Skip to content

NCERT Solutions for Class 5 Maths Chapter 5 Far and Near (PDF) – 2027

aBy aglasem · Updated

NCERT Solutions for Class 5 Maths Chapter 5 Far and Near – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.

Chapter 5 of Math Mela is about measuring length and distance. Saris in a weaving centre, the world’s tallest statues, a 3-km race, the longest train journey in India, a sprouting moong seed and a roll of cloth teach four big ideas: pick the right unit for the thing you are measuring, change one unit into another (mm, cm, m, km), add, subtract, multiply and divide lengths just as you do with plain numbers, and use a double number line to see two units side by side.

NCERT Solutions for Class 5 Maths Chapter 5 Far and Near PDF

All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.

PDFChapterDownload
Solutions PDF (English medium)Far and NearView PDF
Solutions PDF (Hindi medium)दूर और पासView PDF

NCERT Solutions for Class 5 Maths Chapter 5 Far and Near – Questions and Answers

All 39 questions of the chapter (textbook pages 57 – 69) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.

Let Us Find — Page 57Choosing the right unit of measurement

Let Us Find
Q1Identify the appropriate units for measuring each of the following.
QuantityUnit of measurement
Metre (m) or centimetre (cm)
Height of India Gate42 ______
Length of a handkerchief40 ______
Depth of a well50 ______
Length of a mobile phone13 ______
Length of an elephant’s trunk2 ______
Distance between two buttons on a shirt5 ______
The table on page 57 — write m or cm after each number.
Answer

Big things get metres (m). Small things get centimetres (cm). Here is the filled table.

QuantityNumber givenUnitWhy
Height of India Gate42metre (m)It is a huge gate — much taller than your school
Length of a handkerchief40centimetre (cm)It fits in your pocket
Depth of a well50metre (m)A well goes deep down into the ground
Length of a mobile phone13centimetre (cm)It fits in your hand
Length of an elephant’s trunk2metre (m)A trunk is longer than you are tall
Distance between two buttons on a shirt5centimetre (cm)It is about the width of three fingers

Different Units but Same Measure — Pages 57–58Shikha and Sonu at the village weaving centre

Different Units but Same Measure
Q1Fill in the blanks in the double number line. Top line (in cm): 100 cm, ____ cm, 400 cm, 500 cm, 700 cm. Bottom line (in m): 1 m, 2 m, ____ m, ____ m, ____ m.
100 cm____ cm400 cm500 cm700 cm1 m2 m____ m____ m____ m×2×100
The double number line printed on page 57.
Answer

Top blank = 200 cm. Bottom blanks = 4 m, 5 m and 7 m.

100 cm 200 cm 400 cm 500 cm 700 cm 1 m 2 m 4 m 5 m 7 m ×100 ×2 Go down the arrow = multiply by 100. Go up = divide by 100.
The filled double number line. The red numbers are the ones you write in.
1 m = 100 cm
2 m = 2 × 100 = 200 cm   (the top blank)
400 cm = 400 ÷ 100 = 4 m
500 cm = 500 ÷ 100 = 5 m
700 cm = 700 ÷ 100 = 7 m
Q2Shikha and Sonu are measuring the lengths of saris and stoles in the village weaving centre. Find which measures represent the same sari or stole. You can take help of the double number line.
MeasureMeasure
204 cm5 metre 40 cm
540 cm2 metre 204 cm
750 cm2 metre 4 cm
240 cm2 metre 40 cm
404 cm6 metre 150 cm
The table on page 58. Match each measure on the left with the same length on the right.
Answer

All five pairs match. Here they are.

Measure in cmSame asWorking
204 cm2 metre 4 cm200 + 4 = 204 cm ✓
540 cm5 metre 40 cm500 + 40 = 540 cm ✓
750 cm6 metre 150 cm600 + 150 = 750 cm ✓
240 cm2 metre 40 cm200 + 40 = 240 cm ✓
404 cm2 metre 204 cm200 + 204 = 404 cm ✓

Let Us Compare — Page 58Ritika’s rods and the world’s tallest statues

Let Us Compare
Q1Ritika is comparing the lengths of different rods. Compare them using <, =, > signs.
(a) 456 cm ____ 5 m
(b) 55 cm + 200 cm ____ 200 cm + 54 cm
(c) 6 m 5 cm ____ 6 m 50 cm
(d) 2 m 150 cm ____ 3 m 50 cm
(e) 238 cm ____ 138 cm + 1 m
Answer

(a) <   (b) >   (c) <   (d) =   (e) =

PartLeft side in cmRight side in cmSign
(a) 456 cm and 5 m4565 × 100 = 500<
(b) 55 + 200 and 200 + 54255254>
(c) 6 m 5 cm and 6 m 50 cm600 + 5 = 605600 + 50 = 650<
(d) 2 m 150 cm and 3 m 50 cm200 + 150 = 350300 + 50 = 350=
(e) 238 cm and 138 cm + 1 m238138 + 100 = 238=
Q2World’s tallest statue.
(a) What is the difference between the height of the tallest statue in the world and the Statue of Liberty?
(b) Identify the statues whose heights have the least difference.
(c) Identify the statues whose heights have the largest difference.
(d) The height of which statue will be equal to the height of the Statue of Unity, if it is doubled?
StatueCountryHeight
Statue of UnityIndia182 m
Spring Temple BuddhaChina128 m
Guanyin of NanshanChina108 m
Statue of LibertyUSA93 m
The Motherland CallsRussia91 m
Christ the RedeemerBrazil38 m
Heights printed in the book (Some of World’s Tallest Statues, page 58).
Answer

(a) Tallest statue = Statue of Unity (182 m). 182 m − 93 m = 89 m.
(b) Statue of Liberty (93 m) and The Motherland Calls (91 m): 93 − 91 = 2 m, the least difference.
(c) Statue of Unity (182 m) and Christ the Redeemer (38 m): 182 − 38 = 144 m, the largest difference.
(d) The Motherland Calls, Russia: 91 m × 2 = 182 m.

Measuring Long Distances · Let Us Do — Page 59Long Tape, Rodometer, Rangefinder, Laser Distance Meter

Let Us Do
Q1Measure 100 m and 200 m on your school playground, or any other place in and around your school, using a Long Tape. Mark these points and draw a straight line. Walk on the lines and count the number of steps. Use this relationship between the number of steps taken and distance walked to find distances around you for at least 3 locations. Wherever possible, walk and find the number of steps. Otherwise, find the distance and estimate the number of steps.
(a) Identify and write the locations that are the nearest and the farthest from your home.
(b) Write the distances obtained above in increasing order.
(c) Name a location that is equal to or more than 1,000 m from your home.
Answer

(your own places and step counts will be different). My rule: 140 steps make about 100 m.

PlaceSteps countedDistance from home
Neighbour’s house7050 m
Village shop280200 m
School700500 m
Bus stand1,6801,200 m = 1 km 200 m

(a) Nearest location: the neighbour’s house (50 m). Farthest location: the bus stand (1 km 200 m).

(b) In increasing order: 50 m, 200 m, 500 m, 1,200 m.

(c) A location 1,000 m or more from home: the bus stand, which is 1,200 m — more than 1 km away.

Let Us Explore — Page 591,000 m = 1 km

Let Us Explore
Q1Fill in the table: Length of rope / Number of ropes needed to make 1 km. (1,000 m — 1; 100 m — ___; 10 m — ___; 200 m — ___; 500 m — ___; 250 m — ___)
Length of ropeNumber of ropes needed to make 1 km
1,000 m1
100 m 
10 m 
200 m 
500 m 
250 m 
The table as printed on page 59.
Answer

Here is the filled table. Every time, ask: how many of these ropes, laid end to end, make 1,000 m?

Length of ropeNumber of ropes needed to make 1 kmHow we found it
1,000 m11,000 ÷ 1,000 = 1
100 m101,000 ÷ 100 = 10
10 m1001,000 ÷ 10 = 100
200 m51,000 ÷ 200 = 5
500 m21,000 ÷ 500 = 2
250 m41,000 ÷ 250 = 4

Kilometre Race — Page 60Sheena and Jennifer organise a 3-km race

Kilometre Race
Q1Sheena and Jennifer are helping to organise a 3-km race. Water stations are to be arranged after every 500 m. How many water stations must be set up? At what positions from the starting point will these water stations be placed?
Answer

6 water stations. They go at 500 m, 1,000 m, 1,500 m, 2,000 m, 2,500 m and 3,000 m from the start.

3 km = 3 × 1,000 = 3,000 m
3,000 ÷ 500 = 6 water stations
Positions: 500 m, 1 km, 1 km 500 m, 2 km, 2 km 500 m, 3 km
Q2(3-km race) Children need to stand at an interval of 300 m to direct the runners. How many children are needed? At what positions from the starting point will the children be standing?
Answer

10 children. They stand at 300 m, 600 m, 900 m, 1,200 m, 1,500 m, 1,800 m, 2,100 m, 2,400 m, 2,700 m and 3,000 m.

3,000 ÷ 300 = 10 children
Positions: 300 m, 600 m, 900 m, 1,200 m, 1,500 m,
1,800 m, 2,100 m, 2,400 m, 2,700 m, 3,000 m
Q3(3-km race) Red and blue flags are to be placed alternately at every 50 m. How many red and blue flags are needed till the finish line?
Answer

60 flags in all — 30 red and 30 blue.

3,000 ÷ 50 = 60 flag positions
60 ÷ 2 = 30 red flags and 30 blue flags
Total = 30 + 30 = 60 flags

Let Us Do: Longest Train Journey — Pages 60–61The Vivek Express, Dibrugarh to Kanniyakumari

Let Us Do
Q1The longest train journey in India is by The Vivek Express which runs from Dibrugarh in Assam to Kanniyakumari in Tamil Nadu. Look at the stations on the route shown in the table below and answer the questions.
Station numberName of the stationDistance from Dibrugarh
9Dimapur306 km
14Guwahati556 km
22Jalpaiguri Road983 km
34Bhubaneswar2,007 km
40Visakhapatnam2,450 km
45Vijayawada JN2,800 km
55Coimbatore JN3,675 km
65Kanniyakumari4,187 km
The table on page 60 (used for questions 1–5).

The total length of the route from Dibrugarh to Kanniyakumari is _______ km.
Answer

4,187 km.

The table gives the distance of every station from Dibrugarh. Kanniyakumari is the last station, so its distance is the whole journey.

Q2The distance between Vijayawada and Jalpaiguri road is _______. (From the table: Jalpaiguri Road 983 km and Vijayawada JN 2,800 km from Dibrugarh.)
Answer

1,817 km.

2,800 − 983
= 2,800 − 1,000 + 17
= 1,800 + 17
= 1,817 km
Q3Distance between Vijayawada and Visakhapatnam is _______. (From the table: Visakhapatnam 2,450 km and Vijayawada JN 2,800 km from Dibrugarh.)
Answer

350 km.

Vijayawada JN = 2,800 km from Dibrugarh
Visakhapatnam = 2,450 km from Dibrugarh
2,800 − 2,450 = 350 km
Q4Which two stations are farther apart — Guwahati and Dimapur or Bhubaneswar and Jalpaiguri Road? (From the table: Dimapur 306 km, Guwahati 556 km, Jalpaiguri Road 983 km, Bhubaneswar 2,007 km from Dibrugarh.)
Answer

Bhubaneswar and Jalpaiguri Road are farther apart — 1,024 km, against only 250 km for the other pair.

Guwahati and Dimapur:
556 − 306 = 250 km

Bhubaneswar and Jalpaiguri Road:
2,007 − 983 = 1,024 km

1,024 km > 250 km
Q5What is the distance between Guwahati and Coimbatore JN? (From the table: Guwahati 556 km and Coimbatore JN 3,675 km from Dibrugarh.)
Answer

3,119 km.

  3,675
−   556
———————
  3,119 km

Let Us Explore: The World of Small Things — Page 61Sprout, small screws, nail — and the millimetre

Let Us Explore
Q1How can we measure small things like the ones shown here? (a sprout, small screws, a nail)
Answer

We measure them in millimetres (mm), using the tiny marks on the ruler.

1 cm = 10 mm
So a screw of 2 cm 4 mm = 20 + 4 = 24 mm
Q2Let us look at the scale. Do you notice the small marks between 1 cm and 2 cm? Count how many marks are there between 1 cm and 2 cm?
Answer

There are 9 small marks between the 1 and the 2, and they cut that centimetre into 10 equal parts. Each part is 1 millimetre.

Let Us Measure — Page 61The design made of four shapes, one inside another

Let Us Measure
Q1Measure the lines in the design and write their measurements in cm and mm.
The design printed on page 61 — the small boxes are for writing the measurement of the line beside each of them.
Answer

Sample measurements (to the nearest millimetre — yours may differ by 1 mm). Write each one in the box beside that line.

ShapeIts four sides
Outer four-sided figure (black)6 cm 8 mm, 6 cm 0 mm, 6 cm 1 mm, 6 cm 8 mm
Big diamond (blue)4 cm 4 mm, 4 cm 1 mm, 4 cm 4 mm, 4 cm 8 mm
Rectangle (green)3 cm 5 mm, 2 cm 8 mm, 3 cm 5 mm, 2 cm 7 mm
Small tilted square (red)2 cm 5 mm, 2 cm 3 mm, 2 cm 2 mm, 1 cm 9 mm

Let Us Do — Page 62Growing a moong or chana sprout and measuring it

Let Us Do
Q1Soak some seeds of whole moong or black or white chana overnight. Next morning, take them out and wrap them in a moist cloth to sprout them. Over the next 4 days, take out one seed each day and measure the length of sprout. Fill the table: Day 1, Day 2, Day 3, Day 4 — Length of the sprout (in mm).
Number of daysLength of the sprout (in mm)
Day 1 
Day 2 
Day 3 
Day 4 
The table as printed on page 62 — write your own measurement in each row.
Answer

(your own seed will give different numbers):

Number of daysLength of the sprout (in mm)Growth since the day before
Day 13 mm—
Day 28 mm5 mm
Day 315 mm (1 cm 5 mm)7 mm
Day 424 mm (2 cm 4 mm)9 mm

Let Us Draw — Page 62Drawing lines of a given length with a scale

Let Us Draw
Q1Draw lines of the following lengths in your notebook using a scale.
1. 5 cm 5 mm
2. 3 cm 6 mm
3. 8 cm 3 mm
4. 36 mm
5. 67 mm
Answer

Put a dot at the 0 mark of the ruler, put a second dot at the length shown below, and join the two dots along the ruler.

LineWhere the second dot goesSame length in mm
5 cm 5 mmpast 5, then 5 small marks more55 mm
3 cm 6 mmpast 3, then 6 small marks more36 mm
8 cm 3 mmpast 8, then 3 small marks more83 mm
36 mmsame as 3 cm 6 mm36 mm
67 mmsame as 6 cm 7 mm67 mm
5 cm 5 mm = 55 mm 3 cm 6 mm = 36 mm 8 cm 3 mm = 83 mm 36 mm = 3 cm 6 mm 67 mm
The five lines drawn to the same scale. Notice that lines 2 and 4 are exactly the same length.
Q2How did you draw lines of lengths 36 mm and 67 mm? Share your thoughts in class.
Answer

Change the millimetres into centimetres and millimetres first. Your ruler has big numbers for centimetres, so it is much easier to find 3 cm 6 mm than to count 36 tiny marks one by one.

36 mm = 30 mm + 6 mm = 3 cm 6 mm
67 mm = 60 mm + 7 mm = 6 cm 7 mm

Let Us Do — Pages 63–64Relationships between Different Units — 10 mm = 1 cm, 100 cm = 1 m, 1,000 m = 1 km

Let Us Do
Q1Fill in the blanks appropriately in the double number lines given below.
(a)1 cm7 cm15 cm___ cm___ cm___ cm50 cm10 mm___ mm___ mm250 mm320 mm450 mm___ mm×7×__×10×__
(b)1 m4 m10 m___ m___ m___ m21 m___ cm___ cm___ cm1,200 cm1,400 cm1,700 cm___ cm×4×__×100×__
(c)1 km9 km25 km___ km___ km___ km82 km1,000 m___ m___ m41,000 m55,000 m67,000 m___ m×9×__×1,000×__
Three double number lines. Each tick on the top line matches the tick below it on the bottom line.
Answer

(a) 1 cm = 10 mm

1 cm7 cm15 cm 25 cm32 cm45 cm50 cm 10 mm70 mm150 mm 250 mm320 mm450 mm500 mm ×10 ×7 ×7 ×10
(a) filled in. Red is what you write. Both empty boxes are ×10 and ×7.

(b) 1 m = 100 cm

Top line (m)1 m4 m10 m12 m14 m17 m21 m
Bottom line (cm)100 cm400 cm1,000 cm1,200 cm1,400 cm1,700 cm2,100 cm

(c) 1 km = 1,000 m

Top line (km)1 km9 km25 km41 km55 km67 km82 km
Bottom line (m)1,000 m9,000 m25,000 m41,000 m55,000 m67,000 m82,000 m

Empty boxes: (a) ×10 (7 cm → 70 mm) and ×7 (10 mm → 70 mm); (b) ×100 and ×4; (c) ×1,000 and ×9.

Q2Use your understanding from above to fill in the blanks appropriately.
(a) 4 cm 5 mm = ____ mm
(b) 89 mm = ____ cm ____ mm
(c) 234 cm = ____ mm
(d) 514 mm = ____ cm ____ mm
(e) 6 m 34 cm = ____ cm
(f) 20 m 12 cm = ____ cm
(g) 397 m = ____ cm
(h) 5,792 cm = ____ m ____ cm
(i) 9,108 cm = ____ m ____ cm
(j) 34 km = ____ m
(k) 6,870 m = ____ km ____ m
(l) 10,552 m = ____ km ____ m
(m) 29 km 30 m = ____ m
(n) 32 km 359 m = ____ m
Answer

Keep three facts in front of you: 1 cm = 10 mm, 1 m = 100 cm, 1 km = 1,000 m.

PartAnswerWorking
(a) 4 cm 5 mm45 mm4 cm = 40 mm; 40 + 5 = 45
(b) 89 mm8 cm 9 mm89 = 80 + 9; 80 mm = 8 cm
(c) 234 cm2,340 mm234 × 10 = 2,340
(d) 514 mm51 cm 4 mm514 = 510 + 4; 510 mm = 51 cm
(e) 6 m 34 cm634 cm6 m = 600 cm; 600 + 34 = 634
(f) 20 m 12 cm2,012 cm20 m = 2,000 cm; 2,000 + 12 = 2,012
(g) 397 m39,700 cm397 × 100 = 39,700
(h) 5,792 cm57 m 92 cm5,792 = 5,700 + 92; 5,700 cm = 57 m
(i) 9,108 cm91 m 8 cm9,108 = 9,100 + 8; 9,100 cm = 91 m
(j) 34 km34,000 m34 × 1,000 = 34,000
(k) 6,870 m6 km 870 m6,870 = 6,000 + 870
(l) 10,552 m10 km 552 m10,552 = 10,000 + 552
(m) 29 km 30 m29,030 m29 km = 29,000 m; 29,000 + 30
(n) 32 km 359 m32,359 m32 km = 32,000 m; 32,000 + 359

Adding and Subtracting Lengths — Pages 64–65Saji’s walk and the electricians’ cable

Adding and Subtracting Lengths
Q1Saji saw on his smartphone that he walked 3 km 450 m in the morning and another 4 km 650 m in the evening. How much did he walk in the whole day? How would you solve this problem? Share your thoughts in class.
Answer

Saji walked 8 km 100 m in the whole day.

Way 1: 7 km + 1,100 m = 7 km + 1 km 100 m = 8 km 100 m
Way 2: 3,450 m + 4,650 m = 8,100 m = 8 km 100 m
Both ways agree ✓
Q2Electricians are changing the cables in a house. They need 63 m of cable for this purpose. They used 16 m 75 cm cable in the first room. What is the length of the cable left?
Answer

46 m 25 cm of cable is left.

  6,300 cm
− 1,675 cm
———————————
  4,625 cm

4,625 cm = 4,600 cm + 25 cm = 46 m 25 cm

Let Us Do — Page 66Word problems on adding and subtracting lengths

Let Us Do
Q1Rani has two red-coloured ribbon rolls, one of length 3 m 75 cm and another 2 m 25 cm long. How much ribbon does she have?
Answer

Rani has 6 m of ribbon.

3 m 75 cm + 2 m 25 cm
= 5 m + 100 cm
= 5 m + 1 m
= 6 m of ribbon
Q2The distance from Bhopal to Sanchi is 48 km 700 m. Bhadbhada Ghat waterfall is on the way, and 17 km 900 m away from Bhopal. How far is Sanchi from the waterfall?
Answer

Sanchi is 30 km 800 m from the waterfall.

48 km 700 m = 48,700 m
17 km 900 m = 17,900 m

  48,700 m
− 17,900 m
—————————————
  30,800 m = 30 km 800 m
Q3Gulmarg Gondola in Gulmarg, Kashmir is the second longest and second highest cable car in the world. It is divided into two sections. The first section covers 2 km 300 m and the second section covers 2 km 650 m. What is the total distance covered by the cable car?
Answer

The cable car covers 4 km 950 m in all.

2 km 300 m + 2 km 650 m
= 4 km 950 m  (= 4,950 m)
Q4Circle the bigger length and find the difference.
(a) 11 mm and 1 cm
(b) 26 mm and 2 cm
(c) 20 cm and 201 mm
(d) 1,020 mm and 1 m
(e) 2 m and 245 cm
(f) 5,678 m and 6 km
(g) 6 km 1,480 m and 7 km 479 m
Answer

The one rule: change both lengths into the same unit first, then compare and subtract.

PartBoth in one unitBigger length (circle this)Difference
(a) 11 mm and 1 cm11 mm and 10 mm11 mm1 mm
(b) 26 mm and 2 cm26 mm and 20 mm26 mm6 mm
(c) 20 cm and 201 mm200 mm and 201 mm201 mm1 mm
(d) 1,020 mm and 1 m1,020 mm and 1,000 mm1,020 mm20 mm = 2 cm
(e) 2 m and 245 cm200 cm and 245 cm245 cm45 cm
(f) 5,678 m and 6 km5,678 m and 6,000 m6 km322 m
(g) 6 km 1,480 m and 7 km 479 m7,480 m and 7,479 m6 km 1,480 m1 m

Multiplying and Dividing Lengths — Pages 66–67Shirts, cloth for bags, a sari border and a new road

Multiplying and Dividing Lengths
Q1We need a 1 m 80 cm cloth to make a shirt for a 10-year old child. How much cloth will be needed to make shirts for 20 such children?
Answer

36 m of cloth is needed.

20 × 1 m 80 cm
= (20 × 1 m) + (20 × 80 cm)
= 20 m + 1,600 cm
= 20 m + 16 m
= 36 m of cloth
Q2A shop sells cloth for making bags at ₹100 for 5 m. How much money is needed to buy a 1 m cloth? Now, use the double number line to find the cost of the cloth or the length of cloth that we can buy at a particular cost. (Top line: 5 m, 10 m, 20 m, 40 m, ___ m. Bottom line: ₹100, ₹___, ₹___, ₹___, ₹2000. Boxes: ×__, ×__, ×__.)
5 m10 m20 m40 m____ m₹100₹____₹____₹____₹2000× ___× ___× ___
The double number line printed on page 67.
Answer

1 m of cloth costs ₹20.

5 m costs ₹100
1 m costs 100 ÷ 5 = ₹20
Length of cloth5 m10 m20 m40 m100 m
Cost₹100₹200₹400₹800₹2,000
10 m: 10 × 20 = ₹200
20 m: 20 × 20 = ₹400
40 m: 40 × 20 = ₹800
₹2,000: 2,000 ÷ 20 = 100 m

The three empty boxes are ×2 (5 m to 10 m), ×20 (metres to rupees) and ×2 (₹100 to ₹200).
Q3Anita is making an embroidery on the border of a sari. She needs a 1 m long thread to embroider a 50 cm sari. How much thread would she need for a 5 m sari border? A 1 m long thread costs ₹50. How much money will be needed to buy the thread?
Answer

She needs 10 m of thread, and it will cost ₹500.

Border = 5 m = 500 cm
500 ÷ 50 = 10 parts
Thread needed = 10 × 1 m = 10 m
Cost = 10 × ₹50 = ₹500
Q4A road 12 km 600 m long is being laid in a town. The workers lay an equal length of road each day, and complete the work in 6 days. How much road-laying work is done on each day?
Answer

2 km 100 m of road is laid each day.

12 km 600 m = 12,600 m
12,600 ÷ 6 = 2,100 m
2,100 m = 2 km 100 m each day

Let Us Estimate — Page 68Guessing heights and depths using a reference

Let Us Estimate
Q1The height of the tallest building in your neighbourhood. What did you use as a reference to estimate the height?
Answer

The tallest building near my home is a four-storeyed hospital. My reference was a single-storeyed house, which is about 3 m tall. 4 storeys × 3 m = 12 m, so the hospital is about 12 m tall.

Q2The height of the tallest tree in your neighbourhood. What did you use as a reference?
Answer

The tallest tree near my home is a neem tree. My reference was my father, who is about 1 m 70 cm tall; about 8 of him would reach the top. 8 × 170 cm = 1,360 cm, so the tree is about 13 m 60 cm tall.

Q3The depth of a well or swimming pool in your neighbourhood. How did you find out?
Answer

The well in our village is about 12 m deep. I found out by tying a stone to a long rope, lowering it until it touched the bottom, marking the rope at the top of the well, and measuring that length with a long tape.

Let Us Explore — Page 68Feet and inches — the units we use for height

Let Us Explore
Q1In daily life, we use other units of measuring length as well. Height is usually measured in feet and inches. Look at your ruler to see if inches are also marked on it. Find out how many cm and mm equal 1 inch.
Answer

1 inch = 2 cm 5 mm, which is 25 mm. And 1 foot = 12 inches, about 30 cm.

1 inch = 2 cm 5 mm = 25 mm
1 foot = 12 inches
1 foot = 12 × 2 cm 5 mm = 12 × 25 mm = 300 mm = 30 cm

Measure Your Height — Page 69Measuring heights in feet and inches

Measure Your Height
Q1Stand against a wall and mark your height. Measure the distance between the floor and the marked point in feet and inches. Similarly, other students in the class can also measure their heights. Find out who is the tallest student in your class. What is his or her height in feet and inches?
Answer
NameHeight in cmHeight in feet and inches
Meera125 cmabout 4 ft 2 in
Arjun130 cmabout 4 ft 4 in
Fatima135 cmabout 4 ft 6 in
Ravi (tallest)140 cmabout 4 ft 8 in

In this sample class the tallest student is Ravi, whose height is about 4 feet 8 inches.

Try This — Page 69The operation-sign puzzle

Try This
Q1Put appropriate operation sign (+, –, ×, ÷) such that each row and column and each 4 × 4 box should not repeat the sign. (The grid is given with ÷ in row 1 column 1, + in row 1 column 4, × in row 2 column 2, + in row 3 column 3, and – in row 4 column 4.)
÷+×+−
The 4 × 4 grid printed on page 69, with five signs already filled in.
Answer

Here is the completed grid. Every row has all four signs, and so does every column.

Column 1Column 2Column 3Column 4
Row 1÷–×+
Row 2+×–÷
Row 3–÷+×
Row 4×+÷–

Chapter 5 of 15 – Maths

Also for This Chapter

NCERT Solutions Class 5 Maths Chapter 5 Far and Near – Overview

ClassClass 5
SubjectMaths
Chapter5 – Far and Near
Textbook pages57 – 69
Questions solved39
Session2027
FormatFull answers on this page + PDF

NCERT Solutions Class 5 Maths Chapter 5 – FAQs

Where can I download NCERT Solutions Class 5 Maths Chapter 5 Far and Near PDF?

Read every answer on this page, or download the free PDF from the table at the top.

Is this for the 2027 session?

Yes, it follows the latest NCERT Class 5 Maths book for 2027.

How many questions are solved in NCERT Class 5 Maths Chapter 5?

All 39 questions of the chapter (textbook pages 57 – 69) – the in-text questions, activities and the end-of-chapter exercises.

How should I use these solutions?

Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.

Official website: ncert.nic.inNational Council of Educational Research and Training publishes date sheets, admit cards and results here
Visit
Go back to
NCERT Solutions Class 5 MathsNCERT Solutions Class 5NCERT

Ask a question

?

Loading comments…