NCERT Solutions for Class 5 Maths Chapter 9 Coconut Farm – step-by-step answers to every exercise and in-text question of the chapter, as per the latest NCERT syllabus for 2027. Read them online or download the free question-answer PDF.
Chapter 9 of Math Mela is about division. Susie and Sunitha’s coconut farm in Kerala gives the story: 1,117 coconuts to share among customers, husk to weigh, oil to bottle. Along the way you learn that every multiplication fact hides two division facts, that a big division can be done in easy chunks (partial quotients), that place value lets you divide digit by digit, and that when the sharing does not come out even, what is left over is called the remainder.
NCERT Solutions for Class 5 Maths Chapter 9 Coconut Farm PDF
All the answers are on this page below. The PDF also explains every answer – why it is right and how to check it – so download it for revision.
| Chapter | Download | |
|---|---|---|
| Solutions PDF (English medium) | Coconut Farm | View PDF |
| Solutions PDF (Hindi medium) | नारियल का खेत | View PDF |
NCERT Solutions for Class 5 Maths Chapter 9 Coconut Farm – Questions and Answers
All 95 questions of the chapter (textbook pages 119 – 135) are answered below, in the order of the book – in-text questions, activities and the end-of-chapter exercises. Each answer is written the way you would write it in the exam.
Division Facts — Page 119Arrays of coconuts, and the rule N = D × Q
35 ÷ 7 = 5 and 35 ÷ 5 = 7.
First division fact: 35 ÷ 7 = 5
35 split into 7 groups has 5 in each group
Second division fact: 35 ÷ 5 = 7
35 split into 5 groups has 7 in each group
35 ÷ 1 = 35.
Check by multiplying back:
N = D × Q
1 × 35 = 35 ✓
_____ × _____ = _____
_____ ÷ _____ = _____
_____ ÷ _____ = _____
Multiplication fact: 4 × 8 = 32. Division facts: 32 ÷ 8 = 4 and 32 ÷ 4 = 8.
32 ÷ 8 = 4
32 ÷ 4 = 8
Let Us Play — Page 120Fill the circles so that the number in the square is the product or the quotient
Any two numbers whose product is the number in the square are correct. One answer for each square:
| Square (product) | One answer | Check | Other correct answers |
|---|---|---|---|
| 72 | 36 × 2 | 36 × 2 = 72 | 8 × 9, 12 × 6, 24 × 3, 18 × 4 |
| 60 | 30 × 2 | 30 × 2 = 60 | 6 × 10, 12 × 5, 15 × 4, 20 × 3 |
| 48 | 24 × 2 | 24 × 2 = 48 | 6 × 8, 12 × 4, 16 × 3 |
| 36 | 18 × 2 | 18 × 2 = 36 | 6 × 6, 9 × 4, 12 × 3 |
| 24 | 12 × 2 | 12 × 2 = 24 | 6 × 4, 8 × 3, 24 × 1 |
| 40 | 20 × 2 | 20 × 2 = 40 | 8 × 5, 10 × 4, 40 × 1 |
First three puzzles — the square is the answer, so you must find a division that gives it.
| Square (quotient) | One answer | Check | Other correct answers |
|---|---|---|---|
| 54 | 108 ÷ 2 | 2 × 54 = 108 ✓ | 54 ÷ 1, 162 ÷ 3, 216 ÷ 4 |
| 42 | 84 ÷ 2 | 2 × 42 = 84 ✓ | 42 ÷ 1, 126 ÷ 3, 420 ÷ 10 |
| 56 | 112 ÷ 2 | 2 × 56 = 112 ✓ | 56 ÷ 1, 168 ÷ 3, 560 ÷ 10 |
Last three puzzles — here the first circle is already filled and the square is empty. Choose any number that divides it exactly.
| Puzzle | One answer | Square becomes | Other correct answers |
|---|---|---|---|
| 54 ÷ ○ | 54 ÷ 6 | 9 | 54 ÷ 9 = 6, 54 ÷ 2 = 27, 54 ÷ 3 = 18 |
| 42 ÷ ○ | 42 ÷ 6 | 7 | 42 ÷ 7 = 6, 42 ÷ 2 = 21, 42 ÷ 3 = 14 |
| 56 ÷ ○ | 56 ÷ 7 | 8 | 56 ÷ 8 = 7, 56 ÷ 4 = 14, 56 ÷ 2 = 28 |
Let Us Do — Page 120Solve the multiplication problem, then write two division statements
30 × 30 = 900. Division statements: 900 ÷ 30 = 30 (and again 900 ÷ 30 = 30).
900 ÷ 30 = 30
900 ÷ 30 = 30
400 × 8 = 3200. Division statements: 3200 ÷ 8 = 400 and 3200 ÷ 400 = 8.
3,200 ÷ 8 = 400
3,200 ÷ 400 = 8
15 × 60 = 900. Division statements: 900 ÷ 15 = 60 and 900 ÷ 60 = 15.
15 × 60 = 900
900 ÷ 15 = 60
900 ÷ 60 = 15
200 × 16 = 3200. Division statements: 3200 ÷ 16 = 200 and 3200 ÷ 200 = 16.
3,200 ÷ 16 = 200
3,200 ÷ 200 = 16
Let Us Do (Question 2) — Page 121Solve these division problems, notice the patterns and discuss in class
Use the hint each time: think of the multiplication that goes with the division.
| Division | Think of this multiplication | Answer |
|---|---|---|
| 150 ÷ 3 | 50 × 3 = 150 | 50 |
| 80 ÷ 4 | 20 × 4 = 80 | 20 |
| 500 ÷ 5 | 5 × 100 = 500 | 100 |
| 100 ÷ 10 | 10 × 10 = 100 | 10 |
| 300 ÷ 100 | 100 × 3 = 300 | 3 |
| 500 ÷ 50 | 50 × 10 = 500 | 10 |
| 200 ÷ 20 | 20 × 10 = 200 | 10 |
| 440 ÷ 44 | 44 × 10 = 440 | 10 |
| 630 ÷ 63 | 63 × 10 = 630 | 10 |
The three hints filled in:
5 × 100 = 500
44 × 10 = 440
Sample answer for the class discussion — three patterns.
Pattern 1 — ten times a number, divided by that number, always gives 10.
630 ÷ 63 = 10
500 ÷ 50 = 10
200 ÷ 20 = 10
Pattern 2 — a bigger divisor gives a smaller quotient.
500 ÷ 50 = 10
500 ÷ 500 = 1
Patterns in Division and Place Value — Page 121The blue boxes and the two place value charts
| Division | Think of this multiplication | Answer |
|---|---|---|
| 1000 ÷ 10 | 10 × 100 = 1000 | 100 |
| 1000 ÷ 100 | 100 × 10 = 1000 | 10 |
| 1600 ÷ 4 | 4 × 400 = 1600 | 400 |
| 2000 ÷ 2 | 2 × 1000 = 2000 | 1000 |
| 2000 ÷ 20 | 20 × 100 = 2000 | 100 |
| 3700 ÷ 37 | 37 × 100 = 3700 | 100 |
| 3300 ÷ 3 | 3 × 1100 = 3300 | 1,100 |
| 3300 ÷ 300 | 300 × 11 = 3300 | 11 |
| 4000 ÷ 40 | 40 × 100 = 4000 | 100 |
The two hints filled in:
37 × 100 = 3700
| Problem | H | T | O |
|---|---|---|---|
| 40 ÷ 10 = | 4 | ||
| 400 ÷ 10 = | 4 | 0 | |
| 4000 ÷ 10 = | 4 | 0 | 0 |
| 700 ÷ 70 = | |||
| 1400 ÷ 100 = | |||
| 220 ÷ 20 = | |||
| 2200 ÷ 20 = |
The first three rows are done in the book. Here is the whole chart. H means Hundreds, T means Tens, O means Ones.
| Problem | H | T | O | Quotient |
|---|---|---|---|---|
| 40 ÷ 10 = | 4 | 4 | ||
| 400 ÷ 10 = | 4 | 0 | 40 | |
| 4000 ÷ 10 = | 4 | 0 | 0 | 400 |
| 700 ÷ 70 = | 1 | 0 | 10 | |
| 1400 ÷ 100 = | 1 | 4 | 14 | |
| 220 ÷ 20 = | 1 | 1 | 11 | |
| 2200 ÷ 20 = | 1 | 1 | 0 | 110 |
| Problem | H | T | O |
|---|---|---|---|
| 110 ÷ 11 = | |||
| 860 ÷ 86 = | |||
| 7500 ÷ 750 = | |||
| 8800 ÷ 88 = | |||
| 2400 ÷ 24 = | |||
| 440 ÷ 22 = |
| Problem | H | T | O | Quotient |
|---|---|---|---|---|
| 110 ÷ 11 = | 1 | 0 | 10 | |
| 860 ÷ 86 = | 1 | 0 | 10 | |
| 7500 ÷ 750 = | 1 | 0 | 10 | |
| 8800 ÷ 88 = | 1 | 0 | 0 | 100 |
| 2400 ÷ 24 = | 1 | 0 | 0 | 100 |
| 440 ÷ 22 = | 2 | 0 | 20 |
Sample answer for the class discussion.
1. When the dividend grows ten times and the divisor stays the same, the quotient grows ten times.
400 ÷ 10 = 40
4000 ÷ 10 = 400
2. When both the dividend and the divisor grow ten times, the quotient does not change.
3. When the divisor grows and the dividend stays the same, the quotient shrinks.
Let Us Do — Page 122Word problems, the 1-to-8 puzzle, and fill in the blanks
Sabina cycles 8 km each day.
Step 2: Cover one zero in each number → 16 ÷ 2
Step 3: 16 ÷ 2 = 8
Step 4: So 160 ÷ 20 = 8 km
Seema needs 42 notes of ₹100.
We need to find how many ₹100 notes make ₹4200. So we ask: how many hundreds are there in 4200?
Step 2: Dividing by 100 removes two zeros
Step 3: 4200 ÷ 100 = 42 notes
With 5 employees each gets ₹1100. With 10 employees each gets only ₹550 — less. To give ₹1100 to all 10, he would need ₹11,000.
Step 2: Split 5500 into 5000 + 500
Step 3: 5000 ÷ 5 = 1000 and 500 ÷ 5 = 100
Step 4: 1000 + 100 = ₹1,100 each
Step 2: Dividing by 10 removes one zero
Step 3: 5500 ÷ 10 = ₹550 each
One correct filling: 6 ÷ 3 = 2, then 6 − 5 = 1, 2 × 4 = 8, and 1 + 7 = 8. Yes, there is more than one answer — another is 8 ÷ 4 = 2, 8 − 7 = 1, 2 × 3 = 6, 1 + 5 = 6.
(a) _____ ÷ 18 = 100.
(b) _____ ÷ 10 = 610.
(c) _____ ÷ 100 = 72.
(d) _____ ÷ 100 = 10.
(e) 870 ÷ _____ = 87.
(f) _____ ÷ 100 = 70.
(g) 200 ÷ _____ = 2.
(h) 130 ÷ _____ = 13.
Use the rule N = D × Q every time.
| Part | Question | What to do | Answer |
|---|---|---|---|
| (a) | ___ ÷ 18 = 100 | 18 × 100 | 1,800 |
| (b) | ___ ÷ 10 = 610 | 10 × 610 | 6,100 |
| (c) | ___ ÷ 100 = 72 | 100 × 72 | 7,200 |
| (d) | ___ ÷ 100 = 10 | 100 × 10 | 1,000 |
| (e) | 870 ÷ ___ = 87 | 870 ÷ 87 | 10 |
| (f) | ___ ÷ 100 = 70 | 100 × 70 | 7,000 |
| (g) | 200 ÷ ___ = 2 | 200 ÷ 2 | 100 |
| (h) | 130 ÷ ___ = 13 | 130 ÷ 13 | 10 |
Mental Strategies for Division — Page 123Splitting the number, and repeated halving
Here are five. The idea is to break the dividend into parts that your tables already know.
| Division | Split it like this | Divide each part | Answer |
|---|---|---|---|
| 1236 ÷ 6 | 1200 + 36 | 200 + 6 | 206 |
| 728 ÷ 7 | 700 + 28 | 100 + 4 | 104 |
| 2408 ÷ 8 | 2400 + 8 | 300 + 1 | 301 |
| 4515 ÷ 5 | 4500 + 15 | 900 + 3 | 903 |
| 996 ÷ 4 | 1000 − 4 | 250 − 1 | 249 |
Repeated halving works whenever the divisor is 2, 4, 8, 16, 32 … — the numbers you get by doubling 2.
| Divisor | How many times to halve | Example | Answer |
|---|---|---|---|
| 2 | once | 86 → 43 | 86 ÷ 2 = 43 |
| 4 | twice | 128 → 64 → 32 | 128 ÷ 4 = 32 |
| 8 | three times | 96 → 48 → 24 → 12 | 96 ÷ 8 = 12 |
| 16 | four times | 320 → 160 → 80 → 40 → 20 | 320 ÷ 16 = 20 |
Try It! — Page 123Fill the boxes: split the dividend, or halve again and again
64 ÷ 4 = 16.
- Split 64 into two parts that 4 divides easily: 64 = 40 + 24.
- Divide the first part: 40 ÷ 4 = 10.
- Divide the second part: 24 ÷ 4 = 6.
- Add: 10 + 6 = 16.
265 ÷ 5 = 53.
250 ÷ 5 = 50
15 ÷ 5 = 3
50 + 3 = 53
1560 ÷ 8 = 195.
1600 ÷ 8 = 200
40 ÷ 8 = 5
200 − 5 = 195
4824 ÷ 24 = 201.
4800 ÷ 24 = 200
24 ÷ 24 = 1
200 + 1 = 201
168 ÷ 8 = 21.
8 is 2 × 2 × 2, so halve three times.
Halve 84 → 42
Halve 42 → 21
So 168 ÷ 8 = 21
144 ÷ 4 = 36.
4 is 2 × 2, so halve twice.
Halve 72 → 36
So 144 ÷ 4 = 36
Let Us Solve — Page 124Solve using the strategies used in the previous question
256 ÷ 4 = 64.
- Split 256 into 240 + 16.
- 240 ÷ 4 = 60.
- 16 ÷ 4 = 4.
- 60 + 4 = 64.
545 ÷ 5 = 109.
- Split 545 into 500 + 45.
- 500 ÷ 5 = 100.
- 45 ÷ 5 = 9.
- 100 + 9 = 109.
147 ÷ 7 = 21.
- Split 147 into 140 + 7.
- 140 ÷ 7 = 20.
- 7 ÷ 7 = 1.
- 20 + 1 = 21.
1212 ÷ 6 = 202.
- Split 1212 into 1200 + 12.
- 1200 ÷ 6 = 200.
- 12 ÷ 6 = 2.
- 200 + 2 = 202.
648 ÷ 12 = 54.
- Split 648 into 600 + 48.
- 600 ÷ 12 = 50 (because 12 × 5 = 60, so 12 × 50 = 600).
- 48 ÷ 12 = 4.
- 50 + 4 = 54.
9648 ÷ 48 = 201.
- Split 9648 into 9600 + 48.
- 9600 ÷ 48 = 200 (because 48 × 2 = 96, so 48 × 200 = 9600).
- 48 ÷ 48 = 1.
- 200 + 1 = 201.
775 ÷ 25 = 31.
- Split 775 into 750 + 25.
- 750 ÷ 25 = 30 (because 25 × 3 = 75, so 25 × 30 = 750).
- 25 ÷ 25 = 1.
- 30 + 1 = 31.
796 ÷ 4 = 199.
796 is very close to 800, so use the take away split.
- Write 796 = 800 − 4.
- 800 ÷ 4 = 200.
- 4 ÷ 4 = 1.
- 200 − 1 = 199.
Susie’s Farm in Kerala — Pages 124–125Susie’s and Sunitha’s ways of dividing, and packing coconuts into bags
Each customer got 97 coconuts.
Estimate first. 6 × 100 = 600, and 600 is more than 582. So each customer must get a little less than 100 coconuts. Now do the division and see if the answer matches the estimate.
Sunitha’s way — take away one big chunk. She sees straight away that 6 × 90 = 540.
−540 → 42
−42 → 00
90 + 7 = 97
Sunitha’s method is better for a quick answer, because it needs only 2 steps instead of 6.
| Susie’s way | Sunitha’s way | |
|---|---|---|
| Chunks taken away | 120, 120, 120, 120, 60, 42 | 540, 42 |
| Number of steps | 6 | 2 |
| Table facts needed | only 6 × 20 | 6 × 90 |
| Chances of a mistake | more, as there are more subtractions | fewer |
4 bags.
N = D × Q + R
97 = 25 × 3 + 22 ✓
Bags needed = 3 full + 1 part-full = 4 bags
22 bags.
−500 → 35 (25 × 20 = 500)
−25 → 10 (25 × 1 = 25)
Quotient = 20 + 1 = 21, Remainder = 10
Let Us Learn to Divide — Page 125Filling the partial-quotient ladders, and the rule N = D × Q + R
− ____ → 326
−320 → 6
− ____ → 2
726 ÷ 4 = 181 with remainder 2. The blanks are 80 and 1 in the quotient, and 400 and 4 in the take-away steps. We could not write 200, because 4 × 200 = 800 is more than 726.
−400 → 326 (4 × 100 = 400)
−320 → 6 (4 × 80 = 320)
−4 → 2 (4 × 1 = 4)
Quotient = 100 + 80 + 1 = 181
Remainder = 2
−800 → ____
−96 → 6
902 ÷ 16 = 56 with remainder 6. The blanks are 50 and 102 (902 − 800). We write 50 because 16 × 50 = 800 is close to 902 but less than it. We could not use a larger tens: 16 × 60 = 960 is more than 902.
−800 → 102 (16 × 50 = 800)
−96 → 6 (16 × 6 = 96)
Quotient = 50 + 6 = 56
Remainder = 6
Is 726 = 4 × 181? Yes/No. So, 726 = 4 × 181 + ______.
Is 902 = 16 × 56? Yes/No. So, 902 = 16 × 56 + ______.
The relationship is N = D × Q + R.
First one: Is 726 = 4 × 181? No.
724 is 2 less than 726
So 726 = 4 × 181 + 2
Second one: Is 902 = 16 × 56? No.
896 is 6 less than 902
So 902 = 16 × 56 + 6
Let Us Solve — Page 126Solve the following word problems
Packs of 6 are the better single choice — she needs 42 packs and only 2 samosas are left over.
| Pack size | Packs needed | Samosas bought | Left over |
|---|---|---|---|
| 6 | 42 | 252 | 2 |
| 8 | 32 | 256 | 6 |
Reason: Both choices feed all 250 guests. Packs of 6 waste only 2 samosas, packs of 8 waste 6. So packs of 6 are the better buy. (If Rani cares more about carrying fewer packs, packs of 8 mean only 32 packs to carry instead of 42.)
The school needs 9 buses.
Step 2: 41 × 8 = 328 (this fits)
Step 3: 41 × 9 = 369 (too many seats, but 8 buses are not enough)
Step 4: 342 − 328 = 14 students left over
Step 5: Those 14 students also need a bus
Buses = 8 full + 1 more = 9 buses
There are six ways. The neatest is 8 notes of ₹50 and 6 notes of ₹20.
| ₹50 notes | Value | Still to pay | ₹20 notes | Check |
|---|---|---|---|---|
| 0 | ₹0 | ₹520 | 26 | 26 × 20 = 520 ✓ |
| 2 | ₹100 | ₹420 | 21 | 100 + 420 = 520 ✓ |
| 4 | ₹200 | ₹320 | 16 | 200 + 320 = 520 ✓ |
| 6 | ₹300 | ₹220 | 11 | 300 + 220 = 520 ✓ |
| 8 | ₹400 | ₹120 | 6 | 400 + 120 = 520 ✓ |
| 10 | ₹500 | ₹20 | 1 | 500 + 20 = 520 ✓ |
Each person should pay ₹139.
157 + 124 = 281
281 + 136 = ₹417 in all
Step 2 — share it among 3 friends:
417 ÷ 3
Split 417 into 300 + 117
300 ÷ 3 = 100
117 ÷ 3 = 39
100 + 39 = ₹139
(a) 887 ÷ 3
(b) 283 ÷ 8
(c) 745 ÷ 5
(d) 767 ÷ 26
(e) 530 ÷ 41
(f) 888 ÷ 67
| Part | Division | Quotient (Q) | Remainder (R) | Check: N = D × Q + R |
|---|---|---|---|---|
| (a) | 887 ÷ 3 | 295 | 2 | 3 × 295 + 2 = 885 + 2 = 887 ✓ |
| (b) | 283 ÷ 8 | 35 | 3 | 8 × 35 + 3 = 280 + 3 = 283 ✓ |
| (c) | 745 ÷ 5 | 149 | 0 | 5 × 149 + 0 = 745 ✓ |
| (d) | 767 ÷ 26 | 29 | 13 | 26 × 29 + 13 = 754 + 13 = 767 ✓ |
| (e) | 530 ÷ 41 | 12 | 38 | 41 × 12 + 38 = 492 + 38 = 530 ✓ |
| (f) | 888 ÷ 67 | 13 | 17 | 67 × 13 + 17 = 871 + 17 = 888 ✓ |
Kalpavruksha Coconut Oil — Pages 126–127Oil, coir and tender coconuts from Susie and Sunitha’s farm
They extracted 547 litres of oil.
Sunitha’s way — the biggest chunk first. She thinks: 8 × 500 = 4000, and 4000 is close to 4376.
−4000 → 376
−320 → 56
−56 → 00
500 + 40 + 7 = 547
They will earn ₹95,725.
Step 2 — multiply each part:
547 × 100 = 54,700
547 × 70 = 38,290
547 × 5 = 2,735
Step 3 — add them up:
54,700 + 38,290 = 92,990
92,990 + 2,735 = ₹95,725
They sold 431 kg of coconut husk in May.
−9200 → 713 (23 × 400)
−690 → 23 (23 × 30)
−23 → 00 (23 × 1)
Quotient = 400 + 30 + 1 = 431 kg, Remainder = 0
What would happen if 23 is multiplied by 300 or 500?
| Chunk tried | 23 × chunk | What happens |
|---|---|---|
| 300 | 6,900 | It fits, but 3,013 would still be left — you would need extra steps. Too small a chunk. |
| 400 | 9,200 | Fits and comes closest to 9,913. Best choice. |
| 500 | 11,500 | Bigger than 9,913 — you cannot take away more than you have. |
−7000 → 1890
− ____ → 140
− ____ → 00
Ibrahim sold 254 tender coconuts. The blanks are 200 and 4 in the quotient, and 1,750 and 140 in the take-away steps.
−7000 → 1890 (35 × 200 = 7000)
−1750 → 140 (35 × 50 = 1750)
−140 → 00 (35 × 4 = 140)
Quotient = 200 + 50 + 4 = 254, Remainder = 0
The cost of _______ coconuts at ₹20 each = _______ × ₹20 = ₹_______.
He earned ₹8890 from the sale.
The extra amount he earned is ₹8890 – ₹_______ = ₹_______.
He earned ₹3,810 extra.
= 254 × ₹20
= ₹5,080
He earned ₹8,890 from the sale.
Extra amount = ₹8,890 − ₹5,080 = ₹3,810
Division Using Place Value — Pages 128–129Sunitha’s mother shares the candies; dividing Hundreds, Tens and Ones in turn
Each child gets 12 candies, and 2 candies are left over.
5) 62 ( 1 2
−5
──
12 (Ones)
−10
──
2 (remainder)
75 ÷ 8 = 9 with remainder 3. The 7 Tens cannot be shared among 8 without breaking them, so each part gets 0 Tens. We regroup the 7 Tens into 70 Ones, making 75 Ones, and share those: each part gets 9.
8) 75 ( 0 9
−72 (Ones)
──
3 (remainder)
324 ÷ 3 = 108, with no remainder. We put 0 in the Tens place because the 2 Tens cannot be shared among 3 — each part gets 0 Tens. Without the 0 the answer would wrongly read 18.
3) 324 ( 1 0 8
−3 (Hundreds)
──
2 (Tens)
−0
──
24 (Ones)
−24
──
00
136 ÷ 6 = 22 with remainder 4.
6) 136 ( 0 2 2
−12 (Tens)
──
16 (Ones)
−12
──
4 (remainder)
Yes. Compare the divisor with the front of the dividend.
- Look at the first digit of the dividend. If the divisor is smaller than or equal to it, the quotient has the same number of digits as the dividend.
- If the divisor is bigger than that first digit, the quotient has one digit fewer.
| Problem | Divisor vs first digit | Digits in the quotient | Quotient |
|---|---|---|---|
| 324 ÷ 3 | 3 is not bigger than 3 | 3 digits | 108 |
| 136 ÷ 6 | 6 is bigger than 1 | 2 digits | 22 |
| 62 ÷ 5 | 5 is not bigger than 6 | 2 digits | 12 |
| 75 ÷ 8 | 8 is bigger than 7 | 1 digit | 9 |
Let Us Divide — Pages 130–131Each division done twice: with partial quotients and with place value
(a) 7,032 ÷ 6 — complete the partial-quotient working. (The place value working for this division is printed complete in the book: 6) 7,032 ( 1 1 7 2.)
Partial quotients:
− ______ → 1,032
− 600 → 432
− ______ → 12
− ______ → ______
7,032 ÷ 6 = 1,172, with no remainder. The blanks are 100 and 2.
First way — partial quotients (take away chunks).
−6000 → 1032 (6 × 1000)
−600 → 432 (6 × 100)
−420 → 12 (6 × 70)
−12 → 0 (6 × 2)
1000 + 100 + 70 + 2 = 1,172
Second way — place value (Thousands, Hundreds, Tens, Ones).
−6 (Thousands)
10 (Hundreds)
−6
43 (Tens)
−42
12 (Ones)
−12
0
(b) 3,005 ÷ 5 — complete both solutions. Discuss why we have to write the 0 in the quotient.
Partial quotients:
−3,000 → 5
− ____ → 0
Place value:
−30 (Hundreds)
00 (Tens)
−00
0 ___ (Ones)
−5
0
3,005 ÷ 5 = 601, with no remainder. The blanks are 600 and 1. The 0 in the Tens place shows that each part gets no Tens; without it the answer would read 61.
First way — partial quotients.
−3000 → 5 (5 × 600)
−5 → 0 (5 × 1)
600 + 1 = 601
Second way — place value.
−30 (Hundreds)
00 (Tens)
−0
05 (Ones)
−5
0
(c) 2,874 ÷ 14 — complete both solutions.
Partial quotients:
−2,800 → ____
− ____ → ____
Place value:
−28 (Hundreds)
____ ( ______ )
− ____
7 ___ ( ______ )
− ____
____
2,874 ÷ 14 = 205 with remainder 4. The blanks are 200 and 5.
First way — partial quotients.
−2800 → 74 (14 × 200 = 2800)
−70 → 4 (14 × 5 = 70)
Quotient = 200 + 5 = 205, Remainder = 4
Second way — place value.
−28 (Hundreds)
07 (Tens)
−0
74 (Ones)
−70
4 (remainder)
(d) 9,805 ÷ 32 — complete both solutions. Compare both solutions. Also, remember to put 0 in the right places.
Partial quotients:
− ______ → 205
− ____ → ____
Place value:
− ____ (Hundreds)
____ ( ______ )
− ____
____ ( ______ )
− ____
____
9,805 ÷ 32 = 306 with remainder 13. The blanks are 300 and 6.
First way — partial quotients.
−9600 → 205 (32 × 300 = 9600)
−192 → 13 (32 × 6 = 192)
Quotient = 300 + 6 = 306, Remainder = 13
Second way — place value.
−96 (Hundreds)
20 (Tens)
−0
205 (Ones)
−192
13 (remainder)
Compare both solutions — sample answer:
| Partial quotients | Place value | |
|---|---|---|
| What you take away | whole chunks like 32 × 300 | one place value at a time |
| Number of steps | 2 | 4 (Th, H, T, O) |
| Chance of a zero mistake | low — you add the chunks up | higher — the 0 in the Tens place is easy to forget |
| Answer | 306 R 13 | 306 R 13 — the same |
Let Us Do — Page 131Find the missing numbers, and the 3-digit number riddle
| 4) 480 ( □ □ 0 | 3) 906 ( □ 0 □ |
| 20) 400 ( □ 0 | 50) 100□ ( □ 0 |
| □) 8 □ 8 ( 2 1 □ | 3) □ 3 6 ( 3 □ □ |
| □) 8 8 ( □ □ | □) 9 □ 0 ( □ □ □ |
| □) 1 8 0 ( □ □ □ | □) 6,4 8 0 ( □ □ □ |
| Puzzle | Filled in | How to find it | Other answers |
|---|---|---|---|
| 4) 480 ( □ □ 0 | 4) 480 ( 1 2 0 | 480 ÷ 4 = 120 | only one |
| 3) 906 ( □ 0 □ | 3) 906 ( 3 0 2 | 906 ÷ 3 = 302 | only one |
| 20) 400 ( □ 0 | 20) 400 ( 2 0 | 400 ÷ 20 = 20 | only one |
| 50) 100 □ ( □ 0 | 50) 1000 ( 2 0 | 50 × 20 = 1000, so the missing digit is 0 | only one |
| □) 8 □ 8 ( 2 1 □ | 4) 848 ( 2 1 2 | 4 × 212 = 848 | 4) 868 ( 2 1 7 |
| 3) □ 3 6 ( 3 □ □ | 3) 936 ( 3 1 2 | 3 × 312 = 936 | only one |
| □) 8 8 ( □ □ | 4) 88 ( 2 2 | 4 × 22 = 88 | 2) 88 ( 4 4, 8) 88 ( 1 1 and 1) 88 ( 8 8 |
| □) 9 □ 0 ( □ □ □ | 3) 900 ( 3 0 0 | 3 × 300 = 900 | 2) 900 ( 4 5 0, 5) 900 ( 1 8 0, 4) 920 ( 2 3 0 … |
| □) 1 8 0 ( □ □ □ | 1) 180 ( 1 8 0 | only a divisor of 1 keeps the quotient 3-digit | only one |
| □) 6,4 8 0 ( □ □ □ | 8) 6480 ( 8 1 0 | 8 × 810 = 6480 | 9) 6480 ( 7 2 0 |
The number is 210.
Clue 1 — divide me by 5 and you get 42.
So Number = 5 × 42
5 × 42 = 5 × 40 + 5 × 2
= 200 + 10
= 210
Clue 2 — multiply me by 2 and you get 420.
So Number = 420 ÷ 2
= 210
Let Us Solve — Pages 132–133Shows, ice cream, biscuits, remainders, relations, the cycle rally and the carpenter
(a) A total of 475 people bought tickets for a puppet show. How many shows are needed to seat all the people who bought tickets?
(b) There are 2 shows in a day. How many days will be needed to accommodate all the people?
(a) 11 shows. (b) 6 days.
Step 2: 45 × 10 = 450, which fits
Step 3: 475 − 450 = 25 people still without a seat
Step 4: Those 25 need one more show
Shows = 10 full + 1 more = 11 shows
Step 2: 2 × 5 = 10, and 11 − 10 = 1
Step 3: 1 show is left after 5 days, so it needs one more day
Days = 5 + 1 = 6 days
Each friend ate 200 g of ice cream.
1 kg = 1000 g
5 kg = 5 × 1000 = 5000 g
Step 2 — take away what was left:
5000 g − 400 g = 4600 g was eaten
Step 3 — share it among 23 friends:
4600 ÷ 23
23 × 200 = 4600
So each friend ate 200 g
Each person can have 5 biscuits each day.
15 packets × 8 biscuits = 120 biscuits
Step 2 — how many shares?
6 people × 4 days = 24 shares
(one share is what one person eats on one day)
Step 3 — divide:
120 ÷ 24 = 5 biscuits
(a) 9,045 ÷ 5
(b) 1,034 ÷ 4
(c) 2,504 ÷ 7
(d) 8,900 ÷ 15
(e) 9,876 ÷ 32
(f) 7,506 ÷ 24
| Part | Division | Quotient (Q) | Remainder (R) | Check: N = D × Q + R |
|---|---|---|---|---|
| (a) | 9,045 ÷ 5 | 1,809 | 0 | 5 × 1809 = 9,045 ✓ |
| (b) | 1,034 ÷ 4 | 258 | 2 | 4 × 258 + 2 = 1032 + 2 = 1,034 ✓ |
| (c) | 2,504 ÷ 7 | 357 | 5 | 7 × 357 + 5 = 2499 + 5 = 2,504 ✓ |
| (d) | 8,900 ÷ 15 | 593 | 5 | 15 × 593 + 5 = 8895 + 5 = 8,900 ✓ |
| (e) | 9,876 ÷ 32 | 308 | 20 | 32 × 308 + 20 = 9856 + 20 = 9,876 ✓ |
| (f) | 7,506 ÷ 24 | 312 | 18 | 24 × 312 + 18 = 7488 + 18 = 7,506 ✓ |
(a) 340 ÷ 34 = 10
(b) 340 ÷ 17 = ___
(c) 680 ÷ 17 = ___
(d) 680 ÷ 34 = ___
(e) 170 ÷ 17 = ___
(f) 680 ÷ 68 = ___
| Part | Division | Answer | How it follows from the one above |
|---|---|---|---|
| (a) | 340 ÷ 34 | 10 | given in the book |
| (b) | 340 ÷ 17 | 20 | 17 is half of 34 → the answer doubles: 10 × 2 |
| (c) | 680 ÷ 17 | 40 | 680 is double 340 → the answer doubles again: 20 × 2 |
| (d) | 680 ÷ 34 | 20 | dividend doubled, divisor same as (a) → the answer doubles: 10 × 2 |
| (e) | 170 ÷ 17 | 10 | 170 is half of 340 and 17 is half of 34 → answer unchanged |
| (f) | 680 ÷ 68 | 10 | both doubled from (a) → answer unchanged |
(a) 192 ÷ 4 = 48
(b) 192 ÷ 8 = ___
(c) 384 ÷ 8 = ___
(d) 384 ÷ 4 = ___
(e) 384 ÷ 8 = ___
(f) 86 ÷ 2 = ___
| Part | Division | Answer | The relation used |
|---|---|---|---|
| (a) | 192 ÷ 4 | 48 | given in the book |
| (b) | 192 ÷ 8 | 24 | the divisor doubled (4 → 8), so the answer halves: 48 ÷ 2 |
| (c) | 384 ÷ 8 | 48 | both doubled from (a), so the answer is unchanged |
| (d) | 384 ÷ 4 | 96 | only the dividend doubled, so the answer doubles: 48 × 2 |
| (e) | 384 ÷ 8 | 48 | the same question as (c), so the same answer |
| (f) | 86 ÷ 2 | 43 | split 86 = 80 + 6, so 40 + 3 = 43 |
(a) 352 ÷ 11 = 32
(b) 704 ÷ 22 = ___
(c) 704 ÷ 11 = ___
(d) 352 ÷ 22 = ___
(e) 1,408 ÷ 44 = ___
| Part | Division | Answer | The relation used |
|---|---|---|---|
| (a) | 352 ÷ 11 | 32 | given in the book |
| (b) | 704 ÷ 22 | 32 | both doubled from (a), so the answer is unchanged |
| (c) | 704 ÷ 11 | 64 | only the dividend doubled, so the answer doubles: 32 × 2 |
| (d) | 352 ÷ 22 | 16 | only the divisor doubled, so the answer halves: 32 ÷ 2 |
| (e) | 1,408 ÷ 44 | 32 | both are four times those in (a), so the answer is unchanged |
(a) How much distance should they cycle every day, to cover the distance evenly?
(b) After reaching Ratnagiri, they rest for 1 day. How much distance should they cycle each day to reach Goa in 4 days? Assume that they cover the distance evenly.
(a) 48 km each day. (b) 58 km each day.
Step 2: Split 576 into 480 + 96
Step 3: 480 ÷ 12 = 40 and 96 ÷ 12 = 8
Step 4: 40 + 8 = 48 km per day
232 ÷ 4
Split 232 into 200 + 32
200 ÷ 4 = 50 and 32 ÷ 4 = 8
50 + 8 = 58 km per day
(a) A fruit vendor sells 6 baskets of mangoes. Each basket contains 12 mangoes. How much did the vendor earn in total?
(b) A school has 8 classrooms, and each classroom has an equal number of desks. How many desks are there in each classroom?
(c) Rahul buys 5 cricket bats for his team. The total bill is ₹3500. How much does one bat cost?
(d) A restaurant serves 125 plates of idlis in a day. The total earnings from selling all the idli plates is ₹6250. How many idlis are there in each plate?
For each part, first ask: what number do I need that the question has not given me?
| Part | What is missing | A sensible value to add | Answer with that value |
|---|---|---|---|
| (a) | the price of one mango | ₹15 per mango | ₹1,080 |
| (b) | the total number of desks in the school | 96 desks in all | 12 desks per classroom |
| (c) | nothing is missing | — | ₹700 per bat |
| (d) | the price of one idli | ₹10 per idli | 5 idlis per plate |
He can make 30 bookshelves.
| Part | Needed for 1 shelf | In stock | Division | Shelves possible |
|---|---|---|---|---|
| Long panels | 4 | 264 | 264 ÷ 4 = 66 | 66 |
| Short panels | 8 | 306 | 306 ÷ 8 = 38 R 2 | 38 |
| Small clips | 16 | 2,400 | 2400 ÷ 16 = 150 | 150 |
| Large clips | 4 | 120 | 120 ÷ 4 = 30 | 30 ← smallest |
| Screws | 32 | 2,800 | 2800 ÷ 32 = 87 R 16 | 87 |
Answer: 30 bookshelves, because the large clips run out first.
Vegetable Market — Page 134Munshi Lal’s record book, and what a bill records
| S.No. | Vegetable | Cost of 1 kg | Quantity Supplied (in kg) | Total Amount |
|---|---|---|---|---|
| 1. | Radish | ₹26 | 78 | ₹ ________ |
| 2. | Potato | ₹20 | ________ | ₹2,240 |
| 3. | Cabbage | ₹32 | 56 | ₹ ________ |
| 4. | Green peas | ________ | 125 | ₹3,125 |
| Total money earned through the sale | ________ | |||
| S.No. | Vegetable | Cost of 1 kg | Quantity (kg) | Total Amount |
|---|---|---|---|---|
| 1. | Radish | ₹26 | 78 | ₹2,028 |
| 2. | Potato | ₹20 | 112 | ₹2,240 |
| 3. | Cabbage | ₹32 | 56 | ₹1,792 |
| 4. | Green peas | ₹25 | 125 | ₹3,125 |
| Total money earned through the sale | ₹9,185 | |||
Potato: 2,240 ÷ 20 = 112 kg
Cabbage: 32 × 56 = ₹1,792
Green peas: 3,125 ÷ 125 = ₹25 per kg
Total: 2,028 + 2,240 + 1,792 + 3,125 = ₹9,185
| S.No. | Vegetable | Cost of 1 kg | Quantity Supplied (in kg) | Total Amount |
|---|---|---|---|---|
| 1. | Radish | ₹26 | 78 | ₹ ________ |
| 2. | Potato | ₹20 | ________ | ₹2,240 |
| 3. | Cabbage | ₹32 | 56 | ₹ ________ |
| 4. | Green peas | ________ | 125 | ₹3,125 |
| Total money earned through the sale | ________ | |||
The table is Munshi Lal’s sale record — it says what he sold, how much of it, at what rate, and how much money it brought.
Sample answer — a bill written during the role-play:
| S.No. | Item | Rate per kg | Quantity (kg) | Amount |
|---|---|---|---|---|
| 1. | Onion | ₹30 | 3 | ₹90 |
| 2. | Tomato | ₹24 | 2 | ₹48 |
| 3. | Brinjal | ₹40 | 1 | ₹40 |
| 4. | Lady’s finger | ₹35 | 2 | ₹70 |
| Total | ₹248 | |||
138 + 40 = 178
178 + 70 = ₹248
If the customer gives a ₹500 note:
500 − 248 = ₹252 change
Let Us Solve — Page 134Divide, identify the remainder, and check N = D × Q + R
506 ÷ 5 = 101, remainder 1.
500 ÷ 5 = 100
6 ÷ 5 = 1 with 1 left over
Quotient = 100 + 1 = 101, Remainder = 1
918 ÷ 8 = 114, remainder 6.
8) 918 ( 1 1 4
9 Hundreds ÷ 8 = 1 Hundred, 1 Hundred left
1 H + 1 T = 11 Tens ÷ 8 = 1 Ten, 3 Tens left
3 T + 8 O = 38 Ones ÷ 8 = 4 Ones, 6 left
Quotient = 114, Remainder = 6
8,126 ÷ 7 = 1,160, remainder 6.
−7000 → 1126 (7 × 1000)
−700 → 426 (7 × 100)
−420 → 6 (7 × 60)
Quotient = 1000 + 100 + 60 = 1,160, Remainder = 6
9,324 ÷ 4 = 2,331, remainder 0.
8000 ÷ 4 = 2000
1200 ÷ 4 = 300
120 ÷ 4 = 30
4 ÷ 4 = 1
2000 + 300 + 30 + 1 = 2,331, Remainder = 0
876 ÷ 6 = 146, remainder 0.
600 ÷ 6 = 100
240 ÷ 6 = 40
36 ÷ 6 = 6
100 + 40 + 6 = 146, Remainder = 0
7,008 ÷ 3 = 2,336, remainder 0.
3) 7008 ( 2 3 3 6
7 Th ÷ 3 = 2 Th, 1 Th left
1 Th + 0 H = 10 Hundreds ÷ 3 = 3 H, 1 H left
1 H + 0 T = 10 Tens ÷ 3 = 3 T, 1 T left
1 T + 8 O = 18 Ones ÷ 3 = 6 O, nothing left
Quotient = 2,336, Remainder = 0
934 ÷ 12 = 77, remainder 10.
−840 → 94 (12 × 70)
−84 → 10 (12 × 7)
Quotient = 70 + 7 = 77, Remainder = 10
829 ÷ 23 = 36, remainder 1.
−690 → 139 (23 × 30)
−138 → 1 (23 × 6)
Quotient = 30 + 6 = 36, Remainder = 1
705 ÷ 18 = 39, remainder 3.
−540 → 165 (18 × 30)
−162 → 3 (18 × 9)
Quotient = 30 + 9 = 39, Remainder = 3
8,704 ÷ 32 = 272, remainder 0.
−6400 → 2304 (32 × 200)
−2240 → 64 (32 × 70)
−64 → 0 (32 × 2)
Quotient = 200 + 70 + 2 = 272, Remainder = 0
6,790 ÷ 45 = 150, remainder 40.
−4500 → 2290 (45 × 100)
−2250 → 40 (45 × 50)
40 is smaller than 45, so we stop.
Quotient = 100 + 50 = 150, Remainder = 40
5,074 ÷ 21 = 241, remainder 13.
−4200 → 874 (21 × 200)
−840 → 34 (21 × 40)
−21 → 13 (21 × 1)
Quotient = 200 + 40 + 1 = 241, Remainder = 13
Mathematical Statements — Page 135True or false, completing statements, and always / sometimes / never true
(a) 8 × 9 = 70 + 2
(b) 20 – 6 = 7 × 3
(c) 48 ÷ 3 = 4 × 4
(d) 89 – 9 = 90 + 0
(e) 25 + 10 = 45 – 10
Work out each side on its own, then compare.
| Part | Statement | Left side | Right side | True or False |
|---|---|---|---|---|
| (a) | 8 × 9 = 70 + 2 | 72 | 72 | True |
| (b) | 20 − 6 = 7 × 3 | 14 | 21 | False |
| (c) | 48 ÷ 3 = 4 × 4 | 16 | 16 | True |
| (d) | 89 − 9 = 90 + 0 | 80 | 90 | False |
| (e) | 25 + 10 = 45 − 10 | 35 | 35 | True |
(a) 7 × 6 = ____ + 17
(b) 87 + 6 = ____ × 31
(c) 63 + ____ = 74 – 4
(d) ____ ÷ 9 = 16 ÷ 2
(a) 25 (b) 3 (c) 7 (d) 72
(b) 87 + 6 = 93 → 93 ÷ 31 = 3
(c) 74 − 4 = 70 → 70 − 63 = 7
(d) 16 ÷ 2 = 8 → 9 × 8 = 72
The statement is ALWAYS TRUE. Five examples are given below, and no counter-example exists.
| Odd number | Odd number | Sum | Odd or even? |
|---|---|---|---|
| 3 | 5 | 8 | even |
| 7 | 9 | 16 | even |
| 11 | 13 | 24 | even |
| 1 | 7 | 8 | even |
| 25 | 31 | 56 | even |
The statement is NEVER TRUE. There is no such example.
| Number | × 2 | Result | Odd or even? |
|---|---|---|---|
| 3 | 3 × 2 | 6 | even |
| 7 | 7 × 2 | 14 | even |
| 10 | 10 × 2 | 20 | even |
| 25 | 25 × 2 | 50 | even |
| 99 | 99 × 2 | 198 | even |
The statement is SOMETIMES TRUE. Sometimes half a number is even, sometimes it is odd.
Three examples where it IS true:
| Number | Half of it | Odd or even? |
|---|---|---|
| 8 | 4 | even ✓ |
| 16 | 8 | even ✓ |
| 20 | 10 | even ✓ |
Three examples where it is NOT true:
| Number | Half of it | Odd or even? |
|---|---|---|
| 6 | 3 | odd ✗ |
| 10 | 5 | odd ✗ |
| 14 | 7 | odd ✗ |
| Statement | Always True | Sometimes True | Never True |
|---|---|---|---|
| Adding 10 to a number gives a multiple of ten. | |||
| Changing the order of the numbers in subtraction makes no difference. | |||
| In multiplication, doubling one number and halving the other keeps the product the same. | |||
| Multiplication by an odd number gives an even number. | |||
| Multiplying a number by 5 leads to numbers which have ‘0’ in the Ones place. |
| Statement | Always True | Sometimes True | Never True |
|---|---|---|---|
| Adding 10 to a number gives a multiple of ten. | ✓ | ||
| Changing the order of the numbers in subtraction makes no difference. | ✓ | ||
| In multiplication, doubling one number and halving the other keeps the product the same. | ✓ | ||
| Multiplication by an odd number gives an even number. | ✓ | ||
| Multiplying a number by 5 leads to numbers which have ‘0’ in the Ones place. | ✓ |
Chapter 9 of 15 – Maths
- Previous: Chapter 8 Weight and Capacity
- Next: Chapter 10 Symmetrical Designs
- All chapters: NCERT Solutions Class 5 Maths
Also for This Chapter
NCERT Solutions Class 5 Maths Chapter 9 Coconut Farm – Overview
| Class | Class 5 |
| Subject | Maths |
| Chapter | 9 – Coconut Farm |
| Textbook pages | 119 – 135 |
| Questions solved | 95 |
| Session | 2027 |
| Format | Full answers on this page + PDF |
NCERT Solutions Class 5 Maths Chapter 9 – FAQs
Where can I download NCERT Solutions Class 5 Maths Chapter 9 Coconut Farm PDF?
Read every answer on this page, or download the free PDF from the table at the top.
Is this for the 2027 session?
Yes, it follows the latest NCERT Class 5 Maths book for 2027.
How many questions are solved in NCERT Class 5 Maths Chapter 9?
All 95 questions of the chapter (textbook pages 119 – 135) – the in-text questions, activities and the end-of-chapter exercises.
How should I use these solutions?
Read the chapter in the NCERT book first, attempt the questions yourself, then check your answers here.