Skip to content

NCERT Solutions for Class 5 Maths Chapter 4 We the Travellers Ii (PDF) – 2027

aBy aglasem · Updated

NCERT Solutions for Class 5 Maths Chapter 4 We the Travellers Ii – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.

Chapter 4 of Math Mela takes the journey of Chapter 1 further. This time we travel with big numbers — litres of fuel in a tank, kilometres on the North–South Corridor, rupees spent on a train trip — and learn to add and subtract numbers up to five digits, to check an answer the other way round, and to find quick, clever shortcuts instead of always writing columns.

NCERT Solutions for Class 5 Maths Chapter 4 We the Travellers Ii PDF

All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.

PDFChapterDownload
Solutions PDF (English medium)We the Travellers IiView PDF
Solutions PDF (Hindi medium)हम हैं यात्री – 2View PDF

NCERT Solutions for Class 5 Maths Chapter 4 We the Travellers Ii – Questions and Answers

All 64 questions of the chapter (textbook pages 42 – 56) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.

Making Sums Equal — Page 42Making Sums Equal

Try This
Q1Think what will happen to the sums if we interchange 2 and 5? Try interchanging other pairs of numbers and find the one that will make the sums equal. (In (a), the left group is 1, 2, 7, 9 with sum 19, and the right group is 3, 4, 5, 9 with sum 21.)
Answer

Interchanging 2 and 5 moves the sums further apart (22 and 18). Interchange 2 and 3 instead — both sums become 20.

2 ↔ 3:
Left: 1 + 3 + 7 + 9 = 20
Right: 2 + 4 + 5 + 9 = 20
Q2(a) Interchange pairs of numbers between the two groups to make their sums equal, using the least number of moves. Left group: 1, 2, 7, 9 (sum 19). Right group: 3, 4, 5, 9 (sum 21).
Answer

Interchange 2 and 3. One move is enough.

Total = 19 + 21 = 40, so each group needs 40 ÷ 2 = 20.
The left group needs 20 − 19 = 1 more: send out 2, bring in 3.
Left: 1 + 3 + 7 + 9 = 20
Right: 2 + 4 + 5 + 9 = 20
Q3(b) Interchange pairs of numbers between the two groups to make their sums equal, using the least number of moves. Left group: 5, 7, 12, 15 (sum 39). Right group: 9, 11, 13, 14 (sum 47).
Answer

Interchange 5 and 9. One move is enough.

Total = 39 + 47 = 86, so each group needs 86 ÷ 2 = 43.
The left group needs 43 − 39 = 4 more: swap two numbers that differ by 4 — send out 5, bring in 9.
Left: 9 + 7 + 12 + 15 = 43
Right: 5 + 11 + 13 + 14 = 43
Q4(c) Interchange pairs of numbers between the two groups to make their sums equal, using the least number of moves. Left group: 11, 15, 19, 23 (sum 68). Right group: 13, 17, 21, 25 (sum 76).
Answer

Two moves: interchange 11 and 13, and 15 and 17.

  1. Total = 68 + 76 = 144, so each group needs 72. The left group must gain 72 − 68 = 4.
  2. No right-hand number is exactly 4 more than a left-hand number, so one swap cannot work.
  3. 11 ↔ 13 gains 2 and 15 ↔ 17 gains 2: 4 in all.
Left: 13 + 17 + 19 + 23 = 72
Right: 11 + 15 + 21 + 25 = 72
Q5(d) Interchange pairs of numbers between the two groups to make their sums equal, using the least number of moves. Left group: 77, 78, 79, 80 (sum 314). Right group: 81, 82, 83, 84 (sum 330).
Answer

Two moves: interchange 77 and 81, and 78 and 82.

  1. Total = 314 + 330 = 644, so each group needs 322. The left group must gain 322 − 314 = 8.
  2. One swap cannot give 8: the biggest possible gap is 84 − 77 = 7.
  3. 77 ↔ 81 gains 4 and 78 ↔ 82 gains 4: 8 in all.
Left: 81 + 82 + 79 + 80 = 322
Right: 77 + 78 + 83 + 84 = 322

Fuel Arithmetic — Page 43Fuel Arithmetic

Q1A lorry has 28 litres of fuel in its tank. An additional 75 litres is filled. What is the total quantity of fuel in the lorry?
Answer

The lorry now has 103 litres of fuel.

Total = 28 l + 75 l
HTO
1 (carried)1 (carried)
28
+75
103
Q2Do you remember how to add two numbers using place value of numbers?
Answer

Yes. Write ones under ones and tens under tens. Add the ones first. If a column makes 10 or more, write its ones digit and carry 1 to the next column on the left. Example: 28 + 75 = 103.

Q3Find the sum of 49 and 89.
Answer

49 + 89 = 138

HTO
1 (carried)1 (carried)
49
+89
138

Let Us Solve — Page 43Fuel Arithmetic

Let Us Solve
Q1Add the following numbers. Wherever possible, find easier ways to add the pairs of numbers. (a) 15 + 79 (b) 46 + 99 (c) 38 + 35 (d) 5 + 89 (e) 76 + 28 (f) 69 + 20
Answer

(a) 94   (b) 145   (c) 73   (d) 94   (e) 104   (f) 89

SumEasy wayAnswer
(a) 15 + 7979 + 1 = 80, then 80 + 1494
(b) 46 + 9946 + 100 = 146, then take 1 away145
(c) 38 + 3538 + 2 = 40, then 40 + 3373
(d) 5 + 8989 + 1 = 90, then 90 + 494
(e) 76 + 2876 + 4 = 80, then 80 + 24104
(f) 69 + 20only tens change: 6 tens + 2 tens = 8 tens89

Relationship Between Addition and Subtraction — Page 44Relationship Between Addition and Subtraction

Q1Find the relationship between the numbers in the given statements and fill in the blanks appropriately. (a) If 46 + 21 = 67, then 67 – 21 = ___ and 67 – 46 = ___. (b) If 198 – 98 = 100, then 100 + ___ = 198 and 198 – ___ = 98. (c) If 189 + 98 = 287, then 287 – 98 = ___ and 287 – 189 = ___. (d) If 872 – 672 = 200, then 200 + ___ = 872 and 872 – ___ = 672.
Answer
Given factFirst blankSecond blank
(a) 46 + 21 = 6767 − 21 = 4667 − 46 = 21
(b) 198 − 98 = 100100 + 98 = 198198 − 100 = 98
(c) 189 + 98 = 287287 − 98 = 189287 − 189 = 98
(d) 872 − 672 = 200200 + 672 = 872872 − 200 = 672

No working is needed: each fact uses the same three numbers, only rearranged.

Q2In each of the following, write the subtraction and addition sentences that follow from the given sentence. (a) If 78 + 164 = 242, then ___ . (b) If 462 + 839 = 1301, then ___ . (c) If 921 – 137 = 784, then ___ . (d) If 824 – 234 = 590, then ___ .
Answer

Each box has two blank lines, so write two sentences in each.

GivenFirst sentenceSecond sentence
(a) 78 + 164 = 242242 − 164 = 78242 − 78 = 164
(b) 462 + 839 = 13011301 − 839 = 4621301 − 462 = 839
(c) 921 − 137 = 784784 + 137 = 921921 − 784 = 137
(d) 824 − 234 = 590590 + 234 = 824824 − 590 = 234

More Fuel Arithmetic — Page 44More Fuel Arithmetic

Q1A minibus has 18 l of fuel left. After refuelling, the fuel meter indicates 65 l. How much fuel has been filled in the fuel tank of the minibus?
Answer

47 litres of fuel was filled.

Fuel filled = 65 l − 18 l
TO
5 (was 6)15 (was 5)
− 18
47
Q2Check if 18 + 47 = 65?
Answer

Yes. 18 + 47 = 65, so the answer 47 l is correct.

18 l (already in the tank) + 47 l (filled) = 65 l (meter reading) ✓

Let Us Solve — Page 45More Fuel Arithmetic

Let Us Solve
Q1What is the difference between 82 and 37? Check your answer. Is 37 + ____ = 82?
Answer

The difference is 45.

82 − 37
TO
7 (was 8)12 (was 2)
− 37
45

Check: 37 + 45 = 82.

Q257 – 11 = ___
Answer
57 − 11 = 46
  1. Ones: 7 − 1 = 6. No regrouping is needed.
  2. Tens: 5 − 1 = 4.
Q323 – 19 = ___
Answer
23 − 19 = 4
  1. Ones: 3 is smaller than 9, so regroup. Take 1 ten from the 2 tens.
  2. The tens are now 1 and the ones are 13.
  3. Ones: 13 − 9 = 4.
  4. Tens: 1 − 1 = 0.
Q449 – 21 = ___
Answer
49 − 21 = 28
  1. Ones: 9 − 1 = 8.
  2. Tens: 4 − 2 = 2.
Q556 – 18 = ___
Answer
56 − 18 = 38
  1. Ones: 6 is smaller than 8, so regroup. Take 1 ten from the 5 tens.
  2. The tens are now 4 and the ones are 16.
  3. Ones: 16 − 8 = 8.
  4. Tens: 4 − 1 = 3.
Q693 – 35 = ___
Answer
93 − 35 = 58
  1. Ones: 3 is smaller than 5, so regroup. Take 1 ten from the 9 tens.
  2. The tens are now 8 and the ones are 13.
  3. Ones: 13 − 5 = 8.
  4. Tens: 8 − 3 = 5.
Q784 – 23 = ___
Answer
84 − 23 = 61
  1. Ones: 4 − 3 = 1.
  2. Tens: 8 − 2 = 6.
Q870 – 43 = ___
Answer
70 − 43 = 27
  1. Ones: 0 is smaller than 3, so regroup. Take 1 ten from the 7 tens.
  2. The tens are now 6 and the ones are 10.
  3. Ones: 10 − 3 = 7.
  4. Tens: 6 − 4 = 2.
Q965 – 47 = ___
Answer
65 − 47 = 18
  1. Ones: 5 is smaller than 7, so regroup. Take 1 ten from the 6 tens.
  2. The tens are now 5 and the ones are 15.
  3. Ones: 15 − 7 = 8.
  4. Tens: 5 − 4 = 1.

Sums of Consecutive Numbers — Page 45Sums of Consecutive Numbers

Math Talk
Q1In each of the boxes above, state whether the sums are even or odd. Explain why this is happening.
Sum of 2 consecutive numbers
1 + 2 = 3
2 + 3 = 5
3 + 4 = 7
4 + 5 = 9
Sum of 3 consecutive numbers
1 + 2 + 3 = 6
2 + 3 + 4 = 9
3 + 4 + 5 = 12
4 + 5 + 6 = 15
Sum of 4 consecutive numbers
1 + 2 + 3 + 4 = 10
2 + 3 + 4 + 5 = 14
3 + 4 + 5 + 6 = 18
4 + 5 + 6 + 7 = 22
Answer

Box of 2: all sums odd. Box of 3: even and odd by turns. Box of 4: all sums even.

BoxSums printedEven or odd
2 consecutive numbers3, 5, 7, 9all odd
3 consecutive numbers6, 9, 12, 15even, odd, even, odd
4 consecutive numbers10, 14, 18, 22all even

Why: odd + odd = even. Two consecutive numbers are one odd and one even, so the sum is odd. Four consecutive numbers are two odd and two even, so the sum is even. Three consecutive numbers contain 2, 1, 2, 1 odd numbers in turn, so the sums go even, odd, even, odd.

Q2What is the difference between two successive sums in each box? Is it the same throughout?
Sum of 2 consecutive numbers
1 + 2 = 3
2 + 3 = 5
3 + 4 = 7
4 + 5 = 9
Sum of 3 consecutive numbers
1 + 2 + 3 = 6
2 + 3 + 4 = 9
3 + 4 + 5 = 12
4 + 5 + 6 = 15
Sum of 4 consecutive numbers
1 + 2 + 3 + 4 = 10
2 + 3 + 4 + 5 = 14
3 + 4 + 5 + 6 = 18
4 + 5 + 6 + 7 = 22
Answer

Yes, it is the same all the way down each box. The jump equals the count of numbers being added.

BoxSumsJump each time
2 consecutive numbers3 → 5 → 7 → 92
3 consecutive numbers6 → 9 → 12 → 153
4 consecutive numbers10 → 14 → 18 → 224
Q3What will be the difference between two successive sums for — (a) 5 consecutive numbers (b) 6 consecutive numbers
Answer

(a) 5    (b) 6

(a) 1 + 2 + 3 + 4 + 5 = 15 and 2 + 3 + 4 + 5 + 6 = 20 → difference 20 − 15 = 5
(b) 1 + 2 + 3 + 4 + 5 + 6 = 21 and 2 + 3 + 4 + 5 + 6 + 7 = 27 → difference 27 − 21 = 6

In-text Questions — Page 46Sums of Consecutive Numbers

Q1Notice how the sums of 3, 4, and 5 consecutive numbers are related to the numbers being added. Use your understanding to find the following sums without adding the numbers directly. (a) 67 + 68 + 69 (b) 24 + 25 + 26 + 27 (c) 48 + 49 + 50 + 51 + 52 (d) 237 + 238 + 239 + 240 + 241 + 242
1 + 2 + 3 = 6
2 + 3 + 4 = 9
3 + 4 + 5 = 12
1 + 2 + 3 + 4 = 10
2 + 3 + 4 + 5 = 14
3 + 4 + 5 + 6 = 18
1 + 2 + 3 + 4 + 5 = 15
2 + 3 + 4 + 5 + 6 = 20
3 + 4 + 5 + 6 + 7 = 25

In the book, curved arrows join pairs of numbers placed the same distance from the two ends. For example, in 1 + 2 + 3 + 4 = 10 they join 1 and 4 (5) and 2 and 3 (5).

Answer
(a) 67 + 68 + 69 = 3 × 68 = 204
(b) 24 + 25 + 26 + 27 = 2 × (24 + 27) = 2 × 51 = 102
(c) 48 + 49 + 50 + 51 + 52 = 5 × 50 = 250
(d) 237 + 238 + 239 + 240 + 241 + 242 = 3 × (237 + 242) = 3 × 479 = 1,437

The Longest Land Route — Adding Large Numbers — Pages 46–47The Longest Land Route — Adding Large Numbers

Q1One of the places on the North–South Corridor was 1,855 km from Srinagar and 1,862 km from Kanniyakumari. What was the total length of the North–South Corridor in 2019?
Answer

The North–South Corridor was 3,717 km long.

Total length = 1,855 km + 1,862 km
ThHTO
1 (carried)1 (carried)
1855
+ 1862
3717
Q2Do you remember how to add large numbers?
Answer

Yes. Large numbers are added just like small ones. Line up the digits from the right — ones under ones, tens under tens, and so on. Add the ones first, and carry 1 to the next column whenever a column makes 10 or more. Example: 1,855 + 1,862 = 3,717.

Q3Mahesh and his family decide to drive from Srinagar to Kanniyakumari. He spends ₹21,880 on fuel and toll tax, and ₹38,900 on other expenses during this journey. How much did he spend in total?
Answer

Mahesh spent ₹60,780 in all.

Total spent = ₹21,880 + ₹38,900
TThThHTO
1 (carried)1 (carried)
21880
+ 38900
60780
Q4Mentally track the positions of the digits as you add. (Example: 267 + 54)
Answer

267 + 54 = 321. Line up the digits from the right and add column by column, keeping the carries in mind.

11
267
+54
321

Let Us Solve — Page 48The Longest Land Route — Adding Large Numbers

Let Us Solve
Q1Find the following sums. Try not to write TTh, Th, H, T, and O at the top. Just align the digits properly, at least for the smaller numbers. (a) 238 + 367 (b) 1,234 + 12,345 (c) 12 + 123 (d) 46,120 + 12,890 (e) 878 + 8,789 (f) 1,749 + 17,490
Answer

(a) 605   (b) 13,579   (c) 135   (d) 59,010   (e) 9,667   (f) 19,239

(a)
11
238
+367
605
(b)
1234
+12345
13579
(c)
12
+123
135
(d)
11
46120
+12890
59010
(e)
111
878
+8789
9667
(f)
11
1749
+17490
19239
Q2The great Indian road trip! Nazrana and her friends planned a road trip across India, starting from Delhi. They first drove to Mumbai, then Goa, then Hyderabad, and finally Puri. Look at the distances marked on the map and help them find the total distance travelled.
Road trip route
The road trip: Delhi → Mumbai → Goa → Hyderabad → Puri, with the distance marked on each part of the drive.
Answer

They travelled 3,915 km in all.

Part of the journeyDistance
Delhi → Mumbai1,600 km
Mumbai → Goa590 km
Goa → Hyderabad670 km
Hyderabad → Puri1,055 km
  1. 1,600 + 590 = 2,190 km  (Delhi to Goa)
  2. 2,190 + 670 = 2,860 km  (Delhi to Hyderabad)
  3. 2,860 + 1,055 = 3,915 km  (Delhi to Puri)
Q3Find 2 numbers among 5,205, 6,220, 7,095, 8,455, and 4,840 whose sum is closest to the following. (a) 10,000 (b) 15,000 (c) 13,000 (d) 16,000
Answer

Add the likely pairs and choose the sum nearest to each target.

TargetTwo numbersSum
(a) 10,0005,205 + 4,84010,045 (45 more)
(b) 15,0006,220 + 8,45514,675 (325 less)
(c) 13,0008,455 + 4,84013,295 (295 more)
(d) 16,0007,095 + 8,45515,550 (450 less)

Subtracting Large Numbers — Pages 49–50Subtracting Large Numbers

MapSpot these places on the map of India: the ports of Mumbai, Cochin and Chennai.
Answer

Mumbai port — on the west coast, in Maharashtra.
Cochin (Kochi) port — further south on the west coast, in Kerala.
Chennai port — on the east coast, in Tamil Nadu.

Mumbai, Cochin and Chennai ports
The three ports marked on the map of India.
Q1The total distance of the sea route from Mumbai to Chennai is 2,700 km. A ship starting from Mumbai first reaches the Cochin port, travelling 1,083 km by sea. How much more distance does it have to travel to reach the Chennai port?
Answer

The ship still has to travel 1,617 km.

Distance left = 2,700 km − 1,083 km
ThHTO
26 (was 7)9 (was 0)10 (was 0)
− 1083
1617
Q2Do you remember how to subtract numbers using place value?
Answer

Yes. Line up the digits from the right and subtract the ones first. If a top digit is smaller than the digit below it, regroup: take 1 from the next column on the left, which gives 10 more in this column. Example: 2,700 − 1,083 = 1,617.

Q3Check if the solution is correct.
Answer

Yes, it is correct. Add the answer back to the distance already sailed and you land on the full route.

1,617 km (still to sail) + 1,083 km (already sailed) = 2,700 km ✓
Q4As you learnt earlier, the longest land route is 15,150 km between Talon (Russia) and Sagres (Portugal). The longest highway in Africa is 10,228 km long, connecting the cities of Cairo, in Egypt and Cape Town, in South Africa. How much longer is the land route between Talon and Sagres compared to the highway between Cairo and Cape Town?
Answer

The Talon–Sagres route is 4,922 km longer.

Difference = 15,150 km − 10,228 km
TThThHTO
14 (was 5)11 (was 1)4 (was 5)10 (was 0)
− 10228
04922

Let Us Solve — Pages 50–51Subtracting Large Numbers

Let Us Solve
Q1Subtract the following. Try not to write TTh, Th, H, T, and O at the top. Align the digits carefully. (a) 4,578 – 2,222 (b) 15,324 – 11,780 (c) 5,423 – 423 (d) 123 – 12 (e) 77,777 – 777 (f) 826 – 752
Answer

(a) 2,356   (b) 3,544   (c) 5,000   (d) 111   (e) 77,000   (f) 74

(a)
4578
−2222
2356
(b)
41212
15324
−11780
3544
(c)
5423
−423
5000
(d)
123
−12
111
(e)
77777
−777
77000
(f)
712
826
−752
74

Small orange digits show the new value of a place after regrouping.

Q2Mary’s train journey to Delhi. Mary is on a train journey. She starts from Kolkata with ₹12,540. She spends ₹3,275 on food and other expenses during her trip to Varanasi. In Varanasi, her uncle gives her a gift worth ₹4,900. She then travels to Delhi, spending ₹2,645 on the train ticket. She spends ₹1,275 on souvenirs in Delhi. How much money is Mary left with at the end of the Delhi trip?
Answer

Mary is left with ₹10,245.

StageWhat happensMoney in hand
Leaves Kolkatastarting amount₹12,540
Reaches Varanasispends ₹3,275₹9,265
In Varanasigift of ₹4,900 added₹14,165
Ticket to Delhispends ₹2,645₹11,520
In Delhispends ₹1,275₹10,245
  1. 12,540 − 3,275 = 9,265
  2. 9,265 + 4,900 = 14,165
  3. 14,165 − 2,645 = 11,520
  4. 11,520 − 1,275 = 10,245
Q3Members of a school council have raised ₹70,500. They plan to set up a Maths Lab with some games and models worth ₹39,785, buy library books worth ₹9,545, and purchase sports equipment worth ₹19,548. (a) Estimate whether the school council has raised enough money to make the purchases. Share your thoughts in the class. (b) Check your estimate with calculations.
Answer

(a) Estimate — yes, but only just.

₹39,785 → about ₹40,000; ₹9,545 → about ₹10,000; ₹19,548 → about ₹20,000
40,000 + 10,000 + 20,000 = ₹70,000, which is a little less than ₹70,500.

Sample answer: “Each cost is a little below its round number, so the real total is below ₹70,000. ₹70,500 should be enough.”

(b) The exact calculation — yes, and ₹1,622 is left over.

  1. 39,785 + 9,545 = 49,330
  2. 49,330 + 19,548 = 68,878  (total cost)
  3. 70,500 − 68,878 = 1,622
Q4A truck can carry 8,250 kg of goods. A factory loads 3,675 kg of cement and 2,850 kg of steel on it. (a) What is the total weight loaded onto the truck? (b) How much more weight can the truck carry before reaching its maximum capacity?
Answer

(a) 6,525 kg is already loaded. (b) 1,725 kg more can still be loaded.

(a) 3,675 kg + 2,850 kg = 6,525 kg
11
3675
+2850
6525
(b) 8,250 kg − 6,525 kg = 1,725 kg
712410
8250
−6525
1725

Quick Sums and Differences — Pages 51–52Quick Sums and Differences

Math Talk
Q1Sukanta likes the numbers 10, 100, 1,000, and 10,000. He wants to figure out what number he should add to a given number such that the sum is 100 or 1,000. Help him fill in the blanks with an appropriate number. 32 + ______ = 100
Answer

32 + 68 = 100

  1. First aim for 99 instead of 100. Take each digit of 32 away from 9: 9 − 3 = 6 and 9 − 2 = 7. So 32 + 67 = 99.
  2. 100 is 1 more than 99, so add 1 to the 67: 67 + 1 = 68.
  3. So 32 + 68 = 100.
Step 1
32
+67
99
Step 2
11
32
+68
100
Q2Do you think this method will always work?
Answer

Yes. Every digit is 9 or less, so taking each digit away from 9 never needs regrouping and always reaches 99 (or 999, or 9,999). One more then makes 100 (or 1,000, or 10,000).

Try it on 46: 9 − 4 = 5, 9 − 6 = 3, so 46 + 53 = 99
Then 53 + 1 = 54, so 46 + 54 = 100 ✓
Q359 + ______ = 100. Try this method for the number 59.
Answer

59 + 41 = 100

  1. Aim for 99 first. 9 − 5 = 4 and 9 − 9 = 0. So 59 + 40 = 99.
  2. Add 1 to reach 100: 40 + 1 = 41.
  3. So the missing number is 41.
Step 1
59
+40
99
Step 2
11
59
+41
100
Q4Now, use this method to solve the following. 877 + ______ = 1,000 and 666 + ______ = 1,000. 4,103 + ______ = 10,000 and 5,555 + ______ = 10,000
Answer

Take each digit away from 9 (to reach 999 or 9,999), then add 1.

QuestionWorkingAnswer
877 + ___ = 1,000999 − 877 = 122; 122 + 1123
666 + ___ = 1,000999 − 666 = 333; 333 + 1334
4,103 + ___ = 10,0009,999 − 4,103 = 5,896; 5,896 + 15,897
5,555 + ___ = 10,0009,999 − 5,555 = 4,444; 4,444 + 14,445
Q5Will this method work if the units digit is 0? What do you think? What other methods can you use to find the missing number to fill in the blanks? Share your thoughts in the class. (a) 180 + ______ = 1,000 (b) 760 + ______ = 1,000 (c) 400 + ______ = 1,000
Answer

Yes, it still works. A units digit of 0 changes nothing, because 9 − 0 = 9 and there is still no borrowing.

QuestionWorkingAnswer
(a) 180 + ___ = 1,000999 − 180 = 819; 819 + 1820
(b) 760 + ___ = 1,000999 − 760 = 239; 239 + 1240
(c) 400 + ___ = 1,000999 − 400 = 599; 599 + 1600

Other methods: count on in jumps (180 + 20 = 200, then 200 + 800 = 1,000, so 20 + 800 = 820); think in tens (76 tens + 24 tens = 100 tens, so 240); or subtract directly (1,000 − 400 = 600).

Q6Namita likes the number 9. She wants to subtract 9 or 99 from any number. Find a way to quickly subtract 9 or 99 from any number. (a) 67 – 9 (b) 83 – 9 (c) 144 – 9 (d) 187 – 99 (e) 247 – 99 (f) 763 – 99
Answer

The trick: to take away 9, take away 10 and then put 1 back. To take away 99, take away 100 and then put 1 back.

QuestionWorkingAnswer
(a) 67 − 967 − 10 = 57, then 57 + 158
(b) 83 − 983 − 10 = 73, then 73 + 174
(c) 144 − 9144 − 10 = 134, then 134 + 1135
(d) 187 − 99187 − 100 = 87, then 87 + 188
(e) 247 − 99247 − 100 = 147, then 147 + 1148
(f) 763 − 99763 − 100 = 663, then 663 + 1664
Q7Now, use the above solutions to find answers to the following problems. Do not calculate again. Namita wonders if she can get 9 or 99 as the answer to any subtraction problem. Find a way to get the desired answer. (a) 32 – ______ = 9 (b) 56 – ______ = 9 (c) 877 – ______ = 99 (d) 666 – ______ = 99
Answer

Yes, she can — from any number. The number to take away is simply the starting number minus 9 (or minus 99), and that is exactly the quick trick from the last question.

QuestionWorking with the trickAnswer
(a) 32 − ___ = 932 − 10 = 22, then 22 + 1 = 2323
(b) 56 − ___ = 956 − 10 = 46, then 46 + 1 = 4747
(c) 877 − ___ = 99877 − 100 = 777, then 777 + 1 = 778778
(d) 666 − ___ = 99666 − 100 = 566, then 566 + 1 = 567567

Let Us Think and Solve — Page 53Let Us Think and Solve

Let Us Think and Solve
Q1Nitin likes numbers that read the same when read from left to right or from right to left. Such numbers are called palindrome numbers. The numbers 22, 363, 404, and 8,558 are some examples. List all palindrome numbers between 100 and 200. List all palindrome numbers between 900 and 1,200. List all palindrome numbers between 25,000 and 27,000.
Answer

A palindrome number has the same first and last digit, the same second and second-last digit, and so on.

BetweenPalindrome numbers
100 and 200 (10 numbers)101, 111, 121, 131, 141, 151, 161, 171, 181, 191
900 and 1,200 (12 numbers)909, 919, 929, 939, 949, 959, 969, 979, 989, 999, 1,001, 1,111
25,000 and 27,000 (20 numbers)25,052, 25,152, 25,252, 25,352, 25,452, 25,552, 25,652, 25,752, 25,852, 25,952,
26,062, 26,162, 26,262, 26,362, 26,462, 26,562, 26,662, 26,762, 26,862, 26,962
Q2In a 3×3 grid, arrange the numbers 1 to 9 such that each row and each column has numbers in an increasing (inc) order. Each number should be used only once. This time, fill the grid such that each row and column has numbers in decreasing (dec) order.
incincincincincincdecdecdecdecdecdec
Two empty 3×3 grids: in the first, every row and every column must increase; in the second, every row and every column must decrease.
Answer

First grid — every row and every column increasing

123inc →
456inc →
789inc →
inc ↓inc ↓inc ↓

Second grid — every row and every column decreasing

987dec →
654dec →
321dec →
dec ↓dec ↓dec ↓
Q3Now, fill the grids below with numbers (1–9) based on the inc (increasing) and dec (decreasing) conditions, as indicated below.
Grid 1decdecdecincincincGrid 2decdecincdecdecincGrid 3incincdecincdecdec
Three empty 3×3 grids. The word beside each row and under each column says whether its numbers must increase (inc) or decrease (dec).
Answer

Grid 1 — all rows going down, all columns going up

321dec →
654dec →
987dec →
inc ↓inc ↓inc ↓

Grid 2 — rows: dec, dec, inc; columns: dec, dec, inc

861dec →
752dec →
349inc →
dec ↓dec ↓inc ↓

Grid 3 — rows: inc, inc, dec; columns: inc, dec, dec

168inc →
257inc →
943dec →
inc ↓dec ↓dec ↓

Even and Odd Numbers — Page 54Even and Odd Numbers

Q1Circle the numbers that are even. (a) 297 (b) 498 (c) 724 (d) 100 (e) 199 (f) 789 (g) 49 (h) 6,893 (i) 846 (j) 111 (k) 222 (l) 1,023
Answer

The even numbers are (b) 498, (c) 724, (d) 100, (i) 846 and (k) 222. Circle those five.

A number is even when its last digit is 0, 2, 4, 6 or 8.

NumberLast digitEven or odd
(a) 2977odd
(b) 4988even
(c) 7244even
(d) 1000even
(e) 1999odd
(f) 7899odd
(g) 499odd
(h) 6,8933odd
(i) 8466even
(j) 1111odd
(k) 2222even
(l) 1,0233odd
Q2Observe the given arrangement.
Paired arrangement for 18Paired arrangement for 23
The two paired arrangements printed with the question.
Add 2 to 18. What changes or does not change in the arrangement? Add 2 to 23. What changes or does not change in the arrangement?
Answer

In both cases the arrangement gets one more full pair. Whether anything is left over does not change.

  • 18 + 2 = 20: 9 pairs become 10 pairs. Still no counter is left alone, so 20 is even, like 18.
  • 23 + 2 = 25: 11 pairs become 12 pairs. The 1 extra counter is still alone, so 25 is odd, like 23.
Q3What do you notice about the sums in each of the following cases? Do you think it will be true for all pairs of such numbers? Explain your observations. You may use the paired arrangement to explain your thinking.
Paired arrangement for 18Paired arrangement for 23
The two paired arrangements printed with the question.
(a) 12 and 6 are a pair of even numbers. Choose 5 such pairs of even numbers. Add the numbers in each of the pairs. (b) 13 and 9 are a pair of odd numbers. Choose 5 such pairs of odd numbers. Add the numbers in each of the pairs. (c) 7 and 12 are a pair of odd and even numbers. Choose 5 such pairs of odd and even numbers. Add the numbers in each of the pairs.
Answer

(a) even + even = even   (b) odd + odd = even   (c) odd + even = odd. Yes, this is true for every such pair.

PairSumEven or odd
12 and 618even
8 and 412even
20 and 1030even
14 and 1630even
2 and 1820even

(a) Only full pairs + only full pairs gives only full pairs, so the sum is even.

PairSumEven or odd
13 and 922even
7 and 512even
11 and 314even
15 and 2136even
1 and 910even

(b) Each odd number has one counter left alone; the two lonely counters make a pair, so the sum is even.

PairSumEven or odd
7 and 1219odd
3 and 811odd
9 and 615odd
15 and 419odd
11 and 2031odd

(c) The odd number’s lonely counter finds no partner, so the sum is odd.

Let Us Think — Pages 54–55Let Us Think

Let Us Think
Q1Jincy opened her piggy bank. She found 8 coins of ₹1, 9 coins of ₹2 and 5 coins of ₹5. She wants to buy stickers worth ₹38. What possible combination of coins can she use to pay the exact amount?
Answer

Any one of these combinations pays exactly ₹38:

  • 5 coins of ₹5 + 6 coins of ₹2 + 1 coin of ₹1 = 25 + 12 + 1 = ₹38
  • 4 coins of ₹5 + 9 coins of ₹2 = 20 + 18 = ₹38
  • 3 coins of ₹5 + 9 coins of ₹2 + 5 coins of ₹1 = 15 + 18 + 5 = ₹38
Q2Raghu is fond of his grandfather’s torch. He starts playing with it. He presses the switch once and the light turns ON. He presses it a second time and the light turns OFF. He presses the switch a third time and the light turns ON. He keeps doing this several times. Will the torch be ON or OFF after the 23rd press? How do you know? For what number of presses will the torch be ON? For what number of presses of the switch will the torch be OFF?
Answer

After the 23rd press the torch is ON, because 23 is an odd number.

The presses come in ON–OFF pairs. 23 presses = 11 pairs + 1 more press, and that last press turns the torch ON.

The torch is ON after an odd number of presses and OFF after an even number of presses.

PressTorchOdd or even
1ONodd
2OFFeven
3ONodd
4OFFeven
5ONodd
6OFFeven
………
23ONodd
Q3Mountain climbing. Priyanka Mohite is the first Indian woman to climb five Himalayan peaks above 8,000 metres. Read the table and answer:
Mountain RangeHeight (in metres)Climbed in the Year
Mount Kanchenjunga (India and Nepal border)8,5862022
Mount Everest (Nepal–China border)8,8482013
Mount Makalu (China–Nepal border)8,4852019
Mount Lhotse (Tibet–Nepal border)8,5162018
Mount Kilimanjaro (Africa)5,8952016
Mount Elbrus (Russia)5,6422017
Mount Annapurna I (Nepal)8,0912021
(a) Which is the highest peak she climbed? (b) What is the difference in height between the highest and lowest peaks she has climbed, as per the table. (c) What is the difference between heights of Mount Elbrus and Mount Kanchenjunga? (d) If Priyanka was 20 years old when she summited Mount Everest in 2013, in which year was she born?
Answer

(a) Mount Everest, 8,848 m.

(b) Highest − lowest = 8,848 m − 5,642 m = 3,206 m

8848
−5642
3206

(c) Kanchenjunga − Elbrus = 8,586 m − 5,642 m = 2,944 m

715
8586
−5642
2944

(d) 2013 − 20 = 1993. She was born in 1993.

Math Metric Mela — Page 56Math Metric Mela

Q1For each district, find out if the number of certificates were sufficient? If insufficient, calculate how many certificates fell short. If extra, calculate how many certificates were in excess. Chittoor, A.P. — printed 18,225, attended 18,104. Jaunpur, U.P. — printed 19,043, attended 19,265. Raigad, Maharashtra — printed 20,863, attended 19,974.
Answer

Chittoor and Raigad had enough certificates. Jaunpur fell short by 222.

DistrictPrinted / AttendedAnswer
Chittoor18,225 / 18,104Enough: 121 extra
Jaunpur19,043 / 19,265Short by 222
Raigad20,863 / 19,974Enough: 889 extra
Chittoor
18225
−18104
121
Jaunpur
19265
−19043
222
Raigad
19171513
20863
−19974
889

Let Us Do — Page 56Math Metric Mela

Let Us Do
Q1Add. (a) 2,009 + 7,388 (b) 26,444 + 71,111 (c) 777 + 888 (d) 1,234 + 1,234 (e) 56 + 56,789 (f) 777 + 77,777 (f) 5,922 + 9,221 (g) 4,321 + 8,765 (h) 50,050 + 55,000
Answer

Answers: (a) 9,397  (b) 97,555  (c) 1,665  (d) 2,468  (e) 56,845  (f) 78,554  (f, 2nd) 15,143  (g) 13,086  (h) 1,05,050

(a)
1
2009
+7388
9397
(b)
26444
+71111
97555
(c)
111
777
+888
1665
(d)
1234
+1234
2468
(e)
11
56
+56789
56845
(f)
111
777
+77777
78554
(f, 2nd)
11
5922
+9221
15143
(g)
11
4321
+8765
13086
(h)
1
50050
+55000
105050
Q2Subtract. (a) 458 – 226 (b) 7,777 – 4,449 (c) 65,447 – 47,299 (d) 1,234 – 123 (e) 12,345 – 1,234 (f) 56,789 – 56 (f) 87,326 – 11,111 (g) 878 – 52 (h) 749 – 222
Answer

Answers: (a) 232  (b) 3,328  (c) 18,148  (d) 1,111  (e) 11,111  (f) 56,733  (f, 2nd) 76,215  (g) 826  (h) 527

(a)
458
−226
232
(b)
617
7777
−4449
3328
(c)
51531317
65447
−47299
18148
(d)
1234
−123
1111
(e)
12345
−1234
11111
(f)
56789
−56
56733
(f, 2nd)
87326
−11111
76215
(g)
878
−52
826
(h)
749
−222
527
Q3Ambrish saved ₹92,375 over a year to buy cows and goats. He buys a cow for ₹26,000 and a goat for ₹17,000. He also buys a milking machine for ₹19,873. Does he have enough money to buy these? How much more or less does he have than he needs?
Answer

Yes, he has enough. He is left with ₹29,502 after all three purchases.

  1. 26,000 + 17,000 = 43,000  (cow and goat)
  2. 43,000 + 19,873 = 62,873  (add the milking machine)
Total cost = ₹62,873
81113
92375
−62873
29502
92,375 − 62,873 = ₹29,502 more than he needs
Q4A factory produces 54,000 nuts and bolts in a day. An order is placed for 85,300 nuts and bolts. How many more nuts and bolts does the factory need to produce to complete the order?
Answer

The factory needs 31,300 more nuts and bolts.

Still needed = 85,300 − 54,000
85300
−54000
31300
85,300 − 54,000 = 31,300 nuts and bolts
Q5Virat Kohli has scored 27,599 runs. He has 6,758 runs less than Sachin Tendulkar. How many runs has Sachin Tendulkar scored?
Answer

Sachin Tendulkar has scored 34,357 runs.

Sachin’s runs = 27,599 + 6,758
1111
27599
+6758
34357
Sachin Tendulkar’s runs = 34,357 runs

Chapter 4 of 15 – Maths

Also for This Chapter

NCERT Solutions Class 5 Maths Chapter 4 We the Travellers Ii – Overview

ClassClass 5
SubjectMaths
Chapter4 – We the Travellers Ii
Textbook pages42 – 56
Questions solved64
Session2027
FormatFull answers on this page + PDF

NCERT Solutions Class 5 Maths Chapter 4 – FAQs

Where can I download NCERT Solutions Class 5 Maths Chapter 4 We the Travellers Ii PDF?

Read every answer on this page, or download the free PDF from the table at the top.

Is this for the 2027 session?

Yes, it follows the latest NCERT Class 5 Maths book for 2027.

How many questions are solved in NCERT Class 5 Maths Chapter 4?

All 64 questions of the chapter (textbook pages 42 – 56) – the in-text questions, activities and the end-of-chapter exercises.

How should I use these solutions?

Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.

Official website: ncert.nic.inNational Council of Educational Research and Training publishes date sheets, admit cards and results here
Visit
Go back to
NCERT Solutions Class 5 MathsNCERT Solutions Class 5NCERT

Ask a question

?

Loading comments…