 = 18 cm ✓

The Rug and the Four Tables — Page 143Counting patches; which shapes tile a table top; meeting the word area

Q1Preetha and Adrit’s grandmother is making a rug with square patches. The picture below shows the rug. How many patches have they used to make this?
Grandmother’s rug. Every patch is a square of cloth.
Answer

90 patches.

Patches = 15 × 6
Patches = 90 patches
Q2They found that __________, __________ and __________ shapes cover the top of the table without gaps and overlaps. __________ shape leaves gaps.
Table 1
Table 2
Table 3
Table 4
The four tables. Preetha used triangles and circles; Adrit used squares and rectangles.
Answer

Triangles, squares and rectangles cover the top of the table without gaps and overlaps. The circle shape leaves gaps.

TableTile usedAny gaps?
Table 1TrianglesNo gaps
Table 2CirclesGaps left
Table 3SquaresNo gaps
Table 4RectanglesNo gaps
Q3__________ triangles cover Table 1.
Table 1
Table 1, covered with triangles.
Answer

20 triangles cover Table 1.

Squares on the table top = 5 × 2 = 10
Triangles in each square = 2
Triangles in all = 10 × 2 = 20 triangles
Q4__________ squares cover Table 3.
Table 3
Table 3, covered with squares.
Answer

8 squares cover Table 3.

Squares = 4 × 2 = 8 squares
Q5__________ rectangles cover Table 4.
Table 4
Table 4, covered with rectangles.
Answer

12 rectangles cover Table 4.

Rectangles = 3 × 4 = 12 rectangles
Q6Do circles tile? Can we use them to cover a region?
Answer

No, circles do not tile. We cannot use them to cover a region completely: round edges touch only at points, so gaps are always left between them.

Q7The area of Table 1 is __________ triangle units.
Table 1
Table 1, covered with triangles.
Answer

The area of Table 1 is 20 triangle units.

Small squares on the table top = 5 × 2 = 10
Triangles in each square = 2
Area = 10 × 2 = 20 triangle units
Q8The area of Table 3 is __________ square units.
Table 3
Table 3, covered with squares.
Answer

The area of Table 3 is 8 square units.

Squares across = 4
Rows of squares = 2
Area = 4 × 2 = 8 square units
Q9The area of Table 4 is __________ rectangle units.
Table 4
Table 4, covered with rectangles.
Answer

The area of Table 4 is 12 rectangle units.

Rectangles across = 3
Rows of rectangles = 4
Area = 3 × 4 = 12 rectangle units
Q10Now, try to cover the top of your table without gaps and overlaps with the following objects of same size. (a) Notebooks (b) Lunch boxes (c) Pencil boxes (d) Maths textbooks. Which of the above objects covered the region completely?
Answer

The notebooks and the maths textbooks covered our table completely. Objects with straight edges and square corners fit edge to edge without gaps; round or curved objects leave gaps. Your answer depends on the objects you use.

Let Us Do — Page 144Preetha’s desk: how many of each tile would cover it

Let Us Do
Q1Look at the different tiles on her desk and answer how many of the following shapes will cover the desk. (a) Green triangles __________
Preetha’s desk with the tiles she has put on it — one blue square, one red triangle and one green triangle.
Answer

108 green triangles.

Squares on the desk = 9 × 6 = 54
Green triangles in 1 square = 2
Green triangles for the whole desk = 54 × 2 = 108 green triangles
Q2Look at the different tiles on her desk and answer how many of the following shapes will cover the desk. (b) Red triangles __________
Preetha’s desk with the tiles she has put on it — one blue square, one red triangle and one green triangle.
Answer

12 red triangles.

Red triangle = half of a 3 × 3 square
Area of red triangle = (3 × 3) ÷ 2 = 9 ÷ 2 = 4½ squares
Red triangles needed = 54 ÷ 4½
Two red triangles = 9 squares, so 54 ÷ 9 = 6 pairs
Red triangles = 6 × 2 = 12 red triangles
Q3Look at the different tiles on her desk and answer how many of the following shapes will cover the desk. (c) Blue squares __________
Preetha’s desk with the tiles she has put on it — one blue square, one red triangle and one green triangle.
Answer

54 blue squares.

Blue squares = 9 × 6 = 54 blue squares

Comparing Shapes — Pages 144–145Rectangles A, B and C — which has the largest area?

Comparing Shapes
Q1Which of the above rectangles has the largest area? Trace these shapes on to a paper and cut them to find out the one that has the largest area.
ABC
Three rectangles cut from coloured paper.
Answer

Rectangle A has the largest area. B fits completely under A. C does not fit under A at first, but when the part of C that sticks out is cut off and laid beside the rest, all of C fits inside A with space left over.

Q2Do you see that the area of rectangle A is larger than that of B? What about B and C?
ABC
Three rectangles cut from coloured paper.
Answer

Yes, A is larger than B. And C is larger than B. So the order so far is A and C both above B.

Area of A = 3 × 4 = 12 unit squares
Area of B = 2 × 4 = 8 unit squares
Area of C = 2 × 5 = 10 unit squares
Q3Which shape has a larger area among A and C? How will you find out?
ABC
Three rectangles cut from coloured paper.
Answer

A has the larger area. We find out by putting both on a square grid and counting the squares (or by cutting C and fitting it on A):

A is 3 squares wide and 4 squares tall → 3 × 4 = 12
C is 2 squares wide and 5 squares tall → 2 × 5 = 10
12 > 10, so A is larger
Q4Let us put these rectangles on a square grid. Now, can you identify the rectangle that has the largest area?
ABC1 unitArea = 1 unit square
Rectangles A, B and C placed on a square grid, as printed on page 145.
Answer

Yes — rectangle A, with an area of 12 unit squares.

A = 12 unit squares · B = 8 unit squares · C = 10 unit squares
A has the largest area.

Let Us Do — Pages 145–147Two gardens on a grid, your palm, leaves, and the two mats

Let Us Do
Q1Compare the areas of the two gardens given below on the square grid. Share your observations. Area of Garden A = _____ cm square. Area of Garden B = _____ cm square.
1 cmGarden AGarden B
The two gardens on a square grid, with a path between them. Each small square is 1 cm by 1 cm.
Answer

Area of Garden A = 10 square cm. Area of Garden B = 12 square cm. Garden B is bigger, by 2 square cm.

Area of Garden A = 2 × 5 = 10 square cm
Area of Garden B = 4 × 3 = 12 square cm
Difference = 12 − 10 = 2 square cm
Q2Trace your palm on the square grid given below and find the approximate area of your palm. Compare the area of your palm with your friend’s palm. Who has a bigger palm?
1 cm
The square grid for tracing your palm. Each small square is 1 cm by 1 cm.
Answer

Method: trace your palm on the grid, count the full squares, then count the part squares that are more than half inside, and add. Sample answer:

Full squares = 76
Part squares counted in = 14
Approximate area of my palm = 76 + 14 = about 90 square cm
My friend’s palm = about 84 square cm, so my palm is bigger, by about 6 square cm.
Q3Collect leaves of different kinds. Put them on a square grid and find their area. (a) Name the leaf with the largest area.
Answer

(the leaves we measured): the banyan leaf had the largest area, about 86 square cm. Your answer depends on the leaves you collect — write what you actually measured.

LeafFull squaresPart squares countedArea
Banyan7016about 86 square cm
Peepal5214about 66 square cm
Mango4014about 54 square cm
Neem (one leaflet)33about 6 square cm
Tulsi22about 4 square cm
Q4Collect leaves of different kinds. Put them on a square grid and find their area. (b) Name the leaf with the smallest area.
Answer

(from the same table): the tulsi leaf had the smallest area, about 4 square cm. Your answer depends on the leaves you collect.

Smallest area = 4 square cm → the tulsi leaf
Banyan (86) is more than 20 times tulsi (4)
Q5The following mats are made of square patches of equal size. How many square patches will be required to cover each mat? Trace and cut out a small square of the size given below and find the area. Mat (a): Area = ______ Perimeter = ______
(a)(b)
The two mats printed on page 147. The small orange square in the corner of each is the size of one patch.
Answer

Mat (a) needs 10 square patches. Area = 10 square units. Perimeter = 14 units.

Area of mat (a) = 5 × 2 = 10 square units
Perimeter of mat (a) = 5 + 2 + 5 + 2 = 14 units
Q6The following mats are made of square patches of equal size. How many square patches will be required to cover each mat? Mat (b): Area = ______ Perimeter = ______
(a)(b)
The two mats printed on page 147. The small orange square in the corner of each is the size of one patch.
Answer

Mat (b) needs 12 square patches. Area = 12 square units. Perimeter = 14 units.

Area of mat (b) = 4 × 3 = 12 square units
Perimeter of mat (b) = 4 + 3 + 4 + 3 = 14 units
Q7Would both mats require an equal or different number of patches?
(a)(b)
The two mats printed on page 147. The small orange square in the corner of each is the size of one patch.
Answer

A different number. Mat (a) needs 10 patches and mat (b) needs 12 patches, so mat (b) needs 2 patches more.

Mat (a) = 5 × 2 = 10 patches
Mat (b) = 4 × 3 = 12 patches
Difference = 12 − 10 = 2 patches

Trisha’s Two Rectangles — Page 147Does a bigger area always mean a bigger perimeter?

Q1Trisha makes these two rectangles. She says, “I increased the area of my rectangle, and the perimeter increased.” Do you think this is always true?
Trisha’s two rectangles.
Answer

No, it is not always true. It is true for Trisha’s rectangles (area 6 → 12, perimeter 10 → 14), but in this pair the area goes up and the perimeter goes down:

Long thin rectangle 8 × 1: area = 8 square units, perimeter = 8 + 1 + 8 + 1 = 18 units
Square 3 × 3: area = 9 square units, perimeter = 3 + 3 + 3 + 3 = 12 units
Area grew from 8 to 9, but perimeter fell from 18 to 12

Let Us Explore — Pages 147–148Same area but different perimeter; same perimeter but different area

Let Us Explore
Q1Tick the shapes with the same area.
1 cm(a)(b)
(c)(d)(e)(f)
Six shapes drawn on a 1 cm square grid.
Answer

Tick (a), (b), (c), (d) and (f). Each of them covers 12 square cm. Only shape (e) is different — it covers 8 square cm.

ShapeHow it is madeAreaTick?
(a)6 across, 2 down12 square cm✓
(b)2 + (5 × 2) staircase12 square cm✓
(c)3 across, 4 down12 square cm✓
(d)4 across, 3 down12 square cm✓
(e)8 across, 1 down8 square cm✗
(f)12 across, 1 down12 square cm✓
Q2Find the perimeters of these shapes.
1 cm(a)(b)
(c)(d)(e)(f)
Six shapes drawn on a 1 cm square grid.
Answer

Here are the perimeters. They are not the same, even though the areas are.

ShapeAreaWorking for the perimeterPerimeter
(a) 6 × 212 square cm6 + 2 + 6 + 216 cm
(b) staircase12 square cmcount the edge steps18 cm
(c) 3 × 412 square cm3 + 4 + 3 + 414 cm
(d) 4 × 312 square cm4 + 3 + 4 + 314 cm
(e) 8 × 18 square cm8 + 1 + 8 + 118 cm
(f) 12 × 112 square cm12 + 1 + 12 + 126 cm
Q3What do you notice? Discuss.
Answer

We notice this: shapes can have the same area and still have very different perimeters.

All of (a), (b), (c), (d) and (f) have area = 12 square cm
But their perimeters are 16 cm, 18 cm, 14 cm, 14 cm and 26 cm
Q4Tick the shapes with the same perimeter.
1 cm(a)(b)(c)(d)(e)
Five shapes drawn on a 1 cm square grid.
Answer

Tick (c), (d) and (e). Each of these three has a perimeter of 16 cm. Shapes (a) and (b) form a second matching pair, both 12 cm.

ShapePerimeterTick?
(a)12 cm— (matches (b))
(b)12 cm— (matches (a))
(c)16 cm✓
(d)16 cm✓
(e)16 cm✓
Q5Find the areas of these shapes.
1 cm(a)(b)(c)(d)(e)
Five shapes drawn on a 1 cm square grid.
Answer

All five shapes have the same area — 7 square cm each.

ShapeHow to countAreaPerimeter
(a)3 + 3 + 17 square cm12 cm
(b)3 + 2 + 27 square cm12 cm
(c)2 + 1 + 3 + 17 square cm16 cm
(d)4 + 37 square cm16 cm
(e)7 in one row7 square cm16 cm
Q6What do you notice? Discuss.
Answer

We notice this: shapes can have the same perimeter and still be different shapes — and having the same area does not mean having the same perimeter either.

All five shapes: area = 7 square cm
Perimeters: (a) 12 cm, (b) 12 cm, (c) 16 cm, (d) 16 cm, (e) 16 cm

Let Us Do — Pages 149–150Making new shapes with the same area; comparing a square with a triangle

Let Us Do
Q1Draw different shapes having the same area as the given shape. Write the perimeter of each shape. What do you notice? Discuss.
1 cm(a)
The given shape on a 1 cm square grid. The empty part of the grid is for the shapes you draw.
Answer

The given shape is 9 squares across and 2 squares down, so its area is 18 square cm and its perimeter is 22 cm. Every new shape you draw must also cover 18 squares.

9 × 2 : P = 22 cm6 × 3 : P = 18 cmL-shape : P = 20 cm
Shape (all 18 square cm)Perimeter
18 × 1 rectangle2 × 18 + 2 × 1 = 36 + 2 = 38 cm
9 × 2 rectangle (the given one)2 × 9 + 2 × 2 = 18 + 4 = 22 cm
6 × 3 rectangle2 × 6 + 2 × 3 = 12 + 6 = 18 cm
L-shape (4 wide top, 2 wide foot)count round the outline: 4 + 3 + 2 + 3 + 2 + 6 = 20 cm

We notice: all the shapes have the same area, 18 square cm, but their perimeters are different. The shape closest to a square (6 × 3) has the smallest perimeter.

Q2Is the area of shape (a) less than the area of shape (b) given below? Discuss.
(a)(b)
Shape (a) is a square on the grid. Shape (b) is a triangle on the same grid.
Answer

No. The two areas are equal — each shape covers 9 square cm.

Area of (a) = 3 × 3 = 9 square cm
Area of (b) = (6 × 3) ÷ 2 = 18 ÷ 2 = 9 square cm
The areas are equal

Area of a Rectangle — Page 150Grandmother’s square patchwork: Area = Length × Breadth

Q1What are other ways of finding area?
Answer

Other ways of finding area:

  1. Cover with tiles and count them.
  2. Put the shape on a square grid and count the squares (whole squares first, then part squares).
  3. For a rectangle, multiply: squares in one row × number of rows, that is, Length × Breadth.
Q2Preetha and Adrit’s grandmother is making another square patchwork. She arranges the patches as shown below. Can you guess how many patches she will need? How did you find it?
BreadthLength
Grandmother’s patchwork. The patches she has already laid are shown in pink.
Answer

She will need 24 patches.

Patches in one row = 4
Number of rows = 6
Total patches = 6 × 4 = 24 patches
Area of the patchwork = 6 cm × 4 cm = 24 square cm
Q3Did you notice that 6 is the length of one side and 4 is the length of the non-equal side of the rectangle?
Answer

Yes. One side of the patchwork has 6 patches (6 cm) and the other has 4 patches (4 cm). Area = Length × Breadth = 6 cm × 4 cm = 24 square cm — the same as the 24 patches we counted.

Q4Go back to the previous examples and check whether the product of the length and the breadth of the rectangles is the same as the area you had calculated by counting.
Answer

Yes — in every rectangle in this chapter, length × breadth gives exactly the area we had counted.

RectangleArea by countingLength × BreadthMatch?
Table 3 (page 143)8 square units4 × 2 = 8✓
Rectangle A (page 145)12 unit squares3 × 4 = 12✓
Rectangle B (page 145)8 unit squares2 × 4 = 8✓
Rectangle C (page 145)10 unit squares2 × 5 = 10✓
Garden A (page 145)10 square cm2 × 5 = 10✓
Garden B (page 145)12 square cm4 × 3 = 12✓
Mat (a) (page 147)10 patches5 × 2 = 10✓
Mat (b) (page 147)12 patches4 × 3 = 12✓
Shape (a) (page 149)18 square cm9 × 2 = 18✓

From Rectangle to Square — Page 151Perimeter = 2 × Length + 2 × Breadth, and what happens when all sides are equal

Q1What will happen if all the sides of a rectangle are equal, that is, the case of square?
Answer

The rectangle becomes a square, and both formulas get shorter.

Rectangle
Area = Length × Breadth
Perimeter = 2 × Length + 2 × Breadth

Square
Area = Length × Length
Perimeter = 4 × Length
Q2Let us think about a square whose sides are 5 units long. (Find its area and its perimeter.)
Answer

Area = 25 square cm. Perimeter = 20 cm.

Area of square = Length × Length
Area = 5 × 5
Area = 25 square cm

Perimeter of square = Length + Length + Length + Length
Perimeter = 4 × Length = 4 × 5
Perimeter = 20 cm

Let Us Do — Pages 151–153Your classroom floor, five grid shapes, everyday objects, and three word problems

Let Us Do
Q1Find the area of your classroom floor in square meters. Take the help of your teacher to measure the length and breadth of the floor. What is the perimeter of the classroom floor?
Answer

Measure the floor with a measuring tape, then use Area = Length × Breadth and Perimeter = 2 × Length + 2 × Breadth. Sample answer:

Length of floor = 8 m
Breadth of floor = 6 m
Area = 8 m × 6 m = 48 square m
Perimeter = 2 × 8 + 2 × 6 = 16 + 12 = 28 m
Measure your own classroom and write your own numbers.
Q2Find the area and perimeter of the following shapes. (a)
(a)____ cm____ cm
Shape (a) on a 1 cm square grid. Measure its two sides.
Answer

Shape (a) is a square of side 6 cm. Area = 36 square cm. Perimeter = 24 cm.

Area = 6 cm × 6 cm = 36 square cm
Perimeter = 4 × 6 cm = 24 cm
Q3Find the area and perimeter of the following shapes. (b)
(b)____ cm____ cm
Shape (b) on a 1 cm square grid. Measure its two sides.
Answer

Shape (b) is a rectangle 7 cm long and 4 cm broad. Area = 28 square cm. Perimeter = 22 cm.

Area = 7 cm × 4 cm = 28 square cm
Perimeter = 2 × 7 + 2 × 4 = 14 + 8 = 22 cm
Q4Find the area and perimeter of the following shapes. (c)
(c)____ cm____ cm
Shape (c) on a 1 cm square grid. Measure its two sides.
Answer

Shape (c) is a rectangle 12 cm long and 4 cm broad. Area = 48 square cm. Perimeter = 32 cm.

Area = 12 cm × 4 cm = 48 square cm
Perimeter = 2 × 12 + 2 × 4 = 24 + 8 = 32 cm
Q5Find the area and perimeter of the following shapes. (d)
(d)____ cm____ cm
Shape (d) on a 1 cm square grid. Measure its two sides.
Answer

Shape (d) is a square of side 3 cm. Area = 9 square cm. Perimeter = 12 cm.

Area = 3 cm × 3 cm = 9 square cm
Perimeter = 4 × 3 cm = 12 cm
Q6Find the area and perimeter of the following shapes. (e)
(e)____ cm____ cm
Shape (e) on a 1 cm square grid. Measure its two sides.
Answer

Shape (e) is a rectangle 6 cm long and 5 cm broad. Area = 30 square cm. Perimeter = 22 cm.

Area = 6 cm × 5 cm = 30 square cm
Perimeter = 2 × 6 + 2 × 5 = 12 + 10 = 22 cm
Q7Find the area and perimeter of the following objects. Use a scale or measuring tape to find the length and the breadth of each of the objects. (Notebook cover, newspaper, blackboard, ludo board, and two objects of your own.)
Answer

Measure each object, then use Area = Length × Breadth and Perimeter = 2 × Length + 2 × Breadth. Sample answer (sample measurements — measure your own things and write your own numbers):

S. No.Name of the objectLengthBreadthAreaPerimeter
1.Cover of the notebook28 cm21 cm588 square cm98 cm
2.Newspaper (one page)55 cm37 cm2,035 square cm184 cm
3.Blackboard300 cm120 cm36,000 square cm840 cm
4.Ludo board30 cm30 cm900 square cm120 cm
5.Your maths textbook25 cm19 cm475 square cm88 cm
6.Your desk top60 cm40 cm2,400 square cm200 cm
Q8Find the area of a rectangular field whose length is 42 m and breadth is 34 m.
Answer

Area = 1,428 square m.

Area = Length × Breadth
Area = 42 m × 34 m
42 × 30 = 1,260
42 × 4 = 168
1,260 + 168 = 1,428
Area = 1,428 square m
Q9The area of a rectangular garden is 64 square m and its length is 16 m. What is its breadth?
Answer

Breadth = 4 m.

Area = Length × Breadth
64 = 16 × Breadth
Breadth = 64 ÷ 16
Breadth = 4 m
Q10Find the area of the following figure with the dimensions as marked in the figure.
32 cm6 cm12 cm
The figure with the lengths marked on it. The dotted lines are only guide lines.
Answer

Area = 576 square cm.

Width = 32 cm
Height = 6 cm + 12 cm = 18 cm
Area = 32 cm × 18 cm
32 × 10 = 320
32 × 8 = 256
320 + 256 = 576
Area = 576 square cm

Let Us Play — Page 154The tile-and-die game: build up to a perimeter of 24 and win

Let Us Play
Q1Take some square tiles and a die and play the game in pairs. Roll the die and pick the number of tiles equal to the dots on the die. Arrange them to make a shape or figure. (How is the game played?)
Answer

Two players share one tiled figure and take turns adding tiles to it until its perimeter reaches 24. Whoever makes it 24 wins.

Q2Find the perimeter of the tiles.
1111111111
The tiles the first player has put down. Each side of a tile is 1 unit long.
Answer

Perimeter = 10 units. This matches the “= 10” printed in the book.

Perimeter = 3 + 1 + 2 + 1 + 1 + 2 = 10 units
Q3Do not move the tiles. The second player can take turn and add tiles to the same tiled figure. (The die shows 1 and one tile is added — what is the new perimeter?)
111111111111
The same figure after one more tile was added on top.
Answer

The new perimeter is 12 units. This matches the “= 12” printed in the book.

Old perimeter = 10 units
New tile adds 4 sides, join hides 2 sides
Change = 4 − 2 = +2
New perimeter = 10 + 2 = 12 units
Q4Take turns and add tiles to the same figure till the perimeter becomes 24. The one who makes the perimeter 24 wins the game. (How can a player reach exactly 24?)
111111111111111111111111
The tiled figure at the end of the game. Each side of a tile is 1 unit long.
Answer

Keep adding tiles along a single edge, because each such tile adds exactly 2 to the perimeter. From 12 you need 6 more such tiles to reach 24.

Perimeter needed = 24 units
Perimeter so far = 12 units
Still to add = 24 − 12 = 12 units
Each edge-joined tile adds 2 units
Tiles needed = 12 ÷ 2 = 6 tiles

Chapter 11 of 15 – Maths

Also for This Chapter

NCERT Solutions Class 5 Maths Chapter 11 Grandmother s Quilt – Overview

ClassClass 5
SubjectMaths
Chapter11 – Grandmother s Quilt
Textbook pages142 – 154
Questions solved59
Session2027
FormatFull answers on this page + PDF

NCERT Solutions Class 5 Maths Chapter 11 – FAQs

Where can I download NCERT Solutions Class 5 Maths Chapter 11 Grandmother s Quilt PDF?

Read every answer on this page, or download the free PDF from the table at the top.

Is this for the 2027 session?

Yes, it follows the latest NCERT Class 5 Maths book for 2027.

How many questions are solved in NCERT Class 5 Maths Chapter 11?

All 59 questions of the chapter (textbook pages 142 – 154) – the in-text questions, activities and the end-of-chapter exercises.

How should I use these solutions?

Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.

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